Simplify the expression. - 17b + a +235 + 240​

Answer:

5.15m + 10.25 = 9.25m

Step-by-step explanation:

Tricia's savings can be calculated with her beginning amount, $10.25, plus a rate of $5.15 that is multiplied by the number of months she saves up, m.

Or, 10.25 + 5.15m.

Melanie saves $9.25 for her vacation, times the months that she saves up, m.

Or, 9.25m.

These two equations are equal to each other at a certain value of m, so our equation is-

5.15m + 10.25 = 9.25m

I hope this helps ^^ Good luck mate

Answer:

Whereby circle [tex]\bigodot[/tex]P can be obtained from circle [tex]\bigodot[/tex]O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, [tex]\bigodot[/tex]O is similar to [tex]\bigodot[/tex]P

Step-by-step explanation:

The given center of the circle [tex]\bigodot[/tex]O = (-2, 7)

The radius of [tex]\bigodot[/tex]O, r₁ = 5

The given center of the circle [tex]\bigodot[/tex]P = (12, -1)

The radius of [tex]\bigodot[/tex]P, r₂ = 12

The similarity transformation to prove that [tex]\bigodot[/tex]O and [tex]\bigodot[/tex]P are similar are;

a) Move circle [tex]\bigodot[/tex]O 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle [tex]\bigodot[/tex]O is increased by 2.4

We then obtain [tex]\bigodot[/tex]O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle [tex]\bigodot[/tex]P

∴ Circle [tex]\bigodot[/tex]P can be obtained from circle [tex]\bigodot[/tex]O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, [tex]\bigodot[/tex]O is similar to [tex]\bigodot[/tex]P.

Answer:

0.8 = is the proberbilty of getting an even number and a heads when you flip a coin

0.25 = is the proberbility of getting a 2 or 4 out of the bag including 1 - 8

0.5 = the probability of drawing a yellow and green marble

1 =  the probability of drawing an even number or a number greater than 4

Im not really sure about the last one tho

Step-by-step explanation:

Answer:

A sample of 1015 should be taken.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is of:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of 0.12.

This means that [tex]\pi = 0.12[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex]. I used 95% because the confidence level was not given.

How large a sample should be taken to estimate the actual proportion of smokers with a margin of error of 0.02?

This is n for which M = 0.02. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.02 = 1.96\sqrt{\frac{0.12*0.88}{n}}[/tex]

[tex]0.02\sqrt{n} = 1.96\sqrt{0.12*0.88}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.12*0.88}}{0.02}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96\sqrt{0.12*0.88}}{0.02})^2[/tex]

[tex]n = 1014.2[/tex]

Rounding up:

A sample of 1015 should be taken.

Answer:

-1/12, 1/2, -1/16, 1/16, -1/20, 1/20, -1/2, 1/2, -1/10, 1/10

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

10 Fractions

-5/6 = -400/480

5/8 = 300/480

201/480

202/480

203/480

204/480

205/480

206/480

207/480

208/480

209/480

210/480

10 Decimals

5/6 = -0.8333333333

5/8= 0.625

0.226

0.227

0.228

0.229

0.23

0.231

0.232

0.233

0.234

0.235

Answer:

40 Meters

Step-by-step explanation:

Answer:

a) There is not sufficient evidence to support the claim that the mean attendance is greater than 642.

Step-by-step explanation:

since in the question it is mentioned that the average attendance at games should be more 642 and according to this he moving the team with a larger stadium. Also the hypothesis conducted and the conclusion would be failure to deny the null hypothesis

So here the conclusion that should be made in non-technical term is that there should be no enough proof in order to support the claim that the mean attendence is more than $642

Answer:

6: x = 3 and y = 5

7: x = 8 and y = 7

Step-by-step explanation:

In parallelograms opposite sides are congruent

For #6

x + 5 = 2x + 2

step 1 subtract x from each side

2x - x = x

x - x cancels out

now we have 5 = x + 2

step 2 subtract 2 from each side

5 - 2 = 3

2 - 2 cancels out

we're left with x = 3

y + 10 = 2y + 5

step 1 subtract 5 from each side

10 - 5 = 5

5 - 5 cancels out

now we have y + 5 = 2y

step 2 subtract y from each side

y - y cancels out

2y - y = y

we're left with y = 5

For #7

3x - 2 = 2x + 6

step 1 add 2 to each side

-2 + 2 cancels out

6 + 2 = 8

now we have 3x = 2x + 8

step 2 subtract 2x from each side

3x - 2x = x

2x - 2x cancels out

we're left with x = 8

6y - 8 = 4y + 6

step 1 add 8 to each side

-8 + 8 cancels out

6 + 8 = 14

now we have 6y = 4y + 14

step 2 subtract 4y from each side

6y - 4y = 2y

4y - 4y cancels out

now we have 14 = 2y

step 3 divide each side by 2

2y / 2 = y

14 / 2 = 7

we're left with y = 7

Answer: D. 10.200

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

its A

Answer:

