Shade the points in the plane whose x-coordinates are greater than their y-coordinates. Write the inequality that describes these points.

The domain of a composite function is the set of all possible inputs for both functions, and the range is the set of all possible outputs.

A composite function is the combination of two or more functions. The domain of a composite function is the set of all possible inputs for both functions. This means that the domain is the set of all the possible inputs that can be used in either of the functions that make up the composite function. The range of a composite function is the set of all possible outputs. This means that the range is the set of all the possible outputs that can be obtained by the combination of the two or more functions. When graphing a composite function, it is important to remember that the domain and range of the composite function are the union of the domain and range of the individual functions in the composite function. The domain and range of a composite function can be determined by first determining the domains and ranges of the individual functions and then combining them.

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The exponential function formula for the parent function is found to be

[tex]f(x) = 2^x[/tex]

What is an exponential function?

The formula for an exponential function is [tex]f(x) = a^x[/tex], where x is a variable and a is a constant that serves as the function's base and must be bigger than 0.

The general formula to find an exponential function is [tex]f(x) = ab^x[/tex]

From the given graph, we take two points on the graph : (1,2) and (2,4)

Substituting in the above equation, taking f(x) as y

[tex]ab^1 = 2\\\\ab^2 = 4[/tex]

Solving the above equations, we get

a= 1, b=2

So the parent function  [tex]f(x) = 2^x[/tex].

Now using this function we can graph [tex]f(2x), -3f(x), 2f(2x)\\[/tex].

[tex]f(2x) = 2^{2x} = 4^x\\\\-3f(x) = -3 * 2^x\\2f(2x) = 2 * 4^x[/tex]

Therefore using the Desmos, the above exponential functions are graphed.

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There are 29.8 students in the running club overall.

The quotient is the number we get when we divide two numbers. For instance, in the case of 8 4 = 2, where the division result is 2, it is the quotient. The divisor is 4, and the dividend is 8.

The remnant is the amount that does not wholly enter the divisor, whereas the quotient is the number of times a division is completed to the fullest extent possible. By way of illustration, 42 is the quotient and 1 is the remainder when 127 is divided by 3 to provide 42 R 1.

Given,

30+9-46 (2/3) % × 30

Multiply

30 + 9 - (46 × 30) × 0.00666666666666667

Calculate quotient,

30 + 9 - 1380 × 0.00666666666666667

Simplifying quotient,

30 + 9 - 9.2

Then we get,

39 - 9.2

Then 29.8

get the result: 29.8

The complete question is:

Thirty 8 th  graders signed up for running club, however nine dropped out before the first practice. If 46 (2/3)  of the club are 8 th graders, how many total students are in the running club?

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Answer:

-----------------------------

15 inches of wire costs 90 cents, then 1 inch of wire costs:

The length of wire for 72 cents:

Answer:

that is the persons username I got it from

Step-by-step explanation:

3 and 7

6 and 14

9 and 21

12 and 28

15 and 35

Step-by-step explanation:

If the two numbers they give you are 9 and 21, then the cranberry's are 3 ounces and the apples are 7 fliud ounces, then you can divide and multiply them to your will.

The difference between logarithmic and exponential functions can be determined by looking at the form of the equation and by performing a calculation.

A logarithmic equation is written as log_b(x) = y, where b is the base and x and y are variables. An exponential equation is written as b^x = y, where b is the base and x and y are variables.

To determine if an equation is logarithmic or exponential, begin by comparing the form of the equation to the two equations above. If the equation is written in the form of log_b(x) = y, then it is a logarithmic equation. If the equation is written in the form of b^x = y, then it is exponential.

To perform a calculation, plug in a known value for x and then solve for y. For example, if the equation is log_2(x) = 4, then plug in x = 8. The calculation would then be:

log_2(8) = 4

This is a logarithmic equation, as the form of the equation matches log_b(x) = y.

If the equation is b^x = 16, then plug in x = 4. The calculation would then be:

2^4 = 16

This is an exponential equation, as the form of the equation matches b^x = y.

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Answer:

g>5

Step-by-step explanation:

Simply add 6 to both sides to get g>5

The two lines are neither parallel nor perpendicular to each other.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given that the two equations of the lines are y= -1/3x+2 and 5y+15x=-40.

y= -1/3x+2

5y+15x=-40.

5y = -15x - 40

y =-3x - 40/3

Here the slopes of the lines are,

m₁= -1 / 3

m₂ = -3

For the lines to be parallel the slopes should be equal and for the lines to be perpendicular the slopes should be inverse and reciprocal.

Here the slopes are neither equal nor have the inverse reciprocal.

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[tex](\stackrel{x_1}{8}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{2}-\underset{x_1}{8}}} \implies \cfrac{-4 +4}{-6} \implies \cfrac{ 0 }{ -6 } \implies \text{\LARGE 0}[/tex]

The ratio of spice A to spice B is : 49/87

Here, 2 1/3 grams of spice A was mixed with 4 1/7 grams of spice B.

