the structure of carbon dioxide using dots and crosses​

Answer:

false

Explanation:

it happens in light-independent reactions

Answer:

a lot but im pretty sure if u just take avogadros number and multiply it by 9.8 u get the answer

Explanation:

There are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl. Details about number of atoms can be found below.

The number of atoms of a compound can be calculated by multiplying the number of moles of the substance by Avogadro's number.

no of atoms = no of moles × 6.02 × 10²³

According to this question, there are 9.8 moles of NaCl.

no of atoms = 9.8 × 6.02 × 10²³

no of atoms = 5.896 × 10²⁴

Therefore, there are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl.

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Answer:

ΔH = 283kJ/mol

Explanation:

Using Hess's law, the ΔH of a reaction is equal to the sum of ΔH° of products times its coefficient subtracting the sum of ΔH° of reactants times its coefficient. Replacing, for the reaction:

ΔH = 2ΔH°C + 2ΔH°D - (2ΔH°A+ΔH°B)

ΔH = 2*193kJ/mol + 2*-493kJ/mol - (2*-235kJ/mol+ (-413kJ/mol)

Answer:

All 3

Explanation:

Decomposers break apart complex organic materials into more elementary substances: water and carbon dioxide, plus simple compounds containing nitrogen, phosphorus, and calcium. All of these components are substances that plants need to grow.

Some decomposers are specialized and break down only a certain kind of dead organism. Others are generalists that feed on lots of different materials. Thanks to decomposers, nutrients get added back to the soil or water, so the producers can use them to grow and reproduce.

Answer:

neom, sodium bicarbonate

Answer:

270. mL

General Formulas and Concepts:

Acid-Base Titrations

Dilution: M₁V₁ = M₂V₂

Explanation:

Step 1: Define

Identify

[Given] V₂ = 629.1 mL

[Given] M₂ = 11.2 M

[Given] M₁ = 26.1 M

[Solve] V₁

Step 2: Find Stock Volume

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs as our lowest.

269.959 mL ≈ 270. mL

Answer:

I am sure it is D or C. have a nice day

Answer:

80.7 °C

Explanation:

Step 1: Given and required data

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = Q / c × m + T₁

T₂ = -1,200 J / (4.184 J/g.°C) × 20.0 g + 95.0 °C = 80.7 °C

Answer:

81 C

Explanation:

Answer:

The second student with mass 70kg has more momentum

Explanation:

Using the formula:

p = m × v

Where;

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

According to this question, two students are running in a cross country race.

Student 1 has the following; m = 60kg, v = 7m/s

Student 2 has the following; m = 70kg, v = 7m/s

Using p = mv

Student 1, p = 60 × 7 = 420 kgm/s

Student 2, p = 70 × 7 = 490 kgm/s

From the result of the above calculations, student 2 with mass 70kg has more momentum.

Mass and volume are two factors that affect that density of matter!

Answer:

divergence of continental crust

Explanation:

Answer:

NITRATE ION

Explanation:

Answer:

pure

Explanation:

Distilled water is a form of pure water, hence it is not bad or harmful to drink distilled water.

Answer:

I think it's pure. hope this helps◉‿◉

OPTION C is the correct answer.

Answer: The mass of water produced is 27 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of pentane = 18 g

Molar mass of pentane = 72.15 g/mol

Plugging values in equation 1:

[tex]\text{Moles of pentane}=\frac{18g}{72.15g/mol}=0.250 mol[/tex]

The given chemical equation follows:

[tex]C_5H_{12}+8O_2\rightarrow 5CO_2+6H_2O[/tex]

By the stoichiometry of the reaction:

If 1 mole of pentane produces 6 moles of water

So, 0.250 moles of pentane will produce = [tex]\frac{6}{1}\times 0.250=1.5mol[/tex] of water

Molar mass of water = 18 g/mol

Plugging values in equation 1:

[tex]\text{Mass of water}=(1.5mol\times 18g/mol)=27g[/tex]

Hence, the mass of water produced is 27 g

Answer:

See explanation

Explanation:

Electro negativity refers to the ability of an atom in a molecule to attract the shared pair of electrons of a bond closer to itself.

