The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.
a. 7:8 and 49:64
b. 8:9 and 49:64
c. 8:9 and 64:81
d. 7:8 and 64:81

Answer:

1/7

Step-by-step explanation:

Answer:

the answers are 12.5, 5, 2, 0.8 and 0.32

Step-by-step explanation:

2(0.4)^-2

=2(6.25)

= 12.5

2(0.4)^-1

= 2(2.5)

=5

2(0.4)^0

=2(1)

=2

2(0.4)^1

=2(0.4)

=0.8

2(0.4)^2

=2(0.16)

=0.32

The x-component of the 450 N force is 0 N, the y-component is -450 N, and the z-component is 0 N. The angles associated with the force are 90 degrees with the x-axis and 180 degrees with the z-axis.

To determine the x, y, and z components of a force, we need to express the force in terms of its magnitude and direction angles. The x-component represents the force's projection onto the x-axis, the y-component represents the projection onto the y-axis, and the z-component represents the projection onto the z-axis.

In this case, the force has no component along the x-axis, so the x-component is 0 N. The force's entire magnitude is directed in the negative y-direction, so the y-component is -450 N. Similarly, the force has no component along the z-axis, so the z-component is 0 N.

As for the angles, the force is perpendicular to the x-axis, resulting in a 90-degree angle. The force is also directed opposite to the positive z-axis, resulting in a 180-degree angle with the z-axis.

Therefore, the x-component of the force is 0 N, the y-component is -450 N, and the z-component is 0 N. The angles associated with the force are 90 degrees with the x-axis and 180 degrees with the z-axis.

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Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Answer: 4 is i think 0.2 an 5 is 10

Step-by-step explanation:

b=17-12

h=18-14

b=5cm

h=4cm

1cm=0.0328

b=5×0.0328

b=0.164 ft

c=4×0.0328

c=0.131 ft

Give me brainliesst plzzzzz

We can conclude that with 99% confidence, the true population mean energy cost per year falls between $13.38 and $19.62.

A report in a magazine contains information on energy costs per year for 32-inch liquid crystal display (LCD) televisions. According to the report, a sample of 14 randomly selected 32-inch LCD televisions have a sample standard deviation of $3.90. Using a 99% level of confidence, the confidence interval for the true population mean energy cost per year can be calculated. A 99% level of confidence indicates that there is only a 1% chance that the true population mean energy cost per year falls outside the interval.Confidence Interval for Mean = $\bar{X}±t_{\frac{\alpha}{2},n-1}\frac{S}{\sqrt{n}}$Where, $\bar{X}$ is the sample mean,S is the sample standard deviation,n is the sample size,t is the critical value of t-distributionα is the level of significancet= 3.71 (using t-distribution table for 99% level of confidence with n - 1 degrees of freedom)Mean = $16.50 ± 3.71 × \frac{3.90}{\sqrt{14}}$=$16.50 ± 3.12$The 99% confidence interval for the true population mean energy cost per year is (13.38, 19.62). Therefore, we can conclude that with 99% confidence, the true population mean energy cost per year falls between $13.38 and $19.62.

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The problem involves solving Laplace's equation in the upper half plane with the boundary condition given by the equation 4x + y = 0 on the line segment -0 ≤ x ≤ a. Additionally, it is assumed that the solution u(x, y) approaches zero uniformly as y approaches infinity.

Laplace's equation in two dimensions is given by ∇²u = 0, where u(x, y) is the unknown function and ∇² is the Laplacian operator. In this problem, we are specifically interested in solving Laplace's equation in the upper half plane.

To solve Laplace's equation in the upper half plane with the given boundary condition, we can use the method of separation of variables. We assume a solution of the form u(x, y) = X(x)Y(y) and substitute it into Laplace's equation. This leads to two separate ordinary differential equations, one for X(x) and one for Y(y).

Solving the equation for X(x), we obtain a solution in terms of x. Similarly, solving the equation for Y(y), we obtain a solution in terms of y. By applying the given boundary condition 4x + y = 0 on the line segment -0 ≤ x ≤ a, we can determine the specific form of the solution.

