The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that 5 8 of this force is transmitted to the center connection at C and the rest is equally divided between D and B. Calculate the forces in members BE and BC.

Answers

Answer 1

Answer:

BE = 559lb T

BC = 300lb T

Explanation:

Base on the figure attached, let us first find the load on joint B, C and D

FC = 5/8 * 800 = 500lb

FD = 13/28 * 800 = 150lb

FB is also equal to 150lb

The angle alpha α at joint D will be:

Tan α = 6/12

α = tan ^-1 (0.5)

α = 26.6

by using resolution of forces, resolve the force at that point to horizontal and vertical component.

Horizontal component

Fd + DE sin α = 0

DE sinα  = -Fd

DE = -Fd/sinα

DE = -150/26.6

DE = - 335.4lb

Vertical component

-CD - DEcosα = 0

CD = -DEcosα

CD = -(-335.4)cos26.6

CD = 300lb

So let us do the same at joint C and joint E

At joint C

Horizontal component

Fc + CE = 0

CE = -Fc

CE = -500lb

Vertical component

CD - BC = 0

BC = CD

BC = 300lb T

At joint E

The horizontal component will be:

-CE - DEsinα - BEsinα + EFsinα = 0

-(-500) - (-335.4)sin26.6 - BEsin26.6 + EFsin26.6 + EFsin 26.6

650 - BEsin26.6 + EFsin26.6 = 0

Make BE the subject of the formular

BEsin26.6 = 650 + EFsin26.6

BE = (650 - EFsin26.6)/ sin26.6

BE = 1453.2 + EF ................ (1)

The vertical component

DEcosα - BEcosα - EFcosα = 0

substitute all the parameters

- 335.4cos26.6 - BEcos26.6 - EFcos26.6 = 0

Substitute BE in the equation 1 into the equation above

-300 - (1453.2 + EF)cos26.6 - EFcos26.6 = 0

-1599.7 - 1.789EF = 0

EF = -1599.7 / 1.789

EF = -894.2lb

Substitute EF in equation 1

BE = 1453.2 - 894.2

BE = 559lb T

Therefore the forces in members BE and BC

BE = 559lb T

BC = 300lb T

The Signboard Truss Is Designed To Support A Horizontal Wind Load Of 800 Lb. A Separate Analysis Shows

Related Questions

Assume you have a steel beam that is 20 feet long and carries a concentrated load of 500 pounds at a distance of 15 feet from Reaction (R ). Reaction (R ) is pinned 5 feet from the load. What are the values in lbs for R and R ? A. 475 and 25 B. 500 and 00 C. 375 and 125 D. 125 and 375

Answers

Answer:

The answer is "Option D".

Explanation:

[tex]\to \epsilon_T= 0\\\\\to R+R_1=500 \ lb \\\\\to \epsilon \ M_{pin} > 0\\\\\to -R \times 20 +(500 \times 5) =0\\\\\to 2500 =20R\\\\\to 20R= 2500\\\\\to R= \frac{2500}{20}\\\\\to R= \frac{250}{2}\\\\\to R= 125 \ lb \\\\\to R_1 =500-125\\[/tex]

         [tex]=375 \ lb \\[/tex]

Match each titration term with its definition.
Process of slowly adding a solution to react with another solution and determine the Choose... concentration of one of the solutions tased on the reaction between them
Solution of an unknown concentration that has another solution slowly added to it Choose...
When the required amount of one solution has been added to the second solution to Choose... complete the reaction
Solution of known concentration that is slowly added to a solution of unknown Choose... concentration
Glassware that allows a solution to be precisely and slowly added to another solution Choose...
A reagent added to the analyte solution that changes color when the reaction is Choose... complete

Answers

Answer:

1) titration

2) titrand

3) equivalence point

4) titrant

5) Burette

6) Indicator

Explanation:

The process in which a known volume of a standard solution is added to another solution so that the standard solution can react with the solution of unknown concentration such that its concentration is determined  can be referred to as titration.

The solution which is added to another solution  is called the titrant.  The titrand is the solution of unknown concentration

A burette is a glassware used to slowly add a known volume of the titrant to the titrand.

