The hybrid orbital set used by the central atom in no3- is_____ and why?

a. sp
b. sp3
c. SP2
d. sp3d2
e. sp3d

Answers

Answer 1

Answer:

c. SP2

Explanation:

The image in the diagram below shows the structure of  NO₃⁻

Nitrogen is the central atom with the electronic configuration of 1s² 2s² 2p³.

So in its outermost shell, it has 3 electrons and the hybridization is sp²

However,

According to Hund's rule:

The ground state of Nitrogen is;    

1s²    2s²   2p³

↑↓     ↑      ↑  ↑  ↑

At the excited state when it is attached to 3 different oxygen ions, we have:

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑      

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑

                1s²     2s²        2p⁴

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑   ↑

Thus, the 3 sp² orbital lies in a plane and form 3 N - O σ- bond and one π- bond.

The Hybrid Orbital Set Used By The Central Atom In No3- Is_____ And Why?a. Spb. Sp3c. SP2d. Sp3d2e. Sp3d

Related Questions

Scenario Three: Carbon dioxide emissions increase
• Set the carbon dioxide emissions rate to 9.8 gigatons.
• Set the time step size to 10 years.
• Select the step forward button once.
• Increase the carbon dioxide emissions by 0.2 and press step forward.
• Continue stepping forward once, increasing the carbon emissions each time, until you reach 2110.
• Record the data in the table below.

Answers

Maintain carbon dioxide emissions at 9.8 for the rest of scenario one.

2020                               9.8                             58

2030                               9.8                             58.5

2040                               9.8                             58.9

2050                               9.8                             59.1

2060                               9.8                             59.5

2070                               9.8                             59.8

2080                               9.8                             60

2090                               9.8                             60.1    

2100                                9.8                            60.5

2110                                 9.8                            60.9

2.00 mL of a 12.00 M HCL solution was reacted with 0.0450 grams of magnesium.?
Which reactant is the limiting reactant? Mathematically document your answer.

Answers

Answer:

Magnesium Mg will be the limiting reagent .

Explanation:

The limiting reagent is one that is first consumed in its entirety, determining the amount of product in the reaction. When the limiting reagent ends, the chemical reaction will stop.

In other words, the limiting reagent is that reagent that is consumed first in a chemical reaction, determining the amount of products obtained. The reaction depends on the limiting reagent, because the other reagents will not react when one is consumed.

In this case, the balanced reaction is:

Mg + 2 HCl ⇒ MgCl₂ + H₂

You know tha 2.00 mL of a 12.00 M HCl solution was reacted with 0.0450 grams of magnesium.

Being Molarity (M) the number of moles of solute that are dissolved in a certain volume, calculated by the expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]  ( Molarity is expressed in units [tex]\frac{moles}{liter}[/tex])

then the number of moles can be calculated as:

number of moles of solute=molarity* volume

So, being:

molarity= 12 Mvolume= 2 mL= 0.002 L (being 1,000 mL= 1 L)

The number of moles of HCl that react is:

number of moles of HCl= 12 M*0.002 L= 0.024

On the other hand, since the molar mass of magnesium is 24.305 g / mol, then if 0.0450 grams of magnesium react, it indicates that they must react:

[tex]0.0450 grams*\frac{1 mol}{24.305 grams} = 0.00185 moles[/tex]

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), and a simple rule of three as follows: if by stoichiometry 1 mole of Mg reacts with 2 moles of HCl, how much moles of Mg will be needed if 0.024 moles of HCl react?

[tex]moles of Mg=\frac{0.024 moles of HCl*1 moles of Mg}{2 moles of HCl}[/tex]

moles of Mg= 0.012

But 0.012 moles of Mg are not available, 0.00185 moles are available. Since you have less moles than you need to react with 0.024 moles of HCl, magnesium Mg will be the limiting reagent .

What are two cases when a cell must use active transport in order to move materials?

