Two parallel chord of length 30 and 16 cm are drawn on the oppoite ide of the centre of the circle of radiu 17 cm. Find the ditance between the chord
Answers
the distance between the chord is 23 cm
It is given that AB = 30cm and CD = 16cm
Join the lines OA and OC
We know that AO = 17cm and CO = 17cm
Construct OM ⊥ CD and OL ⊥ AB
The perpendicular from the centre of a circle to a chord bisects the chord
We know that
AL = ½ × AB
By substituting the values
AL = ½ × 30
So we get
AL = 15cm
We know that
CM = ½ × CD
By substituting the values
CM = ½ × 16
So we get
CM = 8cm
Consider △ ALO
Using the Pythagoras theorem it can be written as
AO^2 = OL^2 + AL^2
By substituting the values
17^2 = OL^2 + 15^2
So we get
OL^2 = 17^2 - 15^2
On further calculation
OL^2 = 289 – 225
By subtraction
OL^2 = 64
By taking the square root
OL = √64
OL = 8cm
Consider △ CMO
Using the Pythagoras theorem it can be written as
CO^2 = CM^2 + OM^2
By substituting the values
17^2 = 82 + OM^2
So we get
OM^2 = 17^2 - 8^2
On further calculation
OM^2 = 289 – 64
By subtraction
OM^2 = 225
By taking the square root
OM = √225
OM = 15cm
So the distance between the chords = OM + OL
By substituting the values
Distance between the chords = 8 + 15 = 23cm
Therefore, the distance between the chords is 23 cm.
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Answers
Answer:
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
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Answers
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Answers
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answers
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Answers
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Answers
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For every number other than x = 1/2, the function takes on every possible real numbers, since 1/2 x + 7/4 alone takes on all real numbers.
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Step-by-step explanation:
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
....ur welcome........
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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