Solve the problem using a system of equations: The difference of the squares of two numbers is 15. The difference of twice the square of the first number and the square of the second number is 30. Find the numbers.
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Answer:

x to the power of 3

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

yeah-ya............ right?

Check the picture below.

Answer:

x=34 because you simplify it and then take 45 and at it to it

28 years

Step-by-step explanation:

The dog is twice as old as the cat

The monkey is twice as old as the dog.

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Their total age is 4 years 2 months.

1 year has 12 months

=> 4 years have (4 × 12)

= 48 months

Since, the total age is 4 years 2 months, we can express it in "months" by adding "48" and "2".

= 50 months

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Sum of their ages = 50 months

=> x + 2x + 4x = 50

=> 7x = 50

=>x = 50/ 7 months

If we write this in mixed fractions the whole number will represent the number of years.

=

[tex] \mathsf{7 \frac{1}{7} \: \: months}[/tex]

[tex] = \mathsf{7 \: years \: \frac{1}{7} \: \: months}[/tex]

The value of 1/ 7 is really small,I.e., 0.1428...

So, we can ignore the fraction while rounding off the term that makes it

[tex] \mathsf{x = 7yrs.(approx.)}[/tex]

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x is the age of the cat.

The monkey's age is "4x"

= 4 × 7

= 28 years.

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So, the monkey's age is approximately 28 years

Answer:

1.  D

2. B

3. The six in the first one is in the tenths place, the second is in the thousandths. But the answer is A.

4. 5, 0.9, 0.85, 0.438, 0.42, 0.341, 0.253, 0.13, 0.1, 0.087, 0.042, 0.03, 0.023, 0.01, 0.006, 0.002, 0 Sorry, I did greatest to least on accident.

5. 0.9, 0.853, 0.82, 0.51, 0.238, 0.2, 0.187, 0.11, 0.106, 0.103, 0.072, 0.053, 0.05, 0.03 greatest to least.

Uhm, sorry if I ordered some wrong on accident.

Answer:

1024

Step-by-step explanation:

because its going by 4

Answer:

4x + 2y ≤ 20

Step-by-step explanation:

x = burger

y = fries

a.    4x + 2y ≤ 20      at most means ≤

6-7

y < -1 -4

x > -4 y ≥+ 2

hope it helps

wait Lang SA 6-7

Answer:

ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok

Answer:

A

Step-by-step explanation:

Because the x doesn't repeating

Hope it can help you lovelots

#LEARN WITH BRAINLY

Answer:

50 hours

Step-by-step explanation:

Step-by-step explanation:

The exact solutions are: x = 11 + √72 and x = 11 - √72

The approximate solutions are: x = 19.49 and x = 2.51

[tex]\\ \sf\longmapsto (x-11)^2=72[/tex]

[tex]\\ \sf\longmapsto x-11=\sqrt{72}[/tex]

[tex]\\ \sf\longmapsto x-11=\pm 8.48[/tex]

[tex]\\ \sf\longmapsto x=11-8.48\:or\:11+8.48[/tex]

[tex]\\ \sf\longmapsto x\approx 2.52\:or\:19.48(Approximate)[/tex]

[tex]\\ \sf\longmapsto x=3\:or\:19(Exact)[/tex]

Answer:

x = 8, x = 2

Step-by-step explanation:

|2(x-5)|+11=17​

|2(x-5)| = 6

|(x-5)| = 3

x = 8 AND x = 2 because of the absolute value.

Brainliest, please :)

The solution of the given equation will be x = 2 and 8.

What is an expression?

Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that;

The expression is;

| 2 (x - 5) | + 11 = 17

Now, Solve the expression is;

| 2 (x - 5) | + 11 = 17

Subtract 11 both side,

| 2 (x - 5) | + 11 - 11 = 17 - 11

| 2 (x - 5) | = 6

Reduce modulus we get;

2 (x - 5) = ±6

Take positive sign,

2 (x - 5) = 6

x - 5 = 6/2

x - 5 = 3

x = 3 + 5

x = 8

And, Take negative sign,

2 (x - 5) = -6

x - 5 = -6/2

x - 5 = -3

x = 5 - 3

x = 2

Thus, The solution of the given equation will be x = 2 and 8.

