The temperature is 0 degrees, every hr it's dropping 3 degrees the temperature is -6 degrees at a certain time. How mush did the temperature decrease, how many hrs did it take to be at -6 degrees

Answer:

151.2

Step-by-step explanation:

7x12=84

84/3=28

28x5.4=151.2

Answer: Joe earns a monthly salary of 250 plus a commission on his total sales. Last month his total sales were $7,289 and he earned a total of $1,275. What is his commission rate?

Step-by-step explanation:  

250 + $7,289 + $1,275 = 8814

Answer:

∠1and∠5

Step-by-step explanation:

Hello There!

The image shown below shows an example of what corresponding angles look like

Properties of corresponding angles

angles 2 and 4 are on the same side of the transversal however they are supplementary angles not congruent

angles 2 and 4 are an example of adjacent angles therefore this is not the answer

angles 1 and 5 are on the same side of the transversal and they are most definitely congruent

This might be our answer but lets check the last answer just to be sure

Angles 3 and 6 are congruent but they are not on the same side of the transversal

angles 3 and 6 are an example of alternate interior angles therefore this is not the correct answer

So we can conclude that angles 1 and 5 are corresponding angles

The coefficient matrix is a square matrix with dimensions equal to the number of variables in the system of equations.

The coefficient matrix is a matrix of the coefficients of the variables in a system of linear equations.

Now, we arrange these coefficients in a matrix format by placing them row-wise. This gives us the coefficient matrix:

[tex]2x + 3y + 3x3 = 20[/tex]

[tex]3x + 5y + 2x3 = 9[/tex]

[tex]-x + 3y + 5x3 = 4[/tex]

Each row of the coefficient matrix corresponds to an equation in the system, and each column represents the coefficients of a specific variable (x₁, x₂, x₃).

In summary, the coefficient matrix for the given system of equations is:

[tex]| 2 3 3 |[/tex]

[tex]| 3 5 2 |[/tex]

[tex]|-1 3 5 |[/tex]

This matrix provides a compact representation of the coefficients in the system, which can be further used for various operations and calculations.

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Answer:

c because 3.3.3.3 is 3 to the 4th power expanded

Answer:

a ≤ 9

Step-by-step explanation:

Closed circle means ≤ or ≥

Shading to the left means left direction < or ≤

The inequality sign that has both is: ≤

a ≤ 9

Answer:

The answer is C

Step-by-step explanation:

I took the test and I got it right

Answer:

d

Step-by-step explanation:

integer is a whole number

imagine the sum of the first set of 3 integers = 4 + 5 + 6

product = 4 x 5 x 6 = 120

imagine the sum of the 2nd set of 3 integers = 6 + 7 + 8 = 21

6 x 7 x 8 = 3364

Answer:

6,7

Step-by-step explanation:

the squre root of 41 is 6.403

Answer:

i think you're right- you seem to have all numbers squared correctly, also every negative value squared becomes a positive number, which means that your answers are correct.. what is your issue?

Step-by-step explanation:

Answer:

60 degrees

Step-by-step explanation:

Each triangle needs to add up to 180 total degrees.  70+50=120,

180

-

120

___

60

The school is not justified to make this claim because of the reasons defined.

The following is a statement that might be made about the high school to justify its claim No, because the z-score of Z = 1.06 is not uncommon because it does not fall within the range of a typical event, namely within 2 standard deviations of the sample mean.

It has been given to us that:

μ = 511

σ = 119

Sample size (n) = 55

and

s = 119 / √55

= 16.046

As we all know,

Only when z > 2 then, the high school's allegation is valid and warranted.

To locate,

Z's value is

So,

Z = ( X - μ )/σ

by applying the Central Limit Theorem to the values,

z = ( 528 - 511 ) / 16.046

= 1.06

Since, z < 2, as a result, the allegation is unjustified.

