**Unit 10: Circles, Homework 6: Arcs & Angle measures**

I need help doing this question (I would really appreciate it):

Answer:

  right

  D.  6.3 m

Step-by-step explanation:

You want to know if the given triangle is acute, obtuse, or right, and the value of x.

The red icon in the corner indicates the triangle is a right triangle. The Pythagorean theorem applies, so ...

  x² = 4.8² +4.1² = 39.85

  x = √39.85 ≈ 6.3

The value of x in this right triangle is about 6.3 m.

__

Additional comment

The triangle cannot be solved for the remaining side unless you know at least one angle. The marked right angle is sufficient to let you solve for x.

Answer:

➛ The given triangle is a right angle triangle.

➛ Option D) 6.3 in is the correct answer.

Step-by-step explanation :

Here we can see that the one angle of triangle is 90⁰. Therefore, it's a right angle triangle.

Now, Here we have given that the base and altitude of triangle and we need to find the hypotenuse of triangle.

So, by using Pythagoras Theorem we will find the hypotenuse of triangle :

[tex] \sf{\longrightarrow{{(Hypotenuse)}^{2} = {(Altitude)}^{2} + {(Base)}^{2}}}[/tex]

Substituting all the given values in the formula to find hypotenuse :

[tex] \sf{\longrightarrow{{(x)}^{2} = {(4.1)}^{2} + {(4.8)}^{2}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = {(4.1 \times 4.1)} + {(4.8 \times 4.8)}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = {(16.81)} + {(23.04)}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = 16.81 + 23.04}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = 39.85}}[/tex]

[tex] \sf{\longrightarrow{x = \sqrt{39.85}}}[/tex]

[tex]\sf{\longrightarrow{\underline{\underline{x \approx 6.3 \: in}}}}[/tex]

Hence, the value of x is 6.3 in.

If a function is given that h(t) = 2t^2 - t; t = 4, t = 8, then the net change between the given values of the variable is 92 and the average rate of change between the given values of the variable is 23.

Explanation:

Given that: Based on the provided function h(t) = 2t^2 - t and the given values of t = 4 and t = 8.

To determine the net change and average rate of change, follow these steps:

(a) The difference between the two h(x) values is the net change.

To find the net change, we need to evaluate the function at both values of t and then subtract the results:

Net change = h(8) - h(4)
Net change = (2(8)^2 - 8) - (2(4)^2 - 4)
Net change = (128 - 8) - (32 - 4)
Net change = 120 - 28
Net change = 92

(b) The ratio between the net change and the change between the two input values is used to calculate average net change or average rate of change. The average rate of change can be calculated using the same two points and the formula: f(b)-f(a) / b-a .

To determine the average rate of change, we need to divide the net change by the difference in the t values:

Average rate of change = Net change / (t2 - t1)
Average rate of change = 92 / (8 - 4)
Average rate of change = 92 / 4
Average rate of change = 23

So, the net change is 92 and the average rate of change is 23 between the given values of the variable.

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Answer:

7

Step-by-step explanation:

7+7+7+7+7=35

35 ÷ 5

=7( the mean is 7)

The correct option to the above question is Wakeboarding with a central angle of 39.6°.

A central angle is an angle formed by two radii (lines) in a circle, where the vertex of the angle is at the centre of the circle and the sides of the angle intersect the circle. In other words, it is an angle that spans from the centre of a circle to a point on the circle's circumference.

According to the given information:

To calculate the central angle for each lake activity in a circle graph, we need to find the percentage of campers who chose each activity out of the total number of campers surveyed (100). Then we can convert that percentage to degrees using the formula:

Central angle (in degrees) = Percentage * 360°

Let's calculate the percentages for each activity:

Kayaking: 15 campers out of 100, so the percentage is 15%.

Wakeboarding: 11 campers out of 100, so the percentage is 11%.

Windsurfing: 7 campers out of 100, so the percentage is 7%.

Waterskiing: 13 campers out of 100, so the percentage is 13%.

Paddleboarding: 54 campers out of 100, so the percentage is 54%.

