Study each equation, then solve.

18) 5 + r = 6 - r

The gross pay of Adrian Ortega for assembling 70 units of electronics in a week is $425

Gross pay refers to the total payment earned over a period of time.

Adrian Ortega assembled 70 units in one week

Pay for 1–20 units = $4.50 × 20

= $90

Pay for 21 - 30 units = $5.50 × 10

= $55

Pay for 30 - 70 = $7 × 40

= $280

Gross pay = $90 + $55+ $280

= $425

Therefore, Adrian Ortega is paid $425 in a week for assembling 70 electronics.

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The conclusion regarding the test of the hypothesis is given as follows:

At the null hypothesis, it is tested if there is not enough evidence to conclude that the percentage is not of 43% = proportion of 0.43, hence:

[tex]H_0: p = 0.43[/tex]

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the percentage is not of 43%, hence:

[tex]H_1: p \neq 0.43[/tex]

The decision was to not reject the null hypothesis, meaning that there is not sufficient evidence at the 0.02 level of significance that the percentage is not of 43%.

The problem asks to identify the correct conclusion from these two options:

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Surface area of the given prism is 6 square cm .

How to Calculate the Surface Area of Prism?

The steps to determine the surface area of the prism are:

Step 1: Note down the given dimensions of the prism.

Step 2: Substitute the dimensions in the surface area of prism formula (2 × Base Area) + (Base perimeter × height).

Step 3: The value of the surface area of the prism is obtained and the unit of the surface area of the prism is placed in the end (in terms of square units).

The lateral area is the area of the vertical faces, in case a prism has its bases facing up and down. Thus, the lateral surface area of prism = base perimeter × height

The total surface area of a Prism = Lateral surface area of prism + area of the two bases = (2 × Base Area) + Lateral surface area or (2 × Base Area) + (Base perimeter × height).

Area of triangular cross-section:

Area = 1/2 . b . h

Area = 1/2 . 4. 3

Area = 6 square cm

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Answer:

A.-7-100. [Since it is -107]

Answer:

It is an integer.

It is rational.

Step-by-step explanation:

A whole number is in the set

0, 1, 2, 3...

This set starts at zero and only includes zero and the positive numbers. So the given number is NOT a whole number.

It IS an integer. Integers include positive and negative numbers. That is, whole numbers and their opposites.

The number IS rational. That is, it can be written as a ratio:

-560114/1

Since it is rational, it is not irrational.

The sum of the interior angles of a regular polygon with 9 sides will be 1260°. The correct option is A.

An angle is defined in mathematics as the figure formed by joining two rays at their common endpoint. An interior angle is an angle that exists within a shape. Polygons are closed shapes with sides and vertices. All of the interior angles of a regular polygon are equal.

Given that the number of the sides of the polygon is 9. The sum of the interior angles of the polygons will be calculated as,

Sum = ( n - 2 ) 180°

Sum = ( 9 - 2 ) 180

Sum = 7 x 180

Sum = 1260°

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Answer:

Harry made 9 resolutions.

Step-by-step explanation:

Tim made x resolutions.

Harry made five more, x + 5.

Harry and Tim's together was 13.

x + x + 5 = 13

combine like terms.

2x + 5 = 13

subtract 5

2x = 8

divide by 2

x = 4

Tim made 4 resolutions.

Harry made 4 + 5, that is, 9 resolutions.

Check:

Harry and Tim together is 13.

4 + 9 = 13

Harry made 9 resolutions.

(a) 4x + 6y ≥ 500 , (b) The graph of this inequality is a line with a slope of 4/6 and a y-intercept of 500/6.

(a) The inequality expresses the total hours of community service that must be given, which is at least 500 hours. The 4x term represents the hours given by the full members, and the 6y term represents the hours given by the pledges. The ≥ symbol means that the sum of these two terms must be greater than or equal to 500.

(b) To graph the inequality, you first need to find the y-intercept, which is 500/6. Then you need to find the slope, which is 4/6. This means that the line has a positive slope and passes through the point (0, 500/6). The graph of the inequality is a line that passes through this point and has a positive slope of 4/6.

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Equation of option (d) is having different value of x than other 3 equations.

So, option (d) is correct option.