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Correct question:

The average math SAT score is 511 with a standard deviation of 119. A particular high school claims that its students have unusually high math SAT scores. A random sample of 55 students from this school was​ selected, and the mean math SAT score was 528. Is the high school justified in its​ claim? Explain. ▼ No Yes ​, because the​ z-score ​( nothing​) is ▼ unusual not unusual since it ▼ does not lie lies within the range of a usual​ event, namely within ▼ 1 standard deviation 2 standard deviations 3 standard deviations of the mean of the sample means. ​(Round to two decimal places as​ needed.)

Answer:

I THINK it would be B.

Step-by-step explanation:

I’m very sorry if I’m wrong.

Answer:

16.3%

Step-by-step explanation:

21.5 times 0.163= 3.5

It's 12 because if you divide 6 by 0.5 you should get 12, so basically use the opposite operation.

Hope that helps!

Answer:

m=3/4

Step-by-step explanation:

First, let us remind ourselves of the slope formula: m=rise/run=([tex]y_{2}[/tex]-[tex]y_{1}[/tex])/([tex]x_{2}[/tex]-[tex]x_{1}[/tex])

Let's pick two points from the graph to work with. Let's do (3,-6) and (-1,-9).

And let 3=[tex]x_{1}[/tex], -6=[tex]y_{1}[/tex], -1=[tex]x_{2}[/tex], -9=[tex]y_{2}[/tex].

1. Substitute the values into the slope formula: [-9-(-6)]/(-1-3)

2. simplify the expression: [-9-(-6)]/(-1-3)=(-9+6)/-4=-3/-4=3/4

3. As a result, the slope of the line is 3/4

The velocity of the train after 4 hours is 20 miles per hour.

To find the velocity of the train after 4 hours, we need to differentiate the given function s(t) with respect to t.

Velocity is the derivative of position with respect to time.

That is,v(t) = ds(t)/dtTo differentiate s(t) = –13 + 3t² – 4t – 4, we differentiate each term separately.v(t) = d/dt(-13) + d/dt(3t²) - d/dt(4t) - d/dt(4)v(t) = 0 + 6t - 4

The velocity of the train after 4 hours is given by substituting t = 4 in the above equation.v(4) = 6(4) - 4 = 20

The velocity of the train after 4 hours is 20 miles per hour.To sum up, the velocity of the train after 4 hours is 20 miles per hour.

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Therefore, the probability of exactly one card being jack when a hand of four cards is drawn from a standard deck of playing cards with replacement is 0.073 or 7.3%.

Suppose a hand of four cards is drawn from a standard deck of playing cards with replacement, the probability of exactly one card being jack can be determined using the following steps:Step 1: Determine the total number of possible outcomes when four cards are drawn from a standard deck of 52 cards with replacement. The total number of possible outcomes = 52 × 52 × 52 × 52 = 7,311,616.Step 2: Determine the total number of ways in which exactly one card can be a jack. There are four jacks in a standard deck of 52 cards, so the total number of ways in which exactly one card can be a jack = 4 × 48 × 48 × 48 = 53,333,632.Step 3: Determine the probability of exactly one card being jack. Probability of exactly one card being jack = Total number of ways in which exactly one card can be a jack / Total number of possible outcomes= 53,333,632/ 7,311,616 = 7.28 ≈ 0.073 or 7.3%.Therefore, the probability of exactly one card being jack when a hand of four cards is drawn from a standard deck of playing cards with replacement is 0.073 or 7.3%.

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The Laplace transform of the function f on (0,0) defined by f(t) = i Se^4t is L(f)(s) = i S / (2s-4).

Given function is f(t) = i Se^4t

Here, Laplace transform of the function f is given by:

L(f)(s) = ∫[0,∞) e^(-st) f(t) dt

On substituting the given function in the above equation, we get:

L(f)(s) = ∫[0,∞) e^(-st) i Se^(4t) dt

L(f)(s) = i S ∫[0,∞) e^(t(4-s)) dt

We know that the Laplace transform of e^(at) is 1/(s-a).

