Answer:
F = 2000 N
Explanation:
According to Newton's Second Law of Motion, the rate of change of momentum is equal to the force applied. Therefore, the formula written below will be used to solve this problem:
[tex]F = \frac{\Delta P}{t}\\\\[/tex]
where,
F = Force everted = ?
ΔP = Cange in Momentum = 3000 N.s
t = time taken = 1.5 s
Therefore,
[tex]F = \frac{3000\ N.s}{1.5\ s}[/tex]
F = 2000 N
Rogan claims that he can run 8 miles per hour. Use the speed formula to determine how many minutes it would take him to run one mile.
Answer:
he would have to run at a 7 and a half mile to get 8 miles in an hour
Explanation:
Answer:
7.5 minutes
Explanation:
We know that there are 60 minutes in an hour. So, we can say that Rogan can run 8 miles per 60 minutes. Now, we can create an equation to solve for how many minutes it would take per mile.
8/60 = 1/x
x = 7.5
So, it would take Rogan approximately 7.5 minutes to travel 1 mile.
Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.
Answer:
Sorry I I’m a little lost
Explanation:
Answer:
hmm the relation ship would be bad 1 because its not cooperating because I would have to do allot of force to pick up the mass with a tiny string, what an idiot, 2nd the distance is far now that its not a good relationship
Explanation:
hope this helps old pal ( :
Three resistors of 100, 40.0, and
10.0 Ohms are in series with a
24.0 V power supply. What is the
current in the circuit?
Answer:
0.16 A
Explanation:
V = IRtotal
24V = I(100 + 40 + 10)
I = 0.16 A
Answer: 0.16 is correct
Explanation:
can someone help?? 4/5
Answer: I may not have the awser but
Explanation: Try calculating 8.932 times
10^22 kg
Answer:
F = 2.68 x 10²³ N
Explanation:
The force between lo and Jupiter is given by Newton's Gravitational Formula:
[tex]F = \frac{Gm_1m_2}{r^2} \\[/tex]
where,
F = Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of lo = 8.932 x 10²² kg
m₂ = mass of Jupiter = 1.9 x 10²⁷ kg
r = distance between lo and Jupiter = 4.22 x 10⁸ m
Therefore,
[tex]F = \frac{(6.67\ x\ 10^{-11}Nm^2/kg^2)(8.932\ x\ 10^{22}\ kg)(1.9\ x\ 10^{27}\ kg)}{(4.22\ x\ 10^8\ m)^2}[/tex]
F = 2.68 x 10²³ N
Order these sounds from loudest (1) to softest (4). airplane: whisper: crowd at sporting event: rainfall:
Answer:
The arrangement of the following from loudest to softest include:
crowd at sporting event
airplane
rainfall
whisper
Explanation:
When it comes to the arrangements, the pitch of the noise which emerge is what was considered. For example, crowd at sporting event has the highest pitch especially during football matches followed by the airplane sounds during its take-off and landing in the airports. As for whisper, it happens to be the one with softest sound.
Answer:
Airplane. 1
Whisper. 4
Crowd at sporting event. 2
Rainfall. 3
Explanation:
hope this helps
define one ampere current electricity
Is gravitational pull strengthened by distance?
I'm not sure but I think that if objects are closer (less distant), than the gravitational pull is stronger. I'm sorry if I couldn't really help I remember learning about this kind of.
Make a list of all the possible human sources of carbon dioxide
Answer:
car fuel
production waste (like producing plastic, car, materials)
breathing
landfill
cement production
deforestation (cutting down trees)
burning of fossil fuels (coals, oil, natural gases)
Please mark Brainliest
Explanation:
Please answer this
No links please
A cube of wood is 3 cm on each side. It has a mass of 27 g. What is its density?
Answer:
1 gram
Explanation:
Formula -- (density / mass)
3 x 3 x 3 = 27.
27g / 27 g =
=1
-I hope this helps, have a good day/night if so.
Why does mining considered the most important industry?
Answer:
it makes most recourses and gives us most of a materials
Explanation:
Which statement describes an interacting force pair represented by the third law of motion? The force exerted by a cyclist equals the combined forces of friction and air resistance. A car exerts a force on a bug as they collide and the bug exerts an equal force on the car. Gravity exerts a downward force on a refrigerator and the normal force pushes up on the refrigerator. Two people pull on opposite ends of a rope, but the rope does not move because the people pull with equal forces.
Answer:
A car exerts a force on a bug as they collide and the bug exerts an equal force on the car.
Explanation:
Newton's third law of motion states that for every action there is an equal and opposite reaction.
Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,
Furthermore, take for example, While driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e The firefly hit the car and the car hits the firefly.
Hence, the statement which best describes an interacting force pair represented by the third law of motion is, a car exerts a force on a bug as they collide and the bug exerts an equal force on the car.
The ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects in this case, the car and bug. The size of the force on the car equals the size of the force on the bug. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
A schoolbus accelerates to 65 mph and enters the freeway. It travels for 2.3 hours at that speed while on the freeway. What's the distance travelled on the freeway?
