Answer: b1/b1=h1/h2=10/12=15/h2 so use criss cross and equel to 15×12=10h2 both sides devide by 10 and equel 180/10=18
so h2=18
ten students in Ashton class were randomly selected and asked how many phone call they made yesterday their answer where 1,0,10,2,9,15,0 and 3 find the mean of the data find the median of the data find the mode of the data find the range of the data
Answer:
Mean = 2.2
Median = 1
Mode = 0 and 1
Range = 9
Step-by-step explanation:
First arrange the number of calls from least to greatest.
0, 0, 0, 1, 1, 1, 2, 3, 5, 9
Mean is the average. Add the numbers together and divide by 10 since there are 10 numbers in total.
0 + 0 + 0 + 1 + 1 + 1 + 2 + 3 + 5 + 9 = 22
22/10 = 2.2
Mean = 2.2
Median is the middle number. Since there is an even amount of numbers, take the 5 and 6 number in the list, add them together and divide by 2. You are taking the average of the two numbers.
0, 0, 0, 1, 1, 1, 2, 3, 5, 9
1 + 1 = 2
2/2 = 1
Median = 1
Mode is the number that occurs the most.
0, 0, 0, 1, 1, 1, 2, 3, 5, 9
In the list the numbers 0 and 1 both occur 3 times.
Mode = 0 and 1
Range is the biggest number (9) minus the smallest number (0).
0, 0, 0, 1, 1, 1, 2, 3, 5, 9
9 - 0 = 9
Range = 9
Help asap immediately
[tex] \frac{9}{8 \: } = 1 \frac{1}{8} [/tex]
HOPE THIS HELPS :)[tex] \sf \frac{9}{8} [/tex]
Step-by-step explanation:
[tex] \sf9 \div 8 = 1(1left)[/tex]
[tex]1 \frac{1}{8} [/tex]
#Hopethishelp
_______
Moumocl!
The box plot shows the number of home runs hit by 43 players during a baseball season.
Which statement best describes the data?
The number of data values between the lower
quartile and the median is less than the
number of data values between the upper
quartile and the median.
2
9
15 19
28
The number of data values between the lower
quartile and the median is greater than the
number of data values between the upper
quartile and the median.
|++++++
0 4 8 12 16 20 24 28 32
The spread between the lower quartile and
the median is less than the spread between
the upper quartile and the median.
The spread between the lower quartile and
The statement fourth "The spread between the lower quartile and the median is greater than the spread between the upper quartile and the median" is correct.
What is the box and whisker plot?A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.
The box plot is missing.
The box plot is shown (please refer to attached picture)
The given options are:
The number of data values between the lower quartile and the median is less than the number of data values between the upper quartile and the median.The number of data values between the lower quartile and the median is greater than the number of data values between the upper quartile and the median.The spread between the lower quartile and the median is less than the spread between the upper quartile and the median.The spread between the lower quartile and the median is greater than the spread between the upper quartile and the median.As we know the property of box plot the difference between the lower and higher quartiles is greater than the difference between the upper and lower quartiles.
The spread between the lower quartile and the median:
= 15 - 9 = 6
= 19 - 15 = 4
Thus, the statement fourth "The spread between the lower quartile and the median is greater than the spread between the upper quartile and the median" is correct.
Learn more about the box and whisker plot here:
brainly.com/question/3209282
#SPJ1
A card is drawn from a deck of 52 cards what is the probability that it is a number 2?
Answer:
Step-by-step explanation:
Remark
The deck is divided into 4 different kinds of cards
clubs
diamonds
Hearts
Spades
Each kind of card has a 2
So there are 4 twos in a standard deck of cards.
Answer:
P(2) = 4/52P(2) = 1/13P(2) = 0.07692the the radius of a sphere is 8 cm. find the volume. round off to nearest tenth if necessary. use 3.14 for pi
The volume of the given sphere.
Solution:[tex]\large\boxed{Formula:V = \frac{4}{3} \pi {r}^{3}}[/tex]
[tex]\large\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}[/tex]
Let's solve
Substitute the values according to the formula.