Answers

Answer:

A cell must use active transport in order to move materials in the process Phagocytosis and Pinocytosis

3. What is the total mass of Zinc in ZnCI.?

Answers

136.286 g/mol because it’s zinc chloride

why do we need air? If you know please answer this

Answers

Answer:

I found this on the internet People need to breathe, and so do lots of other animals—and plants! Breathing is part of a process called respiration. During respiration, a living thing takes in oxygen from the air and gives out carbon dioxide.

Explanation:

10 Interesting Things About Air | NASA Climate Kidsclimatekids.nasa.gov › 10-things-air

Your welcome!

to breath

with out air we can't live here

1. A physician ordered 2.0 milligrams tetracycline to be given to a patient. If the tetracycline was available as 0.75 mg/mL of solution, how many milliliters would you give to the patient

Answers

Answer:

2.67 mL

Explanation:

The following data were obtained from the question:

Mass of tetracycline = 2 mg

Density of tetracycline = 0.75 mg/mL

Volume of tetracycline =?

We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:

Density = mass /volume

0.75 = 2 / volume

Cross multiply

0.75 × Volume = 2

Divide both side by 0.75

Volume = 2/0.75

Volume = 2.67 mL

Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL

12.5 mL of 6.0 M KCl is diluted to make a 1.5 L solution. The molarity of the dilution solution is ___ M. (Round atomic masses to the nearest whole number. Include 2 sig figs total in your answer.)

Answers

The molarity of the dilution solution is 0.050 M

Further explanation

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

Dilution formula :

[tex]\tt M_1.V_1=M_2.V_2[/tex]

M₁=6 M

V₁=12.5 ml

V₂=1.5 L=1500 ml

[tex]\tt 6\times 12.5=M_2\times 1500\\\\M_2=\dfrac{6\times 12.5}{1500}=0.05~M\\\\for~sig.fig\rightarrow 0.050~M[/tex]

Many materials, such as rocks, expand (get larger) when they are heated and contract (shrink) when they are cooled. This change
in size can cause cracks to form and break large rocks into smaller pieces.
In this example, what is caused by heating and cooling?
OA. decay
ОВ.
weathering
OC.
erosion
OD
earthquakes

Answers

Answer:

OB: weathering

Explanation:

the cycle of heating and cooling causes stresses called thermal fatigue, this causes the material to break down. In hand, weathering is a physical and chemical process that causes rocks and minerals on the Earth's surface to break down and decompose. Therefore, this matches the process you have described.

Answer:

weathering fun way to imagen it: just imagen u saw ur worst enemie and pretende it is the rock and the wind and ice and water are ur best friends THEN BAM wind and ice and water(ur best friends) make the rock(worst enemie) to dust :D

Calculate molecules in 1dm^3 of oxygen

Answers

Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²

Further explanation

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

1 dm³ of oxygen = 1 L Oxygen

mol Oxygen :

[tex]\tt \dfrac{1}{22.4}=0.045`mol[/tex]

molecules of Oxygen :

n=mol=0.045

No = 6.02.10²³

[tex]\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}[/tex]

3. Theoretically how many grams of magnesium is required to produce to 5.0 g of

Magnesium oxide?

Answers

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

How many moles of KCI would be dissolved in 4 L of water to make a 2 M
solution?
1
A.
mole
B. 2 moles
C. 8 moles
D. 4 moles

Answers

The answer is the second one

Answer:

C. 8 Moles

Explanation:

What is Zaitsev's rule?

Answers

Answer:

dear I think this help u

Explanation:

In organic chemistry, Zaitsev's rule is an empirical rule for predicting the favored alkene product in elimination reactions. While at the University of Kazan, Russian chemist Alexander Zaitsev studied a variety of different elimination reactions and observed a general trend in the resulting alkenes.

Which isomer of 1-bromo-4-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?

Answers

Answer:

See explanation.

