The Bruce family set out 8 0’clock in the morning. They arrived at the old port of Ambertini at 09:05. How long their journey took?

pls

Answer:

B

7 less than 3 times a number (X) is (3x-7), and then the sum of these two numbers means we have (3x-7)+X, and then we know this equals 109, leaving us with:

(3x-7)+x = 109

Answer:

cost of renting from company A

C = 15 + 2.30x

cost of renting from company B

C = 22 + 1.90x

equate both the equations

15 + 2.30x = 22 + 1.90x

2.30x - 1.90x = 22-15

0.4x = 7

x = 7/0.4 = 17.5

At 17.5 miles, cost will be equal.

Answer: 17.5 miles

Answer:

900 7/10

Step-by-step explanation:

you add the numbers to gether

Answer:

if you meant (b+3)+(2^b-2), the answer is b+1+2^b

Step-by-step explanation:

but if you meant (b+3)+(2b-2), the aanswer is 3b+1

Answer:

3b+1

Step-by-step explanation:

(b+3)+(2b-2)

b+3+2b-2

3-2

b+1+2b

b+2b

3b+1

Answer: A. 65,250+139,560= 204,810. 204,810/18=11,378

I hope it is right

Answer:

The answer would be 13,050

Step-by-step explanation:

In order to get the answer, you have to do 65,250 divided by 5 years and you should get 13,050 on your calculator.

The amount that Kim Barney spends is $342 for medical expenses.

Buying cost is the cost at which someone buys or is willing to buy shares, bonds.( including the tax)

here, we have,

Given that,

Kim Barney pays a $290.00 yearly premium for a $500.00 deductible insurance plan. 80 percent of the remaining cost is covered by the business. If Kim has medical costs of $2,500.00

To find : The amount that Kim barney spends for the medical expenses.

If the business covers 80% of the remaining balance ($1710), they will be responsible for paying $1368 of it.

10% of 1710 is 171

171x8=1368

The insurance provider covers the $1368.

Kim Barney spends $342.

Consequently, Kim Barney spends the following amount on medical costs $342.

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Answer:

I will answer this soon I don't remember

Answer:

A. Rate: the percent that interest is paid annually as a decimal

Step-by-step explanation:

Edge 2022 got the answer right :)

Think of it this way, a function must pass the vertical line test.  There may not be 2 outputs for one input for example  (0, 1) (0, 2)  However, you can have something like this (1, 0) (2, 0)

This is indeed a function as it meets those criterion.  There are no two outputs for one input.

Answer

Step-by-step explanation:

neither

brainlest

Step-by-step explanation:

that is 12 over 5

12! / (5! × (12-5)!) = 12×11×10×9×8/5×4×3×2 =

= 11×9×8 = 792

9514 1404 393

Answer:

  $935.11

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year

  A = $850(1 +0.024/2)^(2·4) = $935.11

The amount accumulated will be $935.11 after 4 years.

Answer: 15 inches

Step-by-step explanation:

15 × 1 ÷ 12 = 1.25 ft

1.25 ft = 1.25 × 12 = 15 in

Answer:

1. 0.74 = 74%

4. 0.617 = 61.7

6. 68% = 0.68

9. 175% = 1.75

2. 0.15 = 15%

5. 0.834 = 83.4%

7. 34% = 0.34

10. 200% = 2.00

3. 0.09 = 9%

8. 58.5% = 0.585

Step-by-step explanation:

Answer:

17.44

Step-by-step explanation:

if one dozen cost $3.49 than 3.49 × 5 = 17.44

Answer:40

Step-by-step explanation:

Answer:

If they both sell half then Kyle would have 1.5:1 and Yasmine would have 18 pennants.

Step-by-step explanation:

It will change because if they both sell half, they would have to multiply by .05  or divide by 2 because that is half of something.

3/2 or 3*0.5 = 1.5

2/2 or 2*0.5 = 1

36/2 or 36*0.5 = 18

So Kyle would have 1.5:1 pennants left and Yasmine would have 18 pennants left.

Answer:

The answer is 15 cm

Step-by-step explanation:

as one square is 1 cm and there are 15 squares used for this shape then it is 15 cm

Answer:

After 10 weeks: 40 inches

Step-by-step explanation:

Equation

15 + 2.5w = h

15 = beginning height

2.5 = rate per week

w = weeks passed

h = total height

Two or more expressions with an Equal sign is called as Equation.15+2.5W tall l would the sunflower be after w weeks and 40 inches tall after 10 weeks.

Two or more expressions with an Equal sign is called as Equation.

Given that, At the beginning of spring, Caroline planted a small sunflower in her backyard

The initial height of the sunflower was  15 inches tall.

The sunflower then began to grow at a rate of 2.5 inches per week.

We need to find the height of the tree after 10 weeks.

15+2.5(10)

15+25

40 inches tall after 10 weeks.

the sunflower height after w weeks

15+2.5W

Hence 15+2.5W tall l would the sunflower be after w weeks and 40 inches tall after 10 weeks.

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Answer:

1.0833 yd

Step-by-step explanation:

Inches    Yards

37"         1.0278 yd

38"         1.0556 yd

39"         1.0833 yd

40"         1.1111 yd

Have a great day! :D

Answer:

$12.70

Step-by-step explanation:

8 x .25 = 2

2 x 2.55 = 5.10

1 x 2.45 = 2.45

1 x 3.15 = 3.15

__________

2 + 5.10 + 2.45 + 3.15 = 12.70 = $12.70

Answer:

they spent $15.85 in all.

