someone pls help with this equation (subtract the following two equations, to eliminate the x variable then solve for y) ILL MARK YOU BRAINLIEST!!!

The number of the same coin that she has will be 6.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Janice has $2.46 worth of coins in her pocket. The coins are of four different denominations, and she has the same number for each denomination.

If there are any pennies, nickels, dimes, or quarters on Janice. Trial and error led me to the following conclusions:

1 of each coin: 0.01 + 0.05 + 0.10 + 0.25 = 0.41

2 of each coin: 0.02 + 0.10 + 0.20 + 0.50 = 0.82

3 of each coin: 0.03 + 0.15 + 0.30 + 0.75 = 1.23

4 of each coin: 0.04 + 0.20 + 0.40 + 1.00 = 1.64

5 of each coin: 0.05 + 0.25 + 0.50 + 1.25 = 2.05

6 of each coin: 0.06 + 0.30 + 0.60 + 1.50 = 2.46

Based upon these results, Janice has 6 of each coin.

Let x be the number of coins. Then we can set up the equation will be

0.01x + 0.05x + 0.10x + 0.25x = 2.46

0.41x = 2.46

x = 6

The number of the same coin that she has will be 6.

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Answer:

The length of the vector is of [tex]\sqrt{194}[/tex]

The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]

Step-by-step explanation:

Vector from point P(3,-5,2) to Q(-5,4,9)

The vector is:

[tex]PQ = Q - P = (-5-3, 4-(-5), 9-2) = (8,9,7)[/tex]

The length is:

[tex]\sqrt{8^2+9^2+7^2} = \sqrt{194}[/tex]

The length of the vector is of [tex]\sqrt{194}[/tex]

Find a unit vector with the direction of PQ

We divide each component of vector PQ by its length. So

[tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]

The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]

9514 1404 393

Answer:

  ∠A and ∠G

  ∠C and ∠E

Step-by-step explanation:

Vertical angles have the same vertex and are formed from opposite rays. In this figure, the pairs of vertical angles are ...

  {A, G}, {B, H}, {C, E}, {D, F}

Of these pairs, the ones listed in your answer choices are ...

  ∠A and ∠G

  ∠C and ∠E

Answer:

[tex]1) 3x+45=90[/tex]

[tex]3x=90-45[/tex]

[tex]3x=45[/tex]

[tex]\frac{3x}{3} =\frac{45}{3}[/tex]

[tex]x=15[/tex]

1) The angles are complementary

[tex]--------[/tex]

[tex]2)x-20+x=90\\[/tex]

[tex]2x=90+20[/tex]

[tex]2x=110[/tex]

[tex]x=55[/tex]

2) The angles are complementary

[tex]--------[/tex]

[tex]3)2x+(3x+25)=180[/tex]

[tex]2x+3x+25=180[/tex]

[tex]2x+3x=180-25[/tex]

[tex]5x=155[/tex]

[tex]x=\frac{155}{5}[/tex]

[tex]x=31[/tex]

3) The angles are supplementary

[tex]----------[/tex]

hope it helps..

have a great day!!

Answer:

Perimeter of rectangle EFGH = 24 unit

Step-by-step explanation:

Given:

E: (4,2)

F: (10,2)

G: (10,8)

H: (4,8)

Find:

Perimeter of rectangle EFGH

Computation:

Distance = √(x1 - x2)² + (y1 - y2)²

Distance between EF = √(4 - 10)² + (2 - 2)²

Distance between EF = √36

Distance between EF = 6units

Distance between FG = √(10 - 10)² + (2 - 8)²

Distance between FG = √36

Distance between FG = 6 units

Distance between GH = √(10 - 4)² + (8 - 8)²

Distance between GH = √36

Distance between GH = 6 units

Distance between HE = √(4 - 4)² + (8 - 2)²

Distance between HE = √36

Distance between HE = 6 units

Perimeter of rectangle EFGH = 6 + 6 + 6 + 6

Perimeter of rectangle EFGH = 24 unit

Answer:

4/15

Step-by-step explanation:

Answer:

Total surface area of cone = 578.28 unit²

Step-by-step explanation:

Given:

Slanted Hight of cone = 15 unit

Radius of cone = 8 units

Find:

Total surface area of cone

Computation:

Total surface area of cone = πr[l + r]

Total surface area of cone = (22/7)(8)[15 + 8]

Total surface area of cone = (22/7)(8)[23]

Total surface area of cone = (22/7)(184)

Total surface area of cone = 4,048 / 7

Total surface area of cone = 578.28 unit²

Answer:

item total cost: 4.19

Answer:

The correct answer is A. The actual height of the Eiffel Tower is 301 meters.