Answer:
The distance travelled on the freeway is 149.5 miles.
Explanation:
The school bus travels on the freeway at constant speed. According to the statement, we need to calculate the distance travelled by the vehicle by means of the following formula:
[tex]x = v\cdot t[/tex] (1)
Where:
[tex]x[/tex] - Traveled distance, in miles.
[tex]v[/tex] - Speed, in miles per hour.
[tex]t[/tex] - Time, in hours.
If we know that [tex]v = 65\,\frac{mi}{h}[/tex] and [tex]t = 2.3\,h[/tex], then the distance travelled by the school bus is:
[tex]x = v\cdot t[/tex]
[tex]x = \left(65\,\frac{mi}{h} \right)\cdot (2.3\,h)[/tex]
[tex]x = 149.5\,mi[/tex]
The distance travelled on the freeway is 149.5 miles.
42 POINTS!!!!
are players trying to minimize or maximize friction when playing volleyball?
None
Friction in Volleyball
Frication plays a huge role in every aspect of our lives; it can play a negative or positive role. In volleyball there are various types of friction that have positive influences on the way the game is played and there are others that play a negative role in the way the game is played.
Positive friction in volleyball.
In volleyball the aim of the game is to strike a ball into play that your opponent cannot return or finds it difficult to return. A friction force that makes this possible is the friction of the air on the ball, for example when a player hits a ball with topspin into play, the friction of the air on the ball makes it spin faster than it otherwise would. Topspin makes a ball harder to pick-up and pass to the setter.
Another force that is present is the ball itself, if there was no friction it would be virtually impossible to pass set, or hit the ball, the ball would just slip through your arms or hands.
When jumping a player also uses the frictions of their feet on the floor to gain a higher jump to strike the ball at maximal height, if this didn't exist players would be slipping and sliding around all over the court.
Negative friction in volleyball.
Friction also plays a negative part in the game of volleyball, when a player dives for a ball the friction of the court on their skin causes court burn or friction burn. Although the friction of the rubber soles of shoes on the court is a positive it can also be a negative, if there is too much friction players can become injured from the sudden stopping that the friction can cause. Some injuries that can result from this would be hyperextensions of the knees and or ankle injuries.
Building a space station, in which astronauts would live for a considerable time, is essential even if the space station project were to contribute no new knowledge about space or Earth that could not otherwise be obtained. For future missions to explore Mars, we will need the medical knowledge that the space station project will give us about the limits of human capacities to live in spacecraft for an extended time.
The argument makes the assumption that
(A) the exploration of Mars will be carried out by people traveling in spacecraft and not by robots alone
(B) the capacities of astronauts are typical of those of ordinary human beings
(C) no unforeseen medical problems will arise on the first mission to explore Mars
(D) a mission to Mars will be the first of many missions that will explore the solar system
(E) living in spaceship for an extended time presents insurmountable medical problems
Answer:
The argument make the assumption that;
(A) The exploration of Mars will be carried out by people travelling in spacecraft and not by robots alone
Explanation:
The argument is made for the importance of a space station where astronauts live for an appreciable time to aid in the understanding of human capacities for living in the space so as to increase the successful space travel human to Mars, which is a distance further than the Moon and therefore, will require sufficient time travel
The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye
is viewed in a concave mirror with a radius of curvature equal to the diameter
of the eye and the eye is 0.800 × 10^3 mm from the mirror, how far is the image
from the mirror? What is the size of the image? Is the image real or virtual?
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m = [tex]\frac{h'}{h} = - \frac{q}{p}[/tex]
h '= [tex]- \frac{q}{p} \ h[/tex]
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.
Is this statement correct that all charged particles experience same force in uniform electric field
Answer:
No the statement is incorrect.
Explanation:
Mathematically, force F experience of a charge particle of magnitude q in an uniform electric field E is given as
F = E/q
In uniform electric field is where the intensity of electric field remains same throughout. However, from the above equation it is clear that force experience by the charge particle also depends upon the magnitude of charge particle as well. So, with change in charge particles the force experienced by it also changes.
What is the acceleration of a 250 kg object pushed with a force of 7500 newtons?
Answer:
a = 30 m/s²
Explanation:
Given: 250 kg, 7500N
To find: Acceleration (a)
Solution: To find the acceleration (A), divide the force by the weight
A = F ÷ m
= 7500 ÷ 250
= 30 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
PLEASE HELPPPPPPPPPP
Answer:
Peer Review
Explanation:
When scientist check other scientists the process is dubbed "peer review".
A 140 g tennis ball travelling 30° east of north at 15 m/s is struck by a tennis racquet, giving it a velocity of 25 m/s, west. What are the magnitude and direction of the impulse given to the ball? Include a labelled diagram.
Answer:
The magnitude of the impulse is 1.4 Ns in the West direction.