Step-by-step explanation:

2.00 banana 5.10 bread 2.45 oj and 3.15 egg, add it all.

Answer:

1 is 12

2 is 106

3 is 42

Step-by-step explanation:

1: PEMDAS. 5x2=10 4 to the power of 2 is 16 so 18-16=2 2+10=12

2: 9 to the power of 2 is 81. 4x7=28 28-3=25 81+25=106

3: 5 to the power of 2 is 25 7x3=21 25-4=21 21+21=42

In the experiment, the response variable is the dependent variable, or the measured variable.

Reasons:

The study Leonard conducts is a study to determine if the number of

hawks located in the park affects the number of squirrels in the park.

The response variable is the variable of the experimental result, which is

the dependent or output variable obtained by manipulating the input

variable.

In the experiment conducted by Leonard, the variable that is being

manipulated, which is the input variable is the number of hawks in the park

The variable that is being measured, which is the output variable or the

response variable, is; B. the number squirrels in the park.

Learn more here:

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Explanation:

All of these are done the same way.

1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.

2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".

3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".

4. A line through the original point and point R will be perpendicular to the line, as you want.

_____

In problem 1, the point and line are obvious.

In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)

Let [tex]x = \arcsin(y)[/tex], so that

[tex]\sin(x) = y[/tex]

[tex]\tan(x)=\dfrac y{\sqrt{1-y^2}}[/tex]

[tex]dx = \dfrac{dy}{\sqrt{1-y^2}}[/tex]

Then the integral transforms to

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_{y=\sin(0)}^{y=\sin\left(\frac\pi2\right)} \frac{y}{\sqrt{1-y^2}} \ln(y) \frac{dy}{\sqrt{1-y^2}}[/tex]

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy[/tex]

Integrate by parts, taking

[tex]u = \ln(y) \implies du = \dfrac{dy}y[/tex]

[tex]dv = \dfrac{y}{1-y^2} \, dy \implies v = -\dfrac12 \ln|1-y^2|[/tex]

For 0 < y < 1, we have |1 - y²| = 1 - y², so

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = uv \bigg|_{y\to0^+}^{y\to1^-} + \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

It's easy to show that uv approaches 0 as y approaches either 0 or 1, so we just have

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

Recall the Taylor series for ln(1 + y),

[tex]\displaystyle \ln(1+y) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n y^n[/tex]

Replacing y with -y² gives the Taylor series

[tex]\displaystyle \ln(1-y^2) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n (-y^2)^n = - \sum_{n=1}^\infty \frac1n y^{2n}[/tex]

and replacing ln(1 - y²) in the integral with its series representation gives

[tex]\displaystyle -\frac12 \int_0^1 \frac1y \sum_{n=1}^\infty \frac{y^{2n}}n \, dy = -\frac12 \int_0^1 \sum_{n=1}^\infty \frac{y^{2n-1}}n \, dy[/tex]

Interchanging the integral and sum (see Fubini's theorem) gives

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy[/tex]

Compute the integral:

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy = -\frac12 \sum_{n=1}^\infty \frac{y^{2n}}{2n^2} \bigg|_0^1 = -\frac14 \sum_{n=1}^\infty \frac1{n^2}[/tex]

and we recognize the famous sum (see Basel's problem),

[tex]\displaystyle \sum_{n=1}^\infty \frac1{n^2} = \frac{\pi^2}6[/tex]

So, the value of our integral is

[tex]\displaystyle \int_0^{\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \boxed{-\frac{\pi^2}{24}}[/tex]

[tex]\displaystyle \int \limits_{0}^{ \frac{ \pi}{2} } \tt\tan (x) \ln ( \sin (x))\\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin \left( \dfrac{\pi}{2} - x \right) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \:2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(x) \right) \: dx + \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \right) +\ln\left( cos(x) \right) \: dx }[/tex]

[tex]\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \: cos(x) \right) \: dx } \\ \\\displaystyle\sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( \dfrac{sin(2x)}{2}\right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(2x) \right)\:dx-\ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle\sf{ \implies \: 2I = \dfrac{1}{2} \int^{ \pi}_{0} \: \ln \left( sin(t) \right) \:dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\\displaystyle\tt{ \implies \: 2I = \dfrac{1}{2} \cdot2 \int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle \tt{ \implies \: 2I =\int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2)\int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\ \displaystyle \tt{ \implies \: 2I = I - \ln(2) \left[x \right] ^{ \frac{\pi}{2} }_{0} } \\ \\ \displaystyle \tt{ \implies \: I = -\ln(2)\left[ \dfrac{\pi}{2} - 0 \right] }[/tex]

[tex]\displaystyle \sf{ \implies \: I = - \dfrac{\pi}{2} \ln(2) }[/tex]

☞︎︎︎Apologies,if incorrect.

Answer:

A

Step-by-step explanation:

companies can squeeze workers more than normal

926+729299277=5289+83783

Answer:

I would love to help but there is no upload. Would you mind creating a new question with a picture or data of the graph

Step-by-step explanation:

Answer:

Expression: 6x - 26. Equation: 3

Step-by-step explanation:

EXPRESSION

4x - 16 + 2x - 10

6x - 26

EQUATION 1

4x - 16 = 2x - 10 (Seems reasonable. Sorry if this isn't it)

4x = 2x + 6

2x = 6

x = 3

EQUATION 2

4x - 16 + 2x = - 10

6x - 16=  -10

6x = 6

x = 1