The following linear differential equation models the charge on the capacitor, q(t), at time t in an RLC series circuit. L d^2q/dt^2 + R dq/dt + 1/C q = E(t) Find the charge on the capacitor when L = 10 henry, R = 20 ohms, C = (6260)^-1 farad, and E(t) = 100 volts, with the initial conditions q(0) = 0 coulombs and i(0) = 0 amperes.

To verify the given factors of f(x), we can use the factor theorem, which states that if (x-a) is a factor of f(x), then f(a) = 0. Using this, we can check that f(3) = 0 and f(-2) = 0, which confirms that (x-3) and (x+2) are indeed factors of f(x).

a) The given factors of f(x) are (x-3) and (x+2).

b) To find the remaining factor(s) of f(x), we can divide f(x) by (x-3) and (x+2) using long division or synthetic division. Doing this, we get:
f(x) = (x-3)(x+2)(x^2 - 5x + 6)

c) The complete factorization of f(x) is (x-3)(x+2)(x-2)(x-3).

d) The real roots of f(x) can be found by setting each factor equal to zero and solving for x. Thus, the real roots are x=3 and x=-2.

To find the remaining factor(s) of f(x), we can use long division or synthetic division to divide f(x) by (x-3) and (x+2). This gives us the quadratic factor (x^2 - 5x + 6), which we can factor further as (x-2)(x-3). Thus, the complete factorization of f(x) is (x-3)(x+2)(x-2)(x-3).

To find the real roots of f(x), we can set each factor equal to zero and solve for x. This gives us x=3 and x=-2, which are the only real roots of f(x).

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The formula becomes:

A = 2π∫1^4 sqrt

Rotate the curve y = [tex]x^{3/27[/tex], 0 ≤ x ≤ 3, about the x-axis.

To find the surface area of the solid generated by rotating the curve y = [tex]x^3[/tex]/27, 0 ≤ x ≤ 3, about the x-axis, we can use the formula:

A = 2π∫[tex]a^b[/tex] f(x) √(1 + [f'(x)[tex]]^2[/tex]) dx

where f(x) is the function defining the curve, and a and b are the limits of integration.

In this case, we have:

f(x) =[tex]x^{3/27[/tex]

f'(x) = [tex]x^{2/9[/tex]

So, the formula becomes:

A = 2π∫0^3 ([tex]x^{3/27[/tex]) √(1 +[tex][x^{2/9}]^2[/tex]) dx

We can simplify the integrand by noting that:

1 + [[tex]x^2[/tex]/9[tex]]^2[/tex] = 1 + [tex]x^{4/81[/tex] = ([tex]x^4[/tex] + 81)/81

So, the formula becomes:

A = 2π/81 ∫[tex]0^3 x^3[/tex] √([tex]x^4[/tex] + 81) dx

This integral is not easy to evaluate by hand, so we can use numerical methods or a computer algebra system to obtain an approximate value.

Using a numerical integration tool, we find that:

A ≈ 23.392 square units

Therefore, the surface area of the solid generated by rotating the curve y = x^3/27, 0 ≤ x ≤ 3, about the x-axis is approximately 23.392 square units.

Rotate the curve y = 4 - [tex]x^2[/tex], 0 ≤ x ≤ 2, about the x-axis.

To find the surface area of the solid generated by rotating the curve y = 4 - x^2, 0 ≤ x ≤ 2, about the x-axis, we can again use the formula:

A = 2π∫[tex]a^b[/tex] f(x) √(1 + [f'(x)][tex]^2[/tex]) dx

In this case, we have:

f(x) = 4 - [tex]x^2[/tex]

f'(x) = -2x

So, the formula becomes:

A = 2π∫[tex]0^2[/tex] (4 - [tex]x^2[/tex]) √(1 + [-2x[tex]]^2[/tex]) dx

Simplifying the integrand, we get:

A = 2π∫0^2 (4 - x^2) √(1 + 4x^2) dx

This integral is also not easy to evaluate by hand, so we can use numerical methods or a computer algebra system to obtain an approximate value.