Explanation:
The impulse equation is given by:
[tex]\Delta p=m\Delta v[/tex]
Where:
m is the mass of the ballΔv is the difference in velocitySo we will have:
[tex]\Delta p=0.140(25-15)[/tex]
[tex]\Delta p=1.4\: Ns[/tex]
Therefore, the magnitude of the impulse is 1.4 Ns in the West direction.
I hope it helps you!
Wax, like all matter, comes in many phases. What are the three possible
phases?
A. Liquid
B. Solid
C. Gas
D. Mixtures
The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed under the 40 cm mark and carrying a weight of 70 N hanging 2 from the 10 cm mark. The ruler is balanced horizontally by a weight W hanging from the 100 cm mark. Calculate the value of the weight W.
Answer:
W = 30 N
Explanation:
Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.
[tex](70\ N)(40\ cm - 10\ cm)-(30\ N)(50\ cm-40\ cm)-(W)(100\ cm - 40\ cm) = 0\\W(60\ cm) = (70\ N)(30\ cm)-(30\ N)(10\ cm)\\\\W = \frac{1800\ N.cm}{60\ cm}[/tex]
W = 30 N
Pierce conducts an experiment in which waves collide in a way that the energy increases. What has occurred? refraction reflection constructive interference destructive interference
Answer:
constructive interference.
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m.
In this scenario, an experiment is conducted by Pierce in which waves collide in a way that the energy increases. Thus, this is an example of constructive interference i.e constructive interference has occurred.
An interference occurs when two pair of waves such as sound and light waves pass through each other i.e crossing each other's path while traveling through the same medium or space.
Answer:
constructive interference.
Explanation:
A 1500 kg car accelerats from 55.0 m/s to 90.0 m/s. Calculate the impulse experienced by the car
Answer:
The impulse experienced by the car is 52,500 kg.m/s.
Explanation:
Given;
mass of the car, m = 1500 kg
initial velocity of the car, u = 55 m/s
final velocity of the car, v = 90 m/s
The impulse experienced by the car is the change in linear momentum, calculated as follows;
J = ΔP = mv - mu
ΔP = m(v - u)
ΔP = 1500(90 - 55)
ΔP = 52,500 kg.m/s
Therefore, the impulse experienced by the car is 52,500 kg.m/s.
How many joules
of energy is needed
to run a 600 watt
power drill for
5 minutes?
Help!!!
Where can the hoses be attached in order to provide water to a fire engine? (There may be more than one correct answer.)
house faucet
hydrant
generator
pumper truck
Answer:
Explanation:
Hydrant
Our entire ______ _____
is built in the backbone of metals.
Answer:
modern world
Explanation:
what is the difference between atoms and ions
Answer:
[tex]{\huge\purple{\fbox{{࿐αɴѕωєя࿐}}}}[/tex]
[tex] \huge\red{\boxed{\mathfrak{Atoms}}}[/tex]
The smallest unit of an element.Not independent in solution.Atoms form molecules.Electrons and protons are equal.Unstable in nature.[tex] \huge\red{\boxed{\mathfrak{Ions}}}[/tex]
Single particle or collection of particles.Is independent in solution.Ions form electrovalent bond.Electrons and protons are unequal.Stable in nature.✏ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ RainbowSalt2222 ࿐ }} \mid}}[/tex]
Eye at the lowest radiated power of 1,2 x10 x (- 17) W. Determine how many photons of light with a wavelength of 500nm fall on the retina of the eye every second
Answer:
[tex]\frac{n}{t} = 30\ photons/s[/tex]
Explanation:
The radiated power can be given in terms of the wavelength as follows:
[tex]Rasiated\ Power = \frac{nE}{t} = \frac{nhc}{\lambda t}[/tex]
where,
Radiated Power = 1.2 x 10⁻¹⁷ W
n = no. of photons = ?
h = plank's constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 500 nm = 5 x 10⁻⁷ m
t = time
Therefore,
[tex]1.2\ x\ 10^{-17}\ W = \frac{n(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{(5\ x\ 10^{-7}\ m)(t) }\\\\\frac{n}{t} = \frac{1.2\ x\ 10^{-17}\ W}{3.975\ x\ 10^{-19}\ J}\\\\\frac{n}{t} = 30\ photons/s[/tex]
Describe the net transfer of thermal energy and any changes in temperature When a metal block at 300Ak is placed in water at 15°C
Answer:
Q_c = Q_abs
Explanation:
You are asked to describe the process when placing a hot block in cold water.
The first thing to do is put all the quantities in the same units
block temperature T_bloque = T_h = 300 K = 300 -273 = 27ºC
water temperature T_water = T_c = 15ºC
* initially the block cools down decreasing its temperature
* the water temperature increases
* the equilibrium is established when the thermal energy of the two bodies is equal, therefore they have the same temperatures T_f
* Conservation of energy requires that the energy released by the hot block is equal to the energy absorbed by the cold body (water)
transferred thermal energy Q_c = m_block ce_block (T_h-T_f)
absorbed thermal energy Q_abs = m_agua ce_agua (T_f - T_c)
* if we subtract the energy transferred and the absorbed gives zero, therefore the net energy transferred is zero
Q_c = Q_abs