Explanation:

Since potassium tert-butoxide is a strong bulky base, we expect that an elimination reaction predominates.

This reaction is expected to occur by E2 mechanism. The cis isomer of  1-bromo-4-tert-butylcyclohexane is known to react faster by E2 mechanism because it fulfills the anticoplanar arrangement required for for E2 mechanism, where the leaving group and adjacent proton must be anti to each other and in the same plane. The trans isomer can not fulfill this requirement.

A 75 mL solid is estimated by a student to be 81 mL. Calculate the percent error.

Answers

Answer:

8 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]

From the question

error = 81 - 75 = 6 mL

actual volume = 75 ml

We have

[tex]p(\%) = \frac{6}{75} \times 100 \\ = \frac{2}{25} \times 100 \\ = 2 \times 4 \\ = 8 \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

8 %

Hope this helps you

Which of the following best explains how the results of Rutherford’s experiment affected Thomson’s widely-accepted atomic model?

Answers

Explanation:

Thomson's suggested the plum pudding model of the atom in which the atomic space is made up of electrons surround by positive charges.

Rutherford in his gold foil experiment revised the plum pudding model of the atom;

He discovered that most of the alpha particles passed through the foil while a few of them were deflected back. To explain this observation, he suggested the atomic model of the atom. In this model, an atom is made up of a small positively charged center where nearly all the mass is concentrated. Surrounding the nucleus is the extranuclear part made up of electrons.


Weathering is a constructive process.
True or false

Answers

Answer: true

Explanation: Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

I need HALP so yea halp mee please

Answers

Carbon: atomic number 6, non-metal, solid, period 2.

Platinum: atomic number 78, metal, solid, group 10, period 6.

Iron: atomic number 26, metal, solid, group 8, period 4.

Hydrogen: atomic number 1, nonmetal, gas, group 1, period 1.

Cobalt: atomic number 27, metal, solid, group 9, period 4.

Arsenic: atomic number 33, metalloid, solid, group 15, period 4.

Hope this helps!! (:

Which statement describes an example of a chemical property of a metal statue?
O It is metal.
O It can tarnish.
OIt is solid.
OIt is shiny.


Answers

Answer:

The answer is "it can tarnish"

Explanation:

The statement describes an example of a chemical property of a metal statue is that it can tarnish.

Chemical properties are defined as those properties which become evident during or after a chemical reaction  has taken place.

These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and used for building up chemical classifications.

The major chemical properties include flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.

Learn more about chemical property,here:

https://brainly.com/question/1935242

#SPJ7

Blair bought a hutch for her desk that was 23 inches long. The box said that the

hutch was 25 inches long. What was the percent error of the hutch?

Answers

Percent error = observed - true/true * 100, observed = 23, true = 25
23-35 = -2/25 = -0.08 = 8% error
I think (or I might had reversed the observed and true)

give the balanced chemical reaction for the preparation of black oxide from blue vitriol​

Answers

Answer:

Blue vitriol is crystal copper sulphate

Explanation:

The black oxide is the higher oxide of Copper i.e Cu. It is also called as tenorite. It is solid black in color. It is formed by heating copper with air.

[tex]$2Cu +O_2 \rightarrow 2CuO$[/tex]

Blue vitriol is the crystalline form of copper sulphate. It is also known as copper (II) sulphate.

When heating, the blue vitriol undergoes various steps of changes to the black oxide of copper.

