Question is on picture attached

Answer:

just d

Step-by-step explanation:

Hope this helps!❆

Answer:

OMG️️

Step-by-step explanation:

What is this❓

what have you wrote✍️

Answer:

hye nice what have written tell then I will answer you.

Answer:

(x+a)²-7=x²+10x+b

simplifying,we get

x²+2ax+a²-7=x²+10x+b

the coefficient of x on both sides should be equal

therefore

2a=10

a=10/2=5

also for b

a²-7=b

5²-7=25-7=b

b=18

a=5

(x - 10)² is the graph x² by translation of 10 units moved to the right.

Answer:

6/50

Step-by-step explanation:

0.12 as a fraction is 6/50.

Answer:

3/25

Step-by-step explanation:

12/100=6/50=3/25 .

Answer:

  10%

Step-by-step explanation:

The change is 90-100 = -10. As a percentage of the original amount, that is ...

  -10/100 × 100% = -10%

The change from 100 to 90 is a reduction of 10%.

Step-by-step explanation:

The no. of red blood cells is 2.4993*10^13 more than the no. of white blood cells

Supplementary angles sum up to 180°. Take the missing angle as 'x'.

148 + x = 180

x = 180 - 148

x = 32°

=》 Angle ABD = 32°

_________

Hope it helps!

RainbowSalt2222 ☔

Answer:

32 degrees

Step-by-step explanation:

Hi there!

Angle ABC measures 180 degrees since it's a straight line.

To find angle ABD, we simply subtract the given angle that measures 148 degrees from 180:

180-148 = 32

Therefore, angle ABD measures 32 degrees.

I hope this helps!

The true option is: (d) Hugo has 15 songs in his music player. He will add 10 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at least 135 songs?

The inequality is given as:

[tex]\mathbf{135 \le 10r + 15}[/tex]

Rewrite as:

[tex]\mathbf{10r + 15\ge 135 }[/tex]

From the options, we can see that the inequality represents songs in a music player.

Linear inequalities can be represented as:

[tex]\mathbf{mx + b \ge y}[/tex]

Where:

m represents the rate i.e. 10

b represents the y-intercept or base i.e. 15

>= represents at least

So, the inequality can be interpreted as:

Hence, the true option is (d)

Read more about linear inequalities at:

https://brainly.com/question/11897796

Answer:

$22.48 for 4 pairs of jeans is a better deal.

Step-by-step explanation:

To find the price of one pair of jeans, you divide.

39.55 ÷ 7 = price of 1 pair of jeans

39.55 ÷ 7 = $5.65

22.48 ÷ 4 = price of 1 pair of jeans

22.48 ÷ 4 = $5.62

The price difference between the two prices is 3 cents. So, $22.48 for 4 pairs is a better deal that $39.55 for 7 pairs of jeans.

Hope this helps!

Answer:

so when you Mutpliy #*#  = #product

Step-by-step explanation:

EX: 3*4=12

Answer:

B

Step-by-step explanation:

The sentence representing the equation is 912 is the same as 15 decreased by a number.

An equation is a mathematical statement that shows that two mathematical expressions are equal.

Given an equation, 912 = 15 − x

Here, 912 is equal to a number which is being subtracted from 15.

Hence, The sentence representing the equation is 912 is the same as 15 decreased by a number.

For more references on equation, click;

https://brainly.com/question/10413253

#SPJ2

Answer:

y = -4x + 5.

Explanation:

Count rise/run to find the slope, find the y-intercept.

Answer:

y = -4x + 3

Step-by-step explanation:

First, find the slope using two points [(-2, 13), (0, 5)] and the formula [ y2-y1/x2-x1 ].

5-13/0-(-2)

-8/2

-4

Second, find the y-intercept which we know is (0, 5) since we used it in the previous part.

Third, input everything we found.

y = -4x + 5

Best of Luck!

Answer:

A,  2

Step-by-step explanation:

We can immediately rule out B and C; they are odd numbers while S is an even number.

We can also rule out D and E. This is because D and E are greater than or equal to 10, while S is less than 10.

A number that can fulfill the requirements for both A and S is 2

Answer:

r = 5q / (p + 10)

Step-by-step explanation:

p = 5(q - 2r)/r

multiply both sides by r

pr = 5(q - 2r)

distribute

pr = 5q  - 10r

add 10r to both sides

pr + 10r = 5q

Factor out r

r(p + 10) = 5q

divide both sides by p + 10

r = 5q / (p + 10)

Answer:

327.5

Step-by-step explanation:

8452/23 = 327.478

Round to about 327.5 books per class

Answer:

each class gets 367 books

Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

The probability of red is:

[tex]p = \frac{n}{n + 8}[/tex]

Supposing [tex]p = \frac{7}{10}[/tex], we solve for n:

[tex]\frac{n}{n + 8} = \frac{7}{10}[/tex]

[tex]10n = 7n + 56[/tex]

[tex]3n = 56[/tex]

[tex]n = \frac{56}{3}[/tex]

[tex]n = 18.67[/tex]

Since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]

A similar problem is given at https://brainly.com/question/15536019

With number = 6, the while condition is satisfied. Then number is decremented by 3, meaning we replace the value of number (6) with its current value minus 3 6 - 3 = 3.

Then with number = 6, we still have number > 0, so we decrement again and end up with number = 0.

With number = 0, number > 0 is no longer true, so we exit the loop.

Then the print statement simply prints the current value of number, which is 0.

Answer:

u need to use the quadratic formula

Step-by-step explanation:

I think this is about it

Answer:

C = 13

Step-by-step explanation:

A²+B²=C²

where c is the hypothenuse

5²+12²=c²

25+144=c²

169=c²

√169 = c

13 = c

Answer:

[tex]\frac{7}{11}[/tex]

Step-by-step explanation:

We require 2 equations with the repeating digits (63) placed after the decimal point.

let x = 0.636363..... (1) multiply both sides by 100

100x = 63.6363... (2)

Subtract (1) from (2) thus eliminating the repeating digits

99x = 63 ( divide both sides by 99 )

x = [tex]\frac{63}{99}[/tex] = [tex]\frac{7}{11}[/tex] ← in simplest form

Answer:

12

Step-by-step explanation:

the angle is defined by equation ((n-2)*180)/n,where n is number of sides of a regular polygon

so here 180n-360=150n

30n=360

n=12

It looks like given matrices are supposed to be

[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]

[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]

He needed to make a total of 1980 + 630 = $2610

$2610 / 45 = 58

Answer: 58

Answer:

ggggggggggggggggggggg