Solving equations

(a) (-7/8)x-(3/4)=20

adding 3/4  on both sides, we get

(-7/8)x = 20+(3/4)

multiplying (-8/7) on both sides, we get

x = -23.71

(b)  (7/8)x+(3/4)=-20

subtracting 3/4  on both sides, we get

(7/8)x = -20-(3/4)

multiplying (8/7) on both sides, we get

x = -23.71

(c) 7(-1/8)x-(3/4)=20

adding 3/4 on both sides, we get

(-7/8)x = +20+(3/4)

multiplying (-8/7) on both sides, we get

x = -23.71

(d) (-7/8)×(-8/7)x-(3/4)=20×(-8/7)

⇒ x-(3/4) = -22.85

adding 3/4 on both sides, we get

x = -22.85+(3/4)

x = -22.10

So equation in option (d) has different value of x than all other equation.

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Answer:

(a)  11 g

(b)  8.63 g

(c)  Attached

Step-by-step explanation:

Given function:

[tex]Q = 11 \left(\dfrac{1}{2}\right)^{\dfrac{t}{5715}}[/tex]

where:

Substitute t = 0 into the given function to determine the initial quantity:

[tex]\begin{aligned} t=0 \implies Q &= 11 \left(\dfrac{1}{2}\right)^{\dfrac{0}{5715}}\\\\&=11\left(\dfrac{1}{2}\right)^0\\\\&=11\left(1\right)\\\\&=11\; \rm g\end{aligned}[/tex]

Substitute t = 2000 into the given function to determine the quantity present after 2000 years:

[tex]\begin{aligned} t=2000 \implies Q &= 11 \left(\dfrac{1}{2}\right)^{\dfrac{2000}{5715}}\\\\&=11\left(0.784697887...\right)\\\\&=8.63\; \rm g\;\; \sf (2 \; d.p.)\end{aligned}[/tex]

[tex]\begin{aligned} t=10000 \implies Q &= 11 \left(\dfrac{1}{2}\right)^{\dfrac{10000}{5715}}\\\\&=11\left(0.297346855...\right)\\\\&=3.27\; \rm g\;\; \sf (2 \; d.p.)\end{aligned}[/tex]

The graph of the function over the interval t = 0 to t = 10000 is attached.

Answer:

48s + 48

Step-by-step explanation:

Domain is the input and range is the output of a function. By considering the options The domain of both function is all real number and The range of g(x) >0 are the correct answers.

Domain is the input of a function.

Range is the output of a function.

The domain of both functions is the set of all real numbers, since both functions are defined for all values of x.

The range of the function g(x)=5^x is the set of all positive real numbers, since any positive real number can be obtained by raising 5 to the power of a real number

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The equation in standard form of the line that has a slope of 1/4 and passes through the point (4, −8) is written as: -x + 4y = -36.

The equation of a line can be written in standard form as Ax + By = C.

Given the following:

A point (4, -8) = (a, b).

Slope (m) = 1/4.

Substitute m = 1/4 and (a, b) = (4, -8) into y - b = m(x - a):

y - (-8) = 1/4(x - 4)

y + 8 = 1/4(x - 4)

Rewrite the equation in standard form:

4(y + 8) = x - 4

4y + 32 = x - 4

4y = x - 4 - 32

4y = x - 36

-x + 4y = -36

The equation is: -x + 4y = -36.

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The cotangent of the angle is -√570/30

From the question, we have the following parameters that can be used in our computation:

(√30/7,-√19/7)

This means that

(x, y) = (√30/7,-√19/7)

The cot(θ) is calculated as

cot(θ) = y/x

Substitute the known values in the above equation, so, we have the following representation

cot(θ) = (-√19/7)/(√30/7)

Evaluate

cot(θ) = -√19/√30

Rationalize

cot(θ) = -√570/30

Hence, the value of cot(θ) is -√570/30

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y=5/2x+24

Step-by-step explanation:

use the formula y-y1=m(x-x1)

5/2 symbolizes m

put in 4 for y1 and put in -8 for x1

y-(4)=(5/2)(x-(-8)

y-4=5/2(x+8)

y-4=5/2x+20

y=5/2x+24

Answer:

  y = 5/2x -18

Step-by-step explanation:

You want the slope-intercept equation for the line with slope 5/2 through point (4, -8).

It can work well to start with the point-slope equation and rearrange it to the desired form.

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

  y -(-8) = 5/2(x -4) . . . . . line with slope 5/2 through point (4, -8)

Add -8 and eliminate parentheses

  y = 5/2x -10 -8

  y = 5/2x -18 . . . . . . . . simplify

The desired equation is y = 5/2x -18.

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An combined area of 0.10416 to the right means that it must have an area of 0.90 to the left, so the answer is again 1.28.

