the is factoring quadratics with a leading coefficient: 5x to the 2 power - 14x + 8

Answer:

The average speed of the car is 90 km/h

Step-by-step explanation:

The rule of the distance id D = v × t, where

∵ A car can travel 450 km in the same time it takes a train to travel

   350 km

→ That means the time of them are equals

∴ Time of the car = Time of the train

→ From the rule above t = [tex]\frac{D}{v}[/tex]

∵ D(car) = 450 km and D(train) = 350 km

∵ The car's average speed is 20 km/h faster than the average speed

   of the train

→ Assume that the average speed of the train is x km/h

∴ v(train) = x km/h and v(car) = (x + 20) km/h

→ Use the rule of the time above to find the time of each one

∵ t(car) = [tex]\frac{450}{(x+20)}[/tex]

∵ t(train) = [tex]\frac{350}{x}[/tex]

∵ t(car) = t(train)

∴ [tex]\frac{450}{(x+20)}[/tex] =  [tex]\frac{350}{x}[/tex]

→ By using cross multiplication

∵ 450 × x = 350 × (x + 20)

∴ 450x = 350(x) + 350(20)

∴ 450x = 350x + 7000

→ Subtract 350x from both sides

∴ 100x = 7000

→ Divide both sides by 100 to find x

∴ x = 70

∵ x represents the average speed of the train

∴ The average speed of the train = 70 km/h

∵ The average speed of the car = x + 20

∴ The average speed of the car = 70 + 20

∴ The average speed of the car = 90 km/h

k-6:5 + 4-k:6= 6k-36+20-5k:30 =

k-16:30

Answer:

Angle 6

Step-by-step explanation:

Angles on opposite ends are congruent if they are formed by the same two lines or in other words, if the two angles are vertical angles.

Answer:

B. [tex]-2\frac{1}{2}[/tex]

Step-by-step explanation:

First you need to get the least common denominator of the left

-7 3/4 and 1/2 the LCD is 4 so...

(1/1) 3/4 = 3/4 (This doesn't have to change since the denominator is already 4)

(2/2) 1/2 = 2/4

Let's make -7 3/4 into an improper fraction = -31/4

Let's make -2 1/4 into an improper fraction = -9/4

Plug back in

-31/4 - 2w + 2/4 [tex]\leq[/tex] -9/4 (collect like terms)

-29/4 - 2w [tex]\leq[/tex] -9/4 (add 29/4 on both sides)

-2w = 5 (divide by -2)

w = -5/2 or -2 1/2

Hope this helps!!

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[tex] \binom{ | - 18 \: \: \: \: \: - 8| }{ |10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: 18| } = \\ [/tex]

[tex] - 18 \times18 - ( - 8 \times 10) = [/tex]

[tex] - 324 + 80 = - 244[/tex]

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Answer:

D

Step-by-step explanation:

Edge

Answer:

a) 2211.6812281 rad/min

b) 352 rpm

Step-by-step explanation:

A bicycle with 24-inch diameter wheels is traveling at 16 mi/h. Find the angular speed of the wheels in radians per minute. ___ radians per minute

How many revolutions per minute do the wheels make? (Round your answer to three decimal places.) ___ revolutions per minute

truck with 24-in.-diameter wheels is traveling at 16 mi/h.

---------

1 mile per hour = 88 feet per minute

16 mi/hr = 1408ft/minute

----------

Each revolution = pi*d feet = 4pi feet

(b) How many revolutions per minute do the wheels make?

rev/min

-------------

Each revolution = pi*d feet = 4pi feet

rpm = 1408 ft/min / 4pi feet

=~ 352 rpm

---------------

(a) Find the angular speed of the wheels in rad/min.

rad/min

-------------

rad/min = rpm*2*pi

= 352 rpm × 2× π

= 2211.6812281 rad/min

So, the wheels make [tex]224.20 \ rev/min[/tex].

Angular speed measures how fast the central angle of a rotating body changes with respect to time. It is expressed as,

[tex]\omega=\frac{\theta}{t}[/tex]

Given that:

Diameter[tex]=24 \ in[/tex]

Radius[tex]=12 \ in[/tex]

First, we have to find the angular speed([tex]\omega[/tex]):

We use the formula,

[tex]v=\omega r[/tex]

Substituting,

[tex]16 \ mi/hr=\omega \times 12 \ in[/tex]   ([tex]\therefore[/tex] [tex]1mile=63360inches, \ and \ 1hour=60min[/tex])

[tex]=\frac{16 \ mi\times \left ( 63360 \ in/mi \right )}{\left ( 1 \ hr\times 60 \ min/hr \right )}[/tex]

[tex]=\omega \times 12 \ in[/tex]

[tex]\Rightarrow 15840 \ in/min=\omega \times 12 \ in[/tex]

[tex]\omega =16896/12\\w=1408 \ rad/min[/tex]

Now, we have to find rev/min:

([tex]\therefore \ 1 \ revolution=2\pi[/tex])

Thus,

[tex]1408 \ rad/min\times1 \ rev/2\pi \ rad=224.20 \ rev/min[/tex]..

