Solve by using substitution. x+2y=−1 x=y+5

$1862  is Devi red from his biweekly paycheck for medical insurance

percentage, a relative value indicating hundredth parts of any quantity.

The annual cost of Randall coverage is 4900.

The college pays 62% of the cost.

We need to find How much is Devi red from his biweekly paycheck for medical insurance

Let us convert 62% to decimal value by dividing with 100

62/100=0.62

Now multiply 0.62 with 4900

0.62×4900

3038

Now subtract 3038 from 4900

4900-3038

1862

Hence, $1862  is Devi red from his biweekly paycheck for medical insurance

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Answer:

x^2-9

Step-by-step explanation:

-3 + 3 = 0 so the x terms cancel out.  This leaves you with only x^2-9

Answer:

5 × x + 8

Would be the equation you are looking for.

Answer: 88

Step-by-step explanation:

Answer: 88

Step-by-step explanation: 5x5=25 + 9x7=63 ----> 25+63= 88

The builder needs building sand weighing 6.3 * 10⁶ g and contains 9 * 10¹⁰ grains

An equation is used to show the relationship between numbers and variables.

A brick layer needs 6300 kg of building sand

The conversion from kg to g is:

1 kg = 1000 g

a) 6300 kg in grams is:

6300 kg = 6300 kg * 1000 g per 1 kg = 6,300,000 g = 6.3 * 10⁶ g

b) 1 grain = 7 * 10⁻⁵ g

6.3 * 10⁶ g = 6.3 * 10⁶ g * 1 grain / (7 * 10⁻⁵ g) = 9 * 10¹⁰ grain

The builder needs 6.3 * 10⁶ g of building sand

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No solution is a fraction that cannot be represented as a fraction of integers.

A fraction is a division of two numbers, and no solution occurs when the divisor is 0, because division by 0 is undefined.

For example, consider the fraction 2/0. This is a fraction with no solution because division by 0 is undefined. To explain this further, let's look at the formula for division: a/b = c. In this formula, a is the dividend, b is the divisor, and c is the quotient. In the fraction 2/0, the dividend is 2 and the divisor is 0, so when we try to calculate the quotient, we get c = 2/0. Since division by 0 is undefined, the result is no solution.

To summarize, no solution occurs when a fraction's divisor is 0 because division by 0 is undefined. This means that no fraction can be represented as a fraction of integers when the divisor is 0 because there is no solution.

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Answer:

x = 60

Step-by-step explanation:

Let the two opposite angles be equal and let's call them y.

Because of the theory of angles on a straight line 120 +y = 180

y = 60

Because of the theory of angles on a straight line 2x + y = 180

2x + 60 = 180

2x =  120

x = 60

Alternatively. (also a lot easier)

120 and 2x are opposite angles so they are equal and so;

2x = 120

x = 60

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Answer:

56a+40b

Step-by-step explanation:

43a plus 13a is 56a, -12b + 52b is 40b, together it's 56a+40b

Leo's balance after 8 months is $1725.

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant.

Example:

2, 4, 8, 16 is a geometric sequence.

We have,

1500, 1530, and 1560 is a geometric sequence.

First term.

a = 1500

Common ratio.

r = 1.02

The nth term of a geometric sequence is a[tex]r^{n-1}[/tex].

Now,

For n = 8,

8th term.

= 1500 x [tex]1.02^7[/tex]

= 1500 x 1.15

= 1725

Thus,

The balance after 8 months is $1725.

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The equation is y = 2x and the constant of variation k = 2

Therefore, the correct answer is option d.

Here, we can clearly see that y varies directly with x, because as x increases, y increases with the same proportion and vice versa. The constant of variation, k, is the coefficient of proportionality between x and y. To find the constant of variation, we can divide the value of y by the value of x for any one of the given points.

For example, for the point (-2, -4) we have:

k = -4 / -2 = 2

So the equation relating x and y is: y = kx = 2x

Hence, the equation is y = 2x and the constant of variation k = 2

Therefore, the correct answer is option d.

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The complete question is -

Determine whether y varies directly with x. If so, find the constant of variation and write the equation.

x | y

-2 | -4

-4 | -8

-16 | -32

a. No

b. yes; k=-2 and y=-2x

c. yes; k=1/2 and y=1/2x

d. yes; k=2 and y=2x

Relief refers to the highest and lowest point elevation in an area.

Relief

Relief is the term used for the differences in height from place to place on the land’s surface and it is greatly affected by the underlying geology. Relief relies on the hardness, permeability and structure of a rock.

elevation

The elevation of a geographic location is its height above or below a fixed reference point, most commonly a reference geoid, a mathematical model of the Earth's sea level as an equipotential gravitational surface.

geology

Geology describes the structure of the Earth on and beneath its surface, and the processes that have shaped that structure. It also provides tools to determine the relative and absolute ages of rocks found in a given location, and also to describe the histories of those rocks.

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Answer: Relief

Step-by-step explanation:

Relief refers to the highest and lowest point elevation in an area.

Slope is the measure of steepness

Topography refers to the arrangement of the land in an area

Elevation on the other hand is the distance above sea level

We find the sine and cosine of an acute angle by taking the ratio of the length of the side opposite to the angle with respect to the length of the side adjacent to the acute angle.

What is the tangent of the angle?

The ratio of the right-angle triangle's base or perpendicular is known as the tangent of the angle.

The ratio of two of the right-angled triangle's three sides is used to define the sine, cosine, and tangent of an acute angle.

Here,

We have to find out how is a right triangle used to find the sine and cosine of an acute angle is there a unique right triangle that must be used.

We concluded that a right triangle can be used to determine the tangent of any acute angle, by taking the ratio of the length of the side opposite to the angle with respect to the length of the side adjacent to the acute angle.

Hence, we find the sine and cosine of an acute angle by taking the ratio of the length of the side opposite to the angle with respect to the length of the side adjacent to the acute angle.

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:)

ggggggggggggrssdfffffffffffffffffffffffffffffffffrsssssssssshggh

The drama "The Importance of Being Earnest" contains many inconsistencies. Algernon's criticism of the lower class for not providing a better moral example for the upper class is paradoxical because the higher class must set the standard because it is the ruling class.

A remark that logically contradicts itself or runs counter to one's expectations is referred to as a paradox.

It is a claim that, despite appearing to be supported by genuine premises and sound reasoning, leads to a logically untenable or self-contradictory conclusion.

One of the most straightforward yet well-known paradoxes is the liar paradox, sometimes known as the liar's paradox statement.

A paradox exists when someone says, "This statement is a lie" or "This statement is false," because if it were true, the statement would be speaking the truth.

In "The Importance of Being Earnest", the play has multiple contradictions.

Because the upper class is required to lead because it is the governing class, Algernon's dissatisfaction with the lower class for not setting a better moral example for the upper class is paradoxical.

Therefore, the drama "The Importance of Being Earnest" contains many inconsistencies. Algernon's criticism of the lower class for not providing a better moral example for the upper class is paradoxical because the higher class must set the standard because it is the ruling class.

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Answer:

70 members

Step-by-step explanation:

Let's call the number of total members x. We know that 30% or  [tex]\frac{3}{10}[/tex] of the members forgot, so our equation looks like this:

[tex]\frac{3}{10}x = 21[/tex]

Then, we will multiply both sides by 10 to get rid of the fraction:

3x = 210

Finally, we will divide both sides by 3 to find out our variable, x:

x = 70

So, there are 70 members in total.

Hope this helped!

-6,7 is in 2nd Quadrant of a coordinate plane because the coordinate of x is negative integer and the coordinate of y is positive integers.

It is possible to find any point in a 2D plane or 3D space using coordinates, which are ordered pairs of points. We may have observed the use of grids in mathematics. We can plot any point using these grids and its coordinates.

Cartesian coordinates, also known as the coordinates of a point in a 2D plane, are two integers, or occasionally a letter and a number, that identify a specific point's precise location on a grid. This grid is referred to as a coordinate plane.

The X-axis is the horizontal axis and the Y-axis is the vertical axis of a coordinate plane, which has four quadrants.

To plot -6, 7 point on coordinate first we find the point -6 on the left side of plane on x axis. the we go upward and find point y=7 parallel to y axis.

this point is -6,7.

