The overcoming force is equal to the friction. The train's mass is 15,560,880.5 Kg
What is Friction ?Friction can simply be defined as a force that opposes the movement of an object in a plain surfaces.
Given that the heaviest train ever pulled by a single engine was over 2 km long. Suppose a force of 1.13 X 10^8 N is needed to overcome static friction in the train's wheels. If the coefficient of static friction is 0.741, what's the train's mass?
F = μN
Where
F = Frictional force = overcoming force = 1.13 X 10^8 Nμ = coefficient of static friction = 0.741N = Normal reaction = mgSubstitute all the necessary parameters
1.13 X 10^8 = 0.741N
N = 1.13 X 10^8/0.741
N = 152496626.2 N
N = mg
152496626.2 = 9.8m
m = 152496626.2/9.8
m = 15,560,880.5 Kg
Therefore, the mass of the train is 15,560,880.5 Kg.
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A 25 kg box of roofing shingles is lifted 15 meters vertically to the top of a roof. How much work is done on the box?
Important Formulas:
[tex]F=ma[/tex]
force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]m=25kg[/tex]
[tex]d=15m[/tex]
[tex]w=?[/tex]
We know that the acceleration due to gravity is 9.8 m/s^2.
__________________________________________________________
Finding force:
[tex]F=ma[/tex]
[tex]F=25\times9.8[/tex]
[tex]F=245N[/tex]
__________________________________________________________
Finding work:
[tex]w=Fd[/tex]
[tex]w=245\times15[/tex]
__________________________________________________________
[tex]\fbox{w = 3675 Joules}[/tex]
What is the equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel?
Answer:
The equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel is 2.0 Ω.
Explanation:
Please help me thank you
The gravitational potential energy of a body is determined by the equation U=mgh, where m is the body's mass, g is its gravitational force, and h is its height. The relationship between mechanical energy and gravitational potential energy is described by the equation E=U+K.
What is the kinetic energy equation?KE= 1/2 m v2
The relationship between kinetic energy and an object's mass and square of its velocity is direct: K.E. = 1/2 m v2.
We compute kinetic energy because...It provides information on how a substance's mass impacts its velocities. Take this as a case study. A lorry and a sleek vehicle powered by the same engine cannot go at the same pace because to their different designs.
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A car accelerates from the rest at 1.5 m/s^2 for 10 sec. What made the car move?
Accelerating linearly is simple.
What is Acceleration?When the velocity vector length of an object moving in a straight line changes in response to changes in the object's speed (speed being the magnitude of the velocity vector), we have acceleration. Increasing speed is frequently referred to as "positive acceleration" and decreasing speed as "negative acceleration."
A particle's acceleration is the rate at which its velocity changes over time. The term "constant acceleration" refers to the pace at which a particle's velocity changes.
We shall measure acceleration in metres per second per second because our basic units are metres and seconds.
Therefore, Accelerating linearly is simple.
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How long does it take the Earth to spin on its axis once?
Explanation:
it takes the earth 24 hours to spin on it's axis once
What will be the change in temperature if 600 g of water absorbs 5200 J of heat?
The change in temperature of the 600 g of water, given that the water aborbs 5200 J of heat energy is 2.07 °C
How do I determine the change in temperature of the water?First, we shall list out the given parameters from the question. This is given below:
Mass of water (M) = 600 gHeat absorbed (Q) = 5200 JChange in temperature (ΔT) = ?Calorimetry suggest the following formula:
Q = MCΔT
Where
Q is the heat transferred M is the mass C is the specific heat capacity ΔT is the change in temperatureUsing the above formula, the change in temperature of the water can be obtained as follow:
Note: Specific heat capacity of water (C) = 4.184 J/gºC
Q = MCΔT
5200 = 600 × 4.184 × ΔT
5200 = 2510.4 × ΔT
Divide both sides by 2510.4
ΔT = 5200 / 2510.4
ΔT = 2.07 °C
Thus, we can conclude from the above calculation, that the change in temperature of the water is 2.07 °C
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Why the specific heat of water changed as the water state changed?
Answer:
Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.
A 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
b. Find the time it takes for the ball to hit the ground.
From conservation of linear momentum, the final velocity is 15.7 m/s and the time taken is 1.6 s
What is Velocity ?Velocity can be defined as a distance travel in a specific direction per time taken. It is a vector quantity.
