there are no good answers on brainly can someone pls answer this

Answer:

Step-by-step explanation:

[tex]\sf 37-\cfrac{48}{8}[/tex]

Divide numbers ( 48/8 = 6)

Subtract numbers:-

31 is your answer!

___________________

Hope this helps!

Have a great day!

Answer:

Step-by-step explanation:

You want to find a sequence of transformations that will map ∆PZY to ∆RST as shown in the figure.

First of all, we notice the triangles are not the same size. We can find the required dilation factor by finding the ratio of corresponding side lengths.

The first two letters in the triangle designators in the similarity statement are PZ and RS. Since RS is the target size, the dilation factor needs to be ...

  k = RS/PZ

Counting grid squares in the figure, we see this ratio is ...

  k = 2/4 = 1/2

Dilation by a factor of 1/2 will make triangle PZY the same size as ∆RST.

Using the origin as the center of the dilation, all of the points of ∆PZY move to a position that is half their original distance from the origin. The dilated triangle is purple triangle P'Z'Y' in the attached figure.

When we name the vertices of ∆PZY or ∆P'Z'Y', we are naming them in counterclockwise order. The vertices of ∆RST are being named in clockwise order. This reversal of the sequence of vertices is caused by a reflection over a line.

The line of reflection will be halfway between a vertex and its reflected image. For example, reflecting ∆P'Z'Y' across the y-axis give ∆P"Z"Y", as shown in the attached figure. This reflection requires an additional transformation to map P"Z"Y" to RST.

We want to map P' to R, Z' to S, and Y' to T. As it happens the line halfway between these pairs of points is the line y=-x, the dashed line shown in the attachment.

Reflection across the line y = -x will map ∆P'Z'Y' to ∆RST.

This transformation, together with the dilation above, will map the ∆PZY to ∆RST as required.

__

If we use the reflection over the y-axis described above, we are faced with mapping ∆P"Z"Y" to ∆RST. We notice that segment P"Z" points "east" (in the +x direction). We want to map this segment to RS, which points "north" (in the +y direction). That can be accomplished by rotating ∆P"Z"Y" 90° counterclockwise about the origin.

So, another sequence of transformation that will make the required mapping is ...

The order of reflection and rotation is important. The dilation can occur anywhere in the sequence.

Perhaps you realize that we could reflect the figure across the x-axis instead of the y-axis. In that case, the rotation needs to be 90° CW to complete the mapping. That is, yet another sequence could be ...

If you decide you want to do the rotation before the reflection, then the direction of rotation is reversed.

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Additional comment

Figuring the answer to these mapping problems requires a certain amount of spatial sense. It can help to cut a figure from paper or cardboard and label the vertices. Then you can translate it, rotate it, flip it over, to see what works to get it to the right position. If you have a little trouble with the rotation, you can stick a pin through the center of rotation so your figure keeps its appropriate distance and orientation relative to that center.

Tracing paper and/or transparencies can be helpful for these exercises.

well, we know that 37.5% have finished it, that leaves unaccounted for 100% - 37.5% = 62.5%.

now, of those 62.5% fellows only 40% have finished only half of it, how many are those?

well, what's 62.5% of 32?   what's 40% of that much?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{62.5\% of 32}}{\left( \cfrac{62.5}{100} \right)32}\implies 20 ~\hfill \stackrel{\textit{40\% of 20}}{\left( \cfrac{40}{100} \right)20}\implies \text{\LARGE 8}[/tex]

Answer:

Q = 3.667

Step-by-step explanation:

Answer:

[tex]A=9\pi cm^{2}[/tex][tex]=28.27cm^{2}[/tex]

Step-by-step explanation:

If  BC= 6

then r = BC/2 = 6/2 = 3cm

[tex]A=\pi r^{2} =\pi (3)^{2} =9\pi[/tex]

[tex]A=28.27cm^{2}[/tex]

Hope this helps

52s is the maximum time that she can take on her last lap and still make the team.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Given that he mean pace a student needs to achieve on 5 laps of the pool is 60 seconds (s).

The student swims a lap in 63 s, 62 s, 65 s, and 58 s on her first four laps.

We need to find the maximum time (in seconds) that she can take on her last lap and still make the team

Let x be the maximum time (in seconds) that she can take on her last lap

60=(63+62+65+58+x)/5

300=63+62+65+58+x

300=248+x

Subtract 248 on both sides

300-248=x

x=52s

Hence, 52s is the maximum time that she can take on her last lap and still make the team.

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Therefore , the solution of the given problem of expression comes out to be  22[tex]z^{8}[/tex].

A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to compare expressions and phrases. In English, a phrase by itself could contain an action, but it doesn't constitute a full sentence. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Here,

Given : -20[tex]z^{8}[/tex]+ (-2[tex]z^{8}[/tex])

=> -22[tex]z^{8}[/tex]

So ,

In order to find the solution we add them

Thus ,

simplification of given expression is:

=> - 22[tex]z^{8}[/tex]

Therefore , the solution of the given problem of expression comes out to be  22[tex]z^{8}[/tex].

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Answer:

  1400

Step-by-step explanation:

You want to know the number of customers in April if the number in May was 10% lower. That number was 140 fewer.

The problem statement is telling us ...

  April - (10% × April) = April - 140

  10% × April = 140 . . . . . . . . subtract April, multiply by -1

  April = 140/10% = 1400 . . . . divide by 10%

The number of customer visits in April was 1400.

__

Additional comment

The 1400 customers in April fell by 140 to 1260 in may. That's 10% fewer than in April.

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Answer: 5%

Step-by-step explanation:

Answer:

answer is 10

Step-by-step explanation:

Answer:

The three statements that are always true regarding this diagram are:

m∠3 + m∠4 + m∠5 = 180°

m∠2 + m∠3 + m∠5 = 180°

m∠2 + m∠3 = m∠6

Here's why:

The sum of the measures of the interior angles of a triangle is always 180°. Therefore, m∠2 + m∠3 + m∠5 = 180°.

The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles. Therefore, m∠4 = m∠2 + m∠5, and m∠3 + m∠4 + m∠5 = 180°.

The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles. Therefore, m∠6 = m∠2 + m∠3.

The other two statements are not always true. For example, if m∠5 = 100° and m∠3 = 80°, then m∠5 + m∠3 = 180°, but m∠4 ≠ 0°. Similarly, if m∠5 = 100° and m∠6 = 80°, then m∠5 + m∠6 ≠ 180°.

Step-by-step explanation:

Answer: the bottom two graphs show continuous data

Step-by-step explanation:

Step-by-step explanation:

the tax rate gives us a ratio of tax amount to value.

this ratio (in our case 1.25/100) is constant for any value.

therefore, when we know how many $1.25 units are in $2000, we know that there are exactly as many $100 units in the value.

in other words, we multiply

1.25/100 × f/f

so that the numerator reaches the total of $2000 of taxes. and then the enumerator gives us the total value.

f = 2000 / 1.25 = 1600

so, we get

1.25/100 × 1600/1600 = 2000 / 160000

so, the value of the condominium is

value = $160,000

Answer:

To find the resultant force of an object, we need to add up all the forces acting on it. The resultant force is the overall force that the object experiences, taking into account all the individual forces.

In this case, we are given four objects, A, B, C, and D, and the forces acting on them. To find the object with the largest resultant force, we need to calculate the resultant force for each object by adding up all the forces acting on it.

For object A, the forces acting on it are: 10 N, 10 N, and 10 N, for a total of 10 N + 10 N + 10 N = 30 N.

For object B, the forces acting on it are: 5 N, 5 N, 5 N, and 5 N, for a total of 5 N + 5 N + 5 N + 5 N = 20 N.

For object C, the forces acting on it are: 30 N and -5 N, for a total of 30 N + (-5 N) = 25 N.

For object D, the forces acting on it are: 10 N and -5 N, for a total of 10 N + (-5 N) = 5 N.

Therefore, the object with the largest resultant force is object C, with a resultant force of 25 N.