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90 degrees - 78 degrees = 12 degrees

cofunction of sin is cos

answer : cos12

Answer:

NO

Step-by-step explanation:

“PEMDAS” (parenthesis, exponents, multiplication, division, addition, subtraction)

so you need to sole 4x and after add 10

Answer:

17.999999999999999

Step-by-step explanation:

Answer:

25 and 1/12

1/3+1/3+2/3+1/2+1/2+3/4 = 4 and 1/12

6+5+4+3+2+1 = 21

Given info: -17/2 < (-1/2) - 4x ≤ 15/2

Find the value of x ?

Explanation:↓

Given in-equation is -17/2 < (-1/2) - 4x ≤ 15/2

⇛ -17/2 < (-1-8x)/2 ≤ 15/2

On multiplying with 2 then

⇛ 2(-17/2) < 2(-1-8x)/2 ≤ 2(15/2)

⇛ -17 < -1-8x ≤ 15

On adding 1 in the in-equation then

⇛ -17+1 < -1-8x+1 ≤ 15+1

⇛ -16 < -8x ≤ 16

On dividing by 8 in the in-equation then

⇛ -16/8 < -8x/8 ≤ 16/8

⇛ -2 < -x ≤ 2

⇛ 2 > x ≥ - 2

⇛ -2 ≤ x < 2

⇛ x € [-2,2)

Answer:→The solution set = { x : -2 ≤ x < 2, x€R }

The possible values of x = -2,-1,0,1

If you have any doubt, then you can ask me in the comments.

Answer:

C, x + 20 = 41

Step-by-step explanation:

X represents the number of small sea shells that we originally had. When the family adds 20 more shells, that makes x + 20. The total number is 41, so that means the number of sea shells they already had (x) plus the number of sea shells they collected (20) equals the number of shells they have now (41).

hii the answer would be 57°

Answer:

y + 1 = -5(x - 4)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

Step-by-step explanation:

Step 1: Define

Identify variables.

Point (4, -1) → x₁ = 4, y₁ = -1

Slope m = -5

Step 2: Find Equation

Answer:

4

Step-by-step explanation:

You want a cookie?

Answer:

2+2 = 4

Step-by-step explanation:

1+1+1+1 = 4

Hope this helped!

mark me brainliest :D

The the table of values that you would use to graph [tex]f(x) = 3x^{2} -4[/tex]  is option "B"

A point is the basic relationship displayed on a graph. Each point is defined by a pair of numbers containing two coordinates. A coordinate is one of a set of numbers used to identify the location of a point on a graph.

According to the question

Points on graph for equation :

[tex]f(x) = 3x^{2} -4.[/tex]  

Now,

Table of points on graph

x                  y

-2                8

-1                 -1

0                 -4

1                   -1

2                   8

Hence, The the table of values that you would use to graph [tex]f(x) = 3x^{2} -4[/tex]  is option "B" .

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Answer: a little too late but in case anybody else needs it!

Step-by-step explanation:

Answer:

x=13.38

Step-by-step explanation:

Hi there!

We are given triangle ABC, with m<A=45°, CA=13, and BA=x

We want to find the value of x

First, let's find out which side is the adjacent, opposite, and hypotenuse

Using <A as the reference angle:

BC is the opposite

CA is the adjacent

BA is the hypotenuse

Recall the 3 most common trigonometric functions:

Sine is [tex]\frac{opposite}{hypotenuse}[/tex]

Cosine is [tex]\frac{adjacent}{hypotenuse}[/tex]

Tangent is [tex]\frac{opposite}{adjacent}[/tex]

Since we know the values of both the adjacent and the hypotenuse, let's use the cosine of <A

In reference to <A, the ratio will be:

cos(<A)=[tex]\frac{CA}{BA}[/tex]

Substituting all known values gives:

cos(45)=[tex]\frac{13}{x}[/tex]

Now multiply both sides by x

cos(45)x=13

Divide both sides by cos(45)

x=[tex]\frac{13}{cos(45)}[/tex]

Now plug [tex]\frac{13}{cos(45)}[/tex] into your calculator. Make sure that the calculator is in degree mode

x≈13.38

Hope this helps!

Answer:

On the number line, a number and its opposite are, predictably, opposite each other. In other words, they are the same distance from zero, but on opposite sides of the number line. The opposite of zero is defined to be simply zero. The sum of a number and its opposite is always zero, as shown in the following example.