Now, let's calculate the central angle for Wakeboarding:

Central angle for Wakeboarding = Percentage of Wakeboarding * 360°

Central angle for Wakeboarding = 11% * 360°

Central angle for Wakeboarding= 39.6°

So, Wakeboarding has a central angle of 39.6° in the circle graph, which is the activity with the highest percentage of campers surveyed. Therefore, the correct answer is "Wakeboarding".

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The probability that neither of other two studied calculus is 0.36. The probability that both have taken at least one semester is 0.0759. The probability that at least one has had more than one semester) 0.4782

Let's first find the probability that one of your other two groupmates has studied calculus and the other has not. We can do this by multiplying the probabilities of the two events:

P(one studied calculus, one did not) = P(at least one studied calculus) * P(neither studied calculus)

P(one studied calculus, one did not) = (1 - 0.6) * 0.6

P(one studied calculus, one did not) = 0.24

Since we are dealing with three students in the group, there are three ways that one person could have studied calculus and the other two have not. So we need to multiply the above probability by three:

P(neither of other two studied calculus) = 3 * 0.24

P(neither of other two studied calculus) = 0.72

Therefore, the probability that neither of your other two groupmates has studied calculus is 0.36 (as given), and the probability that at least one has studied calculus is:

P(at least one studied calculus) = 1 - 0.36

P(at least one studied calculus) = 0.64

Now let's find the probability that both of your other two groupmates have studied at least one semester of calculus. This is given to be 0.16. We can break this down into two cases: either both of the other two have taken exactly one semester of calculus, or both have taken two or more semesters. So:

P(both have taken exactly one semester) + P(both have taken two or more semesters) = 0.16

Let's use x to represent the probability that a given student has taken two or more semesters of calculus. Then:

P(both have taken exactly one semester) = 0.29 * 0.29 = 0.0841 (since the two events are independent)

P(both have taken two or more semesters) = x^2

So we have:

0.0841 + x^2 = 0.16

x^2 = 0.0759

x = 0.2758 (taking the positive root since we're dealing with probabilities)

Therefore, the probability that both of your other two groupmates have taken two or more semesters of calculus is approximately:

P(both have taken two or more semesters) = 0.2758^2

P(both have taken two or more semesters) = 0.0759

Finally, we can find the probability that at least one of your other two groupmates has had more than one semester of calculus by subtracting the probability that both have taken exactly one semester from the probability that at least one has studied calculus:

P(at least one has had more than one semester) = P(at least one studied calculus) - P(both have taken exactly one semester)

P(at least one has had more than one semester) = 0.64 - 0.0841

P(at least one has had more than one semester) = 0.5559

P(at least one has had more than one semester) = 0.4782 (rounded to four decimal places)

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The function y = x(100 - x²) is increasing on the intervals (-∞, -10/√3) ∪ (10/√3, ∞), and decreasing on the interval (-10/√3, 10/√3).

To determine the intervals on which the function y = x(100 - x^2) is increasing or decreasing, we need to find its first derivative and determine its sign.

y' = 100 - 3x²

To find the critical points, we set y' = 0 and solve for x:

These are the critical points.

Now, we test the intervals between them:

Therefore, the function is

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The value of k that makes the series converge is k > 1.

To solve for the value of k that makes the series ∑(4/ [tex]n^k[/tex] ) converge, we need to apply the convergence test for series with positive terms, known as the p-series test. A p-series is of the form ∑(1/[tex]n^p[/tex]) and converges if p > 1, and diverges if p ≤ 1.

In our case, the given series is ∑(4/ [tex]n^k[/tex]), which is 4 times the p-series

∑(1/ [tex]n^k[/tex]). Since the convergence properties of a series are not affected by multiplying by a constant (4 in this case), we can focus on the series ∑(1/ [tex]n^k[/tex]).

According to the p-series test, this series converges if k > 1. Therefore, the value of k that makes the original series converge is k > 1.

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Here are answers to adding parentheses to the expressions to indicate how Java will interpret them.