First we convert the improper fraction into a proper fraction.

For improper fraction2 1/3,

2 1/3

= (2 × 3)/3 + 1/3

= 6/3 + 1/3

= (6 + 1)/3

= 7/3 which is a proper fraction.

and for 4 1/7

= (4 × 7)/7 + 1/7

= 28/7 + 1/7

= (28 + 1)/7

= 29/7

The ratio of spice A to spice B would be,

(2 1/3) / (4 1/7 )

= (7/3) / (29/7)

= (7/3) × (7/29)

= (7 × 7)/(3 × 29)

= 49/87

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Answer:

F = 24

Step-by-step explanation:

simplify 1/8

(1/8 x F) - 3 = 0

3 = 3/1 = 3 x 8/ 8

F x (3 x 8) / 8 F - 24/ 8

F - 24/ 8 = 0

F - 24/ 8 = 0 x 8

Answer:

  24

Step-by-step explanation:

You want to know f for 1/8f = 3.

Multiply the given equation by 8 to undo the multiplication by 1/8:

  8(1/8f) = 8(3)

  f = 24 . . . . . . . . simplify

The value of f is 24.

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A linear graph is one whose equation is in the form y = mx + b, where m and b are constants. A quadratic graph is one whose equation is in the form y = ax^2 + bx + c, where a, b, and c are constants.

To determine if a given graph is linear, calculate the equation of the line by finding two points on the graph and plugging them into the equation y = mx + b.

For example, if the two points on the graph are (2, 3) and (5, 7), then plugging these values into the equation gives us:

y = mx + b

3 = m*2 + b

7 = m*5 + b

Solving this system of equations gives m = 2 and b = -1, so the equation of the line is y = 2x - 1.

A quadratic graph is one whose equation is in the form y = ax^2 + bx + c, where a, b, and c are constants. To determine if a given graph is quadratic, calculate the equation of the parabola by finding three points on the graph and plugging them into the equation y = ax^2 + bx + c.

For example, if the points on the graph are (1, 6), (2, 13), and (3, 24), then plugging these values into the equation gives us:

y = ax^2 + bx + c

6 = a*1^2 + b*1 + c

13 = a*2^2 + b*2 + c

24 = a*3^2 + b*3 + c

Solving this system of equations gives a = 4, b = -5, and c = 6, so the equation of the parabola is y = 4x^2 - 5x + 6.

An exponential graph is one whose equation is in the form y = a*b^x, where a and b are constants. To determine if a given graph is exponential, calculate the equation of the line by finding two points on the graph and plugging them into the equation y = a*b^x.

For example, if the two points on the graph are (2, 16) and (3, 24), then plugging these values into the equation gives us:

y = a*b^x

16 = a*b^2

24 = a*b^3

Solving this system of equations gives a = 2 and b = 2, so the equation of the line is y = 2*2^x.

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Answer:

(x to the second power)+x+4

Step-by-step explanation:

Ur welcome

Answer:

0.0558

Step-by-step explanation:

3% is out of hundred so we multiply

3%×1.86=0.0558

Checking:

0.0558÷1.86=0.03

0.03=3%

Answer:

Step-by-step explanation:

Ya

Answer:

it 33 pts not 50

Answer:

cant answer sorry i didnt realize it was an equation

Step-by-step explanation:

let's reword this a bit differently, since it looks jumbled

let's find the equation of a line that is perpendicular to y = -5x + 5, and it also passes through (10 , 7), well, keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]y=\stackrel{\stackrel{m}{\downarrow }}{-5}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ -5 \implies \cfrac{-5}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{-5} \implies \cfrac{1}{ 5 }}}[/tex]

so we're really looking for the equation of a line with a slope of 1/5 and that it passes through (10 , 7)

[tex](\stackrel{x_1}{10}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{ \cfrac{1}{5}}(x-\stackrel{x_1}{10}) \\\\\\ y-7=\cfrac{1}{5}x-2\implies {\Large \begin{array}{llll} y=\cfrac{1}{5}x+5 \end{array}}[/tex]

CPCTC

This acronym stands for "corresponding parts of congruent triangles are congruent". The triangles being congruent leads to their corresponding pieces being the same length. It's like saying if two houses are identical, then the front doors must be identical as well. Notice how this builds off the fact the triangles are proven congruent in line 5.

Log () helps to determine the single number to be multiplied.

Log stands for logarithm in algebra. The inverses of equations using exponents are called logarithms. Logs can be used to determine how many times one number needs to be multiplied to get another in its most basic form. For instance, to get 100 in the base-10 system, 10 must be multiplied by 10. In a base-10 system, the logarithm of 100 is therefore 2.

Log () expresses the power or exponent that a base number must be raised to or multiplied by in order to create another number in an ideal world. In situations where the user has data values that are significantly greater or lower than the other values, log scales are quite helpful. When displaying major percentage variations between data points, the user can also utilize a log scale.

