Recall the following statement from Worksheet 11: Theorem 1. If G = (V, E) is a simple graph (no loops or multi-edges) with |V] = n > 3 vertices, and each pair of vertices a, b eV with a, b distinct and non-adjacent satisfies deg(a) + deg(6) > n, then G has a Hamilton cycle. (a) Using this fact, or otherwise, prove or disprove: Every connected undirected graph having degree sequence 2, 2, 4, 4, 6 has a Hamilton cycle. (b) The statement: Every connected undirected graph having degree sequence 2, 2, 4, 4,6 has a Hamilton cycle is A. True B. False.

The correct option is (a). The other options are incorrect because the given series satisfies all the conditions of the alternating series test, and thus, the test is applicable.

The given series is as follows: n+1
(-1)
(n +1)
7t
ns1

An alternating series test is a significant tool for determining whether or not a given series converges. A series is said to be convergent if the sequence of partial sums converges to a finite limit, and divergent otherwise. For the alternating series test to apply to a series, there must be the following three conditions: The series must have alternating terms, meaning that every other term is negative. The sequence of absolute values of the terms of the series must be monotonically decreasing, meaning that the absolute values of each successive term must be smaller than the preceding term's absolute value. The sequence of absolute values must approach zero in the limit. Thus, it can be observed that for the given series, the first two conditions are met. Now, to check the third condition, we must calculate the limit of the terms.

Let us take an=1/(n+1)7tnSince lim an=0, the series passes the third test as well.

Thus, we can apply the alternating series test to the given series. By the alternating series test, we have that the series converges. Thus, the correct option is (a). The other options are incorrect because the given series satisfies all the conditions of the alternating series test, and thus, the test is applicable. Thus, we can safely conclude that option (a) is correct.

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Answer:

[tex] m\angle SXW =113\degree [/tex]

Step-by-step explanation:

In circle with center X, VS is diameter.

So [tex] \widehat {SWV} [/tex] is a semicircular arc.

[tex] \therefore m\widehat{SWV} = 180\degree [/tex]

[tex] \therefore (12x+7)\degree + (21x +8)\degree = 180\degree [/tex]

[tex] \therefore (33x+15)\degree = 180\degree [/tex]

[tex] \therefore 33x+15 = 180 [/tex]

[tex] \therefore 33x = 180-15 [/tex]

[tex] \therefore 33x = 165 [/tex]

[tex] \therefore x =\frac{165}{33} [/tex]

[tex] \therefore x =5 [/tex]

[tex] m\angle SXW =m\widehat{SW} [/tex]

(Measure of central angle is equal to the measure of its corresponding minor arc)

[tex] m\angle SXW =(21x + 8)\degree [/tex]

[tex] m\angle SXW =(21\times 5+ 8)\degree [/tex]

[tex] m\angle SXW =(105+ 8)\degree [/tex]

[tex] m\angle SXW =113\degree [/tex]

Answer:

Building new bike paths.

Step-by-step explanation:

The reason I choose this answer was because the other ones would all use more gas when bike paths would limit the amount of driving and add to the amount of biking done.

Answer:

Step-by-step explanation:

Distributive Property

commutative property of addition.

assosciative property of addition

Answer:

distrubutive property

Step-by-step explanation:

Answer:

The top graph.

Step by step:

Before the tickets go on sale, 120 tickets were already sold.

After that, the tickets sell at a constant rate for a total of 8 hours.

At the end of this time, all the tickets were sold (we have 0 tickets left)

If x (horizontal axis) represents the hours since tickets go on sale, and y (vertical axis) represents the number of raffle tickets sold.

Then, at x = 0, we should already see y = 120

Because we start with 120 tickets sold.

Then, as x increases, the number of tickets sold also should increase, until we get x = 8 hours, where y stops increasing because all tickets are already sold.

Then we should have an increasing line that stops increasing at x = 8 hours.

Then the correct option is the above graph, where we have:

An increasing line.

y = 120 in the vertical axis (y = 120 when x = 0)

The solution to the given integral is: frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

Given integral: int_0^1 (1-t^2)g(x) dt

To solve the given integral, we will make use of Beta function.

The Beta function is defined as follows:

B(p,q) = int_0^1 t^{p-1}(1-t)^{q-1} dt

Using substitution, t = sin theta, we get:

int_0^1 (1-t^2)g(x) dt = int_0^{frac{pi}{2}} (1-sin^2 theta)g(x) cos theta dtheta

= int_0^{frac{\pi}{2}} cos^2 theta g(x) d\theta

= frac{1}{2}\int_0^{\frac{\pi}{2}} (1+\cos 2\theta) g(x) d\theta

= frac{1}{2} \left(\int_0^{\frac{\pi}{2}} g(x) dtheta + int_0^{frac{pi}{2}} g(x) cos 2theta dtheta right)

Using B(p,q)$ for the second integral, we get:

int_0^1 (1-t^2)g(x) dt = frac{1}{2}left(frac{pi}{2}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x) right)

= frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

Hence, the value of the given integral int_0^1 (1-t^2)g(x) dt is frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

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Answer: 96 oz

Step-by-step explanation:

On the graph of f(x) = sin(x) on the interval [0, 2π), the function achieves a maximum value at x = π/2.