(a) a * b - c * d / e
Java interpretation: (a * b) - ((c * d) / e)

(b) a - b * c % d - e
Java interpretation: (a - ((b * c) % d)) - e

(c) -a - b * c / d / e
Java interpretation: (-a) - (((b * c) / d) / e)

(d) a / b % c + d - e
Java interpretation: (((a / b) % c) + d) - e

Note: Adding parentheses to expressions helps to clearly indicate the order in which Java will interpret them. This is important for ensuring the desired outcome of the expression.

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The function f(x) that satisfies f ''(x) = 24x³ − 15x² + 8x is:

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂ [where C₁ and C₂ are arbitrary constants].

Integration is a fundamental concept in calculus that involves finding the antiderivative or the indefinite integral of a function.

More specifically, integration is the process of determining a function whose derivative is the given function.

To find f(x) from f ''(x), we need to integrate f ''(x) twice, since the first antiderivative will give us the derivative of the function f(x), and the second antiderivative will give us f(x) up to two arbitrary constants of integration.

First, we integrate f ''(x) with respect to x to get the first antiderivative f '(x):

f '(x) = ∫ f ''(x) dx = 24∫ x³ dx - 15∫ x² dx + 8∫ x dx

f '(x) = 24(x⁴/4) - 15(x³/3) + 8(x²/2) + C₁

f '(x) = 6x⁴ - 5x³ + 4x² + C₁

where C₁ is the constant of integration.

Next, we integrate f '(x) with respect to x to get f(x):

f(x) = ∫ f '(x) dx = ∫ (6x⁴ - 5x³ + 4x² + C₁) dx

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂

where C₂ is the constant of integration.

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The function f(x) that satisfies f ''(x) = 24x³ − 15x² + 8x is:

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂ [where C₁ and C₂ are arbitrary constants].

Integration is a fundamental concept in calculus that involves finding the antiderivative or the indefinite integral of a function.

More specifically, integration is the process of determining a function whose derivative is the given function.

To find f(x) from f ''(x), we need to integrate f ''(x) twice, since the first antiderivative will give us the derivative of the function f(x), and the second antiderivative will give us f(x) up to two arbitrary constants of integration.

First, we integrate f ''(x) with respect to x to get the first antiderivative f '(x):

f '(x) = ∫ f ''(x) dx = 24∫ x³ dx - 15∫ x² dx + 8∫ x dx

f '(x) = 24(x⁴/4) - 15(x³/3) + 8(x²/2) + C₁

f '(x) = 6x⁴ - 5x³ + 4x² + C₁

where C₁ is the constant of integration.

Next, we integrate f '(x) with respect to x to get f(x):

f(x) = ∫ f '(x) dx = ∫ (6x⁴ - 5x³ + 4x² + C₁) dx

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂

where C₂ is the constant of integration.

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Tom ran from his home to the bus stop and waited. He realized that he had missed the bus so he walked home. The correct distance time graph describing this is graph G.

The distance that an object has come in a certain amount of time is displayed on a distance-time graph.  The graph that shows the results of the distance vs time analysis is a straightforward line graph. When analysing the motion of bodies, we work with the distance-time graph.

A distance-time graph related to a body's motion can be created if we measure a body's motion's distance and time and plot the resulting data on a rectangle graph. Tom ran from his home to the bus stop and waited. He realized that he had missed the bus so he walked home. The correct distance time graph describing this is graph G.

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Your question is incomplete but most probably your full question was,  

Answer:

right as there is a point of 90 degrees

The y-intercept indicates that when the ball was released at t=0, it was thrown upward at 46 feet per second.

The equation given for the speed of a ball that is thrown straight up in the air is:

v(t) = 46 - 32t

where v is the velocity (feet per second) and t is the number of seconds after the ball is thrown.

The y-intercept of this equation is the value of v when t = 0. To find the y-intercept, we can substitute t = 0 into the equation:

v(0) = 46 - 32(0) = 46

So, the y-intercept of this equation is 46, which means that when the ball was released at t=0, it was thrown upward at 46 feet per second.

Therefore, option A is the correct answer: The y-intercept indicates that when the ball was released at t=0, it was thrown upward at 46 feet per second.

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A function notation for two hours after the open, there are 108 people in the auditorium is N(2) = 108.

