Answer:
053.
Explanation:
Given that the radius of curvature of the path, R = 75 m.
Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]
The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v on curved path having radiusR
Ris[tex]F_c = mv^2/R[/tex]
Gravitational force, [tex]F_g[/tex] = mg.
Let tha angle of superelevation is [tex]\theta.[/tex]
As the car does not skid even with zero friction, so
[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]
[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]
On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]
As [tex]v_2[/tex] = 118 m/s is greater than v_so the car tends to skid in upper direction and the frictional
force,f, will acts is downward direction.
As there is no skidding, so
[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]
[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]
where [tex]f= \mu N.[/tex]
[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]
Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.
[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]
From equation (ii)
[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]
[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]
[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]
[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]
=0.53
Hence, the minimum coefficient of friction is 0.53.
A 50 km/hr wind is blowing due northwest what are the components of the wind in the northern
and western direction?
Answer:
The components of the wind in the northern direction is approximately 35.36 km/hr
Similarly, the components of the wind in the western direction is approximately 35.36 km/hr
Explanation:
The given parameters are;
The magnitude of the speed of the wind, v = 50 km/hr
The direction of the wind = The northwest direction
Therefore;
Given that the angle between the northern and western direction = 90°
The angle in the northwestern direction, θ = 90°/2 = 45°
Therefore;
The components of the wind in the northern direction = [tex]v_y[/tex] = v × sin(θ)
Substituting the values, we have;
The components of the wind in the northern direction = [tex]v_y[/tex] = 50 × sin(45°) = 50/√2 ≈ 35.36 km/hr.
Similarly, the components of the wind in the western direction = vₓ = 50 × cos(45°) = 50/√2 ≈ 35.36 km/hr
What acceleration will you give to a 27.8 kg
box if you push it with a force of 75.7 N?
Answer in units of m/s2.
Answer:
2.72m/s²
Explanation:
Given parameters;
Mass of box = 27.8kg
Force on box = 75.7N
Unknown:
Acceleration = ?
Solution:
Force is the product of mass and acceleration;
Force = mass x acceleration
Now insert the parameters and solve;
75.7 = 27.8 x a
a = [tex]\frac{75.7}{27.8}[/tex] = 2.72m/s²
Which of the following best describes inertia?
A. Rowing a boat
B. Moving forward in your seat when the car suddenly stops
C. A rocket taking off from the launching pad
D. A bicycle requires less force to move than a car
in the waves lab, you changed ____ to see how it would affect wave speed.
A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
I need the answer ASAP!
What is the resistance of a 600 W kettle that draws a current of 5.0 A? please answer with steps
prove that:the unit of pressure is a derived units
find the mass of a car that is travelling at a velocity of 60m/a north. The car had 5,040,000 j of kinetic energy
Answer:
2800kg
Explanation:
Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
Answer:
TRUE
Explanation:
The answer is true.
Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.
In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.
What is a transverse wave like?
Answer:
a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation
Explanation:
wave oscillate along paths at right angles to the direction of the wave’s advance.
Explanation:
Pitch describes how high or low a sound is. The pitch of a sound is most dependent upon the of the sound wave.
A.
amplitude
B.
rarefaction
C.
frequency
D.
wavelength
Answer:
The answer is C
Explanation:
Calculate the acceleration of gravity that the moon has, if an astronaut has a mass of 87 kg and the weight force he experiences on the moon is 141 N
Answer:
the acceleration of gravity is 1.62
Explanation:
w=mg
141=87g
141/87=87g/87
1.62=g
If a motorcyclist accelerates from rest to 40 m/s in 8 seconds, what is their acceleration?
Answer:
5 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 40 m/s
t = 8 s
Find: a
a = (v − v₀) / t
a = (40 m/s − 0 m/s) / 8 s
a = 5 m/s²
Which of the following statements does not describe the structure of an atom? (3 points) An atom has a small, dense center called the nucleus. Inside the nucleus of an atom are protons and electrons. Protons are positively charged sub-atomic particles. Electrons are negatively charged sub-atomic particles
Answer:
B is your answer
Explanation:
C, D, and A are true and protons are located inside the nucleus and electrons are located outside the nucleus which means B is your answer.