Step-by-step explanation:

Given that a model of the Eiffel Tower uses a scale of 1 cm - 4 meters, if the model is 75 1/4 a centimeters tall, to determine what is the actual height of the Eiffel Tower the following calculation must be performed:

1 = 4

1/4 = 0.25

75.25 x 4 = X

301 = X

Therefore, the actual height of the Eiffel Tower is 301 meters.

Answer:

916.1 cm^3

Step-by-step explanation:

1) find the radius of the cylinder:

radius = dimater / 2 = 7,3 / 2 = 3.65 cm

2) find the base area of the cylinder:

base area = radius^2 x 3.14 = 3.65^2 x 3.14 = 41.83265 cm^2

3) find the height of the cylinder:

height = 7.3 x 3 = 21.9 cm

4) find the volume

V = base area x height = 41.83265 x 21.9 = 916.135035 cm^3

5) round to nearest tenth:

916. 1 cm^3

Step-by-step explanation:

.........................

.......

Answer:

Step-by-step explanation:

5/2 hours = 2 1/2 hours

2 1/2 hours = 120 minutes + 30 minutes = 150 minutes.

I don't know if he has more than 1 device or not. But if he does, then this time is the base and you just multiply by 2 1/2 for each device.

Answer:

Solution given:

a student typically spends 5/2 hours each week

research time does a student spend each device in 1 week=5/2=2hours and 30min=150minutes

Answer:

x= -2 y = ([tex]\frac{1}{49}[/tex])

x= 0 y = 1

x= 2 y = 49

Step-by-step explanation:

x= -2  -> (7)² = 49, negative power makes it inverse to a fraction

y = ([tex]\frac{1}{49}[/tex])

x= 0  -> anything to the power of 0 is always 1

y = 1

x= 2 -> 7² = 7 × 7 = 49

y = 49

Answer:

[tex]Period = \pi[/tex]

Step-by-step explanation:

Given

[tex]y = -\frac{1}{3} * \sin(2x)[/tex]

Required

The period

A sine function is represented as:

[tex]y =A \sin(Bx + C) + D[/tex]

Where

[tex]Period = \frac{2\pi}{B}[/tex]

By comparing:

[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]

[tex]B = 2[/tex]

So, we have:

[tex]Period = \frac{2\pi}{2}[/tex]

[tex]Period = \pi[/tex]

Hence, the period of the function is [tex]\pi[/tex]

Answer:

4/11...................

Answer: 4/11

Step-by-step explanation:

The total number of books is 35+20=55, which will be the denominator, because the question is asking what fraction of all the books are hardcover. The number of hardcover books, 20, will be the numerator, so we end up with the fraction 20/55. 20 and 55 are both divisible by 5 (this means that when divided by 5, both numbers have a whole number quotient). 20/5= 4 and 55/5=11

So, the answer is 4/11

Answer:

2000 milliliters

Step-by-step explanation:

2 liters = 2000 milliliters

Answer:

2000 milliliters

Step-by-step explanation:

1 liter=1000 milliliters

2x1000=2000

2000 milliliters

Answer:

C for the first one

1,6 for the second

Neither for the third

Step-by-step explanation: EDGE 2021

Answer:

The first Question is C

Question 2 is 1,6

Question 3 is Neither

Step-by-step explanation:

trust me I took the quiz

Answer:

20 = 4n

n = 5

Step-by-step explanation:

Given that :

Number of gifts Keiko wrapped = 20

Let number of gifts wrapped by Henry = n

Keiko wrapped 4 times as many gifts as Henry

Hence,

20 = 4n

The equation that relates the number of gifts wrapped is :

20 = 4n

To obtain n ;

Divide both sides by 4 to isolate n

20/ 4 = 4n / 4

5 = n

Hence,

n = 5

Answer:

y = [tex]\frac{1}{2}x+8[/tex]

Step-by-step explanation:

From the table given in the picture,

Two points lying on the graph are (-4, 6) and (-2, 7)

Let the linear function is,

y = mx + b

Here, m = slope of the line

b = y-intercept

Since, slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

Slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through (-4, 6) and (-2, 7) will be,

m = [tex]\frac{7-6}{-2+4}[/tex]

m = [tex]\frac{1}{2}[/tex]

y-intercept is a point for which x = 0

From the given table,

For x = 0, y = 8

Therefore, y-intercept (b) = 8

Equation of the linear function will be,

y = [tex]\frac{1}{2}x+8[/tex]

Answer:

Step-by-step explanation:

There are an infinite number of solutions.