Answer:

Step By Step:

Letter:A

Answer:

180 miles is answer

cuz it takes 80 miled to travel in 12 hours

Answer:

The speed of the current is 10 mph

Step-by-step explanation:

x= speed of the current

[tex]\frac{80}{20-x} + \frac{120}{20+x} = 12[/tex]

80 (20+x) + 120 (20-x) = 12 (20-x) (20+x)

x=10

Answer:

The answer is 3

Answer:

x = 3

Step-by-step explanation:

-x = 3 - 4x +6

make the -4x positive and then add it to the -x

-x = 3 +6

+4x

3x = 3 +6

then add the 3 +6 together

3x = 3 + 6

         9

3x = 9

we want to get X alone so we are going to divide 3 by both sides

3x/3 = 9/3

1x = 3

and if you did not know we usually don't show the "1" if it is in front of a exponent (you just have to remember that there is a one there)

now you have your answer

x = 3

Answer:

at 5 weeks

Step-by-step explanation:

y = 3x + 40   (David)

y = 6x + 25  (Perla)

since both equal 'y' we can set the expressions equal and solve for 'x'

3x + 40 = 6x + 25

subtract 3x from each side to get:

40 = 3x + 25

subtract 25 from each side to get:

15 = 3x

15/3 = x

5 = x

Answer:

I think this is the answer

[tex]f( - 9) = \frac{1}{3( - 9) {}^{2} } + 5 \\ = \frac{1216}{243} \\ = 5.0041[/tex]

Answer:

t = (log200)/4 hours

Step-by-step explanation:

10,000 = 50(10)^(4t)

Divide both sides by 50

200 = 10^(4t)

Take the log of both sides

log200 = 4t

Divide both sides by 4

(log200)/4 = t

t = (log200)/4    (exact answer)

t ≈ 0.575257498915995 (numeric approximation)

Answer:

cubic

Step-by-step explanation:

y = x³  is a cubic shape  try graphing it

Answer:

C (Sorry if its incorrect)

Step-by-step explanation:

I believe its C

Becuase a converse is switching the hypothis and conclusion around

Answer:2730

Step-by-step explanation:

The number of ways we can choose three different numbers in order for a unique code for this case is 2730

We can use combinations for this case,

Total number of distinguishable things is m.

Out of those m things, k things are to be chosen such that their order doesn't matter.

This can be done in total of [tex]^mC_k = \dfrac{m!}{k! \times (m-k)!}[/tex] ways.

If the order matters, then each of those choice of k distinct items would be permuted k! times.

So, total number of choices in that case would be:

[tex]^mP_k = k! \times ^mC_k = k! \times \dfrac{m!}{k! \times (m-k)!} = \dfrac{m!}{ (m-k)!}\\\\^mP_k = \dfrac{m!}{ (m-k)!}[/tex]

This is called permutation of k items chosen out of m items (all distinct).

Given that:

In a lock, the order of the way numbers are arranged matters.

Because of no repetition allowed, we can simulate this situation as:

The number of ways we can choose 3 numbers out of 15 numbers with order = The number of different ways we can choose three different numbers in order for a unique code.

And we have:

The number of ways we can choose 3 numbers out of 15 numbers with order = [tex]^{15}P_3 = \dfrac{15!}{(15-3)!} = \dfrac{15 \times 14 \times 13 \times 12!}{12!} = 2730[/tex]

Thus, the number of ways we can choose three different numbers in order for a unique code for this case is 2730

Learn more about combinations and permutations here:

https://brainly.com/question/16107928

#SPJ2

Answer:

weak cuz theres no flow its just scattered everywhere

Step-by-step explanation:

Answer:

(Sorry im late) The answer is weak

Step-by-step explanation:

I think i remember taking the test:)

Answer:

8

Step-by-step explanation:

10÷2=5

16÷2=8

so then it means it is 8

Answer:

B. 40°

Step-by-step explanation:

I calculated it logically