Complete question :
Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.
m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C
Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.
M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C
Answer:
Quantity of heat gained = 67401.6 Joules
Quantity of heat lost by hot water = 40854.25 Joules
Explanation:
The heat gained by cold liquid :
Q = m × c × ΔT
m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C
Q = 248.9 * 3.73 * 72.6
Q = 67401.6 Joules
Quantity of heat gained = 67401.6 Joules
Heat lost by hot water :
m × c × ΔT
M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C
Q = 237 * 41.2 * 4.184
Q = 40854.25 Joules
Quantity of heat lost by hot water = 40854.25 Joules
A 200 milliliter sample of gas has a pressure of 1 atmosphere. If the volume of the gas is decreased to 50 milliliters at constant temperature, the new pressure of the gas will be
1) 4 atm
2) 1 atm
3) 3 atm
4) 2 atm
Answer:
Answer is - 2. ...........
At constant temperature, if the volume of the sample of gas decreases, the pressure increases to 4.0atm.
Hence, option1)4 atm is the correct answer.
What is Boyle's law?Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
Initial volume of the gas V₁ = 200mL = 0.2LInitial pressure of the gas P₁ = 1.0atmFinal volume of the gas V₂ = 50.mL = 0.05LFinal pressure of the gas P₂ = ?We substitute our given values into the expression above to determine the new pressure.
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.0atm × 0.2L ) / 0.05L
P₂ = 0.2Latm / 0.05L
P₂ = 4atm
At constant temperature, if the volume of the sample of gas decreases, the pressure increases to 4.0atm.
Hence, option1)4 atm is the correct answer.
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A sample of unknown pressure occupies 0.776L at a temperature of 298K. The sample of gas is then tested under known
conditions and has a pressure of 32.6 kPa and occupies 0.664L at 303K. What was the original pressure of the gas?
A. 27.43 kPa
B. 38.62 kPa
C. 58.73 kPa
D. 84.11 kPa
Answer:
27.43 kPa (Option A)
Explanation:
We can solve this by the use of the Ideal Gases Law.
P . V = n . R . T
As n and R are constant, we avoid them from the equation so:
P₁ . V₁ / T₁ = P₂ . V₂ / T₂
P₁ . 0776L / 298K = 32.6 kPa . 0.664L / 303K
P₁ . 0776L / 298K = 0.0714 kPa .L/K
P₁ . 0776L = 0.0714 kPa .L/K . 298K
P₁ = 21.289 kPa.L / 0.776L
P₁ = 27.43 kPa
5.Name the compound below
Answer:
There isn't anything below, but i can help if you edit the question and put it there
Explanation:
~Bre
What is the temperature of an 11.2-L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3 L at 55 °C and 744 torr? 3C The pressure is not changing, so it looks like a case where charles’ law can be use.
Answer: The tempearture of 11.2 L of CO is [tex]3.0^0C[/tex].
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
[tex]V_1=11.2L\\T_1=?\\V_2=13.3L\\T_2=55^0C=(55+273)K=328K[/tex]
Putting values in above equation, we get:
[tex]\frac{11.2L}{T_1}=\frac{13.3L}{328K}\\\\T_1=276K=(276-273)^0C=3.0^0C[/tex]
Thus the tempearture of 11.2 L of CO is [tex]3.0^0C[/tex], pressure remaining constant.
Which is the limiting reactant?
Answer:
Explanation:
The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
Can you help with question 8
Answer:
pH = 9.4
Explanation:
With the given molarity of OH⁻ species we can calculate the pOH of the solution:
pOH = -log[OH⁻]
pOH = 2.6
Now we can use the pOH to calculate the pH of the solution, with the following formula:
pH = 14 - pOH
pH = 14 - 2.6
pH = 9.4
So a solution containing a OH⁻ concentration of 0.0025 M has a pH of 9.4.
A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg.
a. Will the volume of the balloon increase or decrease? Why?
b. What is the new volume of the balloon? (Assume constant temperature)
Answer:
a. Increase
b. 539 L
Explanation:
Step 1: Given data
Initial volume (V₁): 200.0 LInitial pressure (P₁): 760 mmHgFinal volume (V₂): ?Final pressure (P₂): 282 mmHgStep 2: Calculate the final volume of the gas
The pressure of the gas is inversely proportional to the volume. So, as the pressure decreases, the volume must increase. Assuming constant temperature and ideal behavior, we can calculate the final volume of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 760 mmHg × 200.0 L/282 mmHg = 539 L
A student placed a small piece of magnesium ribbon in a conical flask and added
60 mL hydrochloric acid. The student observed that when the hydrochloric acid
came into contact with the magnesium ribbon, bubbles formed indicating the
release of hydrogen gas. The magnesium dissolved and magnesium chloride
solution formed. Based on the student's observations, which type of reaction
occurred?
Answer:
Single replacement reaction
Explanation:
Let us try to write down the reaction equation for the reaction of a magnesium ribbon with hydrochloric acid.
Mg(s) + 2HCl(aq) ------> MgCl2(aq) + H2(g)
A single replacement reaction is a type of chemical reaction in which one element is replaced by another element in a compound.
In this reaction, magnesium replaced hydrogen to form the product. Hence it is a single replacement reaction.
Chemistry question balance equations
Answer:
I don't understand this question
What is the mass in grams of precipitate formed when 250.0 mL of 0.360 M ZnCl₂ is mixed with excess KOH in the following chemical reaction?
ZnCl₂ (aq) + 2 KOH (aq) → Zn(OH)₂ (s) + 2 KCl (aq)
Answer:
8.95 g
Explanation:
ZnCl₂ (aq) + 2 KOH (aq) → Zn(OH)₂ (s) + 2 KCl (aq)First we calculate how many ZnCl₂ moles reacted, using the given concentration and volume:
250 mL / 1000 = 0.250 L0.360 M * 0.250 L = 0.090 mol ZnCl₂Then we convert ZnCl₂ moles into Zn(OH)₂ moles [ Zn(OH)₂ is the precipitate, as it is the solid]:
0.090 mol ZnCl₂ * [tex]\frac{1molZn(OH)_2}{1molZnCl_2}[/tex] = 0.090 mol Zn(OH)₂Finally we convert 0.090 Zn(OH)₂ moles into grams, using its molar mass:
0.090 mol Zn(OH)₂ * 99.424 g/mol = 8.95 gThe mass of a substance is the product of the molar mass and the moles of the substance. The mass of precipitate formed in the reaction is 8.95 gm.
What is Mass?The mass of the substance is the weight of the compound or the molecule present in the sample.
The balanced chemical reaction is shown as:
[tex]\rm ZnCl_{2} (aq) + 2 KOH (aq) \rightarrow Zn(OH)_{2} (s) + 2 KCl (aq)[/tex]
Given,
Volume (V) of zinc chloride = 0.250 L
Molarity of zinc chloride (M) = 0.360M
Moles of zinc chloride are calculated as:
[tex]\begin{aligned} \rm moles &= \rm molarity \times volume \\\\&= 0.360 \times 0.250\\\\&= 0.090 \;\rm mol\end{aligned}[/tex]
Moles of zinc hydroxide from zinc chloride are calculated as:
[tex]0.090\;\rm mol \; ZnCl_{2} \times \dfrac{ 1\;\rm mol \;\rm Zn(OH)_{2}}{1\;\rm mol\; ZnCl_{2}} = 0.090 \;\rm mol[/tex]
Mass is calculated as:
[tex]\begin{aligned} \rm mass &= \rm moles \times molar \; mass\\\\&= 0.090 \times 99.424 \\\\&= 8.95 \;\rm gm\end{aligned}[/tex]
Therefore, 8.95 gm precipitate is formed.
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Show the work. Convert 150 mm Hg to psi.
pls help me, thanks
Answer:
2.9 psi
Explanation:
Pressure (mmHg) = 150 mmHg
Pressure (psi) =?
The pressure in pound per square inch (psi) can be obtained as follow:
51.715 mmHg = 1 psi
Therefore,
150 mmHg = 150 mmHg × 1 psi / 51.715 mmHg
150 mmHg = 2.9 psi
Thus, pressure in pound per square inch (psi) is 2.9 psi.
1. How is the law of conservation of mass shown by a balanced chemical equation?
A) The subscripts must be the same on both sides of the equation.
B) The total volumes of the substances must be the same on both sides of the equation.
C) The coefficients must be the same on both sides of the equation.
D) The number of each type of atom must be the same on both sides of the equation.
Answer:
D
Explanation:
hope this helps
AN object has a volume
of 77ml and a mass of
429. What is the density
of this object?
Answer:
4.254320865115cm or simplied 4.25cm
Explanation:
what is the major organic product obtained from the following sequence of reactions Br Li Et2O CH2I2 Zn(Cu)
Answer: Hello the complete question showing the sequence is attached below
answer : Option C ( cyclopropane )
Explanation:
The Major organic product obtained from the following sequence of reactions attached below is : cyclopropane
from the sequence of reactions the first product will be lithiated alkaline and it will react with Cu to form Gilman reagent while the Gilman reagent will now react with alkene iodide to form cis alkene . major organic product that would be obtained when cis alkene reacts with Simmons smith reagent will be Cyclopropane
attached below is the detailed description of the products and the major organic product
Propose a mechanism and predict the products for the solvolysis of 2-bromo-2,3,3-trimethylbutane in methanol.
Answer:
See explanation and image attached.
Explanation:
Solvolysis is a reaction in which the solvent is also the nucleophile. The reaction occurs by SN1 mechanism since it yields most stable carbocation. The SN1 mechanism predominates since a weak nucleophile/base is used.