The assumption that u(x, y) approaches zero uniformly as y approaches infinity indicates that the solution must decay as y increases. This condition further constrains the form of the solution and allows us to determine the behavior of the solution as y approaches infinity.

By solving the separated differential equations and applying the boundary condition and the assumption of uniform decay, we can obtain the solution to Laplace's equation in the upper half plane with the given conditions.

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In both cases, the logic used is deductive reasoning. In the first question (a), the logic follows the form of a deductive syllogism. In the second question (b), the logic follows a deductive pattern.

In the first question (a), the logic follows the form of a deductive syllogism. It starts with a general premise that everyone in the Family Madrigal has a special gift. The second premise states that Luisa is in the Family Madrigal. From these two premises, the conclusion is drawn that Luisa has a special gift. This deductive reasoning relies on the truth of the premises and the logical structure of the argument.

Similarly, in the second question (b), the logic follows a deductive pattern. The first premise states that every dog the person has seen is covered in fur. The second premise states that Barky is a dog. From these premises, the conclusion is drawn that Barky is covered in fur. This deductive reasoning relies on the assumption that the person's observations are representative and that Barky fits the category of dogs.

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5

---- is the answer to the question

-6

Answer:

y= 4/6x + 4

Step-by-step explanation:

The "rise" of the slope is 4 and the "run" of the slope is 6.

Answer:

The answer is 56.

Step-by-step explanation:

The formula for a triangle is b×h÷2. So you just input the data. 8×14÷2.

Answer:

See Below.

Step-by-step explanation:

We are given that PQRS is a parallelogram, where X and Y are points on the diagonal QS such that SX = QY.

And we want to prove that quadrilateral PXRY is a parallelogram.

Since PQRS is a parallelogram, its diagonals bisect each other. Let the center point be K. In other words:

[tex]SK=QK\text{ and } PK = RK[/tex]

SK is the sum of SX and XK. Likewise, QK is the sum of QY and YK:

[tex]SK=SX+XK\text{ and } QK=QY+YK[/tex]

Since SK = QK:

[tex]SX+XK=QY+YK[/tex]

And since we are given that SX = QY:

[tex]XK=YK[/tex]

So we now have:

[tex]XK=YK\text{ and } PK=RK[/tex]

Since XY bisects RP and RP bisects XY, PXRY is a parallelogram.

Answer:

320 m2

Step-by-step explanation:

I think the answer would be B) 340 m2

Answer:

about 11.5 cm.

Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.

8^2+b^2=14^2 simplified: 64+b^2=196

Then, I subtracted 64 on both sides, so I would have "b" by itself.

b^2=132

Next, I found the square root of both b^2 and 132, so I would find the true value of "b."

b=11.4891252931

So, the measure of the other leg rounded to the nearest tenth is about 11.5.

Answer:

like egip

Step-by-step explanation:

The permutations value of ₅P₂/₁₀P₄ is 1/252.

To perform the indicated calculation of ₅P₂/₁₀P₄, we need to evaluate the permutations.

The formula for permutations is given by nPr = n! / (n - r)!, where n is the total number of items and r is the number of items selected.

Let's calculate each permutation separately:

₅P₂ = 5! / (5 - 2)!

= 5! / 3!

= (5 * 4 * 3!) / 3!

= (5 * 4)

= 20

₁₀P₄ = 10! / (10 - 4)!

= 10! / 6!

= (10 * 9 * 8 * 7 * 6!) / 6!

= (10 * 9 * 8 * 7)

= 5,040

Now we can substitute the values into the expression:

₅P₂ / ₁₀P₄ = 20 / 5,040

Simplifying the division:

₅P₂ / ₁₀P₄ = 1 / 252

Therefore, the value of ₅P₂/₁₀P₄ is 1/252.