A function notation for the number of people in the auditorium 3 hours after the doors open is the same as the number of people in the auditorium 5 hours after the doors open is N(3) = N(5).

In Mathematics, a function refers to a mathematical expression which can be used for defining and showing the relationship that exist between two or more variables in a data set.

This ultimately implies that, a function typically shows the relationship between input values (x-values or domain) and output values (y-values or range) of a data set, as well as showing how the elements in a table are uniquely paired (mapped).

Based on the information provided, the number of people in the auditorium can be represented by this function notation;

N(t)

Where:

t represents number of hours.

After 2 hours, we have:

N(2) = 108.

For the last statement, we have:

N(3) = N(5).

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The amount she can afford to borrow for a house is $111,316.77

We are given that;

Amount earned per year= $31,350

Now,

Formula for calculating the monthly mortgage payment is:

M=Pr​/1−(1+r)−n

We can rearrange this formula to solve for P:

P=M(1−(1+r)−n)​/r

Plugging in the values we have, we get:

P=531.75(1−(1+0.04/12)−30×12)​/0.04/12

Using a calculator, we get:

P≈111,316.77

Therefore, by unitary method the answer will be $111,316.77.

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Step-by-step explanation:

in a 4-digit number : how many 0 can there be ?

can there be five 0s ?

no, how could there be ? there is no space for five 0s, when there are only 4 positions for digits.

it is said that there are no restrictions on the digits.

so, any digit can occur at any position.

that means simply that there can be

no 0s : e.g. 1234

one 0 : e.g. 1204

two 0s : e.g. 1030

three 0s : e.g. 0030 or 7000 ...

four 0s - only one possibility : 0000

so, the possible values for X are

0, 1, 2, 3, 4

please pick the corresponding answer in your list, as you clearly made some typos there. I cannot tell the difference between some of the options you provided.

the X value for 1020 is 2

the X value for 2478 is 0

the X value for 7130 is 1

if there are more numbers, you did not list them.

The coefficients of the polynomial are 6 and 15 and the width of the rectangle is 3x

Here, we have

3x³(2x² - x + 5)

Expand

6x⁵ - 3x⁴ + 15x³

So, the coefficients of the polynomial are 6, -3 and 15

Here, we have

Length = 4x⁵

The area is calculated as

Area = (4x⁵)²

Evaluate

Area = 16x¹⁰

Here, we have

Area = 12x²

Length = 4x

So, we have

Width = 12x²/4x

Evaluate

Width = 3x

Hence, the width of the rectangle is 3x

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Proved that [tex]a_n[/tex] = a(n-1) + [tex]3^n[/tex] - 2n - 1 for all non-negative integers n.

We will use mathematical induction.

Base Case:

For n = 0, we have:

a0 = 1 - 0 = 1

And

a(-1) = 0 //Since a sequence is not defined for negative indices.

Therefore, the statement is true for the base case.

Inductive Hypothesis:

Assume that the statement is true for some non-negative integer k:

[tex]a_k = ak-1 + 3^k - 2k - 1[/tex]

Inductive Step:

We will prove that the statement is also true for k+1:

[tex]ak+1 = ak + 3^{k+1} - 2(k+1) - 1[/tex]

= (ak-1 + 3^k - 2k - 1) + 3^(k+1) - 2(k+1) - 1 //Using inductive hypothesis.

= ak-1 + 3^(k+1) - 2(k+1) + 3^k - 2k - 2

Now, we will show that ak+1 can be written in the form ak+1 = ak + 3^(k+1) - 2(k+1) - 1:

[tex]a_{k+1} = (ak-1 + 3^k - 2k - 1) + 3^{k+1} - 2(k+1) - 1[/tex]

[tex]= (a_k-1 + 3^{k+1} - 3.3^k - 2k - 2) + 3^{k+1} - 2(k+1) - 1[/tex]

[tex]= (a_k-1 + 3^{k+1} - 2.3^k - 2(k+1)) + 3^{k+1} - 2(k+1) - 1[/tex]

[tex]= a_k-1 + 2.3^{k+1} - 2(k+2) - 1[/tex]

[tex]= a_k + 3^{k+1} - 2(k+1) - 1[/tex]

Therefore, the statement is also true for k+1, completing the inductive step.