Given that 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
The maximum K.E of the ball at it final velocity will be equal to its maximum P.E at height 12.5 m. That is,
K.E = P.E
1/2mv² = mgh
Where
m = 30 Kgg = 9.8 m/s²h = 12.5 mv = ?Substitute all the parameters
1/2 × 30 × v² = 30 × 9.8 × 12.5
v² = 245
v = √245
v = 15.65 m/s
b. The time it takes for the ball to hit the ground can be found through
h = ut + 1/2gt²
but u = 0
h = 1/2gt²
Substitute all the necessary parameters
12.5 = 1/2 × 9.8 × t²
12.5 = 4.9t²
t² = 12.5/4.9
t² = 2.55
t = √2.55
t = 1.6 s
Therefore, the final velocity when the ball hits the ground is 15.65 m/s and the time it takes for the ball to hit the ground is 1.6 s
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Ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A. Is the momentum conserved in the collision? Why?
The mass of ball B and the final velocity of ball A can complement the conservation of linear momentum. The answer is yes.
What is Momentum ?Momentum can simply be defined as the product of mass and velocity. It is a vector quantity.
Given that ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A.
In an elastic head-on collision, momentum is mostly always conserved. That is, the sum of the momentum before collision will be equal to the sum of the momentum after collision.
Mathematically, MaUa = MaVa + MbVb
Is the momentum conserved in the collision?
The answer is yes!
Why?
Because we need to consider the mass of the ball B and the final velocity of the ball A.
Therefore, In consideration of the mass of the ball B and the final velocity of the ball A, we can say that the momentum is conserved.
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A man is attempting to train his dog. He is pulling on the dog with a force of 52.4 Newtons at an angle of 35.1 degrees above the horziontal. Fimd the X and Y component of the applied Force
The formula for the horizontal component (Fx), which is the angle the force makes with the horizontal, is Ftens•cosine(). Ftens• sine() can be used to compute the upward component (Fy), where is the angle that the force produces with the horizontal.
What is the force's horizontal component?The portion of a force that works horizontally with regard to a body is known as its horizontal component. Its vertical component is known as its vertical component.
Why is moving the box with the rope horizontal easier?The pulling of the box is with the rope horizontal. When the rope is angled Because Is less than, the horizontal component (= F cos ) is less. As a result, it is the proper response.
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8:11
GCSE Science - Physics
22 of 25
14 67%
A cat accelerates from rest to 10 m/s
when it sees a dog. This takes 2
the cat?
seconds What is the acceleration of the cat ?
the acceleration of the cat is 5m/s square
Teddy is playing with toy cars on his driveway. He rolls two cars directly at each other so that they will have a head-on collision. Their momentums before and after the collision are shown in the table below.
Momentum Before Momentum After
Car 1 9 g · m/s -2 g · m/s
Car 2 -6 g · m/s 4 g · m/s
Which of the following is true?
A.
This situation does not show a closed system.
B.
The situation shows a closed system.
C.
Car 2 has more mass than Car 1.
D.
Car 2 had a greater velocity before the collision than Car 1 had.
The true statement is " this situation does not show a closed system" because the linear momentum is not conserved.
option A is the correct answer.
What is the principle of conservation of linear momentum?
The principle of conservation of linear momentum states in a closed or isolated system, the total momentum of the system is always conserved.
Mathematically, the formula for the conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentum of the systemPf is the sum of the final momentum of the systemm₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the first objectm₂ is the mass of the second objectu₁ is the initial velocity of the first objectu₂ is the initial velocity of the second objectv₁ is the final velocity of the first objectv₂ is the final velocity of the second objectThe given momentum of the toy cars before and after collision;
Momentum Before Momentum After
Car 1 9 g m/s -2 g m/s
Car 2 -6 gm/s 4 g m/s
Sum of the momentum before the collision = 9 gm/s - 6 g m/s = 3 g m/s
Sum of the momentum after the collision = -2 gm/s + 4 gm/s = 2 g m/s.
The above does not show conservation of linear momentum, hence the system is closed because of the momentum is lost.
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Which of the following best explains the cause and effect relationship between convection currents in the mantle and the movement of tectonic plates?