Every normally distributed random variable has a slightly different distribution shape, the only way to find areas using a table is to standardize the variable - transform our variable so it has a mean of 0 and a standard deviation of 1. How do we do that? Use the z-score!

Z = ( x - μ)/σ

if the random variable X has a mean μ and standard deviation σ,

then transforming X using the z-score creates a random variable with mean 0 and standard deviation 1!

With that in mind, we just need to learn how to find areas under the standard normal curve, which can then be applied to any normally distributed random variable.

An area of 0.10416 to the right means that it must have an area of 0.90 to the left, so the answer is again 1.28.

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Every normally distributed random variable has a slightly different distribution shape, the only way to find areas using a table is to standardize the variable - transform our variable so it has a mean of 0 and a standard deviation of 1. How do we do that? Use the z-score!

Z = ( x - μ)/σ

if the random variable X has a mean μ and standard deviation σ,

An area of 0.10416 to the right means that it must have an area of 0.90 to the left, so the answer is again 1.28.

The equation variation for the electric circuit is  V = 25R.

In each electric circuit, the voltage in a battery is measured in volt and the resistance in the circuit is measured in ohms.

The voltage, V is directly proportional to the resistance, R. In a given circuit the voltage is 200 volts, when the resistance is 8 ohms.

The equation variation for the circuit can be represented as follows:

V α R

V = kR

where

Therefore,

voltage = 200 volts

resistance = 8 ohms

200 = 8k

k = 200 / 8

k = 25

Therefore, the equation is V = 25R

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There is no point of intersection between a line that is tangent to the function () = x²  + 4 at = −1 , and the function () = x²  − 4

To find the point of intersection between the line that is tangent to the function y = x²  + 4 at x = −1 and the function y = x²  − 4 , we can set the two equations equal to each other and solve for x. This will give us the x-coordinate of the point of intersection.

Setting the two equations equal to each other, we have:

x^2 + 4 = x² - 4

This simplifies to:

2 = -8

This equation has no solutions, so the two functions do not intersect. This means that the point of intersection does not exist.

Alternatively, we could see that the two functions have different slopes at the point x = −1 .

However, since the two functions have different y-intercepts, they cannot be tangent to each other at this point. Therefore, the point of intersection does not exist.

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The angles whose measure are greater than the measure of ∠1 are ∠2, ∠3, ∠7, ∠5 .

The general equation of a straight line is -

    where -

Given is a graph as shown in the image.

The ratio of {y/x} is called the slope of a line. So, we can write -

m = 3/2

m = 1.5

Therefore, the ratio of [y] by [x] is equivalent to 1.5.

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The green grapes weigh 0.125 pounds more than the red grapes.

1/4 of a pound = 0.25 pounds

1/8 of a pound = 0.125 pounds

0.25 - 0.125 = 0.125 pounds

Hope this helps :)

A fraction of the bicycles which are silver is 3/4.

You should shade three (3) sections on the pie chart to show the number of bicycles that are silver.

In Mathematics, a pie chart can be defined as a type of graph that is used for the graphical representation of the proportion relationship between each part or unit to a whole, especially by dividing a circle into various sectors.

Based on the information provided, we can logically deduce the following parameters;

Number of silver bicycles = 3 silver bicycles.

Number of green bicycles = 1 green bicycles.

Therefore, the total number of bicycles is equal to 4 bicycles.

For the fraction of silver bicycles, we have;

Fraction = 3/4 bicycles.

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Common logarithm is the logarithm with the base 10, it is written as:

Natural logarithm is the logarithm with the base of e and is written as ln a.

How to rewrite a logarithm [tex]log_a\ b[/tex] as a ratio of logarithms with a different base c:

Apply this to the given logarithm:

a. Common logarithms:

b. Natural logarithms:

Answer:

[tex]\textsf{a)} \quad \dfrac{\log_{10}4}{\log_{10}\dfrac{1}{3}}=-\dfrac{\log_{10}4}{\log_{10}3}[/tex]

[tex]\textsf{b)} \quad \dfrac{\ln 4}{\ln \dfrac{1}{3}}=-\dfrac{\ln 4}{\ln 3}[/tex]

Step-by-step explanation:

Given logarithm:

[tex]\log_{\frac{1}{3}}(4)[/tex]

The common logarithm is the logarithm with base 10.

