Solve the equation with the help of laplace transform (d^2y+dx=2 ,when x(0)=3, x’(0)=1, where d=d/█(dtà)​

Answers

Answer 1

Correct Question:-

Solve the following differential equation using Laplace transformation.

[tex]\rm{x''(t)+x'(t)=2,\quad x(0)=3,\quad x'(0)=1}[/tex]

where [tex]\rm{x'(t)=\dfrac{dx}{dt},\quad x''(t)=\dfrac{d^2x}{dt^2}.}[/tex]

[tex]\quad[/tex]

Solution:-

Let,

[tex]\cal{L}\{\rm{x(t)}\}=X(s)[/tex]

[tex]\cal{L}^{\rm{-1}}\{\rm{X(s)}\}=x(t)[/tex]

Given,

[tex]\longrightarrow\rm{x''(t)+x'(t)=2}[/tex]

We take Laplace transformation of both sides of the equation.

[tex]\longrightarrow\cal{L}\{\rm{x''(t)+x'(t)}\}=\cal{L}\{\rm{2}\}[/tex]

[tex]\longrightarrow\cal{L}\{\rm{x''(t)}\}+\cal{L}\{\rm{x'(t)}\}=\cal{L}\{\rm{2}\}[/tex]

We have,

[tex]\cal{L}\{\rm{x''(t)}\}=\rm{s^2\,X(s)-s\,x(0)-x'(0)}[/tex]

[tex]\cal{L}\{\rm{x'(t)}\}=\rm{s\,X(s)-\,x(0)}[/tex]

[tex]\cal{L}\{\rm{2}\}=\rm{\dfrac{2}{s}}[/tex]

Then,

[tex]\small\text{$\longrightarrow\rm{\big[s^2\,X(s)-s\,x(0)-x'(0)\big]+\big[s\,X(s)-x(0)\big]=\dfrac{2}{s}}$}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)-(s+1)\,x(0)-x'(0)=\dfrac{2}{s}}[/tex]

Given that [tex]\rm{x(0)=3}[/tex] and [tex]\rm{x'(0)=1.}[/tex] Then,

[tex]\longrightarrow\rm{s(s+1)\,X(s)-3(s+1)-1=\dfrac{2}{s}}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)-3s-4=\dfrac{2}{s}}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)=\dfrac{2}{s}+3s+4}[/tex]

[tex]\longrightarrow\rm{X(s)=\dfrac{2}{s^2(s+1)}+\dfrac{3s+4}{s(s+1)}}[/tex]

[tex]\longrightarrow\rm{X(s)=\dfrac{3s^2+4s+2}{s^2(s+1)}\quad\dots(1)}[/tex]

We will factorise this expression by partial fractions.

Assume,

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{As+B}{s^2}+\dfrac{C}{s+1}}[/tex]

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{(As+B)(s+1)+Cs^2}{s^2(s+1)}}[/tex]

[tex]\longrightarrow\rm{3s^2+4s+2=(As+B)(s+1)+Cs^2}[/tex]

[tex]\longrightarrow\rm{3s^2+4s+2=(A+C)s^2+(A+B)s+B}[/tex]

Equating corresponding coefficients,

[tex]\rm{A+C=3}[/tex]

[tex]\rm{A+B=4}[/tex]

[tex]\rm{B=2}[/tex]

Solving each equation we get,

[tex]\rm{A=2}[/tex]

[tex]\rm{B=2}[/tex]

[tex]\rm{C=1}[/tex]

Therefore,

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{2s+2}{s^2}+\dfrac{1}{s+1}}[/tex]

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}[/tex]

Then (1) becomes,

[tex]\longrightarrow\rm{X(s)=\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}[/tex]

Now we will inverse Laplace transformation to obtain the solution.

[tex]\longrightarrow\cal{L}^{\rm{-1}}\{\rm{X(s)}\}=\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}\right\}[/tex]

[tex]\small\text{$\longrightarrow\rm{x(t)}=\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}+\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s^2}}\right\}+\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s+1}}\right\}$}[/tex]

[tex]\small\text{$\longrightarrow\rm{x(t)}=\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}+\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1!}{s^{1+1}}}\right\}+\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s-(-1)}}\right\}$}[/tex]

We have,

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}=\rm{1}[/tex]

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1!}{s^{1+1}}}\right\}=\rm{t}[/tex]

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s-(-1)}}\right\}=\rm{e^{-t}=\dfrac{1}{e^t}}[/tex]

Hence,

[tex]\longrightarrow\rm{\underline{\underline{x(t)=2+2t+\dfrac{1}{e^t}}}}[/tex]

This is the solution to our differential equation.