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Answer:

Step-by-step explanation:

Let angle A = w - 15 degree , angle B = -w + 1 degree and angle X = w + 34 degrees then:

We know that the exterior angle of a triangle is equal to the sum of two interior opposite angles.

therefore, w + 34 = w - 15 + (-w +1)

w + 34 = w - 15 - w + 1

w = -15 - 34 = - 49 degrees

since angle cannot be negative

therefore w = 49 degrees

The values of p that satisfy the inequality for all[tex]$q > 0$[/tex] are

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex]and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]

Given:[tex]$$\frac{3(pq^2 p^2q 3q^2 3pq)}{p q} > 2p^2q^2$$[/tex]

Step 1: Multiply both sides by [tex]$\frac{pq}{3}$[/tex] to get: [tex]$$pq^3 p^2q 3q^2 3pq > 2p^2q^3$$[/tex]

Step 2: Simplify the left side to get: [tex]$$3p^2q^3+3pq^3+3q^2 > 2p^2q^3$$[/tex]

Step 3: Divide both sides by [tex]$q^2$[/tex] to get: [tex]$$3p^2q+3pq+3 > 2p^2$$[/tex]

Step 4: This is a quadratic inequality in[tex]$p$[/tex]with solution[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]. Therefore, the values of p that satisfy the inequality for all  [tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]

the given inequality can be simplified to a quadratic inequality in p by multiplying both sides by[tex]$\frac{pq}{3}$[/tex], simplifying the left side, and dividing both sides by[tex]$q^2$[/tex] The solution of the quadratic inequality is

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and

[tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]. Therefore, the values of p that satisfy the inequality for all [tex]$q > 0$[/tex] are

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex]and

[tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex], which means that any value of p that is greater than[tex]$\frac{3+\sqrt{21}}{2}$[/tex] or less than

[tex]$-\frac{3+\sqrt{21}}{2}$[/tex]will satisfy the inequality for all [tex]$q > 0$[/tex]

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Answer:

  Manuel can make 5 batches of muffins using Recipe 1

Step-by-step explanation:

You want to know the value of b in the equation 2b = 10, where b is the number of batches of muffins Manuel can make using recipe 1.

Divide both sides of the given equation by 2 so solve for the value of b.

  (2b)/2 = (10)/2

  b = 5

Manuel can make 5 batches of muffins using Recipe 1.

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The 3 parts of a quadratic equation are standard form, factored form and vertex form.

A quadratic equation is a polynomial equation of degree two in one variable of type f(x) = ax² + bx + c where a, b, c, ∈ R and a ≠ 0.

There are three forms of quadratic equations

Standard form of quadratic equation y = ax² + bx + c

factored form of quadratic equation y = a(x − r₁)(x − r₂​)

Vertex form of quadratic equation y = a(x − h)² + k

Each of the above quadratic forms looks unique, allowing the different problems to be more easily solved in one form than another.

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Answer:

34 + 23 = 57

57 - 5 = 52

Therefore, she has 52 toy horses.

The number of ducks on the farm is 12 legs / 2 legs/duck = 6 ducks.

To determine this:

Each cow has 4 legs, so the cows have 3 cows * 4 legs/cow = 12 legs.

Each chicken has 2 legs, so the chickens have 8 chickens * 2 legs/chicken = 16 legs.

We know the total number of farm animal legs is 40 legs.

So the number of duck legs can be calculated by subtracting the number of cow legs and chicken legs from the total number of farm animal legs: 40 legs - 12 legs - 16 legs = 12 legs.

Since each duck has 2 legs, the number of ducks on the farm is 12 legs / 2 legs/duck = 6 ducks.

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The amount of the proposed increase is, Rs 1071.4

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

The annual gym subscription for a single member is Rs.1000,

And, An annual family membership is Rs.1500.

Here, A single membership increased cost 5/7 of a family membership.

Hence, The increased cost = 5/7 of 1500

                                          = 1071.4 Rupees

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Step-by-step explanation:

Let A be the sum from 100 to 300

so the sum of 97 to 298 =

A - (299+300) + 97 +98

= A - 403

Answer:

g (x) = −7 x 2 + 26 x + 8

Step-by-step explanation:

A right triangle's hypotenuse is its longest side, its "opposite" side is the one that faces a certain angle, and its "adjacent" side is the one that faces the angle in question.

In a right triangle, the hypotenuse is the longest side, the "opposite" side is the one that faces a particular angle, and the "adjacent" side is the one that faces that angle.

Step 1: Simplify both sides of the equation.

[tex]$$4 g-6=8$$\\Step 2: Add 6 to both sides.$$\begin{aligned}& 4 g-6+6=8+6 \\& 4 g=14\end{aligned}$\\$Step 3: Divide both sides by 4 .$$\begin{aligned}& \frac{4 g}{4}=\frac{14}{4} \\& g=\frac{7}{2}\end{aligned}$$[/tex]

[tex]$g=3 \frac{1}{2}$[/tex]

Therefore, the correct answer is option a)[tex]$g=\frac{7}{2}$[/tex].

