Two identical planets orbit a star in concentric circular orbits in the star's equatorial plane. The planet that is farther from the star must have a greater period than the planet that is closer to the star. The correct answer is option(b).
The period of the planet is directly proportional to the cube of its distance from the star. As a result, when planets are equidistant from a star, their periods will be equal.As a result, the planet that is farther from the star must have a greater period than the planet that is closer to the star.
A planet's gravitational mass is not influenced by the planet's distance from the star, so alternatives c and d can be ruled out. Similarly, the planet's universal gravitational constant is not affected by the planet's distance from the star, so option e can also be ruled out. The planet's period, on the other hand, is influenced by the distance from the star and the planet's mass. As a result, the option a can be ruled out.
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Describe how seismic waves can be used to determine the location of petroleum far beneath the surface.
Answer: The seismic waves are useful for the oil and gas exploration beneath the earth crust.
Explanation:
The seismic waves are sent beneath the earth crust to determine the location of fossil fuels like petrol, and natural gas. These seismic waves bound back and their pattern of reflection and refraction is recorded by using a receiver that is a geophone or can be a hydrophone (in water). The seismic waves bounce back indicating towards the reservoir of fossil fuel exhibit a characteristic pattern that can help in tracing the location of the fossil fuel.
Now we want to analyze a physical system comprised of two particles. Look at the pair-wise potential energy. Suppose r is equal to 1.2s. a) Suppose the particles are momentarily at rest at r = 1.2s (like a ball at the top of its trajectory when thrown straight up). What can you say about the total energy, Etot, and the subsequent motion of the two particles? b) Now suppose at the instant the particles have the separation 1.2s they have total KE equal to 0.1e. What can you say about the total energy, Etot, and the subsequent motion of the two particles
If the particles are momentarily at rest at a separation of r = 1.2s, the potential energy between them would be at a maximum since they are at the maximum distance apart.
a) If the particles are momentarily at rest at a separation of r = 1.2s, the potential energy between them would be at a maximum since they are at the maximum distance apart. At this point, the kinetic energy of the particles would be zero. The total energy, Etot, of the system, would be equal to the potential energy at that distance. The subsequent motion of the two particles would depend on the specific details of the system, but if no external forces act on them, they would start moving towards each other due to the attractive nature of the potential energy between them.
b) If, at the instant, the particles have a separation of 1.2s, their total kinetic energy (KE) is equal to 0.1e, where "e" represents the total potential energy between them, then the total energy, Etot, of the system would be the sum of the kinetic energy and potential energy. Etot = KE + PE = 0.1e + e = 1.1e. The subsequent motion of the two particles would depend on the specific details of the system and the relative magnitudes of the kinetic and potential energies. If the kinetic energy is significantly smaller than the potential energy, the particles would move towards each other under the influence of the attractive potential energy, eventually reaching a closer separation. However, if the kinetic energy is comparable or larger than the potential energy, the particles may exhibit more complex or oscillatory motion depending on the precise characteristics of the potential energy function.
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Light and Polarization: Learn from Einstein the properties of light Virtual Lab
Light is an electromagnetic wave that consists of oscillating electric and magnetic fields. It exhibits various properties, including wavelength, frequency, speed, and polarization.
Polarization refers to the orientation of the electric field vector of a light wave. Unpolarized light consists of electric field vectors oscillating in all possible directions perpendicular to the direction of propagation. Polarized light, on the other hand, has its electric field vectors confined to a specific orientation. Polarization can be achieved through various mechanisms, such as reflection, scattering, or passing light through certain materials. Polarizers, such as polarizing filters, can selectively transmit or block light waves based on their polarization orientation. The study of light and its properties, including polarization, has contributed to numerous advancements in various fields, such as optics, telecommunications, and technology.
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The properties of being
a. clear and bright
b. useful and profitable
make a diamond a gemstone.
c. easy to obtain and beautiful
d. colorful and profitable
Answer:
D !!!
Explanation:
Answer:
D
Explanation:
(a) An insulating sphere with radiusa has a uniform charge density rho. The sphere isnot centered at the origin but at. Show that the electric field inside thesphere is given by.