[tex]\quad[/tex]

Some results of Laplace Transformation:-

[tex]\boxed{\begin{array}{c|c}&\\\rm{x(t)}=\cal{L}^{\rm{-1}}\{\rm{X(s)}\}&\rm{X(s)}=\cal{L}\{\rm{x(t)}\}\\\\=============&==================\\\\\rm{\dfrac{d^nx}{dt^n}}&\rm{s^n\,X(s)}-\displaystyle\sum_{\rm{r=0}}^{\rm{n-1}}\rm{s^{n-r-1}\,\dfrac{d^rx}{dt^r}(t=0)}\\\\----------&--------------\\\\\rm{x'(t)}&\rm{s\,X(s)-x(0)}\\\\----------&--------------\\\\\rm{x''(t)}&\rm{s^2\,X(s)-s\,x(0)-x'(0)}\\\\----------&--------------\\\\\rm{a}&\rm{\dfrac{a}{s}}\\\\----------&--------------\\\\\rm{t^n,\ n}\in\mathbb{N}&\rm{\dfrac{n!}{s^{n+1}}}\\\\----------&--------------\\\\\rm{e^{at}}&\rm{\dfrac{1}{s-a}}\\&\end{array}}[/tex]


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What is the nature of roots of the quadratic equation 9x2 6x 2 0?

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According to the Question:

The given quadratic equation:

9x²-6x-2 = 0

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To Find: the nature of roots of the given quadratic equation.

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= 36 -36(-2)

= 36 + 72

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Tommy and Zach will be 16 miles apart after 2.90 hours.

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The boxplot displays the arm spans for 44 students.
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The statement that is true is there are no outliers in this distribution.

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Selling and providing goods and services to customers is the process of distribution. The phrase is used to refer to marketing channels that are employed to contact clients in various contexts and geographical locations.

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In this scenario, the noticeable outliers in the data sets are 200 and 210. Thus, a statement which is not true about the data provided in the box plot above, is that there are no outliers in this distribution

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What is the arithmetic mean of the data set 4 5 0 10 8 and 2?

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Arithmetic mean of the data set 4, 5, 0, 10, 8 and 3  is '5'

As per the question the given data set is :

4 , 5 , 0 , 10 , 8 and 3

Number of observations in given data set are '6'

We have to determine the value of arithmetic mean of the data

Arithmetic Mean is simply the mean or average for a set of data or a collection of numbers.

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[tex]=\frac{30}{6}[/tex]

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Answer:

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Step-by-step explanation:

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Answer: $2.70

Step-by-step explanation:

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When it comes to doing problems like this, I like to put things in fractions. I have attached the explanation :)

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The probability of getting an ace from a well-shuffled deck of 52 cards is  1/13 and the probability of not getting an ace is 12/13

We can calculate the probability by the following method:

Total number of cards in a pack of cards= 52

Number of ace cards in a pack of cards= 4

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P(E)= Number of ace cards/ Total number of cards

= 4/52

(ii) Probability of any event other than E= 1- Probability of the event E=

If the drawing of a non-ace card is considered an event, suppose E', then

P(E')= 1- the probability of drawing an ace card

= 1- P(E)

= 1-1/13

= (13-1)/ 13

12/13

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Find the coordinates of point $p$ along the directed line segment $ab$ , from $a\left(8,\ 0\right)$ to $b\left(3,-2\right)$ , so that the ratio of $ap$ to $pb$ is $1$ to $4$.

Answers

The required coordinates of point P, following the given coordinate points, are (5.5, -1).

Let's assume that point P has coordinates (x, y). We want to find the coordinates of point P along the directed line segment AB, such that the ratio of AP to PB is 1 to 4.

The coordinates of point A are (8, 0), and the coordinates of point B are (3, -2).