The chemical reaction is --

[tex]$CuSO_4 \cdot5H_2O \rightarrow CuSO_4\cdot 3H_2O {\rightarrow} CuSO_4\cdot H_2O \rightarrow CuSO_3 \rightarrow CuO +SO_2+O_2[/tex]

Preparation of ethanoic acid from 1,1,1-trichloroethane​

Answers

Anaerobic transformations of 1,1,1-trichloroethane (TCA), 1,1-dichloroethane (DCA), and chloroethane (CA) were studied with sludge from a lab-scale, municipal wastewater sludge digester. TCA was biologically transformed to DCA and CA and further to ethane by reductive dechlorination. TCA was also converted to acetic acid and 1,1-dichloroethene (11DCE) by cell-free extract. 11DCE was further biologically converted to ethene. This pathway was confirmed by transformation tests of TCA, DCA and CA, by tests with cell-free extract, and by chloride release during TCA degradation.

plz help me.......
questiion: Following are the correct statements for actual yield except
1:amount of product obtained in a chemical reaction
2:always less than theoretical yield
3:none
4:product calculated from the balanced chemical equation

Answers

i think it’s 4 ........

at what pressure does water boil at room temperature 25 ec

Answers

Answer:      approximately 100 degrees Celsius

to make a solute dissolve more quikly in a solvent wich whould you do? a. stir it in cold water b.stir it in warm water c.solvent d.lets the solute settle down d. nothing to do with the solute?​

Answers

Answer:

b.stir it in warm water

Explanation:

the slobility will be faster in the high temperture

23.1 g of HCl (a strong acid) is added to water to make 1250 mL of solution. Calculate [H3O+] and pH of the solution

Answers

Answer:

Following are the solution to this question:

Explanation:

[tex]\to HCl \ mol = \frac{23.1 \ g}{36.5 \frac{g}{mol}} = 0.633 \ mole\\\\\\\to HCl \ molarity = \frac{ 0.633 \ mole }{1.25 L} \\\\[/tex]

                            [tex]=0.5064 \ m[/tex]

 [tex]HCl +H_2O \longrightarrow H_3O^{+} + Cl^{-}\\\\\\[/tex]

[tex][H_3O^{+}] =[HCl] \\\\\to [H_3O^{+}] =0.5064 \ m \\\\\to PH =-\log [H_3O^{+}] \\\\[/tex]

          [tex]= -\log (0.5064)\\\\= 0.295 \\\\=0.3[/tex]

60
х
8
у
x=
04
09
O 16

Answers

Answer:

The answer is 16

Explanation:

It needs to be hald of the medium so devide the 2 numbers

What are things animals might do to survive?

Answers

Answer:

Animals need food, water, shelter, and space to survive. Herbivores can live only where plant food is available. Carnivores can live only where they can catch their food. Omnivores can live in many places because they eat both plants and animals.

Animal eat hunt elc..........

How much heat is required to raise the temperature of 91.5 g of water from its melting point to its boiling point? Express your answer numerically in kilojoules. Can someone answer this for me in decimal form?

Answers

Answer:

38.2836 kJ

Explanation:

Mass = 91.5g

Initial Temperature = melting point = 0 C = 273 K (upon converting to kelvin)

Final Temperature = Boiling point = 100 C = 373 K

Heat = ?

They are related by the equation;

H = mCΔT

ΔT = Final - Initial Temperature = 373 - 273 = 100 K

C = specific heat capacity = 4.184 J /gK

H = 91.5 * 4.184 * 100

H = 38283.6 J

To convert to kilojoules, divide by 1000. This leaves us with;

H = 38283.6 / 1000 = 38.2836 kJ

0.1400 mole of sucrose, C12H22O11, contains ________ moles of C.
can you show me the formula and the correct format

Answers

Answer:

it has 12 carbon atoms and 22 hydrogen atoms and 11 oxygen atoms

Explanation:

What is the new concentration for 25mL added to 135mL of .150M

Answers

Answer:

The concentration for 25 mL is 0.81 M

Explanation:

Given data:

Initial volume = 135 mL

Initial molarity = 0.150 M

New volume added = 25 mL

Concentration for 25 mL = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 135 mL = M₂ × 25 mL

M₂ = 0.150 M × 135 mL / 25 mL

M₂ = 20.25 M.mL/25 mL

M₂ = 0.81 M

The concentration for 25 mL is 0.81 M.

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