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Solving provided question, we can say that by arithmetic progression number of rows Dodie's plot has, n ≈ 7.3965

The difference between succeeding terms in a sequence is always the same, and this is known as an arithmetic progression. An arithmetic progression with a tolerance of 2 is, for instance, the sequence 5, 7, 9, 11, 13, and 15. The term "arithmetic progression" (A.P.) refers to a progression with a fixed tolerance between any two consecutive values. Mathematic progression can be of two different types: arithmetic series with finite length A series with a finite amount of terms is a finite geometric progression. The terms in the series can be used to determine the early, late, tolerance, and number of terms.

d = 6 is the difference between subsequent rows.

The value increased to a = 1 at the top vertex.

Consequently, the garden's roses represent a mathematical progression.

A = 1 is the first phrase.

d = 6 is the common difference.

The sum of the n terms in an arithmetic progression,, is what determines how many rows Bill's plot will contain.

When Sₙ = 150, we get;

150 = 3·n² - 2·n

3·n² - 2·n - 150 = 0

number of rows Dodie's plot has, n = 7.3965

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The compound inequality that shows the possible heights of the third tree is 8 ≤ x ≤ 18

An equation shows how two or more numbers and variables are related to each other.

The height of two of the trees are 8 feet and 16 feet. If the height of the third tree is x feet, hence:

Sum of three palm tree heights = x + 8 + 16 = x + 24

The sum of three palm tree heights range from 32 to 42 feet. Hence:

32 ≤ x + 24 ≤ 42

32 - 24 ≤ x ≤ 42 - 24

8 ≤ x ≤ 18

The solution to the compound inequality is 8 ≤ x ≤ 18

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FG cannot be multiplied because it is not a numerical value.

Multiplication is a mathematical operation that involves multiplying two numerical values together to produce a single numerical result. In order for multiplication to be possible, both values must be numerical values. FG is not a numerical value, which means that it cannot be multiplied. In order for FG to be multiplied, it would need to be replaced with a numerical value, such as a number or an expression that can be evaluated to a number. Without a numerical value, multiplication is not possible. Multiplying numerical values is done by taking the product of the two values, meaning that the result of the multiplication is the sum of each value multiplied by itself the number of times the other value is. For example, if you were to multiply 3 and 4, the result would be 12 because 3 multiplied by itself 4 times is 12, and 4 multiplied by itself 3 times is also 12. Without numerical values, this operation cannot be performed.

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The functions are p(x) = b² - 16b +32 and q(x) = -32b-32 the x value when the functions are equivalent to each other is 8.

Given that,

The functions are p(x) = b² - 16b +32 and q(x) = -32b-32

We have to find the x value when the functions are equivalent to each other.

We know that,

Take the functions

p(x) = b² - 16b +32 and q(x) = -32b-32

When the function are equivalent

p(x) = q(x)

b² - 16b +32 = -32b-32

b² - 16b +32 +32b+32=0

b² + 16b +64 = 0

Now find the factors for 64

64 =  8×8

b² + 8b + 8b +64 = 0

Taking common terms

b(b + 8) + 8(b + 8)=0

(b + 8)(b + 8)=0

b=8

Therefore, The functions are p(x) = b² - 16b +32 and q(x) = -32b-32 the x value when the functions are equivalent to each other is 8.

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The length of each diagonal is √(196x^2 + 816x + 324) units.

The diagonal of a rectangle can be estimated using the hypotenuse formula, such as using the Pythagorean theorem calculator.

WX^2 = WY^2 + XZ^2

Given that WY = 14x + 10 and XZ = 11x + 22, we can substitute those values in the equation:

WX^2 = (14x + 10)^2 + (11x + 22)^2

WX^2 = 196x^2 + 816x + 324

WX = √(196x^2 + 816x + 324)

The same goes for the other diagonal, WZ.

WZ = √(196x^2 + 816x + 324)

So, the length of each diagonal is √(196x^2 + 816x + 324) units.

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Answer: -2/3x is the slope and the beginning amount is 5 so the equation would be -2/3x+5.

Step-by-step explanation:

Once you find the slope using the formula rise/run you will get 2/3 but since the slope is going downwards it would be -2/3 which gives you the mx. Now to find the beginning amount look where the line intersects the graph which will give you the equation.

per year unit rate becomes 6 inches. This can be solved using the concept of unit rate.

A unit rate is a price for one of anything. This is expressed as a proportion with such a base of one. For instance, you would cover 7 yards on average every second if you covered 70 yards in 10 seconds. The ratios of 70 yards in 10 seconds and 7 yards in 1 second are both rates, however, the latter is a unit rate.

A rate is the ratio of two different measurement units, whereas a unit rate seems to be the ratio of two different units of measurement for just a single object.

unit rate for 30 inches per 5 years:

= 30 inches / 5 years

= 6 inches / 1 year

Thus, per year unit rate becomes 6 inches.

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