In a molecule, the polarity of bonds is determined by the relative electro negativity of the bonding atoms. If the difference in electro negativity between the atoms in a bond is significant, such a bond is polar in nature e.g H-Cl, H-Br, C-F, etc.

However, the occurrence of polar bonds in a molecule alone does not guarantee the polarity of the molecule. The polarity of a molecule also depends on the shape of the molecule since dipole moment is a vector quantity.

A molecule is polar when the resultant dipole moment which is determined by the shape of the molecule is non zero.

For instance, CO2 contains two polar C-O bonds but the molecule is non polar because the two dipole moments cancel out. Also, symmetrical molecules are nonpolar irrespective of the presence of polar bonds in the molecule.

Answer:

Explanation:

Answer:

1.08 M

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 mL

Initial concentration (C₁) = 6 M

Final volume (V₂) = 250 mL

Final concentration (C₂) =?

The final concentration of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

6 × 45 = C₂ × 250

270 = C₂ × 250

Divide both side by 250

C₂ = 270 / 250

C₂ = 1.08 M

Therefore, the final concentration of the solution is 1.08 M.

Answer:

The answer will be Number C that is positively and part of the nucleus

Answer:

Part C best describes a proton, as it is positively charged and part on the nucleus

Answer:

Option A.

Explanation:

1 mol of anything contains 6.02×10²³ particles.

We know that 1 mol of oxygen gas contains 2 moles of O.

1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.

By the way, the mass for 1 mol of O₂ may be:

Option A  →  16 g/mol . 2 mol

32 g

Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.

Another example can be:

1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.

so dfhhdjdjjfjfjjdjdjdj

Answer:

nsksbsjensnsjeiejensbsksks

Answer:

the amount of trials in an experiment

Answer:

A

not sure of answer ndhfhfjfjcjfjfj

Answer:

C-HOC6H12OH and HOOCCH.COOH

hexane-1,6-diol and propane-1,3-dioic acid

Answer: hello your question has some missing data attached below is the missing data

answer:

i) volumetric flow rate = 168 m^3/h = 5932.86 ft^3/h

ii) n = 582.4 Ib mole/hr

Explanation:

Given that the volumetric flow rate is a Linear function of R

V = ∝R + β

where; R1 = 15 , V1 = 40 m/h , R2 = 50, V2 = 96 m/h  input values into equation above

40 = 15∝ + β ----- ( 1 )

96 = 50∝ + β ----- ( 2 )

resolve equations 1 and 2 simultaneously

56 = 35∝ + 0

∴ ∝ = 56 / 35 = 1.6

back to equation 1:  40 = 15(1.6) + β    ∴ β = 40 - 24 = 16

hence ; V = 1.6(95) + 16 = 168 m^3/h = 5932.86 ft^3/h

lets assume room temperature

density of water = 62.4 Ib/ft^3

molecular weight of water = 18

therefore n = ( 62.4 / 18 ) * 168

                  = 582.4 Ib mole/hr

Answer:

-3169

Explanation:

trust the process

-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.

Explanation:

Given:

The reaction of combustion of [tex]C_6H_6(g)[/tex] along with enthalpies of formation of the compounds.

To find:

The enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex]  completely reacts with oxygen.

Solution:

[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g)[/tex]

Enthalpy of the reaction:

[tex]\Delta H^o_{rxn}=\sum [\Delta H^o_{f,products}]-\sum [\Delta H^o_{f,reactants}]\\=[12mol\times \Delta H^o_{f.CO_2(g)}+6mol\times \Delta H^o_{f,H_2O(g)}]-[2 mol\times \Delta H^o_{f.C_6H_6(g)}+15\times \Delta H^o_{f,O_2(g)}]\\=[12mol\times (-393.50 kJ/mol)+6mol\times (-241.82 kJ/mol)]-[2mol\times 82.90kJ/mol+15mol\times 0 kJ/mol]\\=-6338.72 kJ[/tex]

[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g).\Delta H^o_{rxn}=-6338.72 kJ[/tex]

When 1 mole of [tex]C_6H_6(g)[/tex]  reacts with oxygen gas:

[tex]=\frac{\Delta H^o_{rxn}}{\text{2 mol of } C_6H_6}\\=\frac{-6338.72 kJ}{2 mol}\\=-3169.36 kJ/mol\approx -3169 kJ/mol[/tex]

-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.

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