SOMEBODY PLEASE HELP I NEED THIS ASAP

Answer:

36.5

Step-by-step explanation:

First solve for x

Factor:

3x-3-5x+15 = 3

Combine Like Terms:

-2x+12=3

-2x = -9

x = 4.5

PLug it in:

7(4.5)-5

31.5-5

36.5

[tex]{\boxed{\mathcal{\red{Step-by-step\:explanation:-}}}}[/tex]

[tex]3(x - 1) - 5(x - 3) = 3 \\ ⇝3x - 3 - 5x + 15 = 3 \\ ⇝ - 2x + 12 = 3 \\ ⇝ - 2x = 3 - 12 \\ ⇝x = \frac{ - 9}{ - 2} \\ x = 4.5[/tex]

To verify:

[tex]3(4.5 - 1) - 5(4.5 - 3) = 3 \\ ✒ \: 13.5 - 3 - 22.5 + 15 = 3 \\ ✒ \: 28.5 - 25.5 = 3\\✒\: 3 = 3[/tex]

✒ L. H. S. = R. H. S.

[tex]\sf\pink{Hence\:verified.}[/tex] ✔

Now,

7 [tex]x[/tex] - 5 = 7 x 4.5 - 5

= 31.5 - 5

= 26.5

[tex]\sf\purple{Therefore,\:the\:value\:of\:''7\:x-\:5''\:is\:26.5.}[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

You would be correct!

Step-by-step explanation:

10 × 4 = 40 40 + 15 = 55 therefore D is the answer great job!

Answer:

mexico

Step-by-step explanation:

Answer:

13.  4 sqrt(3)

14.  sqrt(7)/2

Step-by-step explanation:

13.  sqrt(2) * sqrt(3) * sqrt(8)

We know sqrt(a) * sqrt(b) = sqrt(ab)

sqrt(48)

Look for perfect squares

sqrt(16*3)

sqrt(16) sqrt(3)

4 sqrt(3)

14.  sqrt(14)/ 2 sqrt(2)

We know sqrt(a) / sqrt(b) = sqrt(a/b)

sqrt(14/2) / 2

sqrt(7)/2

Hence, the Answer is

13.  4 sqrt(3)

14.  sqrt(7)/2

Solution:

13.  sqrt(2) * sqrt(3) * sqrt(8)

We know sqrt(a) * sqrt(b) = sqrt(ab)

sqrt(48)

Look for perfect squares

sqrt(16*3)

sqrt(16) sqrt(3)

4 sqrt(3)

14.  sqrt(14)/ 2 sqrt(2)

We know sqrt(a) / sqrt(b) = sqrt(a/b)

sqrt(14/2) / 2

sqrt(7)/2

Answer:

B. 1,1,2,3,5,8,13,21

Step-by-step explanation:

I calculated it logically

Answer:

A.   x < -1

Step-by-step explanation:

Open circle at -1 with line to the left

A.   x < -1

Answer:

Step-by-step explanation:

Given 10.43, you can 'estimate' it only by rounding off:

10.43 to the nearest tenth is 10.4.

10.43 to the nearest whole number is 10; we drop the fraction 0.43.

1

Answer:

X=1

Step-by-step explanation:

I just did the math and boom but i think you should use this app https://www.tiger-algebra.com

Answer:

#1 Eighty-nine and 23 thousandths. #2 B.

Step-by-step explanation:

9 is more than 8. ‍♀️

Answer:

Step-by-step explanation:

5(2b+3)+8(b-6)

=10b+15+8b-48

=18b-33

=3(6b-11)

Answer:

100,000

Step-by-step explanation:

So, when they say how many times larger 3x10^6 is than 3x10^1, they need you to divide 3x10^6 by 3x10^1.

When doing division and multiplcation with exponents, you subtract and add.