The indicator used signals the point when the reaction is complete by a color change. At this point, a stoichiometric amount of titrant has been added to the titrand. This is also referred to as the equivalence point.

Why do the changes to the mass of the planet NOT AFFECT the orbital path of the Planet?

Answers

Answer:

changes of Mass affect the planet because... I'm sorry If this didn't help.

The orbital path of the planet is determined by the balance of the gravitational pull of that planet and the larger body it orbits. Mass does not change the orbital path because the mass that determines this “balance” is the mass of the body the planet is orbiting, not the mass of the planet itself

.
Describe a ways car manufacturers try to reduce drag and why.

Answers

Answer:

Aerodynamic drag can be reduced by altering the density of the air and the vehicle speed, but these factors are not easily controlled. Instead, to reduce drag, car manufacturers can make the height and width of the front of the car smaller. ... This shape reduces drag and the forces that try to propel the car backwards.

Answer:

Car manufacturers can make the height and width of the front of the car smaller.

Explanation:

The shape reduces drag and the forces it to propel the car backwards.

Don't break or crush mercury-containing lamps because mercury powder may be released.
A) TrueB) False

Answers

A.

It would be released without a doubt so be careful!

Hope this helps :)

Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.

Answers

This question is incomplete, the complete question is;

Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.

The 125-mm-diameter smooth pipe is transporting SAE 10W-30 oil with ρ=920 kg/m3 and µ=0.2 N.s/m2 .

Answer: the greatest pressure drop allowed is 14247 Pascals

Explanation:

LAMINAR FLOW INF PIPE

greatest pressure drop

(P1 - P2) = pressure drop

(P1 - P2) = 32uvl / D²

so (P1 - P2) ∝ V

greatest pressure drop is only at very high velocity

now Re (Reynold Number = svd / u

Re ∝ V

so velocity is high when Re is high

Re = 2000 ( Highest for LAMINAR)

Re = 2000 = svd / u

now in the question we were given that

s = 920 kg/m³, u = 0.2 NS/m², d = 125mm = 0.125m, l = 10m

so we substitute;

2000 = (920 × v × 0.125) / 0.2

v = 3.48 m/s

now pressure drop = (P1 - P2) = 32UVL / d²

we substitute

(P1 - P2)  = (32(0.2) (3.48)(10)) / (0.125)²

(P1 - P2) = 14247 Pascals

therefore the greatest pressure drop allowed is 14247 Pascals

What are the differences between separately and shunt DC motor?

Answers

A separately excited DC motor and a DC shunt motor are similar in construction and in all aspects except the way in which the field winding is excited in both the machines.
In a separately excited DC motors, field winding is excited from a separate source, and the armature is excited from another supply. But in a DC shunt motor the armature and field windings connected in parallel across a supply.
In separately excited motors the flux in the filed winding is independent on the load, but in the case of a shunt motor it depends on the load on the motor.

Hope this helps!

Consider a W21x93. Determine the moment capacity of the beam. Assume the compression flange is not laterally braced and that the unbraced length is 15 feet. Assume Cb

Answers

Answer:

The answer is "828.75"

Explanation:

Please find the correct question:

For W21x93 BEAM,

[tex]Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3[/tex]

For A992 STREL,

[tex]F_y= 50\ ks[/tex]

Check for complete section:

[tex]\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}[/tex]

Design the strength of beam =[tex]\phi_b Z_x F_y\\\\[/tex]

                                                [tex]=0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\[/tex]

calculate the magnitude of the force acting on the pin at D. Pin C is fixed in DE and bears against the smooth slot in the triangular plate.

Answers

Answer:

hello your question lacks the required diagram attached below is the diagram

answer : 58.47 N

Explanation:

The magnitude of the force acting on the Pin D

Fd = [tex]\sqrt{Dx^2 + Dy^2}[/tex]

    = [tex]\sqrt{16.80^2 + 56^2}[/tex]

    = 58.465 N

Dx = 16.80 N

Dy = 56 N

hello attached below is the detailed solution

g At this party, is the fact that a person is from South America independent of that person being majoring in biomedical engineering?