Learn more about the topic Angular Speed: https://brainly.com/question/25648667

Answer:

Answer would be (n) = x(x+y)(x-2y) and the (d) = y^2

Step-by-step explanation:

Hope it helps

Answer:

x = 19.8

Step-by-step explanation:

5x - 9 = 90

5x = 90 + 9

5x = 99

x = 19.8

Hope this helped!

Answer:

19.8

Step-by-step explanation:

5x-9=90

Cancel the 9 on both sides, so you get:

5x=90+9

5x=99

x= 19.8

Answer:

The ramp should be 32.9 feet longer.

Step-by-step explanation:

When the ramp is at [tex]6^{o}[/tex] to the ground, its length can be determined by applying the appropriate trigonometric function. Let the length be represented by l, so that;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin [tex]6^{o}[/tex] = [tex]\frac{3.45}{l}[/tex]

l = [tex]\frac{3.45}{Sin 6^{o} }[/tex]

 = [tex]\frac{3.45}{0.10453}[/tex]

 = 33.0048

l = 33.0 feet

When the angle is reduced to [tex]3^{o}[/tex], the length of the ramp would be;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin [tex]3^{o}[/tex] = [tex]\frac{3.45}{l}[/tex]

l = [tex]\frac{3.45}{Sin 3^{o} }[/tex]

 = [tex]\frac{3.45}{0.05234}[/tex]

= 65.9152

l = 65.9 feet

Change in length of ramp = 65.9 - 33.0

                            = 32.9

The ramp should be 32.9 feet longer.

Step-by-step explanation:

1.2+2.3+3.4+⋯+n(n+1)=∑k=1nk(k+1)

=∑k=1n(k2+k)

=∑k=1n(k2)+∑k=1n(k)

=n(n+1)(2n+1)6+n(n+1)2

=n(n+1)6(2n+1+3)

=n(n+1)6(2n+4)

=n(n+1)6[2(n+2)]

=n(n+1)(n+2)3

Answer:

11000 meters

Step-by-step explanation:

1km=1000m

5km=5000m

5000+6000=11000m

Answer:

Hey bro

Step-by-step explanation:

Answer:

KL =9cm

Step-by-step explanation:

IL = KL {being corresponding side of congruent triangle}

or, 3x = x+6

or, 3x-x = 6

or, 2x = 6

or, x = 6/2

or, x = 3cm

Now,

KL = x+6

= 3+6

=9cm

Answer:

2⁵

Step-by-step explanation:

Given:

Number 96

Computation:

96 = 2 x 2 x 2 x 2 x 2 x 3

96 = 2⁵ x 3  

So, Number 2 repeat 5 times

Answer:

x=5

Step-by-step explanation:

1. Distribute

2. Subtract  8 from both sides of the equation.

3. Simplify

4. Divide both sides of the equation by the same term

5. Simplify

6. Solution : = 5

Answer:

Step-by-step explanation:

SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

[tex]tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84[/tex]

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

[tex]sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32[/tex]

Note: Your exponential expression seems a little unclear. Because 27 is not an exponential expression.

But, I am assuming that your exponential expression is:

The reason is that my solution would still clear your concept about this topic, no matter what the question is.

Answer:

The simplified value of the exponential expression is:

[tex]27^{\frac{1}{3}}=3[/tex]

Step-by-step explanation:

Assuming the exponential expression

[tex]\:27^{\frac{1}{3}}[/tex]

[tex]\mathrm{Factor\:the\:number:\:}\:27=3^3[/tex]

[tex]=\left(3^3\right)^{\frac{1}{3}}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0[/tex]

[tex]\left(3^3\right)^{\frac{1}{3}}=3^{3\cdot \frac{1}{3}}[/tex]

[tex]=3^{3\cdot \frac{1}{3}}[/tex]

[tex]=3^1[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a[/tex]

[tex]=3[/tex]

Therefore, the simplified value of the exponential expression is:

[tex]27^{\frac{1}{3}}=3[/tex]

Answer:

[tex]\displaystyle T_6=\frac{448}{729} f^2t^6[/tex]