(b) An insulating sphere of radius R has a spherical holeof radius a located within its volume and centered adistance b from the center of the sphere. The solid partof the sphere has a uniform volume charge density rho. Findthe magnitude and direction of the electric fieldinside the hole, and show thatis uniform over the entire hole.[Hint: Use the principle of superposition and the resultof part (a).]
a. The electric field is E = (kρa^3/r^2) r
b. The magnitude of the electric field inside the hole of the sphere is (kρa^3/b^2 - kρ(4/3)πa^3/(b^2 - a^2)) j
a)
The electric field inside an insulating sphere with radius a and uniform charge density rho is,
E = (kq/r^2) r
Where
q = volume charge density * volume of the sphere
= rho*(4/3)πa^3
q = (4/3)πa^3ρ
The electric field is:,
E = (kq/r^2) r
= (kρa^3/r^2) r
b)
E = E_solid_sphere - E_hollow_sphere
The electric field due to the charge density inside the hole of the sphere is zero because the sphere is insulating. Therefore, the electric field inside the hole due to the charge density is zero and is uniform over the entire hole.The electric field due to the solid sphere can be found using the result from part (a),E_solid_sphere = (kρa^3/b^2) j
The electric field inside the hole due to the solid sphere is,E_hollow_sphere = -(kρ(4/3)πa^3/(b^2 - a^2)) j
Therefore, the magnitude and direction of the electric field inside the hole of the sphere areE = E_solid_sphere - E_hollow_sphere
= (kρa^3/b^2 - kρ(4/3)πa^3/(b^2 - a^2)) j
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what is the magnitude of the electric force on an electron in a uniform electric field of strength 2270 n/c that points due east?
The magnitude of the electric force on the electron is approximately 3.632 × 10^-16 N. Note that the negative sign indicates that the force is in the opposite direction of the electric field (westward in this case).
The magnitude of the electric force (F) on an electron in a uniform electric field can be calculated using the formula:
F = q * E,
where q is the charge of the electron and E is the electric field strength.
The charge of an electron is approximately -1.6 × 10^-19 C (negative because it is an electron).
Given that the electric field strength is 2270 N/C and it points due east, we can substitute the values into the formula:
F = (-1.6 × 10^-19 C) * (2270 N/C) ≈ -3.632 × 10^-16 N.
The magnitude of the electric force on the electron is approximately 3.632 × 10^-16 N. Note that the negative sign indicates that the force is in the opposite direction of the electric field (westward in this case).
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X rays with a wavelength of 0.085nm diffract from a crystal in which the spacing between atomic planes is 0.213 nm .
Part A
How many diffraction orders are observed?
ANSWER:
N =
X rays with a wavelength of 0.085nm diffract from a crystal in which the spacing between atomic planes is 0.213 nm . The number of diffraction orders observed is N = 4.
In X-ray diffraction, the diffraction pattern is produced when X-rays interact with the crystal lattice. The number of diffraction orders observed can be determined using Bragg's law:
nλ = 2d sinθ
where n is the diffraction order, λ is the wavelength of the X-rays, d is the spacing between atomic planes, and θ is the angle of incidence.
Rearranging the equation, we have:
n = 2d sinθ / λ
Substituting the given values, d = 0.213 nm and λ = 0.085 nm, we can calculate the value of n.
n = 2 * 0.213 nm * sinθ / 0.085 nm
Simplifying the expression, we find:
n ≈ 4
Therefore, the number of diffraction orders observed is N = 4.
When X-rays with a wavelength of 0.085 nm diffract from a crystal with a spacing between atomic planes of 0.213 nm, four diffraction orders are observed.
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A helicopter's speed increases from 25 m/s to 60 m/s in 5 seconds. What is the acceleration of this helicopter?
7 m/s
2-2.3 m/s
2-1.9 m/s
21.67 m/s2
Given, Initial speed of the helicopter = 25 m/s. Final speed of the helicopter = 60 m/s, Time taken by the helicopter to change its speed from 25 m/s to 60 m/s is 5 seconds. Therefore, the acceleration of the helicopter is 7 m/s².Hence, option (A) is correct.
To find the acceleration of the helicopter, we can use the formula:
Acceleration= (Final velocity - Initial velocity)/Time,
Acceleration = (60 m/s - 25 m/s)/5 s,
Acceleration = 35 m/s/5 s,
Acceleration = 7 m/s²
Therefore, the acceleration of the helicopter is 7 m/s².
We know that,
Acceleration = change in velocity / time taken,
Acceleration can be defined as the rate at which an object changes its velocity.
It can be measured in units such as m/s², cm/s², etc.
Here, initial velocity = 25 m/s, Final velocity = 60 m/s time = 5 s.
Hence,
Acceleration= (Final velocity - Initial velocity)/Time
Acceleration = (60 m/s - 25 m/s)/5 s
Acceleration= 35/5
Acceleration= 7 m/s²
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What force is keeping the Earth in orbit around the Sun? * HELP FAST PLEASE.
1 point
A Centripetal Force due to gravity.
B Inertia due to gravity.
C Friction due to gravity.
D Magnetic Force due to gravity.
centripetal force acts *
1 point
A in the same direction as tangential speed.
B perpendicular to tangential speed but in the same plane.
C in the direction opposite tangential speed.
D perpendicular to the plane of circular motion.
Answer:
magnetic force due to gravity
Explanation:
nowno that is because that's what the geography teacher taught us back in don't remember but it's true
A 95 kg falling trunk strikes the ground with a speed of 40 m/s. Assuming that there is no loss of energy due to air resistance, what is the height from which the trunk falls?
Answer:
80 m or 81.3 m
Explanation:
Initially it had no velocity(as at rest). Let the height be h
Using conservation of energy:
Initial KE + PE = final KE + PE
(1/2) m(0)² + mgh = (1/2) m(40)² + mg(0)
mgh = (1/2) m (1600)
2gh = 16000
h = 1600/(2*10) {for g = 10}
h = 80
80 For g = 9.8, h = 81.3 m
Using Newton's eqⁿ of motion:
v² = u² + 2aS
40² = 0² + 2(g)S
1600/2g = S
For g = 10, S = 80 m
g = 9.8, S = 81.33 m
a student is observing an object of unknown mass that is oscillating horizontally at the end of an ideal spring. The student measure the object's period of oscillation with a stopwatch. While the object is continuously oscillating, the student determines the maximum speed of the object during two oscillations. The first speed is 3.5 m/s and the second speed is 2.7 m/s. Which of the following could account for the decrease in the object's maximum kinetic energy?a. Meterstick
b. Motion sensor
c. Balance
d. Photogate
The following could account for the decrease in the object's maximum kinetic energy: Balance. The correct option is C.
The decrease in the object's maximum kinetic energy could be accounted for by using a balance. A balance is a device used to measure mass, and it is not directly related to the object's kinetic energy. The balance measures the gravitational force acting on the object, which remains constant as long as the mass of the object does not change.
The decrease in the object's maximum kinetic energy during oscillation is likely due to the presence of external factors such as air resistance or friction. These factors can cause energy loss in the system, leading to a decrease in the object's maximum kinetic energy over time.
On the other hand, options a (meterstick), b (motion sensor), and d (photogate) are measurement tools that do not directly affect the object's kinetic energy.
A meterstick is used for measuring length, a motion sensor is used to detect motion, and a photogate is used to measure the time it takes for an object to pass through a gate. These tools do not account for the decrease in kinetic energy observed in the object during oscillation. The correct option is C.
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A wagon wheel is a ring (hoop) of mass 77.1 kg and radius 0.630 m. The wagon is moving at 1.22 m/s. What is the TOTAL kinetic energy of the wheel? [?] Remember v = wr Enter
Kinetic energy is the energy that an object possesses due to its motion. Hence, the correct option is [109.5 J].
The formula to calculate kinetic energy is KE = 1/2 mv², where m is the mass of the object and v is its velocity or speed. In this question, the wagon wheel is a ring of mass 77.1 kg and radius 0.630 m. The wagon is moving at 1.22 m/s. We have to calculate the total kinetic energy of the wheel.The velocity of the wagon can be converted into the angular velocity of the wheel by using the formula v = wr. The angular velocity w is calculated as:w = v/rw = 1.22 m/s ÷ 0.630 m ≈ 1.936 rad/sNow that we know the angular velocity of the wheel, we can calculate its total kinetic energy using the formula KE = 1/2 Iw², where I is the moment of inertia of the wheel. For a ring-shaped object, the moment of inertia is given by I = mr².KE = 1/2 Iw²KE = 1/2 (mr²) (w²)KE = 1/2 (77.1 kg) (0.630 m)² (1.936 rad/s)²KE ≈ 109.5 J. Therefore, the total kinetic energy of the wagon wheel is approximately 109.5 J. Note: As per the question, the total kinetic energy of the wheel is required, not of the wagon.