The value of π can be written with upper and lower limits as -

3.12 ± 0.062.

Significant figures of a number in positional notation are digits in the number that are reliable and necessary to indicate the quantity of something.

Given is that Helen draws a random circle, she then measures the circumference and diameter. She gets a circumference {C} of 405mm correct to 2 significant figures She gets a diameter {D} of 130mm correct to 2 significant figures.

We can write -

Circumference {C} = (405 ± 2) mm

Diameter {D} = (130 ± 2) mm

The value of π can be calculated as -

π = {C}/{D}

π = (405 ± 2)/(130 ± 2)

Now, divide the numbers without errors first -

405/130

3.12

Now, we will calculate the relative errors in each number -

2/405 = 0.004

2/130 = 0.016

Adding the relative errors -

0.004 + 0.016

0.02

Absolute error = 0.02 x 3.12 = 0.062

The value of π can be written with upper and lower limits as -

3.12 ± 0.062

Therefore, the value of π can be written with upper and lower limits as -

3.12 ± 0.062.

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Answer: x = 2.

LN = MP = 2.

Solution in the photo, below.

Answer: a) The control in the experiment, 0 kHz, or no sound, serves as a baseline against which to compare the other treatments. By using the control with no sound, researchers can determine whether the deer's response to the sound-emitting devices is due to the sound itself or some other factor. Without the control, it would be unclear what caused any differences in the deer's responses to the different sound treatments.

(b)(i) One advantage to keeping the loudness at a constant 60 decibels for all treatments is that it allows researchers to directly compare the deer's responses to the different sound pitches without the added variable of loudness.

(b)(ii) One disadvantage to keeping the loudness at a constant 60 decibels for all treatments is that loudness may also play a role in deer's response. So, it would be unclear if the different in deer's responses are due to sound frequency only or also caused by sound loudness

(c) Based on the results shown in the bar chart, it can be seen that the deer's response to the sound-emitting devices varies depending on the pitch of the sound. At lower pitches, around 0.28 kHz, the deer's response is more likely to be negative or neutral, indicating that they move away from or don't move towards the highway. At higher pitches, around 15 kHz, the deer's response is more likely to be positive, indicating that they move towards the highway. It suggests that the frequency of sound has an impact on the deer's response. So, based on this data, we cannot recommend using a sound-emitting device to keep deer from running across highways without further research on the optimal frequency and loudness that should be used to make sure that it is effective and safe for the deer.

Step-by-step explanation:

The sound-emitting device may have both advantages and disadvantages depending on the pitch. More research is necessary to find the optimal frequency and volume for the device to be effective and safe.

Based on the results of the experiment, it would not be advisable to use a sound-emitting device to prevent deer from running across highways without further research. The experiment showed that the deer's response varied depending on the pitch of the sound. Although the device showed some advantages, such as moving deer away from the highway at lower pitches, it also presented potential disadvantages. At higher pitches, the deer had a tendency to move towards the highway, which could increase the risk of accidents. More research would be needed to determine the optimal frequency and volume to use for the device to be both effective and safe for the deer.

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Answer:

Step-by-step explanation:

So, the factors of 300 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 25, 30, 50, 60, 75, 100, 150, and 300. [Note: If we divide 300 by 21, we get the quotient and remainder as 14 and 6, respectively. So, 21 is not a factor of 300.

Answer:

Basically, LON would be 8z + 112 + 6z - 17

So, our equation will look like this

8z + 112 + 6z - 17 = -1z + 65

Subtract the 6z from the 8z

2z + 112 - 17 = -1z + 65

112 - 17 = 95

2z + 95 = -1z + 65

add the 1z

3z + 95 = 65

subtract the 95

-30

3z = -30

The answer is -10 :)

Step-by-step explanation:

Answer:

LON=75

Step-by-step explanation:

LON= LOM=NOM

-1z+65=8z+112-6z-17

-1z+65=2z+95

3z=-30

z=-10

LON= -1z+65

       = -1(-10)+65

       = 10+65

LON= 75

The equation to represent the cost of renting the car, given the cost per week and the cost per mile, is y = 42 + 0.25x.