[tex]V = \frac{4}{3} \times 3.14 \times {8}^{3} [/tex]
[tex]V = 2143.573333 \: {cm}^{3} [/tex]
[tex]\large\boxed{= 2143.6 \: {cm}^{3} \: (nearest \: tenth)}[/tex]
Hence, the volume of the given sphere is 2143.6 cubic centimeters.
Fizer Pharmaceutical paid $78 million on January 2, 2021, for 6 million shares of Carne Cosmetics common stock. The investment represents a 25% interest in the net assets of Carne and gave Fizer the ability to exercise significant influence over Carne’s operations. Fizer received dividends of $2 per share on December 21, 2021, and Carne reported net income of $28 million for the year ended December 31, 2021. The fair value of Carne’s common stock at December 31, 2021, was $28.50 per share.
The book value of Carne's net assets was $192 million.
The fair value of Carne's depreciable assets exceeded their book value by $48 million. These assets had an average remaining useful life of twelve years.
The remainder of the excess of the cost of the investment over the book value of net assets purchased was attributable to goodwill.
Prepare the appropriate journal entries related to the investment during 2021. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Enter your answers in millions, (i.e., 10,000,000 should be entered as 10).)
The appropriate journal entries related to the investment during 2021 is: Debit Investment in Carne shares $78 million; Credit Cash $78 million.
Journal entriesJanuary 2, 2021
Debit Investment in Carne shares $78 million
Credit Cash $78 million
January 12, 2021
Debit Cash $12,000,000
($2 per shares x 6,000,000)
Credit Investment in Carne shares $12,000,000
December 21, 2021
Debit Investment in Carne shares $7,000,000
Credit Investment revenue $7,000,000
(25% x $28,000,000)
December 31, 2021
Debit Investment revenue $1,000,000
Credit Investment in Carne shares $1,000,000
[25% x ($48,000,000 ÷ 12 years)]
December 31, 2021
No journal entry for changes in fair value when using equity method.
Therefore the appropriate journal entries related to the investment during 2021 is: Debit Investment in Carne shares $78 million; Credit Cash $78 million.
Lear more about journal entries here:https://brainly.com/question/14279491
#SPJ1
Determine the probability of the treatment group’s mean being greater than the control group’s mean by 8 points or more. Then complete the statements.
The significance level is set at 5%, and the probability of the result is
%, which is
the significance level. The result is
.
The probability of the treatment group’s mean being greater than the control group’s mean by 8 points or more is 0.036.
How to calculate the probability?The probability of the treatment group’s mean being greater than the control group’s mean by 8 points or more will be:
= (26 + 8 + 2)/1000
= 36/1000
= 0.036
The significance level is set at 5%, and the probability of the result is statistically significant because the probability of the difference is less than 5% significance level.
Learn more about probability on:
brainly.com/question/24756209
#SPJ1
find 3 solutions for y=-2x-4
This is for a test please answer
Answer:
25 = b
26 = c
Step-by-step explanation:
Type the correct answer in the box.
The value of is .
With full explanation from the internet like before
3x2-6x+5=0
Answer:
[tex]\sf x=1+i\sqrt{\dfrac{2}{3}} \ \quad and \quad \:x=1-i\sqrt{\dfrac{2}{3}}[/tex]
Explanation:
Given Expression:
3x² - 6x + 5 = 0Use the Quadratic Formula:
[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ \ ax^2 + bx + c = 0[/tex]
insert coefficients
[tex]\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}[/tex]
[tex]\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}[/tex]
[tex]\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}[/tex]
[tex]\Longrightarrow \sf x =1 \pm i\dfrac{\sqrt{6} }{3}[/tex]
[tex]\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}}, \quad 1-i\sqrt{\dfrac{2}{3}}[/tex]
Use quadratic formula
[tex]\\ \rm\Rrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm \sqrt{36-60}}{6}[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm\sqrt{-24}}{6}[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm2\sqrt{6}i}{6}[/tex]
[tex]\\ \rm\Rrightarrow x=1\pm \dfrac{sqrt{2}i}{\sqrt{3}}[/tex]
[tex]\\ \rm\Rrightarrow x=1\pm\sqrt{\dfrac{2}{3}}i[/tex]
A dentist has 420 male and female patients that range in ages from 10 years old to 50 years old and up as shown in the table.