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Answer:

[tex] \sf \: 7.31[/tex]

Step-by-step explanation:

Now we have to,

→ round a number to 2 decimal places.

The number is,

→ 7.3084

Let's solve the problem,

→ 7.3084

→ ≈ 7.308

→ [tex] \boxed{ \sf ≈ 7.31} [/tex]

→ ≈ 7.3

Hence, the answer is 7.31.

One final test that lasts three hours is given in addition to four-hour exams that are given by the teacher. The student's last grade is an 83.29.

The final exam result was an 80, which counts as 31 hour examinations if the exam scores range from 60 to 81, which totals to 97,87. In order to accomplish this, we must multiply three eighty by 62, 81, 97, and 87, which equals a 31-hour exam.

The whole time for the final exam, which is 31 hours, will be added up and divided by 7, giving us an average final grade for the student of 81.To reduce the number's number of significant digits in order to approximate it. Rounding down from 15.4 to 15.5, from 15.51 to 15.5 or 16, from 0.499 to 0, and from 970,000 to 1 million.

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No two values of x in the computation we just did are equal, there are 4 different values of x for which the sequence contains the value 2001.

An ordered list of numbers is all that a sequence is. Number series are collections of numbers that adhere to a pattern or guideline. An arithmetic sequence is one where the rule is to add or take away a number each time.

To estimate a few terms of the sequence in order to obtain a feel how it looks like.

In our case, the definition is that [tex]$\forall$[/tex] (for all) [tex]$n > 1: a_n=a_{n-1} a_{n+1}-1$[/tex].

This can be rewritten as [tex]$a_{n+1}=\frac{a_n+1}{a_{n-1}}$[/tex].

We have [tex]$a_1=x$[/tex] and [tex]$a_2=2000$[/tex], and we estimate:

[tex]$& a_3=\frac{a_2+1}{a_1}=\frac{2001}{x} \\[/tex]

[tex]$& a_4=\frac{a_3+1}{a_2}=\frac{\frac{2001}{x}+1}{2000}=\frac{2001+x}{2000 x} \\[/tex]

[tex]$& a_5=\frac{a_4+1}{a_3}=\frac{\frac{2001+x}{2000 x}+1}{\frac{2001}{x}}=\frac{\frac{2001+2001 x}{2000 x}}{\frac{2001}{x}}=\frac{1+x}{2000} \\[/tex]

[tex]$& a_6=\frac{a_5+1}{a_4}=\frac{\frac{1+x}{2000}+1}{\frac{2001+x}{2000 x}}=\frac{\frac{2001+x}{2000}}{\frac{2001+x}{2000 x}}=x \\[/tex]

[tex]$& a_7=\frac{a_6+1}{a_5}=\frac{x+1}{\frac{1+x}{2000}}=2000[/tex]

At this point we see that the sequence will become periodic: we contain [tex]$a_6=a_1, a_7=a_2$[/tex], and each subsequent term exists uniquely determined by the previous two.

Hence 2001 appears, it contains to be one of [tex]$a_1$[/tex] to [tex]$a_5$[/tex].

As [tex]$a_2=2000$[/tex], we only have four possibilities left.

Clearly [tex]$a_1=2001$[/tex] for x = 2001, and [tex]$a_3=2001$[/tex] for x = 1.

The equation [tex]$a_4=2001$[/tex]

solves to [tex]$x=\frac{2001}{2000 \cdot 2001-1}$[/tex], and the equation [tex]$a_5=2001$[/tex] to [tex]$x=2000 \cdot 2001-1$[/tex]

There are four alternative values of x for which the sequence contains the value 2001 since no two values of x are equal in the computation we just performed.

Therefore, the correct answer is option (D) 4.

The complete question is:
Consider sequences of positive real numbers of the form x, 2000, y, ........  in which every term after the first is 1 less than the product of its two immediate neighbors. For how many different values of x does the term 2001 appear somewhere in the sequence?

(A) 1

(B) 2

(C) 3

(D) 4

(E) more than 4

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Answer:

X of M is 6, Y of M is 4, Pair is (6,4)

Step-by-step explanation:

M = 6

M = 4

M (6,4)