Answer:

$728

Step-by-step explanation:

The formula for simple interest is I = PRT, where I = interest earned/paid, P = principal amount deposited or borrowed, R = rate of interest as a decimal, and T = time in years.

I = PRT

I = (4000)(0.052)(3.5)

I = 728

Simple Interest earned on $4000 in three and half year with 5.2% interest rate is $ 728.

Simple interest is a method to calculate the amount of interest charged on a sum at a given rate and for a given period of time.

Here, Principal = $ 4000

          Time = [tex]3\frac{1}{2}[/tex] years = 7/2 years = 3.5 years

          Rate = 5.2 % =  0.052

Now, SI = P.R.T/100

         SI = 4000 X 3.5 X 5.2 / 100

         SI = $ 728

Thus, Simple Interest earned on $4000 in three and half year with 5.2% interest rate is $ 728.

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Answer:

[tex]k = 1[/tex]

[tex]P(x > 3y) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.[/tex]

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

[tex]\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1[/tex]

Where

[tex]{ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }[/tex]

Substitute values for the interval of x and y respectively

So, we have:

[tex]\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1[/tex]

Isolate k

[tex]k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1[/tex]

Integrate y, leave x:

[tex]k \int\limits^2_{0} y {dx} \, [0,x/2]= 1[/tex]

Substitute 0 and x/2 for y

[tex]k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1[/tex]

[tex]k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1[/tex]

Integrate x

[tex]k * \frac{x^2}{2*2} [0,2]= 1[/tex]

[tex]k * \frac{x^2}{4} [0,2]= 1[/tex]

Substitute 0 and 2 for x

[tex]k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1[/tex]

[tex]k *[ \frac{4}{4} - \frac{0}{4} ]= 1[/tex]

[tex]k *[ 1-0 ]= 1[/tex]

[tex]k *[ 1]= 1[/tex]

[tex]k = 1[/tex]

Solving (b): [tex]P(x > 3y)[/tex]

We have:

[tex]f(x,y) = k[/tex]

Where [tex]k = 1[/tex]

[tex]f(x,y) = 1[/tex]

To find [tex]P(x > 3y)[/tex], we use:

[tex]\int\limits^a_b \int\limits^a_b {f(x,y)}[/tex]

So, we have:

[tex]P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy[/tex]

[tex]P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy[/tex]

[tex]P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy[/tex]

Integrate x leave y

[tex]P(x > 3y) = \int\limits^2_0 x [0,y/3]dy[/tex]

Substitute 0 and y/3 for x

[tex]P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy[/tex]

[tex]P(x > 3y) = \int\limits^2_0 y/3\ dy[/tex]

Integrate

[tex]P(x > 3y) = \frac{y^2}{2*3} [0,2][/tex]

[tex]P(x > 3y) = \frac{y^2}{6} [0,2]\\[/tex]

Substitute 0 and 2 for y

[tex]P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}[/tex]

[tex]P(x > 3y) = \frac{4}{6} -\frac{0}{6}[/tex]

[tex]P(x > 3y) = \frac{4}{6}[/tex]

[tex]P(x > 3y) = \frac{2}{3}[/tex]

Answer:

so, where the dotted line is that is called the height, so you would times it and find your answer.

Answer:

648

Step-by-step explanation:

FInd volume of bottom half (9x6x12)

find voume of pyramid 1/3Bh 1/3(11)(54)

Answer:

1.  LCD= 24

2. LCD= 18

Answer:

2/3

two thirds

0.666666666

Step-by-step explanation:

please mark this answer as brainliest

Answer:

V= 160 ft

Step-by-step explanation:

First 10×8×6 then ÷ 3 = 160

Answer:

Interest  = $261.42

Step-by-step explanation:

amount of interest earned is $

(Round to the nearest cent as needed.)

Amount = Principal + Interest

Amount - Principal = Interest

$ 5,261.42 -  $5000 = Interest  = $261.42