By the principle of mathematical induction, the statement is true for all non-negative integers n. Hence, we have proved that [tex]a_n = a_{n-1} + 3^n - 2n - 1[/tex] for all non-negative integers n.

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Expression: 7x^(-2/3), the factored expression with positive exponents is: 7 * (1 / x^(2/3))

Expression: 7x^(-2/3)

Step 1: Identify the given terms.
In this expression, we have a constant (7) and a variable term (x^(-2/3)).

Step 2: Factor out the constant.
Since there's only one term, the constant (7) is already factored out.

Step 3: Convert negative exponent to positive.
To convert the negative exponent (-2/3) to a positive exponent, we can rewrite the expression as a fraction:

7x^(-2/3) = 7/x^(2/3)

Step 4: Simplify the expression.
In this case, the expression is already simplified, and there is no further factoring needed.

Final Answer: 7/x^(2/3)

Explanation:
The given expression is 7x^(-2/3), which is a single term composed of a constant (7) and a variable term (x^(-2/3)). Since there's only one term, the constant 7 is already factored out. The exponent of the variable term is negative, so we rewrite it as a fraction to make the exponent positive. The expression becomes 7/x^(2/3), which is the final factored form with positive exponents.

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Answer:

  B’

Step-by-step explanation:

You want to know the vertex that has coordinates (24, 12) after dilation by a factor of 6 about the origin.

When the center of dilation is the origin, the scale factor multiplies each coordinate value. Then the coordinates of the original point whose dilated location is (24, 12) is ...

  6(x, y) = (24, 12)

  (x, y) = (24, 12)/6 = (24/6, 12/6) = (4, 2) . . . . . . matches point B

The image point is B'.

The sampling distribution of the mean number of calls per day (I) in an electronics call center, given that the number of daily incoming phone calls is nearly normally distributed with an unknown mean (μ) and an unknown standard deviation (σ). Daniel examines the call logs from a simple random sample of n days , the correct answer is E which describes the sampling distribution correctly.

Here's the explanation:

1. The original distribution of daily incoming phone calls is approximately normal.
2. Daniel takes a simple random sample of n days, which is a representative sample of the population.
3. Since the original distribution is normal and the sample is large enough, the Central Limit Theorem states that the sampling distribution of the sample mean (I) will also be normally distributed.
4. The mean of the sampling distribution will be equal to the population mean (μ).
5. The standard deviation of the sampling distribution will be equal to the population standard deviation (σ) divided by the square root of the sample size (n). This is because the variability in the sample means decreases as the sample size increases.

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Answer:

24576

Step-by-step explanation:

first find the 2nd term, u1 *u3 r u2^2

hence u2 = 24

then find the common ratio

24/ 6 = 96/24 = 4

now complete the formula

6 * 4^(n-1)

now sub in 7 for n

you get 24576

6) The solution is:  x = 1, y = -4, z = -3

7) The solution is: x = 1, y = 3, z = 5/7

8) The solution to the system of equations is: x = -11, y = 0, z = -5.

A quadratic equation is a polynomial equation of the second degree, which means it has a degree of two.

6.) To solve the systems of equations, we can use the Gaussian elimination method.

We will rewrite this system in the augmented matrix form:

[ 3 -1 2 | -4 ]

[ 6 -2 4 | -8 ]

[ 2 -1 3 | -10]

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 1/3 7/3 | -14/3]

Then, we can add (1/3) times the second row to the third row:

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 1/3 21/9 | -10/3]

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 3 7 | -30 ]

7.) We can rewrite this system in the augmented matrix form:

[ 1 1 -1 | 4 ]

[ 3 2 4 | -17 ]

[-1 5 1 | 8 ]

[ 1 1 -1 | 4 ]

[ 0 -1 7 | -29 ]

[ 0 6 0 | 12 ]

Then, we can multiply the second row by -1 and add it to the third row:

[ 1 1 -1 | 4 ]

[ 0 -1 7 | -29 ]

[ 0 0 -42 | -150]