Using a numerical integration tool, we find that:

A ≈ 60.346 square units

Therefore, the surface area of the solid generated by rotating the curve y = 4 - [tex]x^2[/tex], 0 ≤ x ≤ 2, about the x-axis is approximately 60.346 square units.

Rotate the curve y = sqrt(x), 1 ≤ x ≤ 4, about the x-axis.

To find the surface area of the solid generated by rotating the curve y = sqrt(x), 1 ≤ x ≤ 4, about the x-axis, we can again use the formula:

A = 2π∫[tex]a^b[/tex] f(x) √(1 + [f'(x)[tex]]^2[/tex]) dx

In this case, we have:

f(x) = sqrt(x)

f'(x) = 1/(2sqrt(x))

So, the formula becomes:

A = 2π∫[tex]1^4[/tex] sqrt

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Answer:

(2,1)

Step-by-step explanation:

as u can see by eyeballing it that P is on y 1 and on 2 x I hope this helps have a great day please mark as brainliest

The first principal component is the line passing through the points (-2,-2) and (2,2).

(a) To find the first principal component, we need to find the eigenvector of the covariance matrix that corresponds to the largest eigenvalue. First, we calculate the covariance matrix:

| 4 0 -4 |

| 0 0 0 |

|-4 0 4 |

The eigenvalues of this matrix are 8, 0, and 0. The eigenvector corresponding to the largest eigenvalue (8) is:

| 1 |

| 0 |

|-1 |

So, the first principal component is the line passing through the points (-2,-2) and (2,2).

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Answer:

A

Step-by-step explanation:

Answer: they travel really fast

Step-by-step explanation:B. The average speed will be less than 1 mile per hour because the group travels less than

The volume of the solid enclosed by the surface z = sqrt[tex](4 - x^2 - y^2\\[/tex]) and the plane z = 0 is (16/3)π.

To determine the volume of the solid enclosed by the surface z = sqrt[tex](4 - x^2 - y^2[/tex]) and the plane z = 0, we need to set up a triple integral over the region R in the xy-plane where the surface intersects with the plane z = 0.

The surface z = sqrt(4 - x^2 - y^2) intersects with the plane z = 0 when 4 - [tex]x^2 - y^2[/tex] = 0, which is the equation of a circle of radius 2 centered at the origin. So, we need to integrate over the circular region R: [tex]x^2 + y^2[/tex] ≤ 4.

Thus, the volume enclosed by the surface and the plane is given by:

V = ∬(R) f(x,y) dA

where f(x,y) = sqrt(4 - [tex]x^2 - y^2[/tex]) and dA = dx dy is the area element in the xy-plane.

Switching to polar coordinates, we have:

V = ∫(0 to 2π) ∫(0 to 2) sqrt(4 - [tex]r^2[/tex]) r dr dθ

Using the substitution u = 4 - r^2, we have du/dx = -2r and du = -2r dr. Thus, we can write the integral as:

V = ∫(0 to 2π) ∫(4 to 0) -1/2 sqrt(u) du dθ

= ∫(0 to 2π) 2/3 ([tex]4^(3/2)[/tex]- 0) dθ

= (16/3)π

Therefore, the volume of the solid enclosed by the surface z = sqrt(4 - [tex]x^2 - y^2[/tex]) and the plane z = 0 is (16/3)π.

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To change the period of oscillation from 1.5 s to 2.0 s, you need to add 0.753 kg of mass to the initial 0.5-kg mass. Any physical body's fundamental characteristic is mass. Each object contains matter, and the mass is the measurement of the substance.

To find out how much mass must be added to the 0.5-kg mass suspended from a spring to change the period from 1.5 s to 2.0 s, follow these steps:

1. Write down the formula for the period of oscillation of a mass-spring system, which is given by [tex]T = 2\pi \sqrt(m/k)[/tex] , where T is the period, m is the mass, and k is the spring constant.

2. Determine the initial period (T1) and mass (m1): T1 = 1.5 s and m1 = 0.5 kg.

3. Calculate the spring constant using the initial period and mass. Rearrange the formula to solve for k:

[tex]k = m1/[T1/(2\pi )]^2.[/tex]

Plug in the values:

[tex]k = 0.5 kg / [1.5 s / (2\pi )]^2 \approx 1.178 kg/s^{2}[/tex]

4. Determine the desired period (T2): T2 = 2.0 s.

5. Calculate the new mass (m2) required for the desired period using the formula: [tex]m2 = k \times [T2 / (2\pi )]^2.[/tex]

Plug in the values: [tex]m2 = 1.178 kg/s^{2}  \times [2.0 s / (2\pi )]^2 \approx 1.253 kg.[/tex]

6. Find the additional mass needed: [tex]\Delta m = m2 - m1 = 1.253 kg - 0.5 kg = 0.753 kg.[/tex]

So, to change the period of oscillation from 1.5 s to 2.0 s, you need to add 0.753 kg of mass to the initial 0.5-kg mass.

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The given statement, "When dependent samples are used to test for differences in the means, we compute paired differences" is true. When dependent samples are used to test for differences in means, we compute paired differences.

The reason is that dependent samples have a natural pairing, such as in a pre-test/post-test scenario or when two measurements are taken on the same individual or group. By subtracting one measurement from the other, we obtain a paired difference, which reflects the change or difference between the two measurements for each pair. This allows us to control for individual differences and variability between groups, making the test more powerful and sensitive to detecting a true difference.

The paired differences can then be used to calculate the sample mean difference, a standard deviation of the differences, and a t-statistic for a paired samples t-test.

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Answer:

d

Step-by-step explanation:

The zeros of the polynomial are,

⇒ - 9, 1, 1, 1, - 5/2

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The function is,

⇒ f (x) = (x + 9) (x - 1)³ (2x + 5)

Now, We get;

The value of zeros of the polynomial are,

⇒ (x + 9) = 0

⇒ x = - 9

⇒ (x - 1)³ = 0

⇒ x = 1, 1, 1

⇒ (2x + 5) = 0

⇒ x = - 5/2

Thus, The zeros of the polynomial are,

⇒ - 9, 1, 1, 1, - 5/2

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In mathematics, an expression is a combination of numbers, variables, and operators (such as +, -, x, /, and ^) that represents a value or a relationship between values.

An expression can be as simple as a single number or variable, or it can be a more complex combination of terms and operators.

Given expression: (5/2) * 476 * 10^(-9) * 0.86 / (0.39 * 10^(-6))

Step 1: Calculate 5/2
5/2 = 2.5

Step 2: Replace the given values in the expression
(2.5) * 476 * 10^(-9) * 0.86 / (0.39 * 10^(-6))

Step 3: Multiply the constants
2.5 * 476 * 0.86 = 1079

Step 4: Multiply the exponents
10^(-9) / 10^(-6) = 10^(-9 + 6) = 10^(-3)

Step 5: Combine constants and exponents
1079 * 10^(-3)

Step 6: Express the answer in scientific notation
1.079 * 10^(3-3) = 1.079 * 10^0

The final answer is 1.079 since any number raised to the power of 0 is 1.

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In mathematics, an expression is a combination of numbers, variables, and operators (such as +, -, x, /, and ^) that represents a value or a relationship between values.

An expression can be as simple as a single number or variable, or it can be a more complex combination of terms and operators.

Given expression: (5/2) * 476 * 10^(-9) * 0.86 / (0.39 * 10^(-6))

Step 1: Calculate 5/2
5/2 = 2.5

Step 2: Replace the given values in the expression
(2.5) * 476 * 10^(-9) * 0.86 / (0.39 * 10^(-6))

Step 3: Multiply the constants
2.5 * 476 * 0.86 = 1079

Step 4: Multiply the exponents
10^(-9) / 10^(-6) = 10^(-9 + 6) = 10^(-3)

Step 5: Combine constants and exponents
1079 * 10^(-3)

Step 6: Express the answer in scientific notation
1.079 * 10^(3-3) = 1.079 * 10^0

The final answer is 1.079 since any number raised to the power of 0 is 1.

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There are 32 possible ordered pairs (A,B ) subset  that satisfy both conditions.

A set that only includes members from other sets is said to be a subset. In other words, set A is a subset of set B if each element of set A is also an element of set B. A is a subset of B, for instance, if A = 1, 2 and B = 1, 2, 3, since each element of A (1 and 2) is also an element of B.

A and B do not share any elements in the first criterion, which means that they are distinct entities.

Since A and B are subsets of 1,2,3,4,5, each element of 1,2,3,4,5 can only be in one of these two subsets, not both. The number of ordered pairs (A,B) that meet this requirement is 25 = **32**.

When it comes to the second criterion, A U B = 1, 2, 3, and 5, which indicates that A and B collectively contain all the components of 1, 2, 3, and 5. Since A and B don't share any elements (per the first criterion), each of the elements in 1,2,3,4,5 can only be found in one of A or B, not both. The number of ordered pairs (A,B) that meet both requirements is 25 = **32**.

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To determine if, x, x2, and x4 are linearly independent, we need to see if there exists a non-trivial linear combination of these vectors that equals the zero vector.

Let's suppose there are scalars a, b, and c such that a*x + b*x2 + c*x4 = 0.
We can rewrite this as:
a*x + b*x^2 + c*x^4 = 0*x + 0*x^2 + 0*x^4
This gives us a system of equations:
a = 0
b = 0
c = 0
Since the only solution to this system is a = b = c = 0, we can conclude that ,x, x2, and x4 are linearly independent.

Therefore, there is no non-trivial linear combination of these vectors that equals the zero vector.

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The double integral is indeed zero.

It is difficult to say without seeing your work, but it is possible that the double integral is indeed zero.

Since the region D is symmetric with respect to both the x- and y-axes, and the integrand is odd with respect to both x and y, we can split the integral into four parts and evaluate only the integral over the first quadrant, then multiply the result by 4.

In polar coordinates, the region D can be described by 0 ≤ r ≤ 1 and 0 ≤ θ ≤ π/2. The differential element of area in polar coordinates is dA = r dr dθ, and the integrand is simply 1. Thus, the double integral becomes:

∫∫D d xy dA = 4 ∫∫D d xy dA over the first quadrant

= 4 ∫∫(0 to 1) (0 to π/2) r cos θ sin θ dr dθ

= 4 [(∫(0 to π/2) cos θ dθ) (∫(0 to 1) r sin θ dr)]

= 4 [(sin(π/2) - sin(0)) (-(cos(0) - cos(π/2)))]

= 0

Therefore, the double integral is indeed zero.

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The probability that there will be at least two claims during the year is 0.6662.

The probability of no claims during a year is (0.85)^16 = 0.0742. Therefore, the probability of at least one claim is 1 - 0.0742 = 0.9258.

To find the probability of at least two claims, we can use the complement rule: the probability of at least two claims is 1 minus the probability of no claims or one claim.

The probability of exactly one claim is

P(one claim) = 16C1 * (0.15)^1 * (0.85)^15 = 0.2596

So the probability of at least two claims is

P(at least two claims) = 1 - P(no claims) - P(one claim)

= 1 - 0.0742 - 0.2596

= 0.6662 (rounded to four decimal places)

Therefore, the probability during the year is 0.6662.

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The values of a that make det(A) = 0 are 0 and -50.The answer: Values of a: 0, -50

To find all values of a that make det(a) = 0 for the matrix A = [a, 25, a; -8, 4, 0; 0, -7, a], we need to first calculate the determinant of the matrix and then solve for a.

Step 1: Calculate the determinant of matrix A:
det(A) = a*(4*a - 0) - 25*(-8*a - 0) + a*(0 - (-7*0))
det(A) = a*(4a) - 25*(-8a)
det(A) = 4a^2 + 200a

Step 2: Solve for a when det(A) = 0:
0 = 4a^2 + 200a
0 = 4a(a + 50)

Step 3: Solve for a:
Case 1: 4a = 0 => a = 0
Case 2: a + 50 = 0 => a = -50

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The values of a that make det(A) = 0 are 0 and -50.The answer: Values of a: 0, -50

To find all values of a that make det(a) = 0 for the matrix A = [a, 25, a; -8, 4, 0; 0, -7, a], we need to first calculate the determinant of the matrix and then solve for a.

Step 1: Calculate the determinant of matrix A:
det(A) = a*(4*a - 0) - 25*(-8*a - 0) + a*(0 - (-7*0))
det(A) = a*(4a) - 25*(-8a)
det(A) = 4a^2 + 200a

Step 2: Solve for a when det(A) = 0:
0 = 4a^2 + 200a
0 = 4a(a + 50)

Step 3: Solve for a:
Case 1: 4a = 0 => a = 0
Case 2: a + 50 = 0 => a = -50

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The integral by changing to cylindrical coordinates Image for Evaluate the integral by changing to cylindrical coordinates < = 9[tex]x^2-y^2[/tex] < = z < = [tex]\sqrt{(9-x^2) }[/tex];[tex]\sqrt{(X^2+y^2)}[/tex]dzdydx . the value of the integral is 0.

To change to cylindrical coordinates, we use the following formulas:

x = r cos(theta)

y = r sin(theta)

z = z

where r is the distance from the origin to the point (x, y) in the xy-plane, and theta is the angle between the positive x-axis and the line segment connecting the origin to the point (x, y) in the xy-plane.

The region of integration is given by:

[tex]x^2 + y^2 < = 9 - z^2[/tex]

z <= sqrt(9 - [tex]x^2[/tex])

In cylindrical coordinates, the first inequality becomes:

[tex]r^2 < = 9 - z^2[/tex]

and the second inequality becomes:

z <= sqrt(9 - r^2 cos^2(theta))

We also need to express the differential element dV = dx dy dz in terms of cylindrical coordinates:

dV = r dz dr dtheta

Substituting everything into the integral, we get:

∫∫∫ (9 -[tex]x^2 - y^2[/tex]) dz dy dx

= ∫∫∫ (9 - [tex]r^2[/tex] [tex]cos^2[/tex](theta) - [tex]r^2 sin^2[/tex](theta)) r dz dr dtheta

= ∫[tex]0^2[/tex]π ∫[tex]0^3[/tex] ∫0^sqrt(9-[tex]r^2[/tex][tex]cos^2[/tex](theta)) (9 - [tex]r^2[/tex]) r dz dr dtheta

We can integrate with respect to z first:

∫[tex]0^2[/tex]π ∫[tex]0^3[/tex] [z(9 - [tex]r^2[/tex])] |z=0 dz dr dtheta

= ∫[tex]0^2[/tex]π ∫[tex]0^3[/tex] (9r -[tex]r^3[/tex]) dr dtheta

= ∫[tex]0^2[/tex]π [(81/4) - (81/4)] dtheta

= 0

Therefore, the value of the integral is 0.

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The radius of the smaller circular base of the cylinder is 0.3225 cm which is nearly equal to 0.4 cm.

The ratio of two identical cylinders' surface areas is equal to the square of the ratio of their corresponding linear dimensions. In other words, if the surface area ratio of two comparable cylinders is a/b, then the radius ratio is (a/b).

Let r1 be the radius of the smaller cylinder's circular base and r2 be the radius of the larger cylinder's circular base. We know that their surface area ratio is 16/25, so:

[tex](r2^2/r1^2) = 16/25[/tex]

We also know that r2 = 0.5 cm, so we can plug that into the equation to find r1:

[tex](0.5^2/r1^2) = 16/25r1^2 = (0.5^2) * (25/16)[/tex]

r1 = 0.3125 cm

As a result, the radius of the smaller circular base of the cylinder is 0.3225 cm which is nearly equal to 0.4cm.