[tex]\boxed{\textsf{Change of base}: \quad \log_ba=\dfrac{\log_xa}{\log_xb}}[/tex]

Use the change of base formula to rewrite the given logarithm as a ratio of common logarithms:

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\log_{10}4}{\log_{10}\dfrac{1}{3}}[/tex]

[tex]\boxed{\begin{minipage}{5cm} \underline{Log quotient law}\\\\$\log_a \left(\dfrac{x}{y}\right)=\log_ax - \log_ay$\\\end{minipage}}[/tex]

This can be simplified using the log quotient rule:

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\log_{10}4}{\log_{10}\dfrac{1}{3}}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\log_{10}4}{\log_{10}1-\log_{10}3}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\log_{10}4}{0-\log_{10}3}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=-\dfrac{\log_{10}4}{\log_{10}3}[/tex]

The natural logarithm is the logarithm with base e.

[tex]\textsf{Also} \; \log_ex=\ln x[/tex]

Use the change of base formula to rewrite the given logarithm as a ratio of natural logarithms:

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\log_{e}4}{\log_{e}\dfrac{1}{3}}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\ln 4}{\ln \dfrac{1}{3}}[/tex]

[tex]\boxed{\begin{minipage}{5cm} \underline{Log quotient law}\\\\$\ln \left(\dfrac{x}{y}\right)=\ln x - \ln y$\\\end{minipage}}[/tex]

This can be simplified using the log quotient rule:

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\ln 4}{\ln \dfrac{1}{3}}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\ln 4}{\ln1 - \ln 3}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=\dfrac{\ln 4}{0 - \ln 3}[/tex]

[tex]\implies \log_{\frac{1}{3}}(4)=-\dfrac{\ln 4}{\ln 3}[/tex]

An inequality to explain the reason Heather is incorrect is t > $8.75.

In Mathematics, an inequality can be defined as a mathematical relation that is typically used for comparing two (2) or more numerical data and variables in an algebraic equation based on any of the following inequality symbols:

From the histogram, we can logically deduce the following information;

Miguel’s work record during Weekend 1 = 9 hours.

Miguel’s work record during Weekend 2 = 7 hours.

Therefore, the total number of hours which Miguel worked in two Weekends is given by;

Total hours = 9 hours + 7 hours

Total hours = 16 hours.

Next, we would calculate the amount of money that Miguel would earn per hour;

Amount = $140/16

Amount = $8.75 per hour.

Note: Let the variable t represent the total earnings.

In conclusion, the correct inequality is t > $8.75.

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Answer:

Step-by-step explanation:

c 0,4 .01

Answer:

116.7m/s

Step-by-step explanation:

distance(s) = 1km = 1 × 1000m = 1000m

Time(t) = 60– 30 = 30s

initial velocity = u

acceleration (a) = 10m/s

using the formula

S = ut + ½at²

1000 = 30u + ½ × 10 × 30²

1000 = 30u + 5 × 900

1000 = 30u + 4500

30u = 4500 – 1000

30u = 3500

divide both sides by 30

u = 116.7m/s

i hope i helped

The initial state of a queuing system (for example, when a restaurant first opens), is referred to as the primary state.

1) Orderly queue, also known as FIFO (First In, First Out) or FCFS (First Come, First Serve).

2) Stack, also known as LCFS (Last Come First Serve), or LIFO (Last In First Out).

3) SIRO (Serve in Irregular Request).

Let P n(t) represent the probability of having n customers in the system at time t. This is the steady state of a queueing system, where the probability of the number of customers in the system is independent of t.

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Answer:

1 / 7 · 2 = 2 / 7

The number of the tickets purchased for upper reserve is 146 and lower is 470.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that  there were 616 tickets purchased for a major league baseball game. The lower box tickets cost $12.50 and the upper reserved tickets cost $8.00. The total amount of money spent was $6543.50.

The equations will be formed as,

L + U = 616

12.5L + 8U = 6543.5

Solve the above equations,

12.50L + 8 (616-L) = 6543.5

12.5L + 4928 - 8L = 6543.5

12.50L - 8L = 6543.5 - 4428

4.50L = 2118.5

L = 470

U = 616 - 470

U = 146

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Answer: x + 8 - 8 = 10 - 8

Simplifying the left side of the equation gives us:

x = 2

Therefore, the value of x in this equation is 2.

Step-by-step explanation:

since I don't see the options, I can only tell you what it is supposed to be and you need to pick the best fitting option :

the score of the test is simply

the number of correctly answered questions times 3 (as every correctly answered question is with 3 points).

the equation is therefore

y = R(x) = 3x

the independent variable x represents the number of correctly answered questions,

and the dependent variable is y, the test score, because the test score depends on the number of correctly answered questions.

so,

R(25) = 3×25 = 75, meaning 25 correctly answered questions × 3 results in the score of 75.