The type of heat transfer responsible for your computer leaving your desk very hot after you've used it for awhile?​

In the given image A. load, B. fulcrum, C. effort. 1st class. The correct option is B.

The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.

The fulcrum of first-class levers is in the centre. Levers of the second class have the load in the centre.

This indicates that a heavy load can be moved with only moderate effort. - Levers of the third class exert middle-of-the-road force.

The illustration shows a class 1 lever with a fulcrum in the middle and load and effort located at the other two ends.

Thus, the correct option is B.

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By contrasting a fossil with related rocks and fossils of known ages, relative dating can estimate the fossil's age.

By utilising radiometric dating to track the isotope decay inside the fossil or, more frequently, the rocks it is linked with, absolute dating may pinpoint an object's exact age.

It is possible to identify whether one artefact, fossil, or stratigraphic layer is older than another using relative dating, which does not provide particular dates.

Absolute dating techniques offer more precise dates and times of origin, such as a range in age in years.

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The evaluation of the capacitor (in series) network is as follows;

Part A

Q = 3.2 μC

Part B

Q₁ = 3.2 μC

Part C

Q₂ = 3.2 μC

Part D

U = 76.8 μJ

Part E

U₁ = 34 2/15 μJ

Part F

U₂ = 53 1/3 μJ

Part G

V₁ = 21 1/3 V

Part H

V₂ = 26 2/3 V

A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.

The specified parameters are;

The voltage across ab = 48 V

The capacitance of the first capacitor, C₁ = 150 nF

Capacitance of the second capacitor, C₂ = 120 nF

Part A

The total charge in a capacitor network can be found as follows;

[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]

[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]

[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]

Therefore;

[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC

Part B

The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;

Q = C₁V₁ = C₂V₂

The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC

The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC

Part C

The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.

Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC

Q₂ = 3.2 μF

Part D

The total energy stored in the network can be obtained using the formula;

U = (1/2)·C·V²

Where;

U = The energy in the capacitor

C = The equivalent capacitance of the network = 66 2/3 nF

V = The voltage

Therefore;

[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]

[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]

Part E

The energy stored in the 150 nF capacitor is found as follows;

[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁

V₁ = [tex]Q_{eq}[/tex] ÷ C₁

Therefore;

V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V

U₁ = 0.5×C₁×V₁²

Part F

The energy stored in the 120 nF capacitor, U₂, can be found as follows;

V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V

U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]

Part G;

The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V

Part H

The potential difference across the 120 nF, obtained in part F, is 26 2/3 V

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Since Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. The option that MOST likely TRUE about this goal is option A:It is a short-term goal.

A short-term goal is a goal that can be achieved within a relatively short period of time, usually less than a year. In this case, the goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January.

In this case, Taylor's goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. This goal is specific, as it clearly states what Taylor wants to accomplish, and it is measurable.

This goal can be achieved within the month of January and it's a specific, measurable and time-bound goal, which are characteristics of short-term goals.

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See full question below

Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?

It is a short-term goal.

It is a long-term goal.

It is an unrealistic goal.

It is a mental health goal.

Answer:it’s a short-term goal

Explanation:

because it’s only for the month of January she will be doing this goal.

Based on the image shown, the numbers that correspond to the term or phrase assuming that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3 are:

Electrochemical cells are cells that convert chemical energy to electrical energy.

The components of an electrochemical cell are:

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Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.

Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:

You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.

You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.

You could argue that a different reading would imply that the speaker is the one being dumped by her lover.

You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.

But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.

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a) The average velocity at 4s is 12 m/s

b) The instantaneous velocity at t= 6s is 12 m/s

c) The average acceleration is; 12  - 0/ 4 - 0 n= 3 m/s^2

d) The time for the race is 10 s

We know that the velocity time graph is the kind of set up that has two axis and we can be able to use it to be read off the velocity of the acceleration  of the object. I would want us to recall  that the acceleration is the rate of change of the velocity of the object with time.

Now we have that;

The graph for the velocity of the object can be obtained by looking at the image that has been shown and then we read off the points that are on the graph. The  vertical axis shows the velocity of the graph while the horizontal axis shows the time that is covered in the graph.

The acceleration would be the ratio of the change in the velocity to the change in the time of the object.

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As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

A horse trots past you and then a fencepost that is 36m away from you.

Time taken to  make this trot = 11.0 second.

