Pre college need help with 5

Answer:

No, it is not a linear function, rather a rational function

Step-by-step explanation:

Because the term on the left-hand side contains both x and y, then neither variable varies directly with the other, hence, it's a rational function:

2yx=4

yx=2

y=2/x

Answer:

Step-by-step explanation:

the answer is 10

Answer:

360

Step-by-step explanation:

Answer:

360 quarts

Step-by-step explanation:

300/10=30

30*12=360

Answer:

12

Step-by-step explanation:

335 + 13.75x = 500

Subtract 335 from each side

13.75x = 165

Divide each side by 13.75

x = 12

You can attend 12 dance classes with $500.

9514 1404 393

Answer:

  12 classes

Step-by-step explanation:

The total cost for c classes will be ...

  335 + 13.75c = 500

  13.75c = 165 . . . . . . . . . .subtract 335

  c = 12 . . . . . . . . . . . divide by 13.75

You will take 12 classes.

Answer:

1. 9

2. 5

Step-by-step explanation:

Answer:

A would be 9 and I am not sure about B.

Step-by-step explanation:

when a number is in | | these lines then they will always come out positive.

Answer:

[tex]1)6000m \\ \\ 2)0.008km \\ \\\ 3)100ml \\ \ \\ 4)30000g \\ \\ 5)0.034g[/tex]

MARK ME AS A BRAINLIST PLZ

Answer:

1

Step-by-step explanation:

Answer:

-4+7x-3=-21+-4=-25

Step-by-step explanation:

Answer:

x = -1, y = 2

Step-by-step explanation:

6x + 5y = 4

6x - 7y = -20

We already have a similar leading coefficient (6 for X), so we just subtract equation 1 from equation 2 to get:

12y = 24

Now solve normally:

y = 2

Then substitute into the first equation (or second, it doesn't matter)

6x + 10 = 4

6x = -6

x = -1

#5

Compare

[tex]\\ \sf\longmapsto \dfrac{2}{5}>\dfrac{2}{7}[/tex]

#6

[tex]\\ \sf\longmapsto \dfrac{1}{2}=\dfrac{2}{4}[/tex]

Compare

[tex]\\ \sf\longmapsto \dfrac{2}{4}<\dfrac{3}{4}[/tex]

Sonali was faster

Using the interpretation of a confidence interval, it is found that approximately 950 of those confidence intervals will contain the value of the unknown parameter.

A x% confidence interval means that we are x% confident that the population mean is in the interval.

In this problem:

0.95 x 1000 = 950

Hence, approximately 950 of those confidence intervals will contain the value of the unknown parameter.

A similar problem is given at https://brainly.com/question/24303674

Answer:

blue graph

Step-by-step explanation:

that graph looks similar to e^x

so f(-x) will be similar to e^-x

so it will be a reflection over y axis

see the picture below

We can consider that the mean serum protein level of the group of children who received high protein food is different from that of the general population with a normal serum protein value of 7.0g/100ml.

To determine whether the mean serum protein level of the group of 16 children who received high protein food is different from that of the general population with a normal serum protein value of 7.0g/100ml, we can perform a hypothesis test.

Let's denote:

μ1 = Mean serum protein level of the general population (assumed to be 7.0g/100ml)

μ2 = Mean serum protein level of the group fed on high protein food

The null hypothesis (H0) would be that there is no difference between the mean serum protein levels of the two groups:

H₀: μ₁ = μ₂

The alternative hypothesis (Ha) would be that there is a difference between the means:

Hₐ: μ₁ ≠ μ₂

Next, we calculate the sample mean and standard deviation of the group that received high protein food from the given serum protein values.

Assuming the serum protein values (in g/100ml) for the 16 children are as follows:

8.2, 7.6, 7.8, 7.4, 8.0, 7.9, 7.7, 7.5, 7.2, 7.3, 8.1, 7.6, 8.3, 8.0, 7.8, 7.9

Sample mean (x') = (sum of values) / (number of values) = (121.8) / (16) ≈ 7.613 g/100ml

Sample standard deviation (s) ≈ 0.352 g/100ml

Next, we perform a two-sample t-test (assuming equal variances) to compare the means of the two groups. We use the formula:

t = (x'₁ - x'₂) / √[(s₁² / n₁) + (s₂² / n₂)]

where x'₁ and x'₂ are the sample means of the two groups, s₁ and s₂ are the sample standard deviations, and n₁ and n₂ are the sample sizes.

Substituting the values, we get:

t ≈ (7.613 - 7.0) / √[(0.352² / 16) + (0.0² / 16)] ≈ 3.584

Now, we need to find the critical t-value at a given significance level (commonly set at 0.05) and degrees of freedom (df = n1 + n2 - 2). Since we have 16 + 16 - 2 = 30 degrees of freedom, the critical t-value (two-tailed test) is approximately 2.042.

Since the calculated t-value (3.584) is greater than the critical t-value (2.042), we reject the null hypothesis (H0). This means that there is a significant difference between the mean serum protein levels of the two groups.

In conclusion, based on the given data and the hypothesis test, we can consider that the mean serum protein level of the group of children who received high protein food is different from that of the general population with a normal serum protein value of 7.0g/100ml.

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#SPJ4

Answer:

C

Step-by-step explanation:

Answer:

Mention the drawing if you want an answer !!! How are we supposed to answer this question without the drawing the question is referring to ?????

Answer:

Hmmm, maybe this?