Answers

Answer:

Yes, this is completely independent.

Explanation:

Yes, this is completely independent. Even though there are no South American individuals that are majoring in biomedical engineering in this party it is still a completely independent factor. The origin of birth of an individual does not tie them to a specific degree or field of expertise, therefore a South American individual can study anything they want including mechanical engineering, electrical engineering, or biomedical engineering.

Timken rates its bearings for 3000 hours at 500 rev/min. Determine the catalog rating for a ball bearing running for 10000 hours at 1800 rev/min with a load of 2.75 kN with a reliability of 90 percent.

Answers

Answer:

C₁₀ = 6.3 KN

Explanation:

The catalog rating of a bearing can be found by using the following formula:

C₁₀ = F [Ln/L₀n₀]^1/3

where,

C₁₀ = Catalog Rating = ?

F = Design Load = 2.75 KN

L = Design Life = 1800 rev/min

n = No. of Hours Desired = 10000 h

L₀ = Rating Life = 500 rev/min

n₀ = No. of Hours Rated = 3000 h

Therefore,

C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3

C₁₀ = (2.75 KN)(2.289)

C₁₀ = 6.3 KN

What are the two most important things to remember when at the end of your interview?

Answers

Answer:1. Ask questions2. Thank the interviewer for their time Explanation:

1. When the interviewer asked if you have any questions at the end of the interview don't say no. You should always say yes your interviewer is expecting you to ask a few good questions before ending the interview.

2. Always thank the interviewer for their time and effort to interview you. This would look very good for you and its a nice way to help wrap up the interview.

Construct a Mohr circle for the stress element at A in problem 2. Using ruler and compass, draw the Mohr circle to the scale. Draw the stress element for principal normal stresses correctly oriented and show the stresses acting on it. Do the same for the element of maximum shear stress

Answers

Answer:

hello your question is incomplete attached below is the missing diagram to the question and the detailed solution

Answer : principal stresses : 0.82 MPa, -33.492 MPa

              shear stress = 17.157 MPa

              ∅ = 9.09 ≈ 10°

Explanation:

The principal stress ( б1 ) = 0.82 MPa

                                 ( б2 ) = -33.492 MPa

The shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

attached below is the detailed solution and the Mohr's circle

Seth wants to build a wall of bricks. Which equipment will help him in the process?
OA masonry pump
OB. hacksaw
OC. mortar mixer
OD. pressurized cleaning equipment

Answers

Answer:

it's B I think

Explanation:

hopefully that helps you

Answer: C

Explanation: A mortar mixer is the equipment that would help Seth in the process of building a wall of bricks. A mortar mixer is used to mix the mortar, which is the binding material used to hold the bricks together. It ensures the mortar is properly mixed to the right consistency for laying the bricks.

Describe the blade design for a wind turbine that you would choose. Why did you choose this design?

Answers

Answer: aerofoil type blades

Explanation: they are more difficult to make but offer better performance and higher rotational speeds making them ideal for electrical energy generation.

A spherical ball has 3cm internal diameter and its inner surface temperature is 250˚C and the outer surface temperature is 30˚C. Calculate the outer diameter of the ball if the heat loss from the ball is 1600W and has 2.75W/m.˚C thermal conductivity.

Answers

Answer:

The outer diameter of the ball is 6.2138 cm

Explanation:

The formula to apply is ;

Heat loss ,

[tex]Q/t=kA*\frac{( T_1-T_2)}{d}[/tex]

where ;

Q/t=total heat loss from the ball = 1600 w

k=coefficient of heat transmission through the ball= 2.75 W/m.˚C

A=area in m² of the ball with the coefficient of heat transmission

T₁=Hot temperature

T₂=Cold temperatures

d=thickness of the ball

Area of spherical ball using internal diameter, 3cm= 0.03 m will be

Radius = half the diameter = 0.03/2 = 0.015

Area = 4 *π*r²

Area = 4*π*0.015² = 0.002827 m²

Apply the formula for heat loss to get the thickness as:

1600 = {2.75 * 0.002827 *(250-30 ) }/d

1600 =1.711/d

1600d = 1.711

d=1.711/1600 = 0.001069 m

d= 0.1069

Using internal radius and the thickness to get outer radius as;

3 + 0.1069 = 3.1069 cm

Outer diameter will be twice the outer radius

2*3.1069 = 6.2138 cm

Type the correct answer in the box. Spell all words correctly.
Anne works for NASA. She was responsible for developing an aerodynamic design of a space shuttle. What type of engineer is she?
Anne is a(n)
engineer.