So, we have [tex]\frac{3*10^6}{3*10^1}[/tex]

The 3, that doesnt have a exponent on top or bottom, cancels out:

So now we have [tex]\frac{10^6}{10^1}[/tex]

Finally, since we are dividing 10^6 by 10^1, we are actually subtracting the exponents:

So we have [tex]10^5[/tex]

When you distrubute the ^5, you get:

100,000

So this is how many times bigger 3* [tex]10^6[/tex] is than 3*[tex]10^1[/tex]

HOpe this helps! :D

Answer:

Kindly check explanation

Step-by-step explanation:

An appropriate research design which may be employed is to perform a random assignment of the 150 students into two groups whereby a certain group is made to perform the jumping exercise and the other group sitting still for 5 minutes, after this concentration level is measured in both groups in other to evaluate if there are differences in concentration levels between the two groups.

Given the hypothesis :

H0: There is no difference in the mean improvement of long-term concentration for either treatment.

Ha: The mean improvement of long-term concentration is greater for the jumping jacks treatment.

A type 1 error occurs when a true null is rejected ; this means that we conclude that The mean improvement of long-term concentration is greater for the jumping jacks treatment when this is actually not true. Hence, students will be allowed to do jumping jack in class but there won't be any improvement.

A type 11 error occurs when we fail to reject a false null hypothesis ; Hence, we conclude that There is no difference in the mean improvement of long-term concentration for either treatment when the jumping Jacks treatment actually does improve concentration level. Hence, the school will fail to allow students do jumping jack in class.

In my opinion, type 11 error is more serious in this scenario because, the school would have failed to identify and ignored a treatment which makes it's students attain a better level of concentration.

Answer:

The question seems incomplete.

Step-by-step explanation:

Answer:

16 - (4 x 3) + 7

Step-by-step explanation:

16 - (4 x 3) + 7

16 - 12 + 7

4 + 7

11

Answer:

The best estimate of the population mean for heart rate among football players is of 71.4 beats per minute.

Step-by-step explanation:

The best estimate for the population mean is the sample mean.

Sample mean:

Sum of all values in the sample divided by 10(size of the sample). So

[tex]\overline{x} = \frac{62+74+74+64+76+64+80+76+68+76}{10} = 71.4[/tex]

The best estimate of the population mean for heart rate among football players is of 71.4 beats per minute.

Answer: 71.4

Just a confrimation to the below anwser.

Answer:

b

Step-by-step explanation:

Answer:

50%

Step-by-step explanation:

Recall : When given a normal or Symmetric distribution, the mean of the distribution is at the centre with 0.5 or 50% of the distribution to either side (right and left) of the distribution.

Hence, if the mean = 21 ; then the percentage of student body with atleast 21 years is the percentage to the left of the distribution, which is 50%.

Therefore, P(x ≤ 21) = 0.5 = 50%

Answer:

9

Step-by-step explanation:

Highest number is 19 lowest is 10. 19-10 is 9.

Answer:

see first of all it is a quadratic polynomial so it will have 2 zero alpha and beta

now , we will find value of a , b, c

so,

a= 3

b= 5

c= -2

now, sum of the zeros ( alpha + beta) =-b/a

so,-5/3

now product of zeros (alpha *beta) = c/a

so, it will we -2/3

hope you get it !

1) 3.25n

Overall cost of n gallons of gas

2)3.25n = 26

we are spending 26 dollars on 8 gallons of gas

3)40-3.25n

Ammount we have remaining after spending on n gallons of gas out of 40 dollars

4) 40-3.25n = 1.00

The maximum number of gallons of gas we can buy from 40 dollar is 13 gallons and 1 dollar is still remaining to us.

The given representations could be classified thus :

3.25n (Expression)

3.25n=26 (Equation)

40-3.25n (Expression)

40-3.25n=1.00 (Equation)

Total amount to spend = $40

Cost per gallon = $3.25

Number of gallons = n

An expression could be a variable, constant or a combination of both which is related by an operation symbol.

An equation on the other hand maybe defined as a relationship between two expressions linked by an equal to symbol.

Evaluating the representations given :

3.25n : This is an expression as it lacks an equal to sign connecting the expression. The expression means the cost of n gallons of gas.

3.25n = 26 : This is an equation as it contains two Seperate expressions connected by the equal to sign. The equation means that number of gallons of gas, n that can be purchased with $26.

