The length of a rectangle is 6 inches longer than it is wide. If the area is 160 square inches, what are the dimensions of the rectangle?

From the image that we have here, the translation of the image would be:

In the field of mathematics, this is the type of transformation which would take points in an image and move it in similar distance and direction.

It has to do with the movement of points in an horizontal manner or in a vertical manner.

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The interval which the function is negative is (-∞, -6)

The equation of the function is given as:

[tex]g(x) = \sqrt[3]{x + 6}[/tex]

When the function is negative.

It means that g(x) is less than 0

i.e. g(x) < 0

So, we have:

[tex]\sqrt[3]{x + 6} < 0[/tex]

Take the cube of both sides

x + 6 < 0

Subtract 6 from both sides

x < -6

The above represents a value from negative infinity to -6

i.e.  (-∞, -6)

Hence, the interval which the function is negative is (-∞, -6)

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Answer:

[tex] \frac{7}{9} \times 5 \frac{2}{5} = \frac{21}{5} \\ [/tex]

Step-by-step explanation:

[tex]5 \frac{2}{5} = \frac{5 \times 5 + 2}{5} = \frac{27}{5} \\ [/tex]

[tex] \frac{7}{9} \times \frac{27}{5} \\ [/tex]

[tex] \frac{7 \times 27}{9 \times 5} \\ [/tex]

[tex] \frac{7 \times 3}{5} = \frac{21}{5} \\ [/tex]

Answer:

-x-y=1

-x= 1+y

x= -1-y

3x+2y=0

3(-1-y) +2y=0

-3-3y+2y=0

-3-y=0

y= -3

x= -1-(-3)

x= -1+3

x= 2

Therefore, x= 2 and y= -3

The value of (8 kg 300 g 120 mg) − (3 kg 500 g 480 mg) is; 4 kg 799 g 640 mg

We want to find the value of;

(8 kg 300 g 120 mg) − (3 kg 500 g 480 mg)

First of all, let us convert all units to kg as;

120 mg = 0.00012 kg

300 g = 0.3 kg

Thus;

8 kg 300 g 120 mg = 8 + 0.3 + 0.00012 = 8.30012 kg

Similarly, converting the second expression;

480 mg = 0.00048 kg

500 g = 0.5 kg

Thus;

3 kg 500 g 480 mg = 3 + 0.5 + 0.00048 = 3.50048 kg

Thus, we have;

8.30012 kg - 3.50048 kg = 4.77964 kg

Breaking down this gives;

4 kg 799 g 640 mg

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The sum of squares of the lengths  of the triangle is 130 and the square of the length of the hypotenuse is 65

This is a triangle with 3 sides and one side is called the hypotenuse which faces one of the angles 90°

Analysis:

distance between two points = [tex]\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }[/tex]

distance AB with coordinates A(-2,4) B(5,0) = [tex]\sqrt{(5 - -2)^{2} + (0 - 4)^{2} }[/tex] = [tex]\sqrt{65}[/tex]

distance AC with coordinates A ( -2,4) C(2,6) = [tex]\sqrt{(2--2)^{2} + (6-4)^{2} }[/tex] = [tex]\sqrt{20}[/tex]

distance BC with coordinates B(5,0)  C(2,6) = [tex]\sqrt{(2-5)^{2} + (6-0)^{2} }[/tex] = [tex]\sqrt{45}[/tex]

sum of squares of the lengths = [tex](\sqrt{45} )^{2}[/tex] + [tex](\sqrt{65}) ^{2}[/tex] + [tex](\sqrt{20}) ^{2}[/tex] = 65 + 45 + 20 = 130

the square of the length of the hypotenuse = 65

In conclusion, the sum of the squares of the three length is 130 and the square of the hypotenuse is 65

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its b Answer:

Step-by-step explanation:

The cost of the apples is a function of their weight option (A) is correct because the independent variable (x) is the weight of the apples.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

The options are:

From the graph:

The y-axis is representing the cost(c) of the apples in dollars and

The x-axis is representing the weight(w) of the apples in pounds.

c = f(w)

The independent variable (w) is the weight of the apples

The dependent variable (c) is the cost of the apples

Thus, the cost of the apples is a function of their weight option (A) is correct because the independent variable (w) is the weight of the apples.