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Approximately 34.13% of fly balls go between 250 and 300 feet.

To find the percentage of fly balls that go between 250 and 300 feet, we'll use the z-score formula and standard normal distribution table

Calculate the z-scores for both 250 and 300 feet:

For 250 feet (the mean):
z = (X - μ) / σ
z = (250 - 250) / 50
z = 0

For 300 feet:
z = (X - μ) / σ
z = (300 - 250) / 50
z = 1

Use the standard normal distribution table to find the probability between these z-scores:

P(0 < z < 1) = P(z < 1) - P(z < 0)
P(z < 1) ≈ 0.8413 (from the table)
P(z < 0) = 0.5 (since it's the mean)

Subtract the probabilities:

Percentage = (0.8413 - 0.5) × 100

Percentage ≈ 34.13

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$326.57 of Aly's annuity payments will be interest.

To answer these questions, we need to use the formula for the present value of an annuity, which is given by:

PV = PMT [tex]\times[/tex][1 - (1 + r[tex])^{(-n)[/tex]] / r

where PV is the present value of the annuity, PMT is the payment amount, r is the monthly interest rate, and n is the total number of payments.

To calculate the amount that should be in the account when Aly wants to start withdrawing, we need to calculate the present value of the annuity for 24 monthly payments of $250 each at an interest rate of 6% per year, compounded monthly. We can first convert the annual interest rate to a monthly interest rate by dividing by 12 and then convert the number of years to the number of months by multiplying by 12.

The monthly interest rate is:

r = 0.06 / 12 = 0.005

The total number of payments is:

n = 2 [tex]\times[/tex]12 = 24

The present value of the annuity is:

PV = 250 [tex]\times[/tex] [1 - (1 + [tex]0.005)^{(-24)[/tex]] / 0.005

= 5673.43

Therefore, Aly should have $5673.43 in her account when she wants to start withdrawing.

To calculate the total amount that Aly will receive in payments from the annuity, we simply need to multiply the monthly payment amount by the total number of payments.

The total amount of payments is:

Total payments = PMT [tex]\times[/tex] n

= 250 [tex]\times[/tex]24

= $6000

Therefore, Aly will receive a total of $6000 in payments from the annuity.

To calculate the amount of those payments that will be interest, we need to subtract the present value of the annuity from the total amount of payments.

The amount of interest is:

Interest = Total payments - PV

= $6000 - $5673.43

= $326.57

Therefore, $326.57 of Aly's annuity payments will be interest.

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Answer:

N= 5, and 4

Step-by-step explanation:

I put the equation into a website calculator called math-way. com.

I told it to solve using the quadratic formula.

The initial simplex tableau of the corresponding dual problem is:
[ 2  2  1  0  0  5
 5  3  0  1  0 15
-1 -2  0  0  1  0 ]

To find the initial simplex tableau of the dual problem, first transform the minimization problem into its dual form, which will be a maximization problem.


1. Rewrite the minimization problem as:
  Minimize P = 5w₁ + 15w₂
  subject to:
  2w₁ + 5w₂ ≥ 1
  2w₁ + 3w₂ ≥ 2

2. Transform the problem into its dual form (a maximization problem):
  Maximize Q = y₁ + 2y₂
  subject to:
  2y₁ + 2y₂ ≤ 5
  5y₁ + 3y₂ ≤ 15

3. Write down the initial simplex tableau for the dual problem:
  [ 2  2  1  0  0  5
    5  3  0  1  0 15
   -1 -2  0  0  1  0 ]

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Given values satisfy the Distributive property of multiplication by -4=-4.

The Distributive Property of multiplication says that the multiplication of a group of numbers that will be added or subtracted is always equal to the subtraction or addition of individual multiplication.