40 - 3.25n : This is an expression. The amount left after purchasing n gallons from $40.

40 - 3.25n = 1.00 : This is an equation. The number of gallons of gas that can be purchased from $40 and still have $1 left.

Learn more : https://brainly.com/question/18109354

Answer:

3 weeks

Step-by-step explanation:

Two puppies from the same litter are named Bruno Puppy Weight and Jasper. Their weights during the first  weeks are plotted on the coordinate grid. At which age did Bruno and Jasper weigh the same?

Solution:

We can see that Bruno and Jasper weight is represented by a straight line. Let y represent the weight of the puppies in ounce and x represent the age in weeks.

For Bruno:

The line passes through (1, 10) and (5, 16), hence the equation of the line is:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-10=\frac{16-10}{5-1} (x-1)\\\\y-10=\frac{3}{2}(x-1)\\\\y=1.5x+8.5\ \ \ (1)[/tex]

For Jasper:

The line passes through (0, 12) and (3, 13), hence the equation of the line is:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-12=\frac{13-12}{3-0} (x-0)\\\\y-12=\frac{1}{3}(x)\\\\y=\frac{1}{3} x+12\ \ \ (2)[/tex]

To find the age at which both puppies weighed the same, we have to solve equation 1 and 2 simultaneously. Subtract equation 1 from 2:

-1.167x + 3.5 = 0

1.167x = 3.5

x = 3

Put x = 3 in equation (2)

y = (1/3)(3) + 12 = 13

The solution is (3, 13)

Therefore both Jasper and Bruno weigh the same weight of 13 ounce at 3 weeks of age

Answer: 290

Step-by-step explanation: Because a circle area is 360 and if you subtract 70 from 360 you will get 290

And 290 + 70 = 360

Answer:

2 + 3x(N-1) = Amount of money donated

Step-by-step explanation:

Since Aaron participates in a walkathon for charity, and he has a sponsor who has pledged a base donation of $ 2 for the first mile he walks and then a certain dollar amount for each additional mile he walks, and based on this pledge, if Aaron walks 8 miles, the sponsor will donate a total of $ 23 to the charity, to determine a formula that can be used to determine the amount of money this sponsor donates when Aaron walks N miles the following equation should be raised:

2 = fixed amount in the first mile

2 + ((23 - 2) / (8-1)) x (N-1) = Amount of money donated

2 + (21/7) x N = Amount of money donated

2 + 3x (N-1) = Amount of money donated

Thus, if N is 8, as in the example, the quantity is determined as follows:

2 + 3x (8-1) = X

2 + 3x7 = X

2 + 21 = X

23 = X

Answer:

The roots are: 1, -7 and -7

Step-by-step explanation:

When we put x = -1 in F(x) it is equal to 0

Thus, (x + 1) is factor of given function.

When we divide F(x) by (x + 1) it gives the value (x² - 6x - 7)

Now, factorizing x² - 6x - 7 by middle term splitting.

x² - 6x - 7 = x² - 7x + x - 7

⇒ x(x - 7) + 1(x - 7)

⇒ (x + 1) (x - 7)

Thus, x³ - 5x² - 13x - 7 = (x + 1)(x + 1)(x - 7)

Thus, Roots of the given polynomial function is x = -1, -1, 7

Hope this answer helps you :)

Have a great day

Mark brainliest

Answer:

[tex]66.42\%[/tex]

Step-by-step explanation:

Hi there! We can establish the following inequality with the given weights provided in your question:

[tex]85.29\cdot 0.4+81.5\cdot 0.4 +\text{Final Exam Grade}\cdot0.2 \geq 80[/tex]

Solving, we get:

[tex]66.716+\text{Final Grade}\cdot 0.2\geq 80,\\\text{Final Exam Grade}\cdot 0.2\geq13.284,\\\text{Final Exam Grade}\geq\boxed{66.42\%}[/tex]

Thus, to maintain a final semester grade of 80% or higher, you must achieve a minimum of [tex]66.42\%[/tex] on your final exam!