What is the experimental probability that the next patient will be female and in the age range 22-39?
The experimental probability that the next patient will be female and in the age range 22-39 is 56/420
What is the experimental probability?Probability is the odds that a random event would happen. The odds usually lie between 0 and 1.
The experimental probability = number of female in the age range 22-39 / total number of patients
= 56/420
To learn more about experimental probability, please check: https://brainly.com/question/23722574
#SPJ1
Solve for x
x/8 = 3/5 give your answer as an improper fraction in its simplest form
Answer:
24/5
Step-by-step explanation:
x is 4.8, improper simplified is 24/5
quadrilateral ABCD with angle B of 72 degree, angle C of 130 degrees, angle D of 67 degrees What is the measure of ∠A?
Answer:
[tex]m\angle A = 91^{\circ}[/tex]
Step-by-step explanation:
All angles in a quadrilateral must add up to [tex]360^{\circ}[/tex], so [tex]\angle A + \angle B + \angle C + \angle D = 360^{\circ}[/tex]
We can now solve for [tex]\angle A[/tex] by substituting [tex]\angle B, \angle C, \angle D[/tex] for the correct values.
[tex]\angle A + \angle B + \angle C + \angle D = 360\\\angle A + 72 + 130 + 67 = 360\\\angle A + 269 = 360\\\\\boxed{\angle A = 91^{\circ}}[/tex]
That is the answer
- Kan Academy Advance
Please help! I’m really confused on this question
Answer:
noncollinear
Step-by-step explanation:
my guess sorry if im wrong
3(5z - 7) - 2 (9z - 11) = 4 (8z - 13) - 17
Answer z=2
See picture attached for the math
please help! easy! it is due right now!!
Answer:
3 Cups of flour.
Step-by-step explanation:
Jenna is a part-time receptionist at
the dentist's office. Her income last
year was $9,125. Her tax status is
single, she claims one exemption for
herself, and she plans on taking the
standard deduction. What is her
taxable income?
From the information provided, Jenna's taxable income is zero. See the explanation below.
How do you calculate taxable income?The formula for taxable income is given as:
Gross Income Less Standard Deduction.
Since the current effective standard deduction for singles is $12,950 Jenna doesn't need to file a tax return since tax cannot be a negative figure.
it is to be noted that the rate payable for individual single taxpayers in 2022 is $10% up to $10,275.
Learn more about Taxable income at:
https://brainly.com/question/24732919
#SPJ1
I NEED HELP ASAP!!!
Amalia and Alec are studying the growth of a plant over time. They measure the height of the plant at the end of each week for several weeks and display the data in a scatter plot. They then find the equation for the best-fit line to be y=2.5 + 1.25rMULTIPLE CHOICE Question 7 Amalia and Alec are studying the growth of a plant over time. They measure the height of the plant at the end of each week for several weeks and display the data in a scatter plot. They then find the equation for the best-fit line to be y= 2.5 + 1.25x
X = the number of weeks that have passed
= the height of the plant
They want to use the equation to estimate when the height of the plant will be 10
Amalia's estimate is after 6 weeks.
Alec's estimate is after Week 15.
Is either student correct?
Amalia would be correct. They are guessing when the height would be 10, and you are given an equation that will 'predict' that. Height is y, so substitute 10 in the equation and solve for x. You will get x=6
Which expressions will help you find the surface area of this right triangular prism? Select all that apply.
38 × 45
1/2 × 36 × 45
45 × 36
1/2 × 36 × 38
what is the answer here
Answer:
120m²
Step-by-step explanation:
Area¹ = (6*5) = 30*2 surfaces = 60m²
Area² =(6*6) = 36m²
Area of Triangle =(1/2*4*6) = 12* 2 surfaces = 24m²
Total surface area = 60 + 36 + 24 = 120m²
=/120m²
If a tree grew 5 feet in n years, what was the average rate at which the tree grew, in inches per year?