Answers

Answer:

Anne is a mechanical engineer.

Explanation:

There are many different types of engineers (mechanical, industrial, electrical, chemical and civil) around the world. When a job involves designing machines, it falls under mechanical engineering. Such job requires a person to be as creative as possible, so he/she can come up with an innovative design that will be reasonable when used.

Designing machines includes spacecrafts. Therefore, Anne is a mechanical engineer working for NASA.

A steam pipe passes through a chemical plant, where wind passes in cross-flow over the outside of the pipe. The steam is saturated at 17.90 bar and you can assume that the resistances to heat transfer inside the pipe and of the pipe itself are minimal, so that the outside surface temperature of the pipe is equal to the saturation temperature of the steam. The pipe is stainless steel and has an outside diameter of 6.75 cm and a length of 34.7 m. The air flows over the pipe at 7.6 m/s and has a bulk fluid temperature of 27 °C.
A. What is the rate of heat transfer from the pipe to the air?
B. would your answer change if the air flow direction changes to parallel flow? If so, calculate that q as well.

Answers

Answer:

a) the rate of heat transfer from the pipe to the air is 23.866 watts

b) YES, the rate of heat transfer changes to 3518.61 watt

Explanation:

Given that:

steam is saturated at 17.90 bar.

the pipe is stainless steel and has an outside diameter of 6.75 cm

length = 34.7 m

Air flows over the pipe at 7.6 m/s

Bulk fluid temperature of 27°C

we know that

hD/k = 0.028 (Re)^0.8 (Pr)^0.33

Outside diameter of pipe = 6.75 cm

length of the pipe = 34.7 m

velocity of air = 7.6 m/s

Cp of air = 1.005 kJ/Kgk

viscosity of air = 1.81 × 10⁻⁵ kg/(m.sec)

thermal conductivity of air = 2.624 × 10⁻⁵ kw/m.k

so as

hD/k = 0.028 (Re)^0.8 (Pr)^0.33

hD/k = 0.028 (Dvp / u)^0.8 (Cpu / k)^0.33

(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([0.0675 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))

h = 0.0414 w/m².k

a)

Now to find the rate of heat transfer Q

Q = hAΔT

Q = 0.0414 × (2π × 0.03375 × 34.7) × (105.383 - 27)

Q = 23.866 watts

therefore the rate of heat transfer from the pipe to the air is 23.866 watts

b)

Now the flow direction changes to parallel flow, then

(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([34.7 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))

h = 6.1036 w/m².k

so from the steam table, saturated steam at 17.70 bar, temperature of steam will be 105.383°C

so to find the rate of heat transfer Q

Q = hAΔT

Q = 6.1036 × (2π × 0.03375 × 34.7) × (105.383 - 27)

Q = 3518.61 watt

Therefore the rate of heat transfer changes to 3518.61 watt

Match each titration term with its definition.
Process of slowly adding a solution to react with another solution and determine the Choose... concentration of one of the solutions tased on the reaction between them
Solution of an unknown concentration that has another solution slowly added to it Choose...
When the required amount of one solution has been added to the second solution to Choose... complete the reaction
Solution of known concentration that is slowly added to a solution of unknown Choose... concentration
Glassware that allows a solution to be precisely and slowly added to another solution Choose...
A reagent added to the analyte solution that changes color when the reaction is Choose... complete

Answers

Answer:

1) titration

2) titrand

3) equivalence point

4) titrant

5) Burette

6) Indicator

Explanation:

The process of adding a known volume a standard solution to another solution to react with it in order to determine the concentration of the unknown solution is known as titration.