The function f(x) = sin(x) is a periodic function with a period of 2π. Within one period, the function oscillates between the values of -1 and 1. The maximum value of sin(x) is 1, and it occurs when the angle x is π/2.

In the given interval [0, 2π), the function f(x) = sin(x) completes one full period. Starting from x = 0, the function increases and reaches its maximum value of 1 at x = π/2. After that, it starts decreasing and goes through one complete cycle by the time it reaches x = 2π.

Therefore, on the graph of f(x) = sin(x) on the interval [0, 2π), the function achieves a maximum value at x = π/2.

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Answer:

I got 1.75 too

Step-by-step explanation:

20/3.5 is 5.7

10/5.7 is 1.75

The rectangular billboard is 1.75 inches tall in the scale model.

The ratio of the scale of an original thing to a new object that is a representation of it but of a different size is known as a scale factor (bigger or smaller).

The fundamental equation to determine a figure's scale factor is written as, Scale factor is equal to the ratio between the dimensions of the new and old shapes.

Given that, a rectangular billboard for a high school is 10 feet high and 20 feet long.

In a scale model of the school, the billboard is 3.5 inches long.

So, the scale factor = 3.5/20

= 0.175 inches

Thus, the height is 10×0.175

= 1.75 inches

Therefore, the rectangular billboard is 1.75 inches tall in the scale model.

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The range of the function f is (0, [infinity]). The correct option is d.

The range of the function f : [0, [infinity]) → R, defined by the rule f(t) = e^(-2x), can be determined by analyzing the behavior of the exponential function.

As x approaches infinity, e^(-2x) approaches 0, but it never reaches 0. This means that the function f(t) will approach 0 as t approaches infinity, but it will never actually reach 0.

On the other hand, as x approaches negative infinity, e^(-2x) approaches positive infinity. Therefore, the function f(t) will approach positive infinity as t approaches 0.

Based on this analysis, we can conclude that the range of the function f is (0, [infinity]), which means option (d) is the correct answer.

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a. The mean of the data set is 6.3333, the median is 4.5, and there is no mode. b. The range of the data set is 9, and the variance is 11.8667.

a. To compute the mean, we sum up all the values in the data set and divide it by the number of data points. In this case, the sum is 4 + 9 + 10 + 4 + 3 + 12 = 42. Dividing this by 6 (the number of data points), we get a mean of 42/6 = 6.3333.

To compute the median, we arrange the data set in ascending order: 3, 4, 4, 9, 10, 12. Since the number of data points is even, we take the average of the middle two values, which are 4 and 9. The median is (4 + 9) / 2 = 4.5.

The mode is the value(s) that appear most frequently in the data set. In this case, none of the values are repeated, so there is no mode.

b. The range is the difference between the largest and smallest values in the data set. In this case, the largest value is 12 and the smallest value is 3, so the range is 12 - 3 = 9.

The variance measures the variability of the data set. It is calculated by taking the average of the squared differences between each data point and the mean. Using the formula for sample variance, the calculations are as follows:

[tex](4 - 6.3333)^2 + (9 - 6.3333)^2 + (10 - 6.3333)^2 + (4 - 6.3333)^2 + (3 - 6.3333)^2 + (12 - 6.3333)^2 = 71.2[/tex]

Dividing this sum by n-1 (where n is the number of data points) gives us the sample variance: 71.2 / 5 = 14.24.

Therefore, the variance is 14.24.

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Answer:

81

Step-by-step explanation:

81

Answer:

6+3=9x9=81 final answer 81.

Step-by-step explanation:

Answer: x=6

Step-by-step explanation: Hope this help :D

Answer:

2305.33π square inches

Step-by-step explanation:

The volume of a sphere is V = (4/3) πr ^ 3

Because the diameter is 24, the radius is 12.

Substituting 12 for r in the above equation:

V = (4/3) π (12 ^ 3) = (4/3) (1728) π = 2305.33π square inches, or 7238.23 square inches.

Answer:

Measure the length, width and height of the square or rectangle prism or object in inches. Record each of these on paper. Multiply the three measurements together to find the volume using either paper and pencil or a calculator. This is the equation: Volume = length x width x height.

I think that is:

24/2 = 12² = 144 x 3.14 = 452.16.

¯\_(ツ)_/¯

Answer:

it is wrong

Step-by-step explanation:

the reason it is wrong is because I said so

Answer:

I am going to say no BECAUSE there are two y values, on the same point. For it to be linear it should only have one point per value. I think... good luck.

Answer:

-3.5

all u have to do is get the 2 and the 7 and just subtract and the 8 and 10

The forces [tex]F_3[/tex] that must act on the object so that the sum of the forces is zero are [tex]F_3[/tex] = (-10, -10, -12).