Hence,  the average velocity of the horse is = total distance travelled/time interval

= 36/11.0 m/s

= 3.27 m/s.

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The parallel component of the force of gravity is the net force. The perpendicular component of the force of gravity is directed opposite the normal force and as such balances the normal force.

In order to balance the normal force, the perpendicular component of gravity is pointed in the opposite direction. No other force can counteract the parallel component of the gravitational force.

The presence of an imbalanced force will then cause the object to accelerate downward along the inclined plane. This acceleration is brought on by the parallel part of the gravitational force. The net force is a parallel part of the gravitational force.

FGravity=m×g

where m is the object's mass and g is gravity's acceleration, which is 9.8 m/s2. In this case, the negative indicates that the force is downward-directed.

FParallel=FGravity×Cos(Θ)

FParallel=FGravity×Sin(Θ)

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The interaction between the Corn plants and milkweed plants demonstrates as competition.

Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.

In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.

As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and  milkweed plants demonstrates competition.

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The mechanical advantage of the lever is 3.5.

The ideal mechanical advantage of the lever is 4

The efficiency of the lever is 87.5 %.

The mechanical advantage of the lever is the ratio of the load overcame by the lever to the effort applied by the lever.

M.A = Load / Effort

From the graph we will find the change in load to change in effort is calculated as;

M.A = ( 160 N - 20 N ) / ( 50 N - 10 N )

M.A = 3.5

The ideal mechanical advantage of the lever is calculated as follows;

I.M.A = distance travelled by effort / distance travelled by load

I.M.A = ( 2 m ) / ( 0. 5 m )

I.M.A = 4

The efficiency of the lever is calculated as follows;

E = M.A / I.M.A x 100%

E = ( 3.5 / 4 ) x 100%

E = 87.5 %

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The speed at which a clock would have to be moving in order to run at half the rate of a clock at rest depends on the theory of relativity that you are using.

In special relativity, time dilation is the phenomenon where time appears to pass differently for objects in motion relative to an observer at rest.

According to the theory, time appears to slow down for an object as it approaches the speed of light. The rate at which time appears to pass for an object is given by the equation:

T' = T / [tex]\sqrt{(1 - (v^2 / c^2))}[/tex]

Where T is the time as measured by an observer at rest, T' is the time as measured by an observer moving relative to the object, v is the velocity of the object, and c is the speed of light.

In addition, this is a theoretical scenario, practically in order to measure time dilation in a laboratory, it is required a very high precision of measurements, that are currently not possible.

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There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.

The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.

Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.

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The velocity of the experimental vehicle after 2 seconds is 14 m/s.

The displacement of the experimental vehicle after 2 seconds is 14 m.

The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.

The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:

v = u + at

where;

u is the initial velocity = 0 m/s

a is the acceleration = 7 m/s²

t is time = 2 seconds

v = 0 + 7 * 2

v = 14 m/s

The displacement, s, of the vehicle is calculated below as follows:

v² = u² + 2as

14² = 0² + 2 * 7 * s

s = 196 / 14

s = 14 m

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Answer:

The mass is the amount of matter in something. Weight is mass times gravitational field strength and so also includes gravity. Mass is measured in grams (g) and weight is measured in Newtons (N)

The magnitude of the constant acceleration of the ball is 9.7 m/s².

Acceleration is the rate of change of velocity.

To calculate the constant acceleration of the ball, we use the formula below.

Formula:

From the question,

Given:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration is 9.7 m/s².

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The distance travel while accelerating is 90m

The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.

The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .

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Answer:

To solve this problem, you can use the formula for work, which is work = force x distance. In this case, the distance the crate is moved is the height of the loading dock, or 4 meters. The amount of work performed is given as 600 joules. So, you can set up the equation like this:

600 joules = force x 4 meters

To solve for the force, you can divide both sides of the equation by 4 meters:

600 joules / 4 meters = force x 4 meters / 4 meters

This simplifies to:

150 newtons = force

So, the force necessary to raise the 150-newton crate up the ramp to the 4-meter loading dock is 150 newtons.

Answer:

Object 1

Explanation:

Newton's 2nd Law:  F = ma, therefore m = F/a

This shows that mass is inversely proportional to acceleration.  Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass.  Therefore, the object that accelerates at 2 m/s² has the greater mass.  In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.  