8.) To solve for x, y, and z in the system of equations:

x + 5y - 2z = -1 (equation 1)

-x - 2y + z = 6 (equation 2)

-2x - 7y + 3z = 7 (equation 3)

(1) + (2): 3y - z = 5

2(1) + (3): 13y - z = 5

3y - z = 5 (equation A)

13y - z = 5 (equation B)

10y = 0

3(0) - z = 5

z = -5

x + 5(0) - 2(-5) = -1

x + 10 = -1

x = -11

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The distance in the east direction Mr. Jackamonis after Ms Follis walks 5 feet directly north and the distance between them is 13 feet, obtained using Pythagorean Theorem is 12 feet

Pythagorean Theorem states that the square of the length of the hypotenuse side of a right triangle is equivalent to the sum of the squares of the lengths of the other two sides of the right triangle.

Let a represent the length of the hypotenuse side, and let b and c represent the lengths of the other two sides, then according to the Pythagorean Theorem, we get;

a² = b² + c²

The direction Ms. Follis walks = 5 feet directly north

The direction Mr. Jackamonis walks = Directly east

The distance between Ms. Follis and Mr. Jackamonis = 13 feet apart

The distance Mr. Jackamonis walks, d, can  be found using Pythagorean Theorem as follows;

13² = 5² + d²

Therefore;

d² = 13² - 5² = 144

d = √(144) = 12

d = ± 12

Distances are measured using natural numbers, therefore;

d = 12 feet

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The area of the trapezoid is approximately 237.312 square centimeters.

To use the formula for finding the area of a trapezoid, we need to know the height and the length of the two parallel sides (bases).

Let's assume that 10.7 cm is the length of one base and 15.1 cm is the length of the other base, and 18.4 cm is the height.

Using the formula for the area of a trapezoid, we get:

Area = 0.5 × (10.7 cm + 15.1 cm) × 18.4 cm

Area = 0.5 × 25.8 cm × 18.4 cm

Area = 237.312 cm^2

Therefore, the area of the trapezoid is approximately 237.312 square centimeters.

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To find the volume of the solid whose base is the region bounded between the curve y = x^2 and the x axis from x = 0 and x = 2, we need to use the method of disks or washers. The volume is V = 6.4π cubic units.

First, we need to find the equation of the curve when rotated around the x-axis. This will create a series of circular cross-sections that we can integrate to find the volume.

The equation of the curve when rotated around the x-axis is:

V = ∫[0,2] πy^2 dx

Since the base is the region between y = x^2 and the x-axis, we can rewrite the equation in terms of x:

V = ∫[0,2] π(x^2)^2 dx

V = ∫[0,2] πx^4 dx

Using the power rule of integration, we can simplify this to:

V = π/5 [x^5] from 0 to 2

V = π/5 (32)

V = 6.4π cubic units

b.) If we use semicircles to create the base, we need to split the solid into two parts, since each semicircle will create a half-cylinder.

The radius of each semicircle is equal to the function y = x^2, so the area of each semicircle is:

A = 1/2 π(x^2)^2

A = 1/2 πx^4

To find the volume of each half-cylinder, we integrate the area over the interval [0,2]:

V1 = ∫[0,2] 1/2 πx^4 dx

V1 = π/10 [x^5] from 0 to 2

V1 = π/10 (32)

V1 = 3.2π cubic units

The total volume of the solid is twice this amount:

V = 2V1

V = 6.4π cubic units.

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Therefore, the probability that a randomly selected passenger has a waiting time less than 2.75 minutes is 0.55.

Since the waiting times between subway departure schedule and passenger arrival are uniformly distributed between 0 and 5 minutes, the probability density function of the waiting time can be expressed as:

f(x) = 1/5 for 0 <= x <= 5

0 otherwise

To find the probability that a randomly selected passenger has a waiting time less than 2.75 minutes, we need to calculate the area under the probability density function from 0 to 2.75:

P(X < 2.75) = ∫[0, 2.75] f(x) dx

= ∫[0, 2.75] (1/5) dx

= (1/5) [x]_[0, 2.75]

= (1/5) * 2.75

= 0.55

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