To find the forces [tex]F_3[/tex] that must act on the object so that the sum of the forces is zero, we need to find a vector [tex]F_3[/tex] that satisfies the equation

[tex]F_1 + F_2 + F_3 = 0.[/tex]

Given the forces:

[tex]F_1[/tex] = (10, 6, 3)

[tex]F_2[/tex] = (0, 4, 9)

We can rearrange the equation to solve for [tex]F_3[/tex]:

[tex]F_3 = -F_1 - F_2[/tex]

Now, let's calculate [tex]F_3[/tex]:

[tex]F_3[/tex] = -(10, 6, 3) - (0, 4, 9)

  = (-10, -6, -3) - (0, 4, 9)

  = (-10-0, -6-4, -3-9)

  = (-10, -10, -12)

Therefore, the forces [tex]F_3[/tex] that must act on the object so that the sum of the forces is zero are [tex]F_3[/tex] = (-10, -10, -12).

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Answer:

-----------------------

Standard form of a quadratic equation:

Convert the given into standard form:

Compare the equations to find coefficients

The value of x from the figure is [tex]cos^-1(\frac{14}{13} )[/tex]

From the given diagram, we have the following

The required angle is x

Using the SOH CAH TOA identity

[tex]cos \theta =\frac{adj}{hyp}\\ cos \theta =\frac{14}{13}\\ \theta = arccos(\frac{14}{13} )[/tex]

Hence the value of x from the figure is [tex]cos^-1(\frac{14}{13} )[/tex]

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Answer:

1/11

Step-by-step explanation:

(6, 4) and (-5, 3)

Slope:

m=(y2-y1)/(x2-x1)

m=(3-4)/(-5-6)

m= (-1)/(-11)

m = 1/11

Answer:

45

Step-by-step explanation:

3 out of 12 is 1/4, or 0.25, so if you divide 180 by 4, then using the same logic, you can expect 45 kids to have played last year.

3 = 1/4 OR .25 of 12, 12 divided by 4 = 3

180 divided by 4 = 45

Answer:

yes its 45 i did the test and i got an 100

Step-by-step explanation:

heres proof

In the context of the Exponential distribution with parameter β, the statistics βYn and 2nβYn are both pivotal quantities. They can be used to construct confidence intervals for β.

A pivotal quantity is a function of the data and a parameter that has a known distribution regardless of the parameter's true value. In this case, both βYn and 2nβYn are pivotal quantities because their distributions (Gamma and chi-squared, respectively) do not depend on the unknown parameter β.

To construct a 95% confidence interval for β using the first pivot, βYn, we can utilize the properties of the Gamma distribution. The interval will be of the form [a, b], where a and b are the lower and upper bounds determined based on the cumulative distribution function of the Gamma distribution. This interval represents a range of plausible values for the parameter β.

Similarly, to construct a 95% confidence interval using the second pivot, 2nβYn, we can employ the chi-squared distribution. The interval will have the form [c, d], where c and d are the lower and upper bounds determined based on the cumulative distribution function of the chi-squared distribution. This interval also represents a range of plausible values for β.

When comparing both intervals, considerations such as width, interpretability, and efficiency are important. The recommended interval would be the one that is narrower (smaller width) and easier to interpret. Additionally, the efficiency of the estimators used in constructing the intervals should be taken into account.

In conclusion, both pivotal quantities, βYn and 2nβYn, can be used to construct 95% confidence intervals for β. The choice between them depends on factors such as width, interpretability, and efficiency. A comprehensive analysis considering these factors will determine the most suitable interval to use.

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Equilibrium point is a sink, a source, a saddle, or a nodal source (centre).

The equilibrium point is a sink in a phase diagram. A sink is a point towards which any system that begins near it will converge. This is a stable point that attracts nearby systems towards it. When the system comes close to the sink, it will slow down as it approaches, then stop at the sink. A sink is a stable equilibrium point. This is also known as an attractor that attracts nearby points. The phase diagram is a visual representation of the equilibrium point's behavior in the system. The arrows that come into or go out of the sink are pointing towards it, and they represent the direction of the flow of the system. Thus, the sink's shape is inward, indicating that any system near it will converge towards it.

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Answer:

B. Addition Property of Equality; Division Property of Equality

Step-by-step explanation:

The answer is D, because in step c. you add  to both sides to get rid of the  on the right hand, so you use the fact that you can add the same number to both sides of an equation.

Likewise, in step f. you divided both sides by  to get rid of the  coefficient, so you use the fact that you can divide both sides of an equation by the same number.

...............................................................................................................................................

Answer:

Option C and B

Step-by-step explanation:

In the question step C is 23 + 11 = -11 +(-4x) + 11

which is in the form of a + b = c + a

In step C we have added 11 on both the sides to eliminate 11 from right side of the equation.

property which signifies this step is

Addition property of equality :

In step 'f' expression is

In this step equation has been divided by -4 on both the sides to eliminate 4 from the numerator.

In this step division property of equality has been applied.

Therefore Option C and B are the correct options.

Answer:

B. Addition Property of Equality; Division Property of Equality

Step-by-step explanation:

hope it helps...

Answer:

1.

2. 4:7

3.

4.10:4

5.

id k the rest sorry :/

Answer:

3

Step-by-step explanation:

[tex]18*\frac{1}{6} \\\\3[/tex]

Answer:

=3x

Step-by-step explanation:

18x^1 / 6

=3x

Answer:

I believe its 10 but forgive me if I'm wrong