The addition of two sound waves produces a new wave of higher amplitude if their compressions and refractions line up. It is also known as constructive interference.

Interference can be described as a phenomenon in which two waves combine by adding at every single point in space and time, to form a resultant wave of greater or lower amplitude.

Constructive and destructive interference occurs in the interaction of waves that are correlated with each other because they come from the same source.

When two sound waves propagate in the same direction in phase with each other, their amplitude gets added, and the resultant wave is produced from constructive interference.

When two waves interfere with each other and have a displacement in the opposite direction.  When a crest of a wave meets the trough of another wave, the waves undergo destructive interference.

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The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.

The maximum height refers to the maximum vertical distance that an object can travel.

The maximum range is the maximum horizontal distance that an object can travel.

The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.

R = 4Hcot is the relationship between the horizontal range and maximum height.

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Resistors limits the current/amps but keep the voltage the same.

You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.

Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.

So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,

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The statement indicates that angle 3 seems to have a 117 degree measurement.

Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.

An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.

The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.

Angle 3 is therefore = 180 - 63 = 117 degrees.

Consequently, angle 3 has a measure of 117 degrees.

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The ranking of the voltages, V₁, V₂, V₃, and V₄ in the order of decreasing voltage value is; V₂ > V₃ > V₁ > V₄

A voltage is the difference in potential or pressure that pushes or causes the flow of electric current in a circuit or conducting loop.

The current flowing through the circuit can be found using the following formula;

[tex]I=\dfrac{V}{R}[/tex]

The formula for conductivity is presented as follows;

[tex]\sigma =\dfrac{l}{R\times A}[/tex]

Where;

σ = The conductivity of the material

l = The length

R = The resistance to electricity

A = The cross-sectional area of the conductor

Therefore;

[tex]R=\dfrac{V}{I}[/tex]

[tex]R=\dfrac{l}{A\times \sigma}[/tex]

[tex]\dfrac{V}{I} =\dfrac{l}{A\times \sigma}[/tex]

[tex]V=\dfrac{l \times I}{A\times \sigma}[/tex]

Based on the dimensions of the cylinders, obtained from a similar question, we get;

[tex]V_1=\dfrac{3\cdot L \times I}{\pi \cdot D^2\times \sigma} = 3\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_2= \dfrac{2\cdot L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} = \dfrac{8\cdot L \times I}{\pi \cdot D^2\times \sigma} = 8\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_3=\dfrac{L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} =\dfrac{4\cdot L \times I}{\pi \cdot D^2\times \sigma}= 4\times \dfrac{L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_4=\dfrac{L \times I}{\pi \cdot D^2\times \sigma} = 1\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

Therefore;

V₁ = 3·V₄

V₂ = 8·V₄

V₃ = 4·V₄

The rank of the voltages in the order of decreasing value is therefore;

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Based on the data provided about the collision;

The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:

Impulse = change in momentum

Change in momentum = m(v - u)

where;

m is mass

v is the final velocity

u is the initial velocity

Impulse = 1759 (12 - 22)

Impulse = 21105.8 kg.m/s

The average force on the automobile will be:

Force = impulse/time

Force = 21105.8 / 0.11

Force = 191870.91 N

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Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:

Effort Distance = 50 cm

Effort Applied = 5333.33 N

Output work = 2000 J

Mechanical Advantage = 0.75.

When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.

Load (output force) = 4000 N

Height lifted = 50 cm = 0.5 m

Efficiency of the pulley = 75%

Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:

Effort applied (input force) = Load ÷ Efficiency

= 4000 N ÷ 0.75

= 5333.33 N

Output work = Load x Height lifted

= 4000 N x 0.5 m

= 2000 J

Effort distance = Height lifted

= 50 cm

Mechanical advantage = Load ÷ Effort applied

= 4000 N ÷ 5333.33 N

= 0.75

It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.

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The horizontal distance travelled by the box is 143 m.

The horizontal distance travelled by the box is calculated by determining the time of motion of the box and the horizontal velocity of the airplane.

The time of motion of the box from the vertical height in which it was dropped is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 40 / 9.8 )

t = 2.86 seconds

The horizontal distance travelled by the box is calculated as follows;

d = Vₓ t

where

d = ( 50 m/s ) x ( 2.86 s )

d = 143 m

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The complete question is below;

A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible. Find the horizontal distance travelled by the box.

Answer:

c

Explanation: