Answer:
a
Explanation:
wind energy results from solar radiation
Answer:
♡ madeline here ♡
goodmorning!
it's a, have a great day! ☆
- madeline/madi
✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ
Explanation:
The Magnetic Dipole Moment of a Coil Problem A rectangular coil of dimensions 5.40 cm ✕ 8.50 cm consists of 25 turns of wire and carries a current of 20.0 mA. A 0.350 T magnetic field is applied parallel to the plane of the loop. A. What is the magnitude of its magnetic dipole moment?B. What is the magnitude of the torque acting on the loop?
Answer:
a
[tex]\mu = 0.0023 \ A\cdot m^2[/tex]
b
[tex]\tau = 0.00080 \ N \cdot m[/tex]
Explanation:
From the question we are told that
The dimensions of the rectangular coil is 5.40 cm ✕ 8.50 cm = 0.054 m X 0.085 m
The number of turns is [tex]N = 25 \ turns[/tex]
The current it is carrying is [tex]I = 20 \ mA = 0.02 \ A[/tex]
The magnetic field is [tex]B = 0.350 \ T[/tex]
Generally the magnitude of the magnetic dipole moment is mathematically represented as
[tex]\mu = N * I * A[/tex]
Here A is the area which is mathematically represented as
[tex]A = 0.054 * 0.085[/tex]
=> [tex]A = 0.00459 \ m^2[/tex]
So
[tex]\mu = 25 * 0.02 * 0.00459[/tex]
=> [tex]\mu = 0.0023 \ A\cdot m^2[/tex]
Generally the magnitude of the torque acting on the loop is mathematically represented as
[tex]\tau = \mu * B[/tex]
=>[tex]\tau = 0.0023 * 0.350[/tex]
=>[tex]\tau = 0.00080 \ N \cdot m[/tex]
The CEO, ellen misk, left her martian office but accidentally left a cylindricall can of coke (3.1 inches in diameter, 5.42 inches in height) on her desk. If the can exerts a pressure of 510 Pascals, what is the specific gravity of the can?
Answer:
Specific Gravity = 0.378
Explanation:
First, we will find the force exerted by the can on the table. This force will be equal to the weight of the can:
Pressure = Force/Area = Weight/Area
Weight = Pressure*Area
where,
Area = πdiameter²/4 = π[(3.1 in)(0.0254 m/1 in)]²/4 = 4.8 x 10⁻³ m²
Weight = (510 N/m²)(4.8 x 10⁻³ m²)
Weight = 2.48 N
Now, the weight is given as:
Weight = mg
2.48 N = m(9.8 m/s²)
m = (2.48 N)/(9.8 m/s²)
m = 0.25 kg
Now, we calculate volume of can:
Volume = (Area)(Height) = (4.8 x 10⁻³ m²)(5.42 in)(0.0254 m/1 in)
Volume = 6.6 x 10⁻⁴ m³
Hence, the density of can will be:
Density of Can = m/Volume = 0.25 kg/6.6 x 10⁻⁴ m³
Density of Can = 378.32 kg/m³
So, the specific gravity of Can will be:
Specific Gravity = Density of Can/Density of Water
Specific Gravity = (378.32 kg/m³)/(1000 kg/m³)
Specific Gravity = 0.378
what is the speed of rocket that travels 9km in 10 seconds
Answer:
900
Explanation:
v = s / t = 9000m / 10 s = 900m/s
Explanation:
The speed of a rocket that travel 9km in 10 second is 900
answer? physics Q for 3rd secondary..
Answer:
The 300 Ohm resistor
Explanation:
They are in series, so the current has to be the same in both. P = I^2R, so with the same current, the larger resistor dissipates more power.
A tungsten filament at 25-degree celsius has a resistance of 0.350 ohms. What would be the resistance if the temperature is increased to 2850°C? The temperature coefficient of resistance for tungsten is 0.5*10^-3 /°C
Answer:
R₂₈₅₀ = 0.838 ohms
Explanation:
The resistance of an element at some other temperature than 0°C can be given by the following formula:
Rₓ = R₀(1 + ∝ΔT)
where,
Rₓ = Resistance at temperature x
R₀ = Resistance at 0°C
∝ = Coefficient of linear expansion of tungsten = 0.5 x 10⁻³ /°C
ΔT = Change in Temperature
So, for the resistance of tungsten wire at 25°C:
Rₓ = R₂₅ = 0.35 ohms
ΔT = 25°C
Therefore,
0.35 ohms = R₀[1 + (0.5 x 10⁻³ /°C)(25°C)]
R₀ = (0.35 ohms)/1.0125
R₀ = 0.345 ohms
Now, we find the resistance at 2850°C
R₂₈₅₀ = (0.345 ohms)[1 + (0.5 x 10⁻³ /°C)(2850°C)]
R₂₈₅₀ = 0.838 ohms
Table 1
Ball Na
dom
dom
n. Pas
1). Pas
1
4.3
5.86-10
5.91-10
5.89-10
8.09.10
4.91
3
6.02-10
6.32-10
5.24 10
14
5.91-10
6.98 to
8.07.10
6.41 10
5,8910
5.99-10
638-10
5.38.10
4.16
5
5.43
At 20 °C, the density of the ball substance is p = 2,2 10kg/m: fluid is p = 0,91-10kg/m
Distance between two marks is? - 1 m
Answer:
the answer is c.
Explanation:
Consider a person standing in an elevator that is moving at a constant velocity down. The upward normal force N exerted by the elevator floor on the person is Select one: a. smaller than the downward force of gravity on the person. b. identical to the downward force of gravity on the person. c. larger than the downward force of gravity on the person.
Answer:
b. identical to the downward force of gravity on the person.
Explanation:
For an object in an elevator,
F = mg - ma (g > a)
But since the velocity is uniform, a = 0.
Then,
F = mg - 0
F = mg
This is the actual weight of the object.
The object does not feel weightless, so that its actual weight can be measured during the downward motion of the elevator with uniform velocity.
Thus, the upward normal force, N, exerted by the elevator floor on the person is identical to the downward force of gravity on the person.
a current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 seconds determine the p
otential drop across the conductor
Answer:
ou have I=200mA, E=40J, t=30s, and you want to find the voltage drop.
First, you should know that P=V⋅I , so V=PI
Second, you have the amount of energy converted in a certain amount of time, so E=P⋅t
So, find the power and use it to find the voltage drop.
this works , but i thought energy was defined by W = P * t whitch would then be P = W/t
What is the de Broglie wavelength of an electron accelerated from rest through a potential difference of 50.0 V?
(a) 0.100 nm
(b) 0.139 nm
(c) 0.174 nm
(d) 0.834 nm
(e) none of those answers
Answer:
(c) 0.174 nm
Explanation:
According to de Broglie hypothesis, the wavelength of the wave associated with electron is given by:
[tex] \boxed{ \bf{\lambda = \sqrt{\dfrac{150}{V \ (in \ Volt)}} \: \text{\AA}}}[/tex]
V → Potential Difference (50.0 V)
By substituting value of potential difference in the equation, we get:
[tex] \rm \longrightarrow \lambda = \sqrt{\dfrac{150}{50}} \: \text{\AA} \\ \\ \rm \longrightarrow \lambda = \sqrt{3} \: \text{\AA} \\ \\ \rm \longrightarrow \lambda = 1.74 \: \text{\AA} \\ \\ \rm \longrightarrow \lambda = 0.174 \: nm[/tex]
Coach ulcer paces the sidelines. Sarting at the 30 yd. line (A), he moves to the 10 yd. line (B), back to the 50 yd. line (C) and finally to the 20yd. Line (D) in 200 seconds. Determine his average speed and velocity.
Answer:
See the answer below
Explanation:
Average speed = total distance traveled/total time taken
In order to determine the total distance traveled by the coach, consider the attached image.
Distance covered:
30 yd. line to 10 yd. line (A to B)= 20 yds
10 yd. line to 50 yd. line (B to C) = 40 yds
50 yd. line to 20 yd. line (C to D) = 30 yds
Total distance covered = 20 + 40 + 30 = 90 yds
Time taken = 200 seconds
Average Speed = 90/200 = 0.45 yd/s
Velocity = speed with direction
Hence,
His Velocity = 0.45 yd/s to the left of his starting point.
A ball thrown vertically upward returns to the thrower 25s later determine the speed with which it was thrown
25/2=12.5s
12.5*9.8=122.5 m/s
What is the answer to this question
Answer:
0.11 m/s
Explanation:
From the question given above, the following data were obtained:
Initial displacement (d1) = 1.09 m
Final displacement (d2) = 2.55 m
Time (t) = 12.8 s
Average velocity =?
Next, we shall determine the total displacement (i.e change in displacement). This can be obtained as follow:
Initial displacement (d1) = 1.09 m
Final displacement (d2) = 2.55 m
Total displacement = d2 – d1
Total displacement = 2.55 – 1.09
Total displacement = 1.46 m
Finally, we shall determine the average velocity of the beetle. This can be obtained as follow:
Total Displacement = 1.46 m
Total time (t) = 12.8 s
Average velocity =?
Average velocity = Total Displacement / Total time
Average velocity = 1.46/12.8
Average velocity = 0.11 m/s
Thus, the average velocity of the beetle is 0.11 m/s
Jessica pulls on a washing machine with 200 N of force. Mark helps out and pulls on the washing machine in the same direction with 400 N of force. What is the net force on the washing machine
Answer:
600N
Explanation:
2. A force of 500 N separates two objects. The distance between their centers is 67 m. The first object has a mass of 20 kg. What is the mass of the second object?
Answer:
The Equation of Newton's Law of Gravity. G is called the Gravitational Constant, and has the value 6.67×10-11 N ∙m2kg-2 (N is for Newton, the physicists' unit of force)or 1.5×10-11 lb∙m2kg-2
Explanation:
Gravitational force is an attractive force that exists between all objects with mass . an object with mass attracts another object with mass.
Mass of second object is [tex]1.6825*10^{15}[/tex] kg
If two bodies have mass m₁ and m₂ . Then attractive force between them is calculated by formula show below,
[tex]F=G\frac{m1m2}{r^{2} }[/tex]
Where r is distance between bodies. and G is gravitational constant.
G = [tex]6.67*10^{-11}[/tex] [tex]Nm^{2}/kg^{2}[/tex]
Here, F = 500N, m₁=20 kg and r= 67 m
Substituting above values in force equation.
[tex]500=\frac{6.67*10^{-11}*20*m2 }{(67)^{2} } \\\\m2=1.6825*10^{15} Kg[/tex]
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Can someone please answer how to convert mass into weight?
Answer:
To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.
Explanation:
(ii) In two parts of the graph in Figure 1 the forces are balanced.
State the letters of the two parts of the graph where the horizontal forces
acting on the car are balanced.
121
part
and part
this is the graph:
Answer:
Hii I m Indian.......♥️
A painter on a scaffold drops a 1.25 kg can of paint from a height of 5.00 m.
a) What is the kinetic energy of the can when the can is at a height of 3.00 m?
b) With what speed will the can hit the ground? (Neglect air resistance)
Answer:
(a) The kinetic energy of the can when the can is at a height of 3.00 m.
(b) The speed with which the can will hit the ground is 9.9 m/s
Explanation:
(a) Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed.
Kinetic energy is represented by the following formula:
Ec = ½ mv²
Where Ec is kinetic energy, which is measured in Joules (J), m is mass measured in kilograms (kg), and v is velocity measured in meters over seconds (m/s).
On the other hand, potential energy is the energy that measures the ability of a system to perform work based on its position. In other words, this is the energy that a body has at a certain height above the ground.
Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the force of gravity. Then for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:
Ep = m g h
Where Ep is the potential energy in joules (J), m is the mass in kilograms (kg) is h the height in meters (m) and g is the acceleration of fall in m/s² (approximately 9.8 m/s²)
Energy is neither created nor destroyed, but only transforms from one state to another. This principle also extends to mechanical energy, so that in an isolated system, the sum of kinetic and potential energies between two instants of time remains constant:
½ m*v1² + m*g*h1= ½ m*v2² + m*g*h2
where v1 and h1 are the initial speed and height and v2 and h2 the final speed and height.
In this case:
v1= 0 m/sh1= 5 mv2= ?h2= 3 mReplacing:
½ m*0² + m*g*5= ½ m*v2² + m*g*3
Solving:
m*g*5= ½ m*v2² + m*g*3
The mass m appears in all terms, being able to simplify:
g*5= ½ v2² + g*3
Solving for v2:
[tex]v2=\sqrt{\frac{g*5-g*3}{\frac{1}{2} } }[/tex]
being g= 9.8 m/s²:
v2= 6.26 m/s
The speed at 3 meters height is 6.26 m/s
Then the kinetic energy is calculated as:
Ec = ½ mv²
Ec = ½ 1.25 kg* (6.26 m/s)²
Ec= 24.49 J
The kinetic energy of the can when the can is at a height of 3.00 m.
(b) You know:
½ m*v1² + m*g*h1= ½ m*v2² + m*g*h2
where v1 and h1 are the initial speed and height and v2 and h2 the final speed and height.
In this case:
v1= 0 m/sh1= 5 mv2= ?h2= 0 mReplacing:
½ m*0² + m*g*5= ½ m*v2² + m*g*0
Solving:
m*g*5= ½ m*v2²
g*5= ½ v2²
[tex]v2=\sqrt{\frac{g*5}{\frac{1}{2} } }[/tex]
being g= 9.8 m/s²:
v2= 9.9 m/s
The speed with which the can will hit the ground is 9.9 m/s
The x component of vector A is -25.0m and the y component id +40.0m (a) what is the magnitude of A?(b) What is the angle between the direction of A and the positive direction of x?
Answer:
θ = 122°
Explanation:
Components of a Vector
A vector in the plane can be defined by its rectangular components:
[tex]\vec A =<x,y>[/tex]
Or also can be given by its polar components:
[tex]\vec A =<r,\theta>[/tex]
Where r is the magnitude of the vector and θ is the angle it forms with the positive direction of x.
The relation between them is:
[tex]r=\sqrt{x^2+y^2}[/tex]
[tex]\displaystyle \theta=\arctan\frac{y}{x}[/tex]
It's given the x-component of vector A is x=-25 m and the y-component is y=40 m
(a)
The magnitude of the vector is:
[tex]r=\sqrt{(-25)^2+40^2}[/tex]
[tex]r=\sqrt{625+1600}[/tex]
[tex]r=\sqrt{2225}[/tex]
[tex]r\approx 47.2\ m[/tex]
(b)
[tex]\displaystyle \theta=\arctan\frac{40}{-25}[/tex]
[tex]\displaystyle \theta=\arctan (-1.6)[/tex]
The calculator gives us the value
θ = -58°
But the real angle lies on the second quadrant since x is negative and y is positive, thus:
θ = -58° + 180° = 122°
θ = 122°
What average net force is required to accelerate a car with a mass of 1200 kg from rest to 27.0 m/s2 in 10.0 s ?
1620 N
4360 N
444 N
11800 N
3240 N
The average net force required to accelerate the car is 3240 N
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 27 m/sTime (t) = 10 sAcceleration (a) =?a = (v – u) / t
a = (27 – 0) / 10
a = 2.7 m/s²
How to determine the forceMass (m) 1200 KgAcceleration (a) = 2.7 m/s²Force (F) = ?F = ma
F = 1200 × 2.7
F = 3240 N
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For motion maps that illustrate accelerated motion, what does a new level indicate?
change in acceleration or direction
constant acceleration and direlon
increased velocity
decreased velocity
оо
Answer:
A. change in acceleration or direction
Explanation:
A motion map can be defined as the graphical representation of the acceleration, velocity and position of a body or an object at specific intervals (period of time) or time readings.
For motion maps that illustrate accelerated motion, a new level indicates a change in acceleration or direction.
Acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time. Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Additionally, acceleration is a vector quantity because it has both magnitude and direction.
Answer:
A
Explanation:
EDG 2021
you drive your car at a speed of 40 km/hr then slow down to 30km/hr
Answer:
3
Explanation:
3
A diffraction grating with 270 lines per mm is used in an experiment to study the visible spectrum of a gas discharge tube. 1. At what angle from the beam axis will the fourth order peak occur if the tube emits light with wavelength of 665.0 nm?2. At what angle will the second order peak occur?
Answer:
1) θ = 45.91°
2) θ = 21.04°
Explanation:
We are given;
Wavelength; λ = 665 nm = 6.65 × 10^(-7) m.
Distance between slits; d = 1mm/270 = 1/270 mm = (1/270) × 10^(-3) m
1) To find the angle, we will use the formula;
d sin θ = mλ
Where m is the order of peak which in this question is 4.
Thus, we have;
sin θ = mλ/d
sin θ = (4 × 6.65 × 10^(-7))/((1/270) × 10^(-3))
sin θ = 0.7183
θ = sin^(-1) 0.7183
θ = 45.91°
2) Similarly, d sin θ = mλ
Where m is the order of peak which in this question is 2. Thus;
sin θ = (2 × 6.65 × 10^(-7))/((1/270) × 10^(-3))
sin θ = 0.3591
θ = sin^(-1) 0.3591
θ = 21.04°
A 5 kg bowling ball with a velocity of +10 m/s collides with a stationary 2 kg bowling pin. If the ball's final velocity is +8 m/s, what is the pin's final velocity?
a 5 m/s
b 2.5 m/s
c 10 m/s
d 5.2 m/s
Answer:
The pin's final velocity is 5m/sExplanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
A force of 150 N is applied on an object at 60 degrees above the positive x-axis. Determine its
horizontal and vertical components.
Answer:
horizontal component=fcostita
=150cos60
use calculator to evaluate it
for vertical=fsintita
=150sin60
You serve a tennis ball of mass 60g at a speed of 50
m/s, what is the impulse exerted on the ball? ( ball starts from rest )
Answer:
[tex]J = 3~Kg.m/s[/tex]
Explanation:
Impulse and Momentum
The impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it.
The equation can be written as follows:
[tex]J =\Delta p = p_2-p_1[/tex]
Where:
J = Impulse
p2 = Final Momentum
p2 = Initial Momentum
The momentum can be calculated as:
p = m.v
Where m is the mass of the object and v is the velocity.
The tennis ball with mass m=60 g = 0.06 Kg was served from rest (v1=0) to v2=50 m/s. The change in momentum is:
[tex]\Delta p = 0.06Kg~50~m/s-0[/tex]
[tex]\Delta p = 3~Kg.m/s[/tex]
Thus the impulse is:
[tex]\marhbf{J = 3~Kg.m/s}[/tex]
A student bought a 1.55-ounce chocolate bar and left it in
a car on a hot day.
How many ounces of chocolate are in the melted bar?
A. Exactly 1.55 ounces
B. At least 1.55 ounces
C. An unknown number of ounces
D. Less than 1.55 ounces
Answer:
a
Explanation:
A student bought a 1.55-ounce chocolate bar and left it in a car on a hot day. Exactly 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
The change caused by an applied force is smaller the more mass a body has. The kilogram serves as the unit of mass in the International System of Units (SI).
As mass does not depends on the state of the object, exactly same mass of chocolate are in the melted bar that it was in chocolate bar. So, 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.
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describe three possible careers in physical science
Answer:
physical sicence boilagiy sxcience and earth science
Explanation:
If force remains the same, and the mass of an object increases, what happens to the acceleration?
Answer:
Decreases
Explanation:
Force= mass * acceleration
If the mass increases but force stays the same then the acceleration would have to decrease to maintain the same force
Which of the following is a self-fulfilling prophecy?
mutual views that are often held by conflicting people
shared goals that override differences among people and require their cooperation
a perceived incompatibility of actions, goals, or ideas
a belief that leads to its own fulfillment
Answer:
last one
Explanation:
4. A substance has a density of 0.79 g/cm'. It is soluble in water. List all the possibilities of what it might be How could you determine the actual identity?
Answer:
See explanation
Explanation:
Given that the density of the unknown substance is 0.79 g/cm3 and is soluble in water, the possible substances it could be are;
i) t-butanol
ii) ethanol
iii) 2-propanol
iv) acetone
However, the actual identity of the unknown substance can be obtained by carrying out a boiling point test. The four substances listed above have different boiling points. Hence the boiling point of the unknown substance ultimately discloses its identity.