Solve for x please help me

Answer:

55.56%

Step-by-step explanation:

55/99=.5555555...

.55555...*100=55.555...%

55.56%

Answer:

the answer is number 1 !!

• correct me if I'm wrong

Answer:

true

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Pluck in the values, we have:

4.5/2.4 - 6 = 20/2 = 10

Answer:

-5.

Step-by-step explanation:

5 + -5 = 0, so i's -5.

Answer:

Step-by-step explanation:

Drake has 2 houses and makes $50,000,000

Answer:

gek

Step-by-step explanation:

Answer:

the perimeter of the figure is 27.4 mi

Step-by-step explanation:

rectangle perimeter = 6+6+6 = 18

half circle perimeter = 1/2 2πr = 3.14 × 3 = 9.42

the perimeter of the figure is 18+9.42 = 27.42 --> 27.4 mi

Answer:

Actually, Corresponding angles are congruent.

Step-by-step explanation:

They are only supplementary in the special case where they are both 90°

Answer:

Option D

Step-by-step explanation:

Since we know that measure of corresponding angles are equal. So, corresponding angle are congruent to each other

Answer: store b because you can get more ground beat.

Step-by-step explanation:

Answer:

A. 511; 6

Step-by-step explanation:

The margin of error would be [tex]\pm\frac{517-505}{2}=\pm\frac{12}{2}=\pm 6[/tex]

The sample mean would be [tex]505+6=511[/tex] (or [tex]517-6=511[/tex])

Answer:

this is do confusing I do not understand

Answer:

70% right, 30% wrong

Step-by-step explanation:

3 is 30% of 10

Answer:

10.5

Step-by-step explanation:

A=a+b

2h=2+5

2·3=10.5

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

[tex]AD^{2}=AC^{2}+CD^{2}[/tex]

25=9+[tex]CD^2[/tex]

[tex]CD^2[/tex]=25-9=16

[tex]CD=\sqrt{16} =4 units[/tex]

Now

Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]

similarly,

[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]x - 0.20x \: = 1480[/tex]

[tex]0.8x = 1480[/tex]

[tex]x = 1480 \div 0.8[/tex]

I'm not sure if this is correct, but I got this

Last year’s computer models are discounted 20%. If a computer is on sale for $1,480, what is the original price of the computer rounded to the nearest dollar?

20% = 0.2

1,480 x 0.2 = 296

1,480 + 296 = 1,776

Answer: 1,776

Again, I don't know if this is correct, so don't be 100% sure with my response.

150−28w

i think i dont know

Answer:

D. [tex]-5 \frac{5}{6}[/tex]

Step-by-step explanation:

Add the values:

[tex]-3\frac{2}{3}+\left(-2\right)\frac{1}{6}[/tex]

[tex]=-\frac{11}{3}+\left(-2\right)\frac{1}{6}[/tex]

[tex]=-\frac{11}{3}-\frac{1}{3}[/tex]

[tex]-5 \frac{5}{6}[/tex]

Answer:

C. - 1 ½

Step-by-step explanation:

-3⅔ - x = - 2⅙

x = -3⅔ + 2⅙

x = -11/3 + 13/6

x = -22/6 + 13/6

x = -9/6

x = -1 ½

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]

So basically what you have to do is first identify all of the sides or angles that equal eachother then you can see if you did a side side and side in a row etc, like 44 would be SAS because the vertical angles would be inbetween the two sides. 46 would be SSS because after you make the line in the middle for reflexive property you can see that there are three sides in a row. If this didnt help i recommend looking on Khan Academy

Answer: If angle A is congruent to angle E

Step-by-step explanation:

Two t-shirts that are(31.80) plus a hat(6.20) cost £38.00.

which means that one t-shirt costs £15.90 :)

Answer:

1/6

Step-by-step explanation:

P(A) = probability a student buys lunch = 60% = 0.6

P(B) = probability a student buys lunch and dessert = 10% = 0.1

We are looking at the probability that a student buys lunch and dessert on the condition that they already bought lunch. Therefore, we are looking at a conditional probability.

P(B given A) = P(A and B) / P(A)

= 0.1 / 0.6

= 1/6 ≈ 0.167

Answer:

I feel like something is wrong with the equation but the answer is a = 3

Step-by-step explanation:

a + 3a - 3 = 6 + 3 = 9

--> 4a = 12 --> a = 3

Answer:

292.6

Step-by-step explanation: