The chart show the masses and velocities of two colliding objects that stick together after a collision.



According to the law of conservation of momentum, what is the momentum of the object after the collision?

4,500 g · m/s
1,750 g · m/s
1,500 kg · m/s
3,000 kg · m/s

Answers

Answer 1

The momentum of the object after the collision is  1500 kg. m/s.

What is conservation of momentum principle?

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. In inelastic collision, after the collision, the two objects are stick together and final velocity is the common velocity for both the bodies.

Given is the chart show the masses and velocities of two colliding objects that stick together after a collision.

Object        Mass (kg)           Velocity (m/s)

A                   200                      15

B                     150                    - 10

Using the conservation of momentum principle, we have

m₁u₁ +m₂u₂ =(m₁ +m₂) v = Pf

Substitute the values, then the momentum after collision will be

200x15 +150x(-10) =Pf

Pf = 1500 kg. m/s

Thus, the  momentum after collision is 1500 kg. m/s.

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Related Questions

a box is at rest on a ground. An unbalance force acts on the box causes it to start. The box moves 10 meters in 2 seconds and then stop. why did the box moving? what is the box's average speed?

Answers

The box stopped moving because there was a negative acceleration in the x direction caused by friction.
To find the average speed, simply divide the displacement by time: 10 / 2 = 5 m/s

Relate a real life phenomena with each branch of physics..

Answers

Answer:

Absolutely no real-life phenomena/ uses are possible that are related to any branch of physics, except:

1 The device you are reading this answer on. (quantum mechanics, electronics )

2 The air conditioner in your room. ( electromagnetism, electronics )

3 The satellites and space stations in space which will help in the deciphering of the universe will help us look for a suitable planet when we render the earth useless. ( general and special relativity, classical mechanics )

4 Ohh. I forgot, do you wear clothes, well they are made in factories where factories run on the principles of thermodynamics, which is physics.

5 Ever gone somewhere? Well, the transportation uses classical mechanics, thermodynamics, electromagnetism, relativity ( if you know Global Positioning System )

6 GPS itself! It’s used in online maps, navigating, and this sort of stuff. It works on general relativity.

Honestly, this list is endless.

1. What is the relationship between mass, weight and gravity?

Answers

Answer:

Mass

The kilogram (kg) is the SI unit of mass and it is the almost universally used standard mass unit.

Gravity and weight

Since the acceleration due to the force of gravity (g) equals aproximately 9.8 meters/s2, the weight of an object with a mass of 1 kilogram is 9.8 newtons under standard conditions on the Earth's surface.

Answer:

The mass of an object is a measure of the object's inertial property, or the amount of matter it has in it

The weight of an object is a measure of the force/impact  exerted on the object by gravity, or the force needed to support it

The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

Hope This Helped

If you wanted to
reduce the resistance
in a circuit, what
should you do?
A. increase the length of the wire
B. replace a steel wire with a copper wire
C. replace a wide wire with a thin wire

Answers

Answer:

Option C

Explanation:

According to the formula

[tex]\\ \boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]

So

If we use wide wire we increase the area of cross section so resistance decreases

A bullet travels at 850 m/s. How long will it take a bullet to go 1000 m?

Answers

Answer:

I say 150 because i aded 850+150= 1000 so yea thats how i got my answer

Explanation:

How do riders in a Ferris wheel possess Translatory motion but not circular motion?

Answers

Answer:

A wheel on a car, however, rotates around the car's axle, so it does have rotational motion. For this example, if you were to pick a single point on the edge of the wheel, you could also say that it has circular motion.

if line segment g f = 3.2 ft, which is a possible measure of line segment t s? 1.6 ft 3.0 ft 3.2 ft 4.0 ft\

Answers

By applying the relationship of side lengths to interior angles in a triangle, a possible measure of line segment TS is 4.0 ft.

The relationship of sides to interior angles in a triangle.

In Geometry, the relationship of side lengths to interior angles in a triangle include the following:

The shortest side length is always opposite of the smallest interior angle.The longest side length is always opposite of the largest interior angle.

Based on the above theory, we can logically deduce that angle GF < TS or TS > GF because 42° is greater than 56°.

TS > 3.2 ft.

Therefore, a possible measure of line segment TS is 4.0 ft.

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Complete Question:

In the triangles, TR = GE and SR = FE. If Line segment G F = 3.2 ft, which is a possible measure of Line segment TS? 1.6 ft 3.0 ft 3.2 ft 4.0 ft.

The quarks that compose a baryon may have charges of:.

Answers

The quarks that compose a baryon may have charges of +(2/3)e and -(1/3)e which means have negative and positive charges.

What are quarks?

Quarks are the most fundamental particles that make up the atomic nucleus. All solid matter that we know is made of three particles, which are the up and down quarks, 'u' and 'd', and the electron.

Quark is one of the two basic elements that make up matter and is the only one of the particles that interacts through all four fundamental forces.

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Can you explain why number 3 is correct?
Q19. Which waves would be found at the surface at regions A and C?
1. P waves
2. S waves
3. No waves
The correct answer was number 3. But I don’t know why :(

Answers

No waves because Q19 waves would going at the surface at regions

PLEASEE helppp I really need it!

Answers

Answer:

the correct answer is Jupiter has moons orbiting it

How does the force of gravity vary with distance

Answers

The force of gravity vary inversely with square of distance between two objects.

What is gravity?

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/d²

here G is the gravitational constant.

If the distance changes, the force of gravitation changes. The mass remains the same.

Thus, the force of gravity vary inversely with square of distance between two objects.

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You are standing on a river bank. The river is flowing at a rate of $2.0\;\mathrm{ m/s}.$ You see a duck is floating in the river without swimming, and is being carried by the river downstream. You throw two pieces of bread at the duck. One piece lands upstream of the duck, and the other downstream equal distance. The duck can swim at $1.0 \; \mathrm{m/s}.$ The duck is hungry, and wants to reach the bread in the shortest amount of time. What should the duck do

Answers

Let the upstream breadcrumb's position act as the origin, so the position at time [tex]t[/tex] of upstream crumb [tex](B_U)[/tex], duck [tex](D)[/tex], and downstream crumb [tex](B_D)[/tex] are, respectively,

[tex]x_{B_U} = \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_D = d\,\mathrm m + v_D t[/tex]

[tex]x_{B_D} = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

where [tex]d[/tex] is the distance (in m) between the duck and either crumb at the start, and [tex]v_D[/tex] is the velocity of the duck relative to the Earth.

To get both breadcrumbs, the duck has to choose between chasing the upstream or downstream crumb first.

• If the upstream crumb is chosen first, then [tex]v_D[/tex] is 2.0 - 1.0 = 1.0 m/s. Find the time it takes for the duck to reach the upstream crumb:

[tex]x_{B_U} = x_D \implies \left(2.0\dfrac{\rm m}{\rm s}\right) t = d + \left(1.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = d \, \mathrm s[/tex]

In this time, the duck covers a distance of

[tex]x_D = d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) (d\, \mathrm s) = 2d \, \mathrm m[/tex]

while the downstream crumb will have traveled a distance of

[tex]x_{B_D} = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) (d \,\mathrm s) = 4d \,\mathrm m[/tex]

putting a total distance of [tex]2d+4d=6d\,\mathrm m[/tex] between the duck and the remaining crumb.

Take the duck's new position to be the new origin. When the duck turns around and travels with the current, its speed [tex]v_D[/tex] will be 2.0 + 1.0 = 3.0 m/s. Then at time [tex]t[/tex], the duck and remaining crumb have position relative to the new origin given by

[tex]x_D' = \left(3.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_{B_D}' = 6d \,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

Find the time the duck needs to catch up to the downstream crumb:

[tex]x_D' = x_{B_D}' \implies \left(3.0\dfrac{\rm m}{\rm s}\right) t = 6d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = 6d \,\mathrm s[/tex]

Then the total time the duck needs to get both crumbs is [tex]d + 6d = 7d \,\mathrm s[/tex].

• If instead the downstream crumb is chased down first, we start with [tex]v_D[/tex] = 3.0 m/s, so that

[tex]x_D = x_{B_D} \implies d\,\mathrm m + \left(3.0\dfrac{\rm m}{\rm s}\right) t = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = d \, \mathrm s[/tex]

In this time, the duck covers a distance of

[tex]x_D = d\,\mathrm m + \left(3.0\dfrac{\rm m}{\rm s}\right) (d\,\mathrm s) = 4d \,\mathrm m[/tex]

while the upstream crumb moves

[tex]x_{B_U} = \left(2.0\dfrac{\rm m}{\rm s}\right) (d\,\mathrm s) = 2d \,\mathrm m[/tex]

The distance between the duck and remaining crumb is then [tex]4d-2d=2d\,\mathrm m[/tex]. Now the duck turns around with speed [tex]v_D[/tex] = 1.0 m/s. If the crumb's new position is taken to be the origin, then

[tex]x_{B_U}' = \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_D' = 2d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) t[/tex]

Find the time it takes for the duck to get the last crumb:

[tex]x_{B_U}' = x_D' \implies \left(2.0\dfrac{\rm m}{\rm s}\right)t = 2d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = 2d\,\mathrm s[/tex]

Then the duck can get both crumbs in a total of [tex]d+2d=3d\,\mathrm s[/tex].

To get both crumbs in the shortest time, the duck should go after the downstream crumb first. This path over 2 times faster than the other.

A diffraction grating used in a spectrometer causes the third-order maximum of blue light with a wavelength of 490 nm to form at an angle of 6.33º from the central maximum (m = 0). What is the separation between the lines of the grating?

Answers

The separation between the lines of the grating is 13.33μm.

What is diffraction grating?

The diffraction grating is the continuous lines with very minute slits or grating space in mm.  It divides light composed of various wavelengths into light components by particular wavelength.

dsinθ = nλ

Substitute n =3, λ =490 x 10⁻⁹ m and angle θ =6.33°, we get

d = [3 x 490 x 10⁻⁹ /sin 6.33°]

d = 13.33 x 10⁻⁶ m

Thus, the separation between the lines of the grating is 13.33μm.

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Two boxes need to be moved into storage. Jamal and Jude each want to move a box. The force of gravity on both the boxes is 50 N. Jamal is lifting with a force of 60 N, and Jude is lifting with a force of 45 N.

Which best describes the movement of the boxes?

Jamal moved his box to storage, but Jude could not move his.
Jamal and Jude can successfully move each box into storage.
Jamal could not move his box to storage, but Jude could.
Neither Jamal nor Jude could move the boxes into storage.

Answers

Answer:

Explanation:

Remark

If both are trying to get the box into storage and they can only  use lifting to do it, then Jude won't be able to do it. This assumes they cannot slide the boxes. Jude is not using enough force to overcome gravity so the box will just sit.

On the other hand Jamel is putting enough force to not only lift the box but it will move upwards against gravity. If we ignore that fact, then Jamel will get his box into storage.

Answer: A

a straight current-carrying wire in a uniform magnetic field, oriented at right angles to the wire. The 0.25-m wire carries a 4.75-A current and experiences a force of 0.38 N. What is the strength of the magnetic field?
0.45 T
0.56 T
0.32 T
0.72 T

Answers

Hello!

Using the equation for the magnetic force on a current-carrying wire:
[tex]F_B = \vec{B} \times i\vec{L}[/tex]

[tex]F_B[/tex] = Magnetic Force (0.38 N)
B = Magnetic field strength (T)
i = Current in wire (4.75 A)
L = Length of wire (0.25 m)

This is a cross product, so we can rewrite the equation as:
[tex]F_B = BiLsin\phi[/tex]

Where φ is the angle between the magnetic field vector and the length vector. In this instance, since the field is perpendicular to the wire, sin(90) = 1. We can simplify the equation to:
[tex]F_B = BiL[/tex]

Rearrange the equation to solve for 'B':
[tex]B = \frac{F_B}{iL}[/tex]

Plug in given values and solve.

[tex]B = \frac{0.38}{(4.75 * .25)} = \boxed{0.32 T}[/tex]

The strength of the magnetic field will be 0.32 T.Option B is correct.

What is magnetic field strength?

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

Given data:

(I) current = 4.75-A

(B)induced magnetic field strrength=?

(L)length of the wire=0.25-m

(F)Magnetic force=0.38 N

The strength of the magnetic field is found as:

[tex]\rm F_B=BILsin \theta \\\\\ \theta = 90^0 \\\\ \rm F_B=BIL \\\\[/tex]

Substitute the values:

[tex]\rm 0.38 = B \times 4.75 \times 0.25 \\\\\ B= \frac{0.38}{4.75 \times 0.25 } \\\\\ B=0.32 \ T[/tex]

The strength of the magnetic field will be 0.32 T.

Hence, option B is correct.

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Question 2 of 34
You are adding two vectors pointing in the same direction. How do you find
the magnitude of the resultant vector?
OA. By subtracting the magnitude of the shorter vector from the
magnitude of the longer vector
B. By adding the magnitudes of the two vectors
O C. By subtracting the magnitudes of the two vectors
D. By subtracting the magnitude of the longer vector from the
magnitude of the shorter vector

Answers

You can find the magnitude of the resultant vector : (B). By adding the magnitudes of the two vectors

Meaning of Vectors

A vector can be defined as any quantity which possesses magnitude and also has direction.

A Vector quantity is very useful because This type of quantity gives more details to the student or teacher analyzing it.

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Consider the soccer ball is kicked toward a goal at a speed of 35 mph and an angle of 25 ° from horizontal, what is the maximum height the ball will reach? Is this height more than a standard soccer goal's height, which is 8 feet from the ground?

(Recall: 1 mile = 1,609 meters and 1 hr = 3,600 s and 1 ft = 0.3048 meters)

Answers

The maximum height the ball will reach 7.316 ft. This height is less than a standard soccer goal's height.

What is projectile?

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

Maximum height reached is given by

H = u²sin²θ /2g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Consider the soccer ball is kicked toward a goal at a speed of 35 mph and an angle of 25 ° from horizontal,

Given is the speed 35mph = 35 x 1609/3600 = 15.65 m/s, θ =25 ° and g = 9.81 m/s²

Substituting the values, we get

H = (15.65)² (sin25 °)² / 2 x 9.81

H = 2.23 m

in feet, H = 7.316 ft

Thus, the maximum height is 7.316 ft. This height is less than  a standard soccer goal's height, which is 8 feet from the ground.

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A train traveling at 50m/s comes to a complete stop in 45 seconds. what was the rate of acceleration of the train?

Answers

The magnitude of the acceleration of the car is determined as 1.11 m/s².

Acceleration of the train

The acceleration of the train is determined as the rate of change of velocity with time.

The magnitude of the acceleration of the car is calculated as follows;

a = v/t

a = 50/45

a = 1.11 m/s²

Thus, the magnitude of the acceleration of the car is determined as 1.11 m/s².

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Olivia is on a swing at the playground.

A girl is swinging on a swing set. At W she is about 45 degrees up and to the left. At X she is near the bottom of the swing just to the left. At Y she is near the bottom of the swing just to the right. At Z she is about 45 degrees up and to the right.
If the swing is moving from W to Z, at which point is her kinetic energy increasing and her potential energy decreasing? (based on a starting point of W)

W
X
Y
Z
Mark this and return Save and Exit Next Submit

Answers

Olivia is on a swing at the playground. The kinetic energy is increasing and her potential energy decreasing at point X.

What is kinetic energy and potential energy?

The kinetic energy of an object is the ability to do work by virtue of its motion and potential energy is the ability to do work by virtue of its position.

At point W and Z, Olivia is at the maximum displacement from the mean position, where kinetic energy is zero and potential energy is maximum.

At point Y, it is approaching to increase its potential energy and decreasing kinetic energy. Opposite to this, at point X, kinetic energy is increasing and potential energy is decreasing.

Thus, the kinetic energy is increasing and her potential energy decreasing at point X.

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Explain how birds, bats, insects, airplanes, rockets, and hot air balloons achieve their flight.

Answers

The birds, bats, insects, airplanes, rockets, and hot air balloons achieve their flight by creating high pressure below the aircraft and low pressure above it

What are living and non-living things?

They both consist of fundamentally simple building blocks. They are composed of substances or mass. Atmospheric and molecular building blocks make up the world.

In order to create high pressure below the aircraft and low pressure above it, airplanes employ specially built wings.

The wing receives sufficient airflow past it to counteract the weight and drag of the aircraft by utilizing a device to provide thrust, such as a propeller.

High pressure underneath the aircraft and low pressure above it is produced by specially constructed wings used by airplanes.

The wing receives enough airflow through it by the use of a thrust-generating device, like a propeller, to overcome the weight and drag of the aircraft.

The differences between how living and non-living things fly;

1. Moving both living and non-living objects consumes energy. Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

In contrast to most air vehicles, where the components that generate lift, wings, and thrust engines or propellers are distinct, the wings stay stationary.

Animal aviators like birds as well as natural parachuters like patagial as well as human inventions like aircraft as well as rockets that can power spacecraft and spaceplanes are just a few examples of the many things that can fly.

Hence, birds, bats, insects, airplanes, rockets, and hot air balloons achieve their flight by creating high pressure below the aircraft and low pressure above it

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For an object on a flat surface, the force of gravity is 15 newtons downward and the normal force is 15 newtons upward. The applied force is 10 newtons toward the left and the frictional force is 8 newtons toward the right. What is the magnitude and direction of the net force?
2 newtons toward the right
2 newtons upward
2 newtons toward the left
2 newtons downward

Answers

Answer:

There is a net force of 2 N to the left.

With 8 N to the left the up/down and left/right forces are in balance.

The force left over is 2 N to the left.

A student on a tower 49 m height drops a stone. One second later he throws a second stone after the first. They both hit the ground at the same time, with what speed did he throw the second stone. [Ans: 10.1m/s]​

Answers

By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

How to determine the speed?

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

Note: Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

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What do echolocation and ultrasounds have in common?

Answers

They both are mechanical waves.

Explanation:

Echolocation and ultrasounds are both mechanical waves that require a medium to trace through. They both process and transfer information through waves; the difference is that we humans cannot hear ultrasound waves.

Try to solve this question:

Answers

Explanation:

w = mg

on earth

w = mg

w = 60 × 9.8 = 588 N

on moon

w = mg

w = 60 × 1.6 = 96 N

on Mars

w = mg

w = 60 × 3.7 = 222 N

Given data:Mass of object=60kggravity on earth=9.8ms^2gravity on moon=1.6ms^2gravity on mars=3.7ms^2RTC=Weight of object on earth,mars and moon.SOLUTION

In this question,we solve it using the formulae below:

W=mg.

So to find the weight of the object in 1.Earth.Enter the given data on formula:

W=mg

W=60×9.8

W= 588N.

2.Weight on the moon.

W=mg

W=60×1.6

W=96N

3.Weight on Mars.

W=mg

W=60×3.7

W=222N.

What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2

Answers

Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

What name carries the hypothetical artificial megastructure surrounding a star in order to capture its power?.

Answers

A Dyson sphere is a hypothetical megastructure that completely encompasses a star and captures a large percentage of its solar power output.

Two particles with oppositely signed charges nC are placed at two of the vertices of an equilateral triangle with side length 3 m. What is the magnitude of the electric field at the third vertex of the triangle

Answers

The magnitude of the electric field at the third vertex of the triangle is determined as zero.

Electric field at the third vertex of the triangle

The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;

E = E(13) + E(23)

E = (kq₁)/r² + (kq₂)/r²

where;

q1 is positive chargeq2 is negative charge

E =  (kq₁)/r² - (kq₂)/r²

E = 0

Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.

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The diameter of the Earth is 12.7 x 10 6 m. The diameter of Mars is 6800 km.
The difference in the diameters of the two planets is:

Answers

Answer:

5.9 × 10⁶m

Explanation:

The diameter of the Earth is 12.7 ×10⁶m.We have to convert the diameter of the mars in the same exponent as that of the earth so that we can easily subtract.The diameter of mars = 6800km = 6800 × 10³ m = 6.8 × 10⁶mNow we can subtract the diameters.The difference between the diameters = (The Diameter of Earth - The diameter of Mars)

                         = 12.7×10⁶ - 6.8 × 10⁶

                         = 5.9 × 10⁶m

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A spinning turbine at an electrical plant produces energy that flows through wires to your house. The energy in the wires can be used to light up a computer screen. In this example, what type of energy transformations occurred

Answers

The spinning turbine converts mechanical energy into electrical energy that is converted into light energy used to light up the house.

What is law conservation of energy?

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

The spinning turbine works on the principle of mechanical energy.

Thus, the spinning turbine converts mechanical energy into electrical energy that is converted into light energy used to light up the house.

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For this situation, i push on a heavy chair. suppose i push moderately on the chair, and this time the chair does move. then the strength of the force the chair exerts on me is group of answer choices

Answers

It is equal to the force you exert on the chair.
Other Questions
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