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Complete question:

Perform the indicated calculation: ₅P₂/₁₀P₄

Given:

The formula for nth term of a sequence is:

[tex]\dfrac{5}{6}+\dfrac{1}{2}n[/tex]

To find:

The 12th term in the given sequence.

Solution:

Consider the formula for nth term of a sequence:

[tex]a_n=\dfrac{5}{6}+\dfrac{1}{2}n[/tex]

Putting [tex]n=12[/tex], we get

[tex]a_{12}=\dfrac{5}{6}+\dfrac{1}{2}{12}[/tex]

[tex]a_{12}=\dfrac{5}{6}+6[/tex]

[tex]a_{12}=\dfrac{5+36}{6}[/tex]

[tex]a_{12}=\dfrac{41}{6}[/tex]

Therefore, the 12th in the given sequence is [tex]\dfrac{41}{6}[/tex].

The better approximation for f'(0) using Richardson's extrapolation is approximately 1.75254. So none of the options are correct.

Richardson's extrapolation is a technique used to improve the accuracy of numerical approximations by combining multiple estimates of a quantity. It is commonly applied in numerical analysis and computational mathematics.

To use Richardson's extrapolation, we can apply the formula:

[tex]f'(0) =\frac{2^p * f'(h) - f'(2h)}{2^p - 1}[/tex]

Given the values:

f'(0) = 0.08248 for h = 1

f'(0) = 0.91751 for h = 0.5

We can substitute these values into the Richardson's extrapolation formula:

[tex]f'(0) =\frac{2^1 * 0.91751 - 0.08248}{2^1 - 1}[/tex]

[tex]f'(0)= \frac{1.83502 - 0.08248}{1}[/tex]

[tex]f'(0)=1.75254[/tex]

Therefore, the better approximation for f'(0) using Richardson's extrapolation is approximately 1.75254.

None of the provided options (a, b, c, d) match this value, so none of them are correct.

The question should be:

A formula of order 4 for approximating the first derivative of a function f gives:

f'(0) = 0.08248 for h = 1

f'(0) = 0.91751 for h = 0.5

By using Richardson's extrapolation on the above values, a better approximation of f'(0) is:

a. 0.17095

b. 1.00177

c. 0.97318

d. 1.93645

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Answer:

Simple Interest (I) =  Principle * Rate * Time

so I = PRT

P = $47300

R = 3% = 0.03

T = 4months = 0.33years

so

Assuming its per year after 4month

I = (47300)(0.03)(0.333333)

I = 472.999527

I = $473

Now we'd add the interest(I) to the Principle

$47300 + $473 = $47773.00

Assuming it is per month, after 4months

I = PRT

I = (47300)(0.03)(4)

I = $5676.00

Now add the interest to the principle

$47300 + $5676 = $52976.00

Step-by-step explanation:

there you go hope this help

Answer:

B: 60mm

Step-by-step explanation:

Answer:

B. 60 mm

Step-by-step explanation:

1 cm = 10 mm

6 cm = 6 * 1 cm = 6 * 10 mm = 60 mm

Answer: B. 60 mm

Answer:

I think 60 s.sq m

Answer:

Cubes in each layer: 6

Number Of Layers: 5

Volume: 30

Answer:

-8

Step-by-step explanation:

The rule for the sequence is ×2

E.g.

-1×2=-2

-2×2=-4

-4×2=-8

Answer:

-8 is the correct answer according to the sequence's rule.

To solve the given differential equation y'' + 2y' - 8y = 3e^(-3x) - e^(-x) by variation of parameters, we first need to find the complementary solution to the homogeneous equation y'' + 2y' - 8y = 0.

The characteristic equation associated with the homogeneous equation is r^2 + 2r - 8 = 0, which factors as (r - 2)(r + 4) = 0. Therefore, the complementary solution is y_c = c1e^(-4x) + c2e^(2x).

Next, we can find the particular solution using the method of variation of parameters. We assume the particular solution has the form y_p = u1(x)e^(-4x) + u2(x)e^(2x). We then find the derivatives y_p' and y_p'' and substitute them into the original differential equation, which allows us to solve for u1'(x) and u2'(x).

After finding u1'(x) and u2'(x), we integrate them to obtain u1(x) and u2(x). Finally, we substitute these values back into the particular solution y_p = u1(x)e^(-4x) + u2(x)e^(2x) to obtain the complete solution to the nonhomogeneous differential equation.

The explanation paragraph would further detail the steps involved in finding the complementary solution, setting up the particular solution using variation of parameters, and solving for the unknown functions u1(x) and u2(x). It would explain how the initial conditions are applied to find the specific values of the constants in the general solution. The final result would be the complete solution to the given differential equation satisfying the initial conditions.

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Answer:

Hi! The answer to your question is C. 52

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☆Brainliest is greatly appreciated!☆

Hope this helps!

- Brooklynn Deka

The working class was unable to achieve much, despite valiant efforts, due to their lack of solidarity and the capitalist's willingness to use violence against them.The middle class responded to the struggle between labor and capital, as well as the changes that American society underwent during the late nineteenth century, by supporting a variety of social reform movements.

After the Civil War, Reconstruction failed to establish racial equality and black freedom in the United States. The rapid industrialization of the United States under the system of "free labor" in the years following the Civil War contributed to a social crisis by the end of the nineteenth century. This crisis seemed to be causing the disappearance of traditional American values of democracy, equality, and opportunity, and class conflict was threatening to tear society apart.In their struggle against each other, capitalists and working classes attempted to enhance their own power and interests. Capitalists attempted to enhance their power by instituting new labor policies, cutting wages, and lowering working conditions.

The working class was unable to achieve much, despite valiant efforts, due to their lack of solidarity and the capitalist's willingness to use violence against them.The middle class responded to the struggle between labor and capital, as well as the changes that American society underwent during the late nineteenth century, by supporting a variety of social reform movements. They sought to provide relief for the urban poor and to reform politics by promoting women's suffrage and demanding the elimination of political corruption.In conclusion, Reconstruction failed to establish racial equality and black freedom in the United States. The rapid industrialization of the United States under the system of "free labor" in the years following the Civil War contributed to a social crisis by the end of the nineteenth century. Capitalists and working classes attempted to enhance their power and interests in their struggle with each other. The working class was unable to achieve much, despite valiant efforts. The middle class responded to the struggle between labor and capital, as well as the changes that American society underwent during the late nineteenth century, by supporting a variety of social reform movements.

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Answer: No

Step-by-step explanation: Vincent started 10 miles ahead so Bill will never catch up at this rate

Answer:

-3.5

Step-by-step explanation:

The following statement (d) "R must be an equivalence relation, and ([x]_R: x∈X) must equal P." is true

The relation R defined as R={(x,y):x∈A and y∈A for some A∈P} is an equivalence relation.

1. Reflexivity: Since the set P does not contain the empty set, Ø∉P, for any element x∈X, there exists a set A∈P such that x∈A. Therefore, (x,x)∈R for all x∈X, making R reflexive.

2. Symmetry: Let (x,y)∈R, which means there exists a set A∈P such that x∈A and y∈A. Since A is a subset of X, it follows that y∈A and x∈A as well. Hence, (y,x)∈R, and R is symmetric.

3. Transitivity: Let (x,y)∈R and (y,z)∈R, which means there exist sets A and B in P such that x∈A, y∈A, y∈B, and z∈B. Since the union of all sets in P is X, the union of A and B is also a set in P. Thus, x∈A∪B, and z∈A∪B. Therefore, (x,z)∈R, and R is transitive.

Since R is reflexive, symmetric, and transitive, it satisfies the properties of an equivalence relation.

Additionally, the equivalence classes ([x]_R: x∈X) of R are equal to the set P. Each equivalence class [x]_R represents a subset of X that contains all elements y∈X such that (x,y)∈R. In this case, for each x∈X, the corresponding equivalence class [x]_R is the set A∈P such that x∈A.

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