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What is number 5?! I’m so confused.
Answer:
i think it's A
Explanation:
Answer:
The answer is A
Explanation:
Remember that the Sun produces 400 trillion trillion joules per second via the proton-proton chain, and that the Sun has a mass of 2 million trillion trillion kilograms. How many years would the Sun have to shine before one percent of its mass is converted to energy? Your answer should be significant to only one or two digits.
The Sun would have to shine for approximately 2 billion years for one percent of its mass to be converted into energy.
To calculate the time required for the Sun to convert one percent of its mass into energy, we need to determine the total energy the Sun can produce and then calculate the amount of mass that would be converted.
Energy produced per second by the Sun via the proton-proton chain = 400 trillion trillion joules (4 x 10²⁶joules)
Mass of the Sun = 2 million trillion trillion kilograms (2 x 10³⁰ kilograms)
First, we need to calculate the total energy the Sun can produce per year:
Energy produced per year = Energy produced per second × Number of seconds in a year
Number of seconds in a year = 365 days × 24 hours × 60 minutes × 60 seconds
Number of seconds in a year = 31,536,000 seconds
Energy produced per year = 4 x 10²⁶joules/second × 31,536,000 seconds/year
Now, we can calculate the mass that would be converted to energy:
Mass converted to energy per year = Energy produced per year / (Speed of light)²
The speed of light (c) is approximately 3 x 10⁸meters per second.
Mass converted to energy per year = (4 x 10²⁶ joules/second × 31,536,000 seconds/year) / (3 x 10^8 meters/second)²
Now, let's calculate the mass converted to energy as a percentage of the Sun's total mass:
Mass percentage = (Mass converted to energy per year / Mass of the Sun) × 100
Mass percentage = ((4 x 10²⁶ joules/second × 31,536,000 seconds/year) / (3 x 10⁸ meters/second)²) / (2 x 10³⁰ kilograms) × 100
Finally, we can calculate the number of years required for one percent of the Sun's mass to be converted into energy:
Years = 1% / Mass percentage
Years = 1% / ((4 x 10²⁶ joules/second × 31,536,000 seconds/year) / (3 x 10⁸ meters/second)²) / (2 x 10³⁰kilograms) × 100
After performing the calculations, the result is approximately 2 billion years.
The Sun would have to shine for approximately 2 billion years for one percent of its mass to be converted into energy.
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A carbon resistor is 8 mm long and has a constant cross section of 0.3 mm2. The conductivity of carbon at room temperature is σ = 3 ✕ 104 per ohm·m. In a circuit its potential at one end of the resistor is 15 volts relative to ground, and at the other end the potential is 21 volts. A thin copper wire in the same circuit is 8 mm long and has a constant cross section of 0.3 mm2. The conductivity of copper at room temperature is σ = 6 ✕ 107 ohm-1m-1. The copper wire is in series with the carbon resistor in the same circuit mentioned above, with one end connected to the 21 volt end of the carbon resistor. Calculate the resistance R of the copper wire and the potential Vat end at the other end of the wire.
R =___ ohms
V at end = ____V
You can see that for most purposes a thick copper wire in a circuit would have practically a uniform potential. This is because the small drift speed in a thick, high-conductivity copper wire requires only a very small electric field, and the integral of this very small field creates a very small potential difference along the wire.
The resistance (R) of the copper wire in the circuit is 1600 ohms, and the potential (V) at the other end of the wire is 21 volts.
To calculate the resistance of the copper wire (R), we use the formula R = (ρ * L) / A, where ρ represents the resistivity of the material, L is the length of the wire, and A is the cross-sectional area. In this case, the length of the copper wire is 8 mm (0.008 m), and the cross-sectional area is 0.3 mm^2 (0.3 * 10^(-6) m^2). With the resistivity of copper being 6 * 10^7 ohm^(-1) m^(-1), we can calculate the resistance as follows: R = (6 * 10^7 ohm^(-1) m^(-1) * 0.008 m) / (0.3 * 10^(-6) m^2), which gives us 1600 ohms. Since the copper wire and the carbon resistor are connected in series in the circuit, the potential difference (V) across each component is the same. In the case of a thick, high-conductivity copper wire, the small drift speed of electrons requires only a very small electric field, resulting in a negligible potential difference along the wire. As a result, the potential throughout the thick copper wire remains practically uniform.
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The Brazilian rain forest is an area with significant biodiversity.
As the rain forest is replaced with agricultural land, it is
reasonable to predict a reduction in -
consumption of solar energy.
sustainability over time.
precipitation levels.
average daily temperature.
Answer:
sustainability over time.
Explanation:
The largest Brazilian rainforest is the Amazon rainforest, which is the largest rainforest in the world and occupies 42% of the Brazilian territory. The forest is composed of a rich environmental diversity, constituted by many species of fauna and flora and diverse river resources.
However, there is a growing transformation in the Amazon rainforest caused by organizational exploitation that uses its resources to transform the forest area into agricultural land and pastures for livestock. This problem will cause a reduction in sustainability over time, which will cause serious negative effects on the environment, such as a reduction in biodiversity and an increase in the emission of gases responsible for the greenhouse effect on the planet.
Answer:
Bb
Explanation:
a thin-walled, hollow sphere of mass m and radius r is free to rotate around a vertical shaft that passes through the center of the sphere. initially, the sphere is at rest. a small ball of clay of the same mass m moving horizontally at speed v grazes the surface of the sphere at its equator. after grazing the surface, the ball of clay is moving at speed v/2 . what is the angular momentum of the ball of clay about the shaft before it grazes the surface? express your answer in terms of the variables
The angular momentum of the ball of clay before grazing the surface is (2/3)mrv.
What is the angular momentum of the sphere?The angular momentum of the ball of clay about the shaft before it grazes the surface is calculated as follows;
Moment of inertia of the ball;
I = (2/3) mr²
where;
m is the mass of the spherer is its radius.Angular velocity is given as;
ω = v / r
where;
v is linear velocityr is the radiusThe angular momentum of the ball of clay before grazing the surface is calculated as;
L = Iω
L = (2/3)mr² x (v / r)
L = (2/3)mrv
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An electron moves left to right in the plane of the page when it enters a magnetic field going into the page. The acceleration of the electron is
A- up
B- down
C- direction of motion
D- opposite direction of motion
E- into page
F- out of page
The required correct answer would be either A (up) or B (down), depending on the specific configuration of the magnetic field and the motion of the electron.
The direction of the acceleration of the electron depends on the interaction between the magnetic field and the motion of the electron. According to the right-hand rule for magnetic fields, the direction of the acceleration can be determined as follows:
Extend the right hand with the thumb pointing in the direction of the electron's velocity (left to right).
Curl the fingers of the right hand in the direction of the magnetic field (into the page).
The direction in which the palm of the hand faces indicates the direction of the acceleration.
Using this right-hand rule, we can determine that the acceleration of the electron will be perpendicular to both the velocity and the magnetic field. Therefore, the acceleration will be either up or down, depending on the specific orientation of the magnetic field and the motion of the electron.
Given the options provided, the correct answer would be either A (up) or B (down), depending on the specific configuration of the magnetic field and the motion of the electron.
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Which one of the following items contains matter in the plasma state?
Stars
liquid water
ice cubes
Answer:
Stars i think
Explanation:
how many oxygen atoms are there in the products of this equation: C6H12O6+6O2 ➪6CO2+6H2O+energy?
Air containing 0.06% carbon dioxide is pumped into a room whose volume is 300 m3. The air is pumped in at a rate of 60 m3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount A(t), in mº, in the room at time t.
The subsequent amount A(t), in mº, in the room at time t is A(t) = (0.0006 * 60 - 0.002 * 60) * t = (-0.00084) * t
To determine the subsequent amount A(t) of carbon dioxide in the room at time t, we can use the formula A(t) = (C_in * V_in - C_out * V_out) * t, where C_in is the initial concentration of carbon dioxide, V_in is the volume of air pumped into the room per unit of time, C_out is the concentration of carbon dioxide in the circulated air, V_out is the volume of air pumped out of the room per unit of time, and t is the time in minutes.
Given the values C_in = 0.2%, V_in = 60 m³/min, C_out = 0.06%, V_out = 60 m³/min, and t is the desired time, we can substitute these values into the formula to calculate the subsequent amount of carbon dioxide in the room at time t.
Substituting the given values, we have A(t) = (0.0006 * 60 - 0.002 * 60) * t = (-0.00084) * t. Since the coefficient of t is negative, it indicates that the subsequent amount of carbon dioxide in the room will decrease over time.
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the planet that has the lowest density is _____ while the planet that is tilted 90° to the orbital plane is _____.
The planet that has the lowest density is Saturn, while the planet that is tilted 90° to the orbital plane is Uranus.
Which planet has the least density, and which one is tilted 90° to its orbital plane?Saturn, the second-largest planet in our solar system, has the lowest average density among all the planets. With its famous rings made up of icy particles and rocky debris, Saturn has an average density of about 0.687 grams per cubic centimeter. This low density is primarily due to its composition, which includes a significant amount of hydrogen and helium, making it less dense than water.
On the other hand, Uranus, the seventh planet from the Sun, holds a peculiar distinction in our solar system. It is tilted approximately 98 degrees, which means its axis is almost perpendicular to the plane of its orbit. This extreme tilt causes Uranus to experience dramatic seasonal variations, where one pole faces the Sun continuously for half of its orbit, while the other pole faces prolonged darkness. This unique axial tilt sets Uranus apart from the other planets, making it the planet tilted 90° to its orbital plane.
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Select the correct answer. A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car? A. The net force acting on the car from all directions is zero. B. The net force acting on the car is greater than the car's weight. C. The net force acting on the car is in the direction of the car's motion. D. The net force acting on the car is in the opposite direction of the car's motion.
Answer:
i think try theanswer
Explanation:
proper
Answer:
A
Explanation:
For an object to move with constant speed the forward force is opposed by the effects of forces. There is no resultant force acting or constant speed is a result of no resultant force.
Newton's second law states that an object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Newton's Second Law states: F = ma. F is the net force acting on an object.
Also if velocity or speed is constant the acceleration will be 0 the F=m×0
F=0.
A 72.0 kg ice skater is moving at 3.1 m/s on frictionless ice throws a 0.21 kg snowball horizontally at a speed of 28.0 m/s. What is the final velocity of the skater?
Answer:
the final velocity of the skater after throwing the snowball is 3.17 m/s.
Explanation:
Given;
mass of the ice skater, m₁ = 72 kg
initial velocity of the ice skater, u₁ = 3.1 m/s
mass of the snowball, m₂ = 0.21 kg
initial speed of the snowball, u₂ = 28.0 m/s
Let the final velocity of the skater after throwing the snowball = v
Apply the principle of conservation of linear momentum to determine v;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
72 x 3.1 + 0.21 x 28 = v(72 + 0.21)
229.08 = v(72.21)
v = 229.08 / 72.21
v = 3.17 m/s
Therefore, the final velocity of the skater after throwing the snowball is 3.17 m/s.
n2 Find a linear homogeneous recurrence relation with constant coefficients that the sequence An = (n-3) (2") + NEN 2n satisfies. Do not forget to specify initial values.
The linear homogeneous recurrence relation with constant coefficients that the sequence is: An = -(-1)n + (3)n or An = (1)n + (3)n
The sequence An = (n-3)(2n) + n(2n) satisfies the linear homogeneous recurrence relation with constant coefficients. In order to prove this, we need to first find the general formula of the sequence.
The formula can be found by replacing n with n+1 as follows:
An+1 = (n+1-3)(2n+2) + (n+1)(2n+2)
An+1 = n(2n+4) + (n+1)(2n+2)
An+1 = 2n² + 4n + 2n² + 4n + n + 2n + 2
An+1 = 4n² + 7n + 2
The characteristic equation of the linear homogeneous recurrence relation is given by:
r² - 2r - 3 = 0
Solving this quadratic equation, we get:r = -1 or r = 3
Hence, the general formula of the sequence is given by:An = A(-1)n + B(3)n
Now, we need to find the values of A and B using the initial values of the sequence. The first two terms of the sequence are given by:
A0 = -6 and A1 = 2
Substituting these values in the general formula, we get:
-6 = A + B2 = -A + 3B
From the above two equations, we can solve for A and B to get:
A = -1 and B = 1
Hence, the linear homogeneous recurrence relation with constant coefficients that the sequence An = (n-3)(2n) + n(2n) satisfies is given by:
An = -(-1)n + (3)n or An = (1)n + (3)n
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What is the maximum flow rate of water in a smooth pipe 8.0 cm diameter if the flow is to be laminar
Answer:
0.05 m/s
Explanation:
We start by finding the average velocity of water in the pipe. This is done by saying
R(e) = ρv(avg)d/μ
Where,
R(e) = Reynolds number, and that's 2000
ρ = Density of water, 1000 kg/m³
μ = Viscosity of water, 10^-3
d = diameter of pipe
v(avg) = average velocity
Since we're interested in average velocity, we make v(avg) the subject of formula. So that
V(avg) = R(e).μ/ρ.d
V(avg) = 2000 * 10^-3 / 1000 * 0.08
V(avg) = 2 / 80
V(avg) = 0.025 m/s
The maximum flow rate of water in the pipe usually is twice the average velocity, and as such
V(max) = 2 * V(avg)
V(max) = 2 * 0.025
V(max) = 0.05 m/s
irina is told to use a meter stick to find the length of a room. she makes six independent measurements: 4.402 m, 4.217 m, 4.345 m, 4.925 m, 4.372 m, 4.289 m. how should she report the best estimate of the length of the room? 01
Irina should report the best estimate of the length of the room as 4.425 meters.
Irina should report the best estimate of the length of the room by calculating the average of all the measurements.
The average of the six independent measurements can be found using the formula:
Average = (Sum of measurements) / (Total number of measurements)
Therefore, the average of the six independent measurements can be calculated as follows:
Average =
(4.402 m + 4.217 m + 4.345 m + 4.925 m + 4.372 m + 4.289 m) / 6
= 26.55 / 6= 4.425 m
This is the best estimate of the length of the room because it is the average of all the independent measurements made by Irina.
In science, measurements play a vital role. Scientists use a range of tools to measure things, from simple ruler or meter stick to highly sophisticated equipment. It is crucial for the measurements to be as precise and accurate as possible because any error in the measurement can affect the results of experiments.
To minimize the error in measurement, scientists often make multiple measurements and then report the average of those measurements as the best estimate of the measurement.
This process is known as taking the average, or mean, of the measurements. In the example given above, Irina made six independent measurements of the length of the room using a meter stick. She then calculated the average of those measurements and reported it as the best estimate of the length of the room.
This method is widely used in science to minimize the error in measurement and to ensure that the results of experiments are as accurate as possible.
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Use the drop-down menus to complete the statements. Outlook allows users to insert symbols and characters not located on the , but they can have shortcut keys. Inserting horizontal lines in the message body breaks up different sections and mostly benefits people using Outlook on .
Answer:
Keyboard and Mobile devices
Explanation:
got it right on edge 2021
Answer:
Outlook allows users to insert symbols and characters not located on the
keyboard
, but they can have shortcut keys.
Inserting horizontal lines in the message body breaks up different sections and mostly benefits people using Outlook on
mobile devices
.
Explanation:
How are light waves used to bring far away objects into view and how does the eye translate them?
HELPPP
Answer:
When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.
Explanation:
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1) longer storms should print in the correct order, with 200ms between each event in the array and 400ms between each flash! and boom!
For accurate printing of longer storms, it is important to ensure that the events in the array are arranged in the correct order, with a 200ms delay between each event and a 400ms delay between each flash and boom.
When printing longer storms, it is crucial to maintain the correct order of events in the array. By arranging the events in the correct sequence, the storm will be printed accurately, providing a realistic representation. To achieve this, a delay of 200ms should be implemented between each event in the array. This delay ensures that each event is printed with the appropriate timing, creating a smooth and coherent storm simulation.
Additionally, it is necessary to introduce a 400ms delay between each "flash" and "boom" in the storm. This delay creates a distinct gap between these two elements, mimicking the natural occurrence of a lightning flash followed by the accompanying thunder. By allowing sufficient time between the flash and boom, the printed storm will convey a more realistic and immersive experience.
In summary, to accurately print longer storms, it is essential to maintain the correct order of events in the array and introduce appropriate delays. A 200ms delay between each event ensures accurate timing, while a 400ms delay between each flash and boom replicates the natural occurrence of lightning and thunder. Following these guidelines will result in a more realistic representation of storms when printing them.
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