The total cost of renting the car at any given point, would be:

= Cost to rent per week + ( Cost per mile x Number of miles driven)

If we assume the number of miles driven is denoted by x, then the equation becomes :
= 42 + 0. 25 x

If we further take y to be the total cost, the equation then becomes :

y = 42 + 0. 25 x

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Answer: ( see image )

Step-by-step explanation:

Answer:y=(x+3)2−17

Step-by-step explanation: 3,11 5,15

Answer:

10.74666666666667 per quart

Step-by-step explanation3 divided 36.24

Answer:

Step-by-step explanation:

if 2021 is 35% decrease of the original number then 2020 is 100% ,and 2021 = 65%.

so, we do the rule of three:

x = (94900 * 100)/ 65

x = 146000

and that is the population in 2020.

Answer:

Hey there! Based on the information provided, it seems that the population of the town decreased by 35% between 2020 and 2021. We can use this information to calculate that in 2021, the population of the town was 65% of its population in 2020. If the population of the town in 2021 was 94,900, then we can use this information to calculate that the population of the town in 2020 was 146,155. Does that make sense?

The solution is Option A.

The shortest distance is given by the two hypotenuses of the triangles and the distance is X = 7.8 cm

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

Given data ,

Let the shortest distance be represented as X

Let the first triangle be the first face of the rectangular box ΔABC

The length of the triangle AB = 3 cm

The height of the triangle BC = 2 cm

Now ,

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

The measure of AC = √ ( 3² + 2² )

The measure of AC = √13 cm

And , the second triangle is the second face of the rectangular box ΔDEF

The length of the triangle DE = 4 cm

The height of the triangle EF = 2 cm

The measure of DF = √ ( 4² + 2² )

The measure of DF = √18 cm

Now , the shortest distance X = The measure of AC  + measure of DF

Substituting the values in the equation , we get

The shortest distance X = √13 cm + √18 cm

The shortest distance X = 3.60 + 4.24

The shortest distance X = 7.8 cm

Therefore , the value of A is 7.8 cm

Hence , the shortest distance for the ant is 7.8 cm

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it is found that 29 are taking algebra, 14 are taking physics, and 5 are enrolled in both using principle of inclusion-exclusion we can say 38 students are enrolled in either algebra or physics.

To find how many students are enrolled in either algebra or physics, you can use the principle of inclusion-exclusion, which states that the total number of elements in two sets can be found by adding the number of elements in each set and then subtracting the number of elements that are in both sets.

So, the number of students enrolled in either algebra or physics is:

29 (students enrolled in algebra) + 14 (students enrolled in physics) - 5 (students enrolled in both) = 38

So, 38 students are enrolled in either algebra or physics.

It is important to notice that in the table you provided is a two-way frequency table also known as a contingency table, it shows the relationship between two variables, in this case, Algebra and Physics and the frequencies of each combination.

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On solving the provided question we can say that - from the graphs n f (x) and g( x) are 1 and 5 .

Graphs are visual representations or charts used in mathematics to methodically express data or values. A relationship between two or more objects is frequently represented by a point on a graph. A non-linear data structure called a graph is made up of nodes, or vertices, and edges. Connect the nodes, also known as vertices. This graph comprises a set of vertices V= 1, 2, 3, 5, and a set of edges E= 1, 2, 1, 3, 2, 4, and (2.5), (3.5), (4.5). Statistics graphs (bar charts, pie charts, line charts, etc.) Exponential diagrams. triangle graph, a logarithmic graph

by graphs of the function f (x) and g( x).

[tex]lim f ( x) + lim g ( x )\\= -1 + 2 = 1\\ f ( -1 ) + lim g ( x)\\= 3 + 2\\= 5[/tex]

from the graphs n f (x) and g( x) are 1 and 5 .

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Answer:

0.27 is the answer

I wish you luck in your assignments.

Answer:

Step-by-step explanation:

0.27

Step-by-step explanation:

please refer to the 3 pages of sketch for details