The solution to which another solution of known concentration is added is called the titrand while the solution of known concentration is called the titrant.

A burette is a glassware used to slowly add a known volume of the titrant to the titrand. An indicator shows the point when the reaction is complete by a color change. This is the point when the required amount of one solution has been added to the second solution. It is also called the equivalence point.

I. The process of slowly adding a solution to react with another solution and determine the concentration of one of the solutions based on the reaction between them: Titration.

II. A solution of an unknown concentration that has another solution slowly added to it: Analyte.

III. When the required amount of one solution has been added to the second solution to complete the reaction: Endpoint.

IV. A solution of known concentration that is slowly added to a solution of unknown concentration: Titrant.

V. A glassware that allows a solution to be precisely and slowly added to another solution: Burette.

VI. A reagent added to the analyte solution that changes color when the reaction is complete: Indicator.

Titration is also referred to as titrimetry or volumetric analysis and it can be defined as a chemical process in which a solution of known concentration is slowly added to a solution of unknown concentration, in order to determine the concentration or quantity of the analyte (solution of an unknown concentration)

For example, titration can be used to determine the concentration of a basic solution by titrating it with an acid solution of known concentration that is required to neutralize the basic solution.

In Chemistry, the following terms and apparatus are used for the titration of solutions:

Analyte.Indicator.Burette.Ring stand.Endpoint.Titrant.Conical flask.

Read more: https://brainly.com/question/23307058

Which of the following is considered a bated standard

Answers

Answer:

is it multiple choice or....

Common car loan duration

Answers

Answer:

In 2019, the average term length was 69 months for new cars and 65 months for used vehicles. Most car loans are available in 12 month increments, lasting between two and eight years. The most common loan terms are 24, 36, 48, 60, 72, and 84 months, according to Autotrader

Explanation:

Which color of white light bends the most when it is refracted by a prism? red green yellow orange

Answers

The color of white light bends the most when it is refracted by a prism is green after the violet.

Why green bents towards the light?

The shorter the wavelength of the mild, the greater its miles refracted. As a result, crimson mild is refracted the least, and violet mild is refracted the most - inflicting the colored mild to unfold out to shape a spectrum.

The hues of white mild withinside the order of lowering wavelength are crimson orange-yellow inexperienced blue indigo violet. Fro the listing we are given withinside the alternatives inexperienced has the shortest wavelength than others. Therefore inexperienced will bend the most.

Read more about the refracted :

https://brainly.com/question/1360744

#SPJ2

Stack memory is implemented as a stack data structure. Provide the sequence of push and pop operations on stack memory when the collatz method (provided below) is called with n = 5. Note that an enqueue and dequeue is associated with a method call. For example, the first and last operations in the sequence should be push(collatz(4)) and pop(collatz(4)) respectively. public void collatz(int n) { if (n == 1) return; else if (n % 2 == 0) collatz(n / 2); else collatz(3*n + 1); }

Answers

Answer:

attached below is the solution

Explanation:

hello  attached below is the sequence of push and pop operations on stack memory

For The collatz method below

public void collatz(int n) {

if (n == 1) return;

else if (n % 2 == 0)

collatz(n / 2);

else collatz(3*n + 1); }


Help!!
Which of the following describes the first and foremost guideline in dimensioning?
A. Legibility
B. Measurement
C. Accuracy
D. Sketching

Answers

Answer:

it should be accuracy

Explanation:

Answer:

option C

Explanation:

The insulator is the connection between the grounded circuit conductor and the equipment grounding conductor at the service.

Answers

The answer to your question is correct/ true

What motivated software engineers to move from the waterfall model to the incremental or spiral model

Answers

Answer:

1. They needed to develop multiple components in software programs.

2. The ability to overlap the development to be more evolutionary in nature.

3. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.

Explanation:

Software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

In SDLC, a waterfall model can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.

An incremental model refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.

Also, a spiral model can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.

What motivated software engineers to move from the waterfall model to the incremental or spiral model is actually due to the following fact;

They needed to develop multiple components in software programs. The ability to overlap the development to be more evolutionary in nature. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.