Answer:
0.01
Step-by-step explanation:
so i divided 5 by 365 because 365 days or in a year so 5/365=0.01369863013 and usually just said as 0.01
Hope This Helped
**Find the perimeter of the region.**
The circle are congruent to each other.
The circles are tangent to each other, and the straight
segments are tangent to the circles.
The straight
segments are 5 units long.
Find the perimeter of the region.**
The circle are congruent to each other.
The circles are tangent to each other, and the straight
segments are tangent to the circles.
The straight
segments are 5 units long
Which of the following solutions to the inequality -7x+14>-3x -6? Select all that apply
-10
10
-5
5
-3
3
0
I went thru it and im pretty sure that only these work
-10
-5
-3
willams bought piece of woods that is 3 feet long.he cuts it in to two pieces.one piece is 14 in long how long is the other piece
Answer:
22 inches
Step-by-step explanation:
3 feet = 36 inches
36-14=22
The other half is 22 inches long
Determine whether these two ratios make a proportion 5/9, 56/99. True or False
Answer: The answer is True .
The statement is false, these two ratios don't make a proportion.
What is ratio?The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
here, we have,
5/9, 56/99
we know, that, two ratios make a proportion if, a:b=c:d
but, here,
5/9= 5:9
56/99 = 56: 99
Hence, The statement is false, these two ratios don't make a proportion.
To learn more on ratio click:
brainly.com/question/13419413
#SPJ5
Find the interquartile range (IQR) of the data in the dot plot below VV
(PLS HELP ME PLSSS)
The interquartile range of the data that is represented on the dot plot is: 2 chocolate chips.
What is the Interquartile Range?Interquartile range (IQR) = upper quartile - lower quartile.
Upper quartile (Q3) = center of the second half of the data = 5
Lower quartile (Q1) = center of the first half of the data = 3
Interquartile range (IQR) = 5 - 3
Interquartile range (IQR) = 2 chocolate chips.
Learn more about the interquartile range on:
https://brainly.com/question/4102829
#SPJ1
Find the mean of the following data. (a) 9, 7, 11, 13, 2, 4, 5, 5 (b) 16, 18, 19, 21, 23, 23, 27, 29, 29, 35 (c) 2.2, 10.2, 14.7, 5.9, 4.9, 11.1, 10.5 (d) 11/4, 21/2, 51/2, 31/4, 21/2
Answer:
a) 7 b) 24 c) 8.5 d) 11.4 (i think)
Step-by-step explanation:
Sergio is creating a college fund for his son Diego, who is now 4 years old. Sergio put $1600 in a CD that will earn 8.25% simple interest. How much will be in the account when Diego turns 18?
well, Diego is 4 now, so by his 18th birthday that'll be 14 years later.
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1600\\ r=rate\to 8.25\%\to \frac{8.25}{100}\dotfill &0.0825\\ t=years\dotfill &14 \end{cases} \\\\\\ A=1600[1+(0.0825)(14)]\implies A=1600(2.155)\implies A=3448[/tex]
Question 1 of 10
f(x) = 3x³ - 2x² + 4x - 5
g(x) = 6x - 7
Find (f + g)(x).
Done!
Answer:
[tex](f+g)(x)=3x^3-2x^2+10x-12[/tex]
Step-by-step explanation:
Given:
[tex]\begin{cases}f(x)=3x^3-2x^2+4x-5\\g(x)=6x-7 \end{cases}[/tex]
[tex]\begin{aligned}(f+g)(x) & = f(x)+g(x)\\& = (3x^3-2x^2+4x-5)+(6x-7)\\& = 3x^3-2x^2+4x-5+6x-7\\& = 3x^3-2x^2+4x+6x-5-7\\& = 3x^3-2x^2+10x-12\end{aligned}[/tex]