According to the ratio given, we have:

AP/PB = 1/4

Now, we can use the midpoint formula to find the coordinates of point P. The midpoint formula states that the coordinates of the midpoint M between two points (x₁, y₁) and (x₂, y₂) are given by:

Midpoint M = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)

Let's use the midpoint formula to find the coordinates of point P:

x = (8 + 3) / 2
  = 5.5

y = (0 + (-2)) / 2
  = -1

So, the coordinates of point P are (5.5, -1).

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How do you find the height of a box when given the volume and base?

Answers

In order to determine the  height of a box we can use the formula h = V/b or if the given box is a square box or a cube then we can calculate its height by finding the cube root of its volume.

In the formula , V = volume and b = base

Volume is calculated in three dimension , it is the measure of the space occupied by an object . Any given solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

There are various shapes in geometry and all of them have a specific formula to calculate the volume.

The SI unit of volume for a cube is m³.

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The senior class is collecting orders for graduation, So far, 54% have ordered their yearbook, 58% have ordered their gown and 15% have ordered their gown but not their yearbook. Find that probability that a randomly selected senior...
1. has ordered both a gown and a yearbook.
2. has ordered a yearbook or a gown.
3. has ordered neither a yearbook nor a gown.
4. has ordered a yearbook but not a gown.

Answers

Answer:

1. has ordered both a gown and a yearbook: 54%

2. has ordered a yearbook or a gown: 58% + 54% = 112%

3. has ordered neither a yearbook nor a gown: 100% - (58% + 54%) = 88%

4. has ordered a yearbook but not a gown: 54% - 15% = 39%

Step-by-step explanation:

determine the 2.5th percentile of the normal distribution with a mean of 72.5 and a standard deviation of 15 as a decimal rounded to the nearest tenth.

Answers

Answer:

43.1

Step-by-step explanation:

2.5 % = .025    look for this value on the z-score table to find this corresponds to z = - 1.96   Standard Deviations

72.5      - 1.96 * 15    = 43.1  

1/cosx-tanx=3 what is the value of sinx

Answers

The value of sinx is 1 - 3cosx

What is Trigonometry?

Trigonometry is a field of mathematics that explores the connections between triangle side lengths and angles. The topic arose in the Hellenistic civilization during the third century BC from geometric applications to astronomical research. Today, four varieties of trigonometry are used: core, plane, spherical, and analytic. The ratio of the sides and angles of a right triangle is the subject of core trigonometry.

Solution:

1/cosx - tanx = 3

we can write tanx as sinx/cosx

this is because we know that sinx = Perpendicular / Hypotenuse

and cosx = Base / Hypotenuse

so if we divide sinx by cosx we will find that it is equal to Perpendicular / Base which is nothing but tanx

1-sinx = 3cosx

sinx = 1 - 3cosx

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How do you factor x3 y3?

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The factor of x³y³ is x.x.x.y.y.y or x²xy²y.

What is an expression?

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

x³y³

This can be factorized as,
x.x.x.y.y.y

or

x²xy²y

Thus,

The factor is x.x.x.y.y.y or x²xy²y.

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How do you find the value of X and Y in a given figure?

Answers

The value of angle x is 70° and angle y is 60° in the given figure with exterior angle = 120°

From the given figure, we know that the Exterior angle = 120°

To find the values of x and y we will follow the following steps.

We know that the sum of interior opposite angles is equal to the exterior angle of the triangle.

The exterior angle of the triangle=120°

The interior angles are x and 50°

50° + x = 120°

x = 120°- 50°

x = 70°

Also, we know that the sum of the y and the exterior angle is 180° because they are forming a linear pair.

Hence we have,

y + 120° = 180°

y = 180° - 120°

y = 60°

Therefore, the value of angle x is 70° and angle y is 60°.

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see this and pls give me the answers pls

Answers

can you give a more clearer image if possible, please?

For 1 it is option c
For each options just count the y axis for each graph, if you read the graph carefully, you will find that number of boys and girls in the class is the same.

What is the slope of the line given by the equation 3x 4y =- 12?

Answers

The line produced by the equation 3x + 4y=-12 has a slope of -3/4.

To find the slope of a line represented by the equation 3x + 4y = -12, you need to have the equation in the form y = mx + b, where m is the slope and b is the y-intercept (the point at which the line crosses the y-axis).

To put the equation 3x + 4y = -12 in this form, you can start by isolating the y term on one side of the equation:

3x + 4y = -12

4y = -3x - 12

y = (-3/4)x - (12/4)

The slope of the line produced by the equation 3x + 4y=-12 is therefore -3/4.