Suppose an underground storage tank has been leaking for many years, contaminating a groundwater and causing a contaminant concentration directly beneath the site of 0.30 mg/L. The contamination is flowing at the rate of 0.5 ft/day toward a public drinking water well 1 mile away. The contaminant degrades with a rate constant of 1.94 x 10^-4 1/day. Draw a picture of the system. Estimate the steady-state pollutant concentration expected at the well. If the slope factor is 0.02 (mg/kg-day)^-1.

Required:
Estimate the cancer risk for an adult male drinking the water for 10 years.

Answers

Answer: the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶

Explanation:

firstly, we find the time t required to travel for the contaminant to the well;

Given that, contamination flowing rate = 0.5 ft/day

Distance of well from the site = 1 mile =  5280 ft

so t = 5280 / 0.5 = 10560 days

k is given as 1.94 x 10⁻⁴ 1/day

next we find the Pollutant concentration Ct in the well

Ct = C₀ × e^-( 1.94 x 10⁻⁴ × 10560)

Ct = 0.3 x e^-(kt)  

Ct= 0.0386 mg/L

next we determine the chronic daily intake, CDI

CDI =  (C x CR x EF x ED) / (BW x AT)

where C is average concentration of the contaminant(0.0368mg/L), CR is contact rate (2L/day), EF is exposure frequency (350days/Year), ED is exposure duration (10 years), BW is average body weight (70kg).

now we substitute  

CDI = (0.0368 x 2 x 350 x 10) / ((70x 365) x 70)

= 257.7 / 1788500

= 0.000144 mg/Kg.day

CDI = 1.44 x 10⁻⁴ mg/kg.day  

Finally we calculate the cancer risk, R

Slope factor SF is given as 0.02 Kg.day/mg

Risk, R = I x SF

= 1.44 x 10⁻⁴ mg/kg.day  x 0.02Kg.day/mg    

R = 2.88 × 10⁻⁶

therefore the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶

A closed system of mass 20 kg undergoes a process in which there is a heat transfer of 1000 Q6: ki from the system to the surroundings. The work done on the system is 200 kl. If the initial 5 specific internal energy of the system is (250+R:) kl/kg, what is the final specific internal energy, in kj/kg? Neglect changes in kinetic and potential energy:

Answers

The final specific internal energy : 190 kJ/kg

Further explanation  

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

The equation is:  

[tex]\tt E_{in}-E_{out}=\Delta E~system\\\\\Delta E=\Delta U+\Delta KE+\Delta PE\\\\\Delta U=m(U_2-U_1)\\\\Q-W=\Delta U+\Delta KE+\Delta PE[/tex]  

 

Energy owned by the system is expressed as internal energy (U)  

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

A closed system of mass 20 kg⇒m=20 kg

Heat transfer of 1000 kJ from the system to the surroundings⇒Q=-1000 kJ

The work done on the system is 200 kJ⇒W=+200 kJ

The initial specific internal energy of the system is 250 kJ /kg⇒U₁ = 250 kj/kg

Neglect changes in kinetic and potential energy⇒ΔKE+ΔPE=0, so

Q-W = ΔU

Input in equation

[tex]\tt -1000-200=20(U_2-250)\\\\-1200=20U_2-5000\\\\3800=20U_2\\\\U_2=190~kJ/kg[/tex]

Due within next 5 minutes... Should scientists be allowed to research human cloning? Explain and defend your answer.

Answers

Answer:

science is hard but human cloning this is legendary but still its up to the government but me i would allow this because its something that science can upgrade to

Explanation:

A transmitter has an output power of 0.1mW while the fiber has coupling loss of 12dB, attenuation of
6dB/km for the length of 500m. The link contains two connectors of 2dB average loss. The receiver has a
minimum acceptable power ( sensitivity) of -35dBm. The designer has allowed a 4dB margin. Based on
the given information,
a) Calculate total link loss
b) Determine the receiver's sensitivity
c) Identify this system is good practice or not​

Answers

The answer is C identify this system is good practice or not
Other Questions
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