Combine the fractions on the left with a common denominator:

[tex]\dfrac a{x+1} + \dfrac b{x-1} + \dfrac c{(x+1)^2} = \dfrac{a(x+1)(x-1) + b(x+1)^2 + c(x-1)}{(x-1)(x+1)^2}[/tex]

It follows that

[tex]3x^2+3x-2 = a(x+1)(x-1) + b(x+1)^2 + c(x-1)[/tex]

Expand the right side and collect like powers of x :

[tex]3x^2+3x-2 = a(x^2-1) + b(x^2+2x+1) + c(x-1)[/tex]

[tex]3x^2+3x-2 = (a+b)x^2 + (2b + c)x -a +b - c[/tex]

Then we have the system of equations

[tex]\begin{cases}a+b=3\\2b+c=3\\-a+b-c=-2\end{cases}[/tex]

or in matrix form,

[tex]\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix} \begin{bmatrix}a\\b\\c\end{bmatrix} = \begin{bmatrix}3\\3\\-2\end{bmatrix}[/tex]

Compute the determinant of the coefficient matrix:

[tex]\det\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix} = -4[/tex]

Then the inverse of the coefficient matrix is equal 1/det times the adjugate of the coefficient matrix (a.k.a the transpose of the cofactor matrix):

[tex]\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix}^{-1} = \dfrac1{-4} \begin{bmatrix}-3 & -1 & 2 \\ 1 & -1 & -2 \\ 1 & -1 & 2\end{bmatrix}^\top = -\dfrac14 \begin{bmatrix}3&-1&-1\\1&1&1\\-2&2&-2\end{bmatrix}[/tex]

Multiply both sides of the equation by the inverse :

[tex]\begin{bmatrix}a\\b\\c\end{bmatrix} = -\dfrac14 \begin{bmatrix}3&-1&-1\\1&1&1\\-2&2&-2\end{bmatrix} \begin{bmatrix}3\\3\\-2\end{bmatrix} = \begin{bmatrix}2\\1\\1\end{bmatrix}[/tex]

So, we have a = 2 and b = c = 1, and the partial fraction decomposition is

[tex]\dfrac{3x^2+3x-2}{(x+1)^2(x-1)} = \dfrac 2{x+1} + \dfrac 1{x-1} + \dfrac 1{(x+1)^2}[/tex]

Answer:

Step-by-step explanation:

One can solve for a, b, c a little more directly than using a system of 3 equations.

If we multiply the rational expression by (x+1)², we get ...

  (3x² +3x -2)/(x -1) = (x+1)²(a/(x+1) +b/(x-1)) +c

Evaluating this for x = -1 gives ...

  (3(-1)² +3(-1) -2)/(-1 -1) = c

  -2/-2 = 1 = c

Similarly, multiplying by (x -1) gives ...

  (3x² +3x -2)/(x +1)² = (x -1)(a/(x +1) +c/(x +1)²) + b

Evaluating this for x = 1 gives ...

  (3·1² +3·1 -2)/(1 +1)² = b

  4/4 = 1 = b

Now, we need to find the value of 'a'. The identity will hold true for any value of x, so we can see what happens when we substitute x=0. We can use the values of 'b' and 'c' that we found above.

  (3·0² +3·0 -2)/((0 +1)²(0 -1)) = a/(0 +1) +1/(0 -1) +1/(0 +1)²

  -2/-1 = a -1 +1   ⇒   a = 2

_____

System of equations solution

When the terms of the right-side expansion are combined, the numerator of the result is ...

  a(x +1)(x -1) +b(x +1)^2 +c(x -1) = (a+b)x² +(2b+c)x +(-a+b-c) ≡ 3x² +3x -2

Equating the coefficients gives the system of equations whose augmented matrix is:

  [tex]\left[\begin{array}{ccc|c}1&1&0&3\\0&2&1&3\\-1&1&-1&-2\end{array}\right][/tex]

Transforming this to reduced row-echelon form using any of a variety of available tools gives ...

  [tex]\left[\begin{array}{ccc|c}1&0&0&2\\0&1&0&1\\0&0&1&1\end{array}\right][/tex]

which tells you the solution is (A, B, C) = (2, 1, 1).