Step-by-step explanation:

Binomial Theorem

Any power of x + y can be expanded into a sum of the form:

[tex]\displaystyle (x+y)^{n}={n \choose 0}x^{n}y^{0}+{n \choose 1}x^{n-1}y^{1}+{n \choose 2}x^{n-2}y^{2}+\cdots +{n \choose n-1}x^{1}y^{n-1}+{n \choose n}x^{0}y^{n}[/tex]

For any given term k, counted from 0 to n:

[tex]\displaystyle T_k={n \choose k}x^{n-k}y^{k}[/tex]

Note if we have to find the 7th term, we have to use k=6. The expression is:

[tex]\displaystyle \left(4f+\frac{t}{3}\right)^8[/tex]

For n=8, x=4f, y=t/3, k=6:

[tex]\displaystyle T_6={8 \choose 6}(4f)^{8-6}\left (\frac{t}{3} \right )^{6}[/tex]

[tex]\displaystyle T_6={8 \choose 6}(4f)^{2}\left (\frac{t}{3} \right )^{6}[/tex]

[tex]\displaystyle T_6={8 \choose 6}16f^2\frac{t^6}{3^6}[/tex]

Calculate:

[tex]\displaystyle {8 \choose 6}=\frac{8!}{2!\cdot 6!}=28[/tex]

Thus:

[tex]\displaystyle T_6=28\cdot 16f^2\frac{t^6}{729}[/tex]

Simplifying, the 7th term is:

[tex]\mathbf{\displaystyle T_6=\frac{448}{729} f^2t^6}[/tex]

Answer:

Hello! What are the questions? You can type them in Comments and I will edit my answer :)

Step-by-step explanation:

Answer:

what are the questions I don't see any?

Step-by-step explanation:

Answer: 1750J

Step-by-step explanation:

The work done that will be used to loft the barbell and the hanging chain will be:

W1 = (1300 + (1/2 × 600))

= 1300 + 300

= 1600J

The work done that'll be used in lifting the upper part of the chain will be:

W2 = (1/2 × 600) × (1/2 × 1).

= 300 × 0.5

= 150J

Total work down will be:

=W1 + W2

= 1600J + 150J

= 1750J

Answer:

a) +-12-6

b) 70.5 * 18 = 1,269 + 120 = 1389 - 4 = 1385

c) 18

Step-by-step explanation:

Answer:

Step-by-step explanation:

there are a couple ways to find slope

1. Rise over Run Method:

for this method, you use basic counting

to do this, you count the number of x spaces it takes the line to get from one y space to the next

for your line, the run is 3 because it takes 3 x spaces to get from one whole number to the next on the y spaces

you would say the rise is -1 because the line is going down, and it takes 3 x spaces to get the next pot that is on a y-axis increment

so we know the rise is -1 and the run is 3

if you put this into rise/run format, you get 1/-3

so -1/3 is you slope

2. Using the Coordinates

in this line, you see two points

the points are 1. (-1, -1), and 2. (2, -2)

using the coordinates means that you use a formula: [tex]\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]

the y2 is the y value of the second coordinate (-2), the y1 is the y value of the first coordinate (-1)

the x2 is the x value of the second coordinate (2), the x1 is the x value of the  first coordinate (-1)

if you plug these it you get: -2 - (-1) / 2 - (-1)

this can be simplified to -2 + 1 / 2 + 1

and simplified again to -1/3

Qhat ever method you use, you should get the same answer. Using both methods is a good way to check your work.

Answer:

9y+7=2y+98

7y+7=98

7y = 91

y = 13

m<PDV = 2y+98

             = 2(13)+98

             = 26+98

             = 124

Answer:

(1,1)

Step-by-step explanation:

Answer:

For any equation X€R But here is Nothing like it.

Step-by-step explanation:

0 = -x^-4 is wrong to say.

Answer:

-125

Step-by-step explanation:

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To find the inverse first we need to solve the equation for x ,

Then put x instead of y .

_________________________________

[tex]f(x) = 8x + 2[/tex]

[tex]y = 8x + 2[/tex]

[tex]8x + 2 = y[/tex]

Subtract sides 2

[tex]8x + 2 - 2 = y - 2[/tex]

[tex]8x = y - 2[/tex]

Divide sides by 8

[tex] \frac{8x}{8} = \frac{y - 2}{8} \\ [/tex]

[tex]x = \frac{y - 2}{8} \\ [/tex]

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Thus ;

[tex] {f}^{ - 1} (x) = \frac{x - 2}{8} \\ [/tex]

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