Step-by-step explanation:

Answer:B

Step-by-step explanation:

A: cannot be because it’s the same but the -m is not equal .

B: is the same as ,and B: because 2 (minus number) = right number .

C:Is nOne oF the AboVe

Sorry if explanation is not clear but yes it’s is 99% B ;)

But I do think it is wrong…

Hope you have a. Great day!

:)

Answer: Not Function

Step-by-step explanation:

The pattern is not consistent.

Step-by-step explanation:

option c is correct answer

Answer:

A) -11/-4

Step-by-step explanation:

-11/-2=11/4

Rewrite the fraction.

-(-11/4)

=11/4

Hope this helps :)

Answer:

So lets isolate y

we have

-2x+3y=9

2/3x +2y=0

Im gonna do the first equation

so -2x + 3y = 9

Add 2x on both sides

3y= 9+ 2x

Now divide by 3 to isolate y

y= 3+ 2/3x

Now we can subsitute y into any eqaution (I’m gonna do the second one) to solve.

2/3x+ 2(3+ 2/3x)= 0

Solve:

2/3x+ 6 + 4/3x = 0

6/3x +6= 0

2x+6=0

2x= -4

x= -2

Now we can subsitute this for any equation.

so I’m gonna do the first equation

-2(-2)+3y=9

4+3y=9

3y= 5

y= 5/3

y= 1 2/3

Final answer:

x=-2

y= 1 2/3

Answer:

20:12

brainlest if it helped

Step-by-step explanation:

Answer:

20:12

Step-by-step explanation:

if you multiply 5:3 by 4, they'll end up with 20:12.

well, first off let's check which term has the highest degree, hmmm in this case it has to be the x³, so that's the leading term and its coefficient is 9.

This is an interesting problem.

But first, let us define what are the three possible cases :

A system of linear equations : a system of equation is when you have two equations with the same unknown variables, that you need to solve both together. Example : "x+y = - 7 AND x + y = - 4" are two equations that form a system of equation.

Plus they are linear, a linear equation is simply an equation of the form : y = ax + b where a and b are real numbers.

Here for example x + y = - 7 is a linear equation. Because y = 1 × x - 7

where a = 1 and b = - 7.

Consistent Dependent : A system of equation is consistent Dependant when it has an infinite number of solutions.

Consistent Independent : A system of equation is consistent Dependant when it has exactly one solution.

Inconsistent : A system of equation is Inconsistent if it haas no solutions.

Now, with those definitions above, we can work on our problem :

1. x + y = - 7 and x + y = - 4

Look at the picture attached the lines are parallel to each other so here the answer is Inconsistent

2. Same line : consistent dependent

3. Parallel Lines : Inconsistent

4. Lines cross at exactly one point :Consistent Independent

5. Lines cross at exactly one point : Consistent Independent.

You can see the graph of each systems in the pictures attached below.

Good luck, you will succeed :)

Based on the information given the balance in Coloma’s capital account at the end of the year is: d. $164,000.

First step is to calculate the interest on capital for each partner

Alexander=$90,000×5%=$4,500

Bertrand=$100,000×5%=$5,000

Coloma=$160,000×5%=$8,000

Second step is to calculate Coloma capital and drawing

Coloma capital =$160,000 + (5% x $160,000)

Coloma capital=$160,000+ $8,000

Coloma capital=$168,000

Coloma drawing=$168,000-$25,000

Coloma drawing=$143,000

Third step is to calculate Coloma share of profit

Share of profit=$115,000-$45,000-$4,500-$5,000-$8,000

Share of profit=$52,500

Coloma profit=4/(3+3+4)×$52,500

Coloma profit=4/10×$52,500

Coloma profit=4/(3+3+4)×$52,500

Coloma profit=$21,000

Fourth step is to calculate balance in Coloma’s capital account

Coloma’s capital account balance=$143,000+$21,000

Coloma’s capital account balance=$164,000

Inconclusion the balance in Coloma’s capital account at the end of the year is: d. $164,000.

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Using simple interest, it is found that:

a) The monthly payment will be of $222.57.

b) In total, the car will cost $18,251.9275.

c) $16,025.1775 will be paid in interest.

The amount of money accrued after t years, using simple interest, with an initial value of P and a decimal rate of r is given by:

[tex]A(t) = P(1 + rt)[/tex]

In this problem:

Item a:

The amount of money accrued will be of:

[tex]A(6) = 12618.25[1 + 0.045(6)] = 16025.1775 [/tex]

Payment over 6 x 12 = 72 months, hence, the monthly payment will be of:

[tex]m = \frac{16025.1775}{72} = 222.57[/tex]

The monthly payment will be of $222.57.

Item b:

The total cost is composed by:

Hence:

[tex]T = 0.15(14845) + 16025.1775 = 18251.9275[tex]

In total, the car will cost $18,251.9275.

Item c:

As found in item a, $16,025.1775 will be paid in interest.

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The coefficient of kinetic friction between the oil-covered road

and the car tires. is 0.51

To solve this question, we would consider one of the equations of motion.

v² = u² + 2as, where

v = final velocity, which is also equal to 0

u = initial velocity, which is 20m/s

s = skid marks, which is 40 meters long

a = acceleration, which is unknown

0² = 20² + 2*a*40

0 = 400 + 80a

80a = -400

a = -400/80

a = -5 m/s

Also, it is known that acceleration a = (mu)g, where mu is the coefficient of kinetic friction and g is the acceleration due to gravity.

-5 = mu * 9.8

mu = -5/9.8

mu = 0.51

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