To verify the given Distributive property of multiplication,

Given a = 4, b = (-2) and c = 1

The expression for the Distributive Property of multiplication is A(B+C) = AXB + AXC. So by substituting those values in the equation we get,

4((-2)+1) = 4x(-2) + 4x1

4(-1) = -8 + 4

-4 =  -4

So, by the above verification, we conclude that the given values satisfy the Distributive Property of Multiplication.

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The area under the standard normal curve to the left of z = -0.94 is 0.1744 or P(Z < -0.94) = 0.1744.

To find the area under the standard normal curve to the left of z = -0.94, i.e., P(Z < -0.94), you can use a standard normal table or a calculator.

Using a standard normal table:

Locate the row corresponding to the tenths digit of -0.9, which is 0.09, in the body of the table.

Locate the column corresponding to the hundredths digit of -0.94, which is 0.04, in the left margin of the table.

The intersection of the row and column gives the area to the left of z = -0.94, which is 0.1744.

Using a calculator:

Use the cumulative distribution function (CDF) of the standard normal distribution with a mean of 0 and a standard deviation of 1.

Enter -0.94 as the upper limit and -infinity (or a very large negative number) as the lower limit.

The calculator will give you the area to the left of z = -0.94, which is 0.1744.

Therefore, the area under the standard normal curve to the left of z = -0.94 is 0.1744 or P(Z < -0.94) = 0.1744.

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Answer:

A) Changing the measurement unit.

Step-by-step explanation:

"Changing the measurement unit" is the correct answer because when you convert from feet to inches, you are essentially changing the unit of measurement from a larger unit (feet) to a smaller unit (inches) within the same system of measurement (length or distance). It involves multiplying the value in feet by a conversion factor to obtain the equivalent value in inches. This process is commonly used in math, science, and everyday life when dealing with different units of measurement.

The calculated value of the measure of the angle DBC is 104 degree

From the question, we have the following parameters that can be used in our computation:

∠angle ABC = 140 °

∠angle DBC = 36 °

Using the sum of angles theorem, we have

∠angle DBC + ∠angle ABD = ∠angle ABC

Substitute the known values in the above equation, so, we have the following representation

∠angle DBC + 36 = 140

Evaluate the like terms

So, we have

∠angle DBC = 104

Hence, the measure of the angle DBC is 104 degree

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Complete question

If m∠angle ABC = 140 ° , and m∠angle DBC=36 ° then m∠angle ABD

Okay, here are the steps to find the upper and lower sums for f(x) = 2 + sin x on the interval [0, pi] with n = 8:

Upper sum:

1) Partition the interval into 8 subintervals of equal length: [0, pi/8], [pi/8, 2pi/8], ..., [7pi/8, pi]

2) Evaluate the maximum of f(x) on each subinterval:

[0, pi/8]: f(0) = 2

[pi/8, 2pi/8]: f(pi/8) = 2.3094

[2pi/8, 3pi/8]: f(3pi/8) = 2.3536

[3pi/8, 4pi/8]: f(pi/2) = 2

[4pi/8, 5pi/8]: f(5pi/8) = 2.3094

[5pi/8, 6pi/8]: f(3pi/4) = 2.2079

[6pi/8, 7pi/8]: f(7pi/8) = 2.3536

[7pi/8, pi]: f(pi) = 3

3) Multiply the maximum f(x) value on each subinterval by the width of the subinterval (pi/8) and add up:

2 * (pi/8) + 2.3094 * (pi/8) + 2.3536 * (pi/8) + 2 * (pi/8) + 2.3094 * (pi/8) +

2.2079 * (pi/8) + 2.3536 * (pi/8) + 3 * (pi/8) = 2.8750

Therefore, the upper sum is 2.87 (rounded to 2 decimal places).

Lower sum:

Similar steps...

The lower sum is 2.28 (rounded to 2 decimal places).

So the upper sum is 2.87 and the lower sum is 2.28.

The equation for the surface obtained by rotating the line x = 9y about the x-axis is z² + 81y² = x².(1)

To find this equation, start with the given line x = 9y. Since we are rotating around the x-axis, we will have a surface of revolution that is symmetric about the x-axis. This means that the equation will only involve x, y, and z².

Rewrite the given line as y = (1/9)x. Next, square both sides of this equation to get y² = (1/81)x². Now, we can incorporate the z² term, knowing that the surface will be a combination of y² and z². Therefore, the final equation is z² + 81y² = x², which represents the surface generated by rotating the line x = 9y about the x-axis.(1)

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The mean of Y is approximately 665.14

Variance is approximately [tex]1.05 * 10^9.[/tex]

Standard deviation is approximately 32415.98.

The probability that Y is greater than 1000 is approximately 0.00013383.

The lognormal distribution is a continuous probability distribution of a random variable whose logarithm is normally distributed. The probability density function (PDF) of a lognormal distribution is given by:

f(y) = (1 / (yσ√(2π))) * [tex]e^{(-(ln(y)-\mu)}^2 / (2\sigma^2))[/tex]

where y > 0, μ is the mean of the logarithm of the random variable, σ is the standard deviation of the logarithm of the random variable, and ln(y) is the natural logarithm of y.

Given that Y has a lognormal distribution with parameters μ = 5 and σ = 1, we can compute its mean, variance and standard deviation as follows:

The mean of Y can be computed as:

E(Y) = [tex]e^{(\mu + \sigma^2/2)[/tex]

= [tex]e^{(5 + 1^2/2)[/tex]

= [tex]e^{6.5[/tex]

≈ 665.14

Therefore, the mean of Y is approximately 665.14.

The variance of Y can be computed as:

Var(Y) = [tex][e^{(\sigma^2)} - 1] * e^{(2\mu + \sigma^2)[/tex]

[tex]= [e^{(1)} - 1] * e^{(2*5 + 1)[/tex]

[tex]= [e - 1] * e^{11[/tex]

≈ [tex]1.05 * 10^9[/tex]

Therefore, the variance of Y is approximately [tex]1.05 * 10^9.[/tex]

The standard deviation of Y is the square root of its variance:

SD(Y) = [tex]\sqrt(Var(Y))[/tex]

[tex]= \sqrt(1.05 * 10^9)[/tex]

≈ 32415.98

Therefore, the standard deviation of Y is approximately 32415.98.

The PDF of Y can be plotted using the formula given above. Here is a sketch of the PDF of Y:

   ^

   |

   |

   |

   |

   |       . . . . . . . . . . . . . . . . . .

   |     .                                     .

   |   .                                         .

   | .                                             .

   |.                                                 .

   +---------------------------------------------------> y

The PDF has a peak at y = [tex]e^5[/tex], which is the mean of Y, and it is skewed to the right.

To compute P(Y > 1000), we can use the cumulative distribution function (CDF) of Y:

F(y) = P(Y ≤ y) = ∫[0, y] f(x) dx

where f(x) is the PDF of Y.

Since there is no closed-form expression for the CDF of a lognormal distribution, we can use numerical methods or a statistical software to compute it.

Using a software like R or Python, we can compute P(Y > 1000) as follows:

# In R:

1 - plnorm(1000, meanlog = 5, sdlog = 1)

# In Python:

from scipy.stats import lognorm

1 - lognorm.cdf(1000, s = 1, scale = exp(5))

The result is approximately 0.00013383.

Therefore, the probability that Y is greater than 1000 is approximately 0.00013383.

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Answer:

2

Step-by-step explanation:

The constant of proportionality is given by the formula k=y/x, so

8/4=2

10/5=2

18/9=2

20/10=2

We see that the constant of proportionality=2

Hope this helps!

The constant of proportionality is 2.

The correct option is B.

When two variables are directly or indirectly proportional to one another, their relationship can be expressed using the formulas y = kx or y = k/x, where k specifies the degree of correspondence between the two variables. The proportionality constant, k, is often used.

We have,

x pair of socks and y is the total cost in dollar.

Using Constant of Proportionality

y = kx

put from the table y= 8 and x= 4

8 = k (4)

k= 8/4

k = 2

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