A. The tectonic plates will heat up the mantle due to being closer to the surface of the earth and sun. The less dense particles in the mantle fall and cool toward the core, driving the convection cycle.
B. The tectonic plates drive the convection cycles in the mantle. As the plates move apart or push together, particles in the mantle will be thrust toward the core.
C. The heat from the core will make the particles in the mantle more dense and rise, causing plates in the
lithosphere to move in the opposite direction of the convection current.
D. The heat from the core will make particles in the mantle less dense and rise, causing plates in the
lithosphere to move in the direction of the convection current.
C) The mantle's particles will become more dense and rise as a result of the core heat, causing the lithosphere's plates to move in the opposite direction of the convection current.
How does the mantle's density change as it heats up?Convection Currents The lithosphere becomes denser than the surrounding magma and sinks back toward the core as the heated mantle transfers heat energy to it.
How does heat travel from the core to the crust in the mantle?Conduction from the core directly heats the lower mantle. As atoms collide, heat is transferred in conduction. Convection is the movement of warm and cool materials upward and downward. Material that is hot rises to the surface through conduction.
When the mantle rises, what takes place?“hot spots," which are non-plate tectonic volcanic regions, are probably caused by mantle plumes. A diapir is formed when a mantle plume reaches the upper mantle. Volcanic eruptions are sparked by the heat generated by this molten material in the asthenosphere and lithosphere.
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H
Question 12 of 15:
Select the best answer for the question.
12. A 150-lb block of ice has a temperature of 22 F. How much heat will the ice absorb before it begins to melt?
O A. 1500.0 Btu
O B. 1663.2 Btu
C. 756.0 Btu
OD. 2419.2 Btu
Answer:
I think it is A
Explanation:
It is A because if you calculate the weight minus the F, then you have to divide that by the amount of absorbation (the lb) before timsing it by 1000.
What will be the final temperature of a sample of water, if 32 kJ of heat is removed to lower 836
g of water starting with an initial water temperature of 25*C?
The final temperature of a sample of water is 15.89 ⁰C.
What will be the final temperature of the sample of water?
The final temperature of the sample of water is calculated by using the formula for heat capacity of water.
Q = mcΔθ
where;
Q is the heat capacity of the water = 32 kJm is the mass of the water = 836 gc is the specific heat capacity of water = 4200 J/kgCΔθ is the change in the temperature of the water = ?Δθ = Q / mc
The change in the temperature of the sample of water is calculated as follows;
Δθ = ( 32,000 ) / ( 0.836 x 4200 )
Δθ = 9.11 ⁰C
The final temperature of the water when heat is removed is calculated as follows;
T₂ = 25 ⁰C - 9.11 ⁰C = 15.89 ⁰C
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5. If a jump rope is shaken fast enough to produce a wave with a wavelength of 0.5 m and
the crest of the wave passes a specific point 6 times per second, what is the velocity of the
wave?
Answer:
After solving the equation the wave is traveling at a velocity of 3 m/s.
What is velocity?Velocity is a vector quantity that describes the rate at which an object changes its position. It is a measure of both the speed and the direction of an object. Velocity is typically expressed in terms of meters per second (m/s). When an object is in uniform motion, its velocity is constant, meaning that it is not changing in magnitude or direction. If an object is accelerating, its velocity is changing over time, either in magnitude, direction, or both.
The velocity of the wave can be calculated using the following equation:
Velocity = Wavelength x Frequency
In this case, the wavelength is 0.5 m and the frequency is 6 Hz (6 cycles per second). So, the velocity of the wave is:
Velocity = 0.5 m x 6 Hz = 3 m/s
This means that the wave is traveling at a velocity of 3 m/s.
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brandon buys a new seadoo. he goes 12km north from the beach he jumps wakes for 6km to the east what distance did he cover what was his displacement
Total distance covered by Brandon is 18 km and total displacement covered by him is 13.41 km.
Displacement: What is it?The definition of displacement is the changing of an object's position. It has a magnitude and direction and is a vector quantity. It is shown as an arrowhead that travels from the initial location to the end. An object's position changes, for instance, if it moves from position A to position B.
Distance covered by Brandon is-
12 + 6 = 18 km
Displacement covered by Brandon is-
d²= 12² + 6²
= 144 + 36
d²= 180
d = √180
d = 13.41 km.