Which statement describes the interaction between the permanent magnets and the electromagnet in an electric motor? A. The current in the electromagnet is reversed by the permanent magnets B. The current in the permanent magnets is reversed by the electromagnet C. The poles of the permanent magnets are reversed by the electric field of the electromagnet. D. The metal loop in the electromagnet turns because of the magnetic field of the permanent magnets
Answer:D
Explanation:AP3X
The statement describes the interaction between the permanent magnets and the electromagnet in an electric motor is option D.
What is magnet?A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.
A bar is a magnet which can attract the particle which are charged. It has two poles North and South.
The permanent magnet create magnetic field very strong. The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.
Thus, the correct option is D.
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- An impulse is equivalent to
a. the change in mass of an object.
b. the change in volume of an object.
c. a force applied to an object for a period of time.
d. the original momentum of the object.
Answer:
c
Explanation:
impulse Is the product of force and distance so it's generally formula
The impulse should be equivalent to the option c. a force applied to an object for a period of time.
What is an impulse?Impulse of force represent the product of the resultant force ΣF and also the duration of the force Δt when the force should be constant. Also it should be lead to the changed to motion and changes to momentum
Therefore, The impulse should be equivalent to the option c. a force applied to an object for a period of time.
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A car has an acceleration of -6.5 mi/hr/s. Which of the statements below is true
Where are the answer choices
Jorge conducted an experiment,and included the graph shown below as part of his lab report.
Jorges experiment involved which if the following?
-A Chemical change.
-A change in the chemical properties of a substance.
-A physical change.
-the formation of a new substance.
The correct answer is A physical change
Explanation:
Jorge's experiment shows water at different temperatures; in this experiment, it is expected at low temperatures such as -20°C water is in solid-state (ice), at medium temperatures such as 40°C water is in a liquid state (liquid water), and at high temperatures such as 120°C water is in gaseous state (water vapor). This implies during this experiment the changing factor is the physical state (solid, gas, or liquid), and this is a physical change because only the physical properties of water change but not its composition or identity. According to this, the correct answer is physical change.
1. A motorcycle stunt driver rides his motorcycle off a small ledge
that is 8.4 meters high. His initial velocity as he rides off the cliff is
24 m/s in the horizontal direction.
a. How long does it take before he lands on the ground below?
b. How far away from the base of the cliff does he travel while in
the air?
Answer:
Explanation:
Given
Height S = 8.4m
Initial velocity u = 24m/s
Required
Time it will take to reach the ground
Using the equation of motion
S = ut +1/2gt²
8.4 = 24t + 1/2(9.8)t²
8.4 = 24t+4.9t²
4.9t²+24t - 8.4 = 0
Multiply through by 10
49t²+240t-84 = 0
Factorize
t = -240±√240²-4(49(-84)/2(49)
t = -240±√57600+16464/98
t = -240±√74064/98
t = -240±272.15/98
t = 32.15/98
t = 0.328seconds
Hence it takes 0.328seconds before it lands on the ground below.
b) The horizontal distance is the range expressed as;
R = u²/g
R = 27²/9.8
R = 729/9.8.
R = 74.39m
a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.
b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in the air is 31.44 meters.
Given the following data:
Maximum height = 8.4 meters.Initial velocity = 24 m/s.We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]
a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
g is the acceleration due to gravity.H is the maximum height.Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]
Time = 1.31 seconds.
b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in the air:
[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]
Horizontal distance = 31.44 meters.
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HELP THIS IS DUE IN 10 MINS
Find the definitions of the following terms.
A. Force of impact
B. Total Velocity
C. Horizontal Velocity
D. Vertical Velocity
100 points
you stole point from me, if you really didn't know the answer you shouldn't have wasted time.