The complete question is:-

What is the slope of the line given by the equation 3x +4y =- 12?

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Multiple choice math. Make sure you are correct tho!

Answers

Answer: The answer is option 1

Step-by-step explanation

The given equation is [tex](p^{2} r^{3} /pr^{4} )^{2}[/tex]

 [tex](p^{2} r^{3} /pr^{4})^{2}[/tex]  =  [tex]p^{4} r^{6} /p^{2}r^{8}[/tex]  (the given equation whole square is applied)

[tex]p^{4} r^{6} /p^{2} r^{8}[/tex]  =  [tex]p^{2} /r^{2}[/tex]   (the p and r are canceled out )

Therefore the correct answer is  [tex]p^{2} /r^{2}[/tex]

Construct a table and find the indicated limit. If h(x) = square root x + 2/x - 5, then, Complete the table below.

Answers

The limit of h(x) as x approaches infinity is ∞, and as x approaches 0, is undefined due to division by zero.

x h(x)

1 2 + 2

2 1.41 + 1

4 2 + 0.25

8 2.83 + 0.125

16 4 + 0.0625

To find the limit of h(x) as x approaches infinity, we see that h(x) = √(x) + 2/x - 5. As x increases without bounds, the square root of x and 2/x both approach infinity, but the value of -5 is constant. Therefore, the limit of h(x) as x approaches infinity is infinite.

To find the limit of h(x) as x approaches 0, we see that h(x) = √(x) + 2/x - 5. As x approaches 0, the value of the square root of x approaches 0, and the value of 2/x approaches infinity. However, the value of -5 is constant. Therefore, the limit of h(x) as x approaches 0 is -5 + ∞, which is undefined.

The limit of h(x) as x approaches 0 is undefined.

You could also say that the function is not defined at x = 0, meaning that the limit as x approaches 0 does not exist.

It's worth noting that the original function is not defined when x=0 as we are dividing by x, so it's impossible to calculate the limit of this function at that point.

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What is the slope of the line 5x 3y 15?

Answers

-a/b=-5/3  is the slope of the line 5x 3y 15

for

ax+by=c

the slope is -a/b

the slope of paralell lines are the same

find slope

5x+3y=15

-a/b=-5/3

paralell as same slope

the slopes are:

L1: slope 3

L2: slope -3

L3: slope -1/3

So now multiply the slopes of each pair of lines:

L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular

L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular

L1 and L3: (3) *  (-1/3) = -1 => Yes, they are penpendicular.

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What is the solution of 2x² 5x 3 0?

Answers

The solution of the equation 2x^2 + 5x + 3 = 0 is x = -3 and x = -1/2. This can be found by using the Quadratic Formula, which states that for any quadratic equation of the form ax^2 + bx + c = 0, the solutions are x = (-b +/- sqrt(b^2 - 4ac))/2a.

The solution of the equation 2x^2 + 5x + 3 = 0 can be found by using the Quadratic Formula. The Quadratic Formula states that for any quadratic equation of the form ax^2 + bx + c = 0, the solutions are x = (-b +/- sqrt(b^2 - 4ac))/2a. By substituting the given coefficients a = 2, b = 5, and c = 3 into this equation, we can solve for x. First, we calculate the discriminant b^2 - 4ac, which in this case is 25 - 24 = 1. Because the discriminant is positive, the equation has two real solutions. Next, we use the Quadratic Formula to calculate the solutions. To calculate the first solution, we substitute the given coefficients into the formula and solve for x: x = (-5 +/- sqrt(1))/2 = (-5 +/- 1)/2 = -3 and -1/2.

Therefore, the solution of the equation 2x^2 + 5x + 3 = 0 is x = -3 and x = -1/2.

Discriminant: b^2 - 4ac = 25 - 24 = 1

Solution 1: x = (-5 +/- sqrt(1))/2 = (-5 +/- 1)/2 = -3

Solution 2: x = (-5 +/- sqrt(1))/2 = (-5 +/- 1)/2 = -1/2

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How do you know if a figure is similar or congruent?

Answers

Answer:

Congruent means the same shape but perhaps moved or rotated or reflected

Similar means a shape that has been enlarged by a scale factor

Step-by-step explanation:

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