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Answer:

-0.16875 or -27/16

Step-by-step explanation:

multiply whole numbers with denominator and add with numerator then divide

so it turns into (9/2) divided by (-8/3)

then use the keep change flip method

(9/2) x (-3/8)

now multiply

-27/16 or -0.16875

Answer:

There is a moderate positive linear association between the variables

Step-by-step explanation:

Since 0.5<r<0.7, there is a moderate positive linear association between the variables. The closer r is to 1, the stronger the positive linear association.

Answer:

-0.33333 (3 is repeating )

Step-by-step explanation:

Answer:

10

Step-by-step explanation: The sum of 3+7 is 10

Answer:

10

Step-by-step explanation:

3+7 is 10

if you add 1 on to 7 three times, we get

8,9,10

(i know this is a troll question lol)

hope this helps!

give brainliest :)

The expression calculates the population x years from now will be given as y = 1024 (0.75)ˣ.

Consider the function:

y = a (1 ± r) ˣ

Where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is a plus sign, then there is exponential growth happening by r fraction or 100r %

If there is a minus sign, then there is exponential decay happening by r fraction or 100r %

The population of sea turtles decreases by 25% per year. The population size is currently 1,024.

Let y be the population of sea turtles and x be the number of years.

Then we have

y = 1024 (1 - 0.25) ˣ

y = 1024 (0.75) ˣ

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The linear function which computes the total cost C (in dollars) to deliver x cubic yards of mulch is C(x) = 44x + 22

Using the slope-intercept form (y = mx +b),

The delivery charge of $22 is a constant and will represent the y-intercept.

The $44 per cubic yard of mulch will represent the slope.

Therefore,

C(x) = 44x + 22

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The greatest whole possible whole number length of the unknown side is 9 inches.

Let us have:

H = biggest side of the triangle

And let we get  A and B as rest of the two sides.

Then we get:

If

[tex]A^2 + B^2 < C^2[/tex]

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

[tex]A^2 + B^2 < C^2[/tex]

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

[tex]A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2[/tex]

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

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Answer:

50cm squared

Step-by-step explanation:

Imagine the width is 'a'

Then the length will be 2a as it's twice as wide as it's long.

The formula for perimeter is 2(L+W)

If we subsitute the algebra/numbers in we get

P = 2(L+W)

30 = 2(2a+a)

30 = 2(3a)

30 = 6a

5 = a

a = 5cm

Then the area is the following

A = LW

A = 2a(a)

A = (2(5))(5)

A = 10(5)

A = 50cm squared

Answer:

Arrange the following number in descendig otder

Answer:

The answer is actually 50

Step-by-step explanation:

Based on the given conditions

formulate:

150 × 25% ÷ (1 - 25%)

150 × 0.35 = 37.5

1 - 0.25 0.75

Rewrite the fraction

3750 = 50

75

The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

Which is the required equation of a line in a point-slope form.

we know that            

The equation of the line into point-slope form is equal to                        

y-y₁ = m(x-x₁)

we have          

(x₁, y₁) = (4, 1/3)

m = 3/4

substitute the given values                

y-y₁ = m(x-x₁)

y - 1/3 = 3/4 ( x - 4)

therefore,

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

Thus, option A is correct.

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Answer:

  W = k·n^(-1/2)

Step-by-step explanation:

When two quantities are proportional, their relationship can be described by the linear equation y = kx, where k is the constant of proportionality.

Saying two quantities are inversely proportional is the same as saying one is proportional to the inverse of the other. Then "inversely proportional to the square root" is the same as "proportional to the inverse of the square root."

__

W is inversely proportional to the square root of n, so we have ...

  [tex]W=k\cdot\dfrac{1}{\sqrt{n}} = \dfrac{k}{n^{\frac{1}{2}}}\\\\\boxed{W=kn^{-\frac{1}{2}}}[/tex]

_____

Additional comment

The rules of exponents let us write the square root as a fractional power, and the inverse as a negative power. Thus our power function ends up with a negative fractional power.

The Power function representing the verbal statement is W = k.[tex]n^{1/2}[/tex].

A power function is in the form of f(x) = kxⁿ, where k = all real numbers and n = all real numbers. You can change the way the graph of a power function looks by changing the values of k and n.

When two quantities are proportional, their relationship can be described by the linear equation y = kx, where k is the constant of proportionality.

Now "inversely proportional to the square root" is the same as "proportional to the inverse of the square root."

According to question,

       W α 1/√n

      W = k/√n

      W = k.[tex]n^{-1/2}[/tex]

Thus, the Power function representing the verbal statement is W = k

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In trigonometry, secant in a right triangle, is the reciprocal of the cosine of an angle symbol: sec while cosine is in a right triangle, is the ratio of the length of the side adjacent to an acute angle to the length of the hypotenuse.

The cosine of an angle is the ratio of the length of the side adjacent to the angle divided by the length of the hypotenuse of the triangle. The cosine of ∠A will be abbreviated as cos ∠A

The secant of x is 1 divided by the cosine of x: sec x = 1 cos x , and the cosecant of x is defined to be 1 divided by the sine of x: csc x = 1 sin x .

Answer:

Step-by-step explanation:

Suppose a right triangle ABC in which

BC=3 units and AC=5 unit and angle B=90 degree

Let x be the missing angle of right triangle

We know that

Hence, there is no difference between using cosine ratio to solve for a missing angle in a right triangle versus using the secant ratio.

A number is divided in the ratio of 5:9. If the first part is 35, the number will be 7.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

A number is divided in the ratio of 5:9. If the first part is 35, then we need to find the number.​

By unitary method

5x = 35

x = 7

Then the other number will be

9x = 9(7)

= 63

Thus, A number is divided in the ratio of 5:9. If the first part is 35, the number will be 7.

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Answer:

The answer is 2 or A

sorry if wrong

Answer:

Using translation concepts, it is found that the equation of the resulting graph is given by:

[tex]y = 2.5(\cos{(4x - 60^\circ)} - 3)[/tex]

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is given by:

[tex]y = \cos{x}[/tex]

The transformations are as follows:

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The attached graph represents the scatter plot of the points

The lists of options are not given. So, I will plot the points and upload the scatter plot as an attachment.

The points are given as:

(1,31), (2,8), (3, 38), (4, 14), (5, 22), (6, 31), (7, 27), (8, 47), (9,34), (10,3), (11, 33), (12, 35)

The above points would be plotted using the following scale:

See attachment for the scatter plot

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Step-by-step explanation:

by using the radical and suds rule

The equation written in standard form represents the number of servings of chicken strips and carrots that Will may have eaten is:

x*110 + y*29 = 333

We know that he consumed a total of 333 calories.

There are x chicken strips and y carrots, so we must have that:

x*110 + y*29 = 333

That is the equation in standard form that we must solve to find how many carrots and how many chicken strips he ate.

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hope you can understand

[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4}v^2\stackrel{\stackrel{b}{\downarrow }}{-16}v\stackrel{\stackrel{c}{\downarrow }}{+7}=0 \qquad \qquad v= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ v= \cfrac{ - (-16) \pm \sqrt { (-16)^2 -4(4)(7)}}{2(4)} \implies v= \cfrac{ 16 \pm \sqrt { 256 -112}}{ 8 } \\\\\\ v=\cfrac{16\pm\sqrt{144}}{8}\implies v=\cfrac{16\pm 12}{8}\implies v= \begin{cases} \frac{7}{2}\\[1em] \frac{1}{2} \end{cases}[/tex]