A space vehicle is coasting at a constant velocity of 22.4 m/s in the y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.206 m/s2 in the x direction. After 40.5 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the y direction.
Answer:
a. 23.9 m/s b. 69.58°
Explanation:
a. Since the space vehicle is moving at a constant velocity of 22.4 m/s in the y direction relative to the space station, its initial vertical velocity v = 22.4 m/s.
Also, since the space vehicle moves in the y direction, its initial horizontal velocity u = 0 m/s.
Since its acceleration a = 0.206 m/s² for time, t = 40.5 s, we find the final horizontal velocity u' from u' = u + at.
Substituting the values of the variables into the equation, we have
u' = u + at
u' = 0 m/s + 0.206 m/s² × 40.5 s
= 8.343 m/s
≅ 8.34 m/s
The resultant velocity relative to the space station V = √(v² + u'²)
= √[(22.4m/s)² + (8.34 m/s)²]
= √[501.76 m²/s² + (69.56 m²/s²]
= √[571.32 m²/s²]
= 23.9 m/s
b. The direction of the vehicle's velocity relative to the space station is thus θ = tan⁻¹(v/u')
= tan⁻¹(22.4 m/s/8.34 m/s)
= tan⁻¹(2.6959)
= 69.58°
3. A student fills a plastic bottle full of water. He make a hole in the bottle half-way up,
and another hole at the bottom.
(a) Does the water come faster out of the hole in the middle or the hole at the bottom?
Explain your answer.
Answer:
It would go out the bottom hole faster.
Explanation:
It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.
If an object is in free fall, on the way down it will
Answer:
It will find a worm when it hits the ground and starts Johnny sins fvcl<ing the worm
Why the car floated before it started to sink? Explain.
A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
coaster? (Formula: PE = mgh)
O 800 kg
O 7,840 kg
O 8,000 kg
O 78,400 kg
Answer:
800 kg
Explanation:
I just did it :)
HELPP
Viewed from Earth, it seems as if the Sun moves across the sky each day. This is because:
A. the sun isn't moving; observations made from Earth are rotating with the Earth
B. the Earth goes around the Sun over the course of a year
C. the Sun revolves around the Earth
D. the Earth isn't moving
Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0
d. 17.4
b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
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Two asteroids with masses 3.45 x 103 kg and 6.06 x 104 kg are separated by
a distance of 7,200 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity =
Gm) m2. The gravitational constant
Gis 6.67 x 10-11 N.m2/kg?
O A. 4.03 N
O B. 2.69 x 10-10 N
O C. 3.38 x 1032 N
O D. 1.93 x 10-6N
The gravitational force between the asteroids is 2.7 × 10^-10 N.
What is gravitation?
Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
Given that:
Two asteroids with masses 3.45 x 10^3 kg and 6.06 x 10^4 kg are separated by a distance of 7,200 m.
Hence, the gravitational force between the asteroids:
F = GmM/r²
= ( 6.67 x 10^-11 × 3.45 x 10^3 × 6.06 x 10^4)/( 7,200)² N
= 2.7 × 10^-10 N.
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Answer:
B 2.69 x 10-10 N
Explanation:
test right yes yes
A 60.-kilogram physics student would weigh 1560
newtons on the surface of planet X. What is the
magnitude of the acceleration due to gravity on the
surface of planet X?
Answer:
26m/s²
Explanation:
Given parameters:
Mass of the student = 60kg
Weight = 1560N
Unknown:
Acceleration due to gravity = ?
Solution:
Weight is a force on a body due to gravity;
Weight = mass x gravity
Insert the given parameters and solve;
1560 = 60 x gravity
Gravity = [tex]\frac{1560}{60}[/tex] = 26m/s²
Willing to give brainliest!
A motorbike accelerates from 12 m s-¹ to 36 m s-¹ 3 seconds.
Calculate the acceleration of the motorbike.
Answer:
acceleration is 8 m/s²
Explanation:
a = 36 - 12 / 3
a = 24 / 3
a = 8
hope this helps :)
Answer:
1
Explanation:
1