two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415 N

Answer:

The field will remain the same

Explanation:

This is because electric field given as

E1= kq1/r²

And that of second charge

E² = kq2/r²

Is not affected by the size of the second charge q2

Answer:

It's actually C. food webs

Explanation:

took the test

Answer: c

Explanation:

edge 2020

Answer:

B).315mph

Explanation:

Let the speed of the plane = p

Let the speed of the wind = w

Set up the system equation as;

                                     Relative V:               Time:                          Distance:

in wind direction:          p + w                         2                                  700

against wind:                 p - w                         2.5                                700

2(p + w) = 700

2.5(p - w) = 700

2p + 2w = 700

2.5p - 2.5w = 700

2.5  x:     5p + 5w = 1750

2  x:        5p - 5w = 1400

10p = 3150

p = 315 mph

Therefore, he speed of the plane in still air is 315 mph

Answer:

Jims is better

Explanation:

His number is more complex which means it is more accurate

Answer:

1- origin

2- y coordinate

3- y axis

4- x axis

5- x coordinate

Explanation:

Answer:

[tex] \boxed{\sf Distance \ travelled = 44 \ m} [/tex]

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

[tex] \boxed{ \bold{s = (\frac{v + u}{2} )t}}[/tex]

By substituting value of v, u & t in the equation we get:

[tex] \sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\ \\ \sf \implies s = \frac{22}{2} \times 4 \\ \\ \sf \implies s = 11 \times 4 \\ \\ \sf \implies s = 44 \: m[/tex]

[tex] \therefore[/tex]

Distance travelled by car (s) = 44 m

Answer:

Energy transfer is the movement of energy from one location to another. Energy transformation is when energy changes from one type to another. While energy can be transferred or transformed, the total energy always remains the same.

Explanation:

Answer: The SI unit

Explanation: The SI units are used to describe the distance an object moves

Answer:because each individual works best at a different time of day. D. because scheduling prevents everyone from studying at a set time. emilleexo818 is waiting for your help.

Explanation:

Answer:

The correct and overall question would be: Because each individual works best at a different time of day

Explanation:

(I'm smart and I took the quiz, I hope this helped guys! :)

Answer:

true

Explanation:

i did the test its right

Answer:

true

mark mine as brainiest, i could use the points

Answer:

Explanation:

The recommendations that need to be urgently addressed by the workshop and it's employees are

1) Training of all employees (particularly the tool operators) on the safe and proper use of all tools used in the course of the carpentry work.

2) Training of all employees in health, safety and environment (HSE). This training will help them appreciate the importance of always wearing personal protective equipment (PPE) when at the workshop or during the course of a work (because if the apprentice was putting on an engineer's helmet, he could have been safe).

3) Employees who fail to adhere strictly to the use of PPE should be sanctioned or even dismissed from the workplace

Answer: acceleration

Explanation:

he is accelarting from 3 meters per second to 5 meters per second

Answer:

acceleration

Explanation:

Answer:

Explanation:

Using one of the equation of motion v = u + at where;

v is the final velocity = 0m/s (the ball comes to rest after throw)

u is the initial velocity = 46m/s

a is the acceleration = -5m/s² (the body decelerates)

t is the time taken by the ball in air

substituting the given parameters into the formula to get t, we will have;

0 = 46 +(-5)t

0 = 46 - 5t

subtract 46 from both sides

0-46 = 46-5t-46

-46 = -5t

Divide both sides by -5

-46/-5 = -5t/-5

t = 46/5

t = 9.2seconds

Hence it will take the ball 9.2seconds in the air before coming to rest.

Answer: 9.2sec

Explanation. 9.2sec

Explanation:

A=23.5-12.1/7.81

1.46

b)(18.9^2-(33.4)^2)/2(109)

-3.5

c)8.9^2-(21.5)^2/2(109)

-1.76

Answer:

Her final displacement is 0.4 km North

Her total distance is  8.2 km

Explanation:

Given;

initial position, = 2.5 km north

then 4.3 km south

final position = 1.4 km north

let northward direction = positive direction

let southward direction = negative direction

The final displacement = 2.5 km North - 4.3 km South + 1.4 km North

The final displacement = -0.4 km North

Thus, the magnitude of the final displacement = 0.4 km North

In distance, the direction of the motion is not considered

The total distance = 2.5 km + 4.3 km + 1.4 km

The total distance = 8.2 km

Answer:

0.25 second  

Explanation:

Given :

Velocity, v = 10 m/s

The height,

[tex]$ h = \frac{v^2}{2g} $[/tex]

[tex]$ h = \frac{10^2}{2\times 9.8} $[/tex]

   = 5 m

Therefore the time at which both the bodies meet is

[tex]$ t = \frac{h}{v+v} $[/tex]

[tex]$ t = \frac{5}{10+10} $[/tex]

[tex]$ t = \frac{5}{20} = 0.25$[/tex]

So, time taken is 0.25 seconds

Answer:

0 [tex]\leq[/tex] t [tex]\leq[/tex] 40

Explanation:

Apex :)

Answer:

The correct option is;

C. The direction of the acceleration is the same direction as that of the net force, which is parallel to the ground

Explanation:

Newton's second law of motion states that the acceleration which a net force on an object  produces has a magnitude that is directly proportional to that of the magnitude of the net force, and the direction of the acceleration is the same as that of the net force that produces it.

Therefore, given that the net force which tends to push the lawn mower across the grass acts parallel to the ground, the direction of the is in the same direction of the net force, moving parallel the ground.

Answer:

If you say it like this (x^10)^10, then it would be x^100.

Answer:

46m

Explanation:

Given the following :

Initial Velocity (u) = 60

Angle(θ) = 30°

Maximum height it will reach?

The maximum height if a projection is calculated using the formula :

H = u²sin²θ / 2g

Where H = maximum height, g = acceleration due to gravity = 9.8m/s²

H = (60²sin × 0. 5²) / 2(9.8)

H = 900 / 19.6

H = 45.918m

H = 46m

Answer:13.6

Explanation:

Answer:

From the figure,

The free-body diagrams for  and  are shown in the figures below. The only forces on the blocks are the upward tension  and the downward gravitational forces  and  . Applying Newton’s second law, we obtain:   

which can be solved to yield 

Substituting the result back, we have 

(a) With  and , the acceleration becomes   

(b) Similarly, the tension in the cord is   

Answer: the father of the nuclear physics is Ernest Rutherford

Explanation:

Answer:

Explanation: societal law is A statement about how things act in the natural world. the wire and electro magnet need to touch in question 2. a decrease in spee decreases kinetic energy. the test variable was the distance traveled by the scrunched paper.

Answer:

B

Explanation:

The shape is the only thing that changes.

Answer:

26.85 Celsius.

493.15 Kelvin

86F

26.85

493.15

Tk=Tc+273.15

Answer: a) B = 6811N

              b) m = 603.2kg

              c) 86.8%

Explanation: Buoyant force is a force a fluid exerts on a submerged object.

It can be calculated as:

[tex]B=\rho_{fluid}.V_{obj}.g[/tex]

where:

[tex]\rho_{fluid}[/tex] is density of the fluid the object is in;

[tex]V_{obj}[/tex] is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

[tex]B=10^{3}.0.695.9.8[/tex]

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are Buoyant, Tension and Force due to gravity:

B = T + [tex]F_{g}[/tex]

B = T + mg

mg = B - T

[tex]m=\frac{B - T}{g}[/tex]

Calculating:

[tex]m=\frac{6811 - 900}{9.8}[/tex]

m = 603.2kg

c) When the shpere comes to rest on the surface of the water, there are only buoyant and gravity acting on it:

B = m.g

[tex]\rho_{w}.V_{sub}.g=m.g[/tex]

[tex]V_{sub}=\frac{m}{\rho_{w}}[/tex]

[tex]V_{sub}=\frac{603.2}{1000}[/tex]

[tex]V_{sub}[/tex] = 0.6032m³

Fraction of the submerged volume is:

[tex]\frac{V_{sub}}{V_{obj}}[/tex] = [tex]\frac{0.6932}{0.695}[/tex] = 0.868

Answer:

1. 180 m

2. 1.5 miles/hour

3. 0 m/s

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = 180 m

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = 1.5 miles/hour

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = 0 m/s

Answer:

1) 3 applications of pressure in daily life are :-

● The area of sharp edge of knife, scissor or handsaws are much less then blunt edge. So, for same total force pressure is more for sharp edges than the blunt one. Hence sharp knife, scissors etc, cuts easily than a blunt one.

●Broad handles in bags and suitcases are provided for the comfort. Broad handles have large area. So, the pressure exerted on hands and shoulders would be small while carrying the bags and the suitcases.

●Trucks carrying heavy loads have more than four tyres. More tyres in case of trucks increase the area of contact with the road. This results in reduced pressure on the tyres.

2) Area of the surface which is on ground = 1.5×1

= 1.5m^2

Mass of the block = 300kg

Force applied by the block = Mass × g = 300×10

= 3000N (where g = acceleration due to gravity )

Pressure = Force applied / Area of the surface

= 3000N / 1.5m^2

= 2000 Pa

3)

a) The above experiment signifies that more the area of the surface of an object , less the pressure an object applies.

b) B exerts the minimum pressure because the area of its surface to ground is greater than others & as it has more area of surface , it exerts less pressure. ( area is inversely proportional to pressure )

c) D exerts the maximum pressure because the area of its surface to ground is lesser than others & as it has less area of surface , it exerts more pressure. ( area is inversely proportional to pressure )

d) It depend upon the way an object is kept on ground. If an object is kept in such a way dat the area of the surface to the ground is more , then pressure will be least exerted .If an object is kept in such a way dat the area of the surface to the ground is less, then pressure will be exerted more .

e) Do it yourself . only i will suggest that make the tip of the cone ( which is to the ground ) more narrower.

Explanation:

Answer:

I think it would be muscle

Explanation:

bones strengthened by calcium

aerobics is more of a gymnastical exercise

leaving a muscle strengthen

Answer:

Technically all 3

Explanation:

Include activities that make their hearts beat faster, build muscles (like climbing or doing push-ups), and strengthen bones (like running or jumping).

Traditional pushups are beneficial for building upper body strength. They work the triceps, pectoral muscles, and shoulders. When done with proper form, they can also strengthen the lower back and core by engaging (pulling in) the abdominal muscles. Pushups are a fast and effective exercise for building strength.Jun 22, 2018

Aerobic exercise (also known as cardiovascular exercise) builds your endurance. Anaerobic exercise typically means activities such as weightlifting and push-ups and sit-ups, which builds muscle and physical strength through short bursts of strenuous activity.