[URGENT!] - Equilibrium Problem

Consider the following reaction:

4A + 2B ⇌ 2C + D (all gases at STP)

Initially, the reaction system is at equilibrium, with [A] = [B] = 2.60 M, and [C] = [D] = 3.10 M, making K = 0.0964. The reaction takes place in a 5.00-liter container. Moles of B are removed until the new equilibrium concentration of C is 2.70. How many moles of B were removed?

Answers

Answer 1

The equilibrium constant expression for this reaction is:

K = [C]2[D] / [A]4[B]2

We can rearrange this expression to solve for [B]:

[B] = √([A]4[C]2[D] / K)

Plugging in the given values, we get:

[B] = √((2.60 M)4(2.70 M)2(3.10 M) / 0.0964)

= √(6.76 M)

= 0.26 M

The initial concentration of B is 2.60 M, so the change in concentration of B is 2.60 M - 0.26 M = 2.34 M.

Since the reaction takes place in a 5.00-liter container, the number of moles of B that were removed is 2.34 M * 5.00 L = 11.7 moles.

Therefore, 11.7 moles of B were removed.


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A sample of gas is kept at a temperature of 300 k, a volume of 1.45L, and a pressure of 3.00 kPa. How many moles of has are in the sample

Answers

Answer:

the number of moles of the gas is 0.00174 mol.

Explanation:

Given;

temperature of the, T = 300 K

volume of the gas, V = 1.45 L

Pressure of the gas, P = 3.0 kPa

The number of moles of the gas is calculated using Ideal gas equation, as follows;

PV = nRT

Where;

n is number of moles of the gas

R is the ideal gas constant, = 8.315 L.kPa/mol.K

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Can you help me please

Answers

Answer:

11.5 or 11.52, depending on however many decimal places you round it to

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the equation for mass ( using the specific heat capacity equation) is energy transferred divided by temperature change x the specific heat capacity.

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The temperature of 200 mL of gas originally at STP is changed to –25o C at constant volume. Calculate the final pressure of the gas in mmHg.

Answers

Answer:

691.6 mmHg

Explanation:

At standard temperature and pressure, temperature of a system = 273K, and pressure= 1atm

T1= 273.15K

P1= 1atm

T2= (–25°C +273.15 )= 248.15K

From Gay-Lussac's law which expressed that at constant volume, pressure of a particular mass of gas is directly proportional to temperature . It can be expressed as

P1 / T1 = P2 / T2

Where P1= initial pressure

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T1= initial temperature

P2= final pressure

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P2= 0.91 atm

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0.91 atm= X mmHg

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How many moles do I have of Lithium if I have 116.3g

Answers

Answer:

16.85mol

Explanation:

The number of moles of a substance can be calculated by dividing the mass of that substance by its molecular mass. That is;

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