Therefore, Laplace transform of e^(t(4-s)) = 1/(s - (4-s)) = 1/(2s - 4).

Therefore,L(f)(s) = i S * ∫[0,∞) e^(t(4-s)) dt

L(f)(s) = i S * 1/(2s-4) * [-e^(-(4-s)t)]_0^∞

L(f)(s) = i S * 1/(2s-4) * [0 - (-1)] (since the exponentials evaluated at ∞ is zero)

L(f)(s) = i S * 1/(2s-4) * 1

L(f)(s) = i S / (2s-4)

Therefore, the Laplace transform of the function f on (0,0) defined by f(t) = i Se^4t is  L(f)(s) = i S / (2s-4).

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The composite functions fog and g • f are not equal to x. The function fog simplifies to 4x² - 20x + 25, while g • f simplifies to 45. Therefore, neither composite function equals x.

To determine whether the composite functions fog and g • f are equal to x, we need to evaluate each expression separately and compare the results.

1. fog (or f(g(x))):

f(g(x)) = f(2x - 5)

To compute f(2x - 5), we substitute (2x - 5) into the function f(x) = x²:

f(2x - 5) = (2x - 5)²

Expanding this expression, we get:

f(2x - 5) = 4x² - 20x + 25

Therefore, fog is not equal to x since f(2x - 5) simplifies to 4x² - 20x + 25, not x.

2. g • f (or g(f(x))):

g(f(x)) = g(25)

To compute g(25), we substitute 25 into the function g(x) = 2x - 5:

g(25) = 2(25) - 5

g(25) = 50 - 5

g(25) = 45

Therefore, g • f is not equal to x since g(25) evaluates to 45, not x.

In conclusion, neither fog nor g • f is equal to x. The composite functions do not simplify to x; fog simplifies to 4x²- 20x + 25, and g • f simplifies to 45.

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Answer:

the blue one but not sure

Answer:

the third one i think

Step-by-step explanation:

The ordered pair (2,3) is not a solution of the system

From the question, we have the following parameters that can be used in our computation:

−8x + 4y > 3

6x - 7y < −5

The solution is given as

(2, 3)

Next, we test this value on the system

So, we have

−8(2) + 4(3) > 3

-4 > 3 --- false

This means that (2,3) is not a solution of the system

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Options :

A.

33.5%

B.

20,000 and 33.5%

C.

500 and 20,000

D.

20,000

Answer:

A.) 33.5%

Step-by-step explanation:

A statistic value is simply a numerical statistical estimate or value which is obtained from the sample data or value. Here the statistic is the statistical value which is obtained the sample of 500 customers selected from the about 20000 population value 500 itself is the sample size while 33.5% is the sample. Proportion of supermarket customers who do not buy store-brand products.

20,000 = population size ;

500 = sample. Size

33.5% =. Statistic

The potential that satisfies the given boundary conditions in part (a) and (b) is: [tex]\[u(r, \theta) = \sin(\theta)\][/tex] and [tex]\[u(r, \theta) = \sin(\theta)\][/tex] respectively.

Consider the circular annulus (a plane figure consisting of the area between a pair of concentric circles) specified by the range:

[tex]$1 \leq r \leq 2$.[/tex]

a) Find the potential that satisfies the following boundary conditions:

[tex]\[\begin{aligned}u(1,0) &= \sin(\theta) \\u(2,0) &= 0 \\u(\theta, 1) &= 1 + (1 - \cos(2\theta))\end{aligned}\][/tex]

b) Find the potential that satisfies the following boundary conditions:

[tex]\[\begin{aligned}u(1,0) &= \sin(\theta) \\u(2,0) &= 0 \\u(\theta, 1) &= 1 + (1 - \cos(20\theta))\end{aligned}\][/tex]

To solve this problem, we can use separation of variables and assume a solution of the form:

[tex]\[u(r, \theta) = R(r)\Theta(\theta)\][/tex]

Plugging this into Laplace's equation [tex]$\nabla^2u = 0$[/tex] and separating variables, we get:

[tex]\[\frac{1}{R}\frac{d}{dr}\left(r\frac{dR}{dr}\right) + \frac{1}{\Theta}\frac{d^2\Theta}{d\theta^2} = 0\][/tex]

Solving the radial equation gives us two solutions:

[tex]\[R(r) = A\ln(r) + B\quad \text{and} \quadR(r) = C\frac{1}{r}\][/tex]

For the angular equation, we have:

[tex]\[\Theta''(\theta) + \lambda\Theta(\theta) = 0\][/tex]

The general solution to this equation is given by:

[tex]\[\Theta(\theta) = D\cos(\sqrt{\lambda}\theta) + E\sin(\sqrt{\lambda}\theta)\][/tex]

To satisfy the boundary conditions, we can impose the following restrictions on [tex]$\lambda$[/tex] and choose appropriate constants:

For part (a)

[tex]\[\begin{aligned}R(1) &= 0 \implies B = -A\ln(1) = 0 \implies B = 0 \\R(2) &= 0 \implies A\ln(2) + B = 0 \implies A\ln(2) = 0 \implies A = 0 \\\Theta(0) &= \sin(0) \implies D = 0 \\\Theta(0) &= \sin(0) \implies E = 1\end{aligned}\][/tex]

Therefore, the potential that satisfies the given boundary conditions in part (a) is:

[tex]\[u(r, \theta) = \sin(\theta)\][/tex]

For part (b)

[tex]\[\begin{aligned}R(1) &= 0 \implies B = -A\ln(1) = 0 \implies B = 0 \\R(2) &= 0 \implies A\ln(2) + B = 0 \implies A\ln(2) = 0 \implies A = 0 \\\Theta(0) &= \sin(0) \implies D = 0 \\\Theta(0) &= \sin(0) \implies E = 1\end{aligned}\][/tex]

Therefore, the potential that satisfies the given boundary conditions in part (b) is:

[tex]\[u(r, \theta) = \sin(\theta)\][/tex]

Please note that in both parts (a) and (b), the radial solution does not contribute to the potential due to the boundary conditions at r=1 and r=2. Thus, the solution is purely dependent on the angular part.

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Answer:

69

Step-by-step explanation:

Answer:

Step-by-step explanation:

62.00

To make the 2% solution of tetracaine hydrochloride isotonic, a 0.9% solution of sodium chloride should be used.

The amount of the 0.9% sodium chloride solution needed can be calculated by setting up a proportion based on the concentration percentages.

Let's assume x represents the volume of the 0.9% sodium chloride solution needed in milliliters.

Since the 0.9% solution is isotonic, it means that the concentrations of tetracaine hydrochloride and sodium chloride should be equal. Therefore, the proportion can be set up as follows:

(0.9 / 100) = (2 / 100) * (x / 30)

Simplifying the proportion, we have:

0.009 = 0.02 * (x / 30)

To solve for x, we can multiply both sides of the equation by 30 and divide by 0.02:

x = (0.009 * 30) / 0.02

x ≈ 13.5 mL

Therefore, approximately 13.5 milliliters of the 0.9% sodium chloride solution should be used in compounding the prescription to make the 2% tetracaine hydrochloride solution isotonic.

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Answer:

x = 30

Step-by-step explanation:

2x + x = 90

3x = 90

x = 30

Answer: 65

Step-by-step explanation:

8nn+7 is your given expression. Plug in 7 for n, the number of tickets: 8(7)+9=56+9=65

Answer:

21/20

Step-by-step explanation:

Answer:

85

Step-by-step explanation:

425 divided by 8= 85

Answer:

He as 85 race cars.

Step-by-step explanation:

Just divide 425 by 5 and you have your answer.