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A lawnmower is pushed with a force of 72 Newtons at an angle of 40 degrees from the horizontal. How much work is done to the mower if it moves 740 meters?
The work done to the mower is the product of the external force applied on the object and the distance covered by the object which is equal to 40,811 Joules.
What is Work done?Work done on an object can be defined as the product of external force applied on the object and the distance over which the force is being applied on the object. Work is done on an object when a force is applied to an object and the object is moved through certain distance.
From this we can see that the horizontal component of the force:
X-Component (horizontal component):
cos(θ) = x/F
Then,
X= F cos(θ).…..(1)
Now putting the values of F and θ in equation (1) we get,
X = 72 N × cos(40)
X = 72 N × 0.766
X= 55.15 N this is the x-component force
The work done to the mower is:
W = F × d
W = 55.15 × 740
W = 40,811 Joules
The work done to the mower is 40811 Joules.
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Please help with this
A unit vector must have length equal to 1. By calculating the length of (1, 1), we discover that (12 + 12) = 2 = 1.414, which is not the same as 1, is the length.
How do you write unit vector notation?I,J notation is a way to describe a vector. In Cartesian coordinates, a unit vector is a vector with length 1. The unit vectors along the axis are denoted by the letters I and j, respectively. The form ai+bj an I + b j can be used to represent any two-dimensional vector.Numerous operations, including addition, subtraction, and vector multiplication, can be carried out with the aid of the vector form of representation. A=xi+yj+zk is the vector form of the cartesian representation of the three points (x, y, and z). A is equal to x I y j, and z k.Vy = Vyj, Vz = Vz k, and Vx = Vxî. V = Vx + Vy + Vz = Vxî+ Vyj+ Vz k is the result of applying the triangle rule to vector addition twice. The unit vector notation is used in this situation.To learn more about vector refer to:
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How long will a boy sitting near the window of a train travelling at 36 km h see a train passing by in the opposite direction with a speed of 18 km h^-1.The length of the slow- moving train is 90 m.
Answer:
5/18 is used to convert km/hr into m/s
1 km = 1000 m
1 hr = 3600 sec
1 km/hr to m/s
1*1000/1*3600
1000/3600metre/sec
10/36metre/sec
5/18 metre/sec
Explanation:
srry if this is wrong!
An object has 100 J of kinetic energy. If the object’s mass doubles, what is its kinetic energy?
An object has 100 J of kinetic energy. If the object’s mass doubles, then its kinetic energy will be 200J and is denoted as option C.
What is Kinetic energy?This is referred to as the type of energy that it possesses due to its motion and can also defined as the work which is needed to accelerate a body of a given mass from rest to its stated velocity.
The unit is in Joules and the formula is 1/2mv² where m is the mass and v is the velocity of the body or object. In a scenario where the mass is doubled or tripled and the velocity is constant then the kinetic energy will also be doubled or tripled respectively.
For instance, lets assume initial mass is 50kg and the v² is 50m/s then the kinetic energy is 1/2mv² which is 1/2 × 50 × 50 = 1250J. When the mass is doubled it becomes 100kg which 1/2 × 100 × 50 = 2500J which depicts that it was also doubled.
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The options are:
A. 50 Joules.
B. 100 Joules.
C. 200 Joules.
D. 400 Joule
Assuming an object has 100 Joules of kinetic energy. If the object’s mass doubles, its kinetic energy would be equal to: C. 200 Joules.
What is kinetic energy?In Science, kinetic energy can be defined as a type of energy that's possessed by a physical object or body, especially due to its motion or a change in velocity (acceleration).
This ultimately implies that, a physical object or body would gain more of kinetic energy as it falls back toward the Earth because it is in motion.
How to calculate kinetic energy?Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
Where:
K.E represents the kinetic energy.m represents the mass.v represents the speed or velocity.Since the mass of the object doubles, its kinetic energy would be twice that of its initial kinetic energy;
Kinetic energy = 2 × initial kinetic energy
Kinetic energy = 2 × 100
Kinetic energy = 200 Joules.
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Complete Question:
A. 50 Joules.
B. 100 Joules.
C. 200 Joules.
D. 400 Joules.
Net work W would accelerate an object from rest to velocity v. What net work is needed to accelerate the object from rest to velocity 2v?
The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
What is net work done?When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.
Given that, the velocity is 5.0
Time is 2 sec
The given mass is 2.0 kg
First, we calculate the acceleration
Acceleration = v / t = 10 / 5.0 = 2
From Newton's second law, we know that
force = mass x acceleration
F = ma
F = 2.0 x 2 = 4.0 m/s
Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
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The question is incomplete. Your most probably complete question is given below:
What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?
A man drags a 10.0 kg bag of mulch at a constant speed applying a 22.5 N force at a 32-degree angle. What is the friction force acting on the bag?
The
friction
force acting on the bag is 4.36µ.
What is friction force?
The
force
preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
Given,
Force =F=22.5 n
Mass=m= 10 kg
mu=µ=?
(1N= 1kg m/s²)
Gravitational force =g= 9.81 m/s²
As we know,
F= µ*m*g
µ= m*g/F
= 10*9.81/ 22.5
µ= 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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The bag is subject to a friction force of 4.36. A man applies a 22.5 N force at a 32° angle while dragging a 10.0 kilogram bag of mulch at a steady speed.
How much friction is there?Friction refers to the force that resists hard surface, fluid layering, and materials ingredients from gliding past one another. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.
Force = 22.5 N
Mass = 10 kg
⇒ mu = µ (1N= 1kg m/s²)
⇒ g = 9.81 m/s²
As we know, F= µ × m × g
⇒ µ = (m × g)/F
⇒ (10 × 9.81)/ 22.5
⇒ µ = 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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helpp tyy
Which of the following is a way to make magnets?
heating
freezing
pressure
heating or pressing but heating is most appropriate, so the answer is heating.
What is the average time for the toy car to move 1.0 m on cement?
Answer:
24.4
Explanation:
you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4
Gravity on earth is 9.8
Jaydens mass is 50 kilograms his weight is
While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run. 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s Answer in units of J.
Answer:
Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:
[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].
Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].
In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:
[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].
you are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the mesosphere
PLS I RLLY NEED SOME HELP
The things would which would be needed to survive the mesosphere include the following below:
Food and waterOxygen supply.What is a Mesosphere?This is refereed to as the third layer of the atmosphere which is present above the stratosphere and directly below the thermosphere.
It has a low density of gas and water vapor present in the area which is why it is no place for human life as there is a shortage of oxygen and other gases needed for some biochemical reactions in the ecosystem. This is therefore the reason why things such as food, water and oxygen supply is neeeded tio survive in the mesosphere.
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a boy is swinging a toy on apiece of string in a vertical circle. the toy has mass 150g and the radius of circle is 0.8m. a) he swings the toy with a linear velocity 2m/s. will the top move in a circle? explain your answer.
The top move will in a circle because there is tension at the top which will add up with the weight of the toy to maintain equal centripetal force providing the circular motion.
What is tension of the top of the vertical circle?
The tension experienced by the top of the vertical circle is calculated by using the following formula.
T = Fc - W
where;
Fc is the centripetal force of the toyW is the weight of the toyT = mv²/r - mg
where;
m is the mass of the toyv is the linear speed of the toyg is acceleration due to gravityr is the radius of the vertical circleThe tension experienced by the toy at the top of the vertical circle is calculated as follows;
T = ( 0.15 x 2² / 0.8 ) - ( 0.15 x 9.8 )
T = 0.75 - 1.47
T = -0.72 N
Thus, with the negative tension at the top of the vertical circle, the sum of the tension force and the weight of the toy will be equal to the centripetal force to maintain the orbit of the toy in a circular path.
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What is the power of a lightbulb that has a current of 0.480 A at 120.0 V?
Answer:
The power is 57.6 watts
Explanation:
We can use the Electric Power Equation to evaluate the power.
Electric Power Equation
[tex]P=IV[/tex]
[tex]P[/tex] is the power in watts
[tex]I[/tex] is the current in amps
[tex]V[/tex] is the voltage in volts
Our lightbulb has current of 0.480 A and a voltage of 120.0 V.
[tex]I=0.480\\V=120.0[/tex]
Now we can evaluate power.
Substitute our values in for the variables.
[tex]P=0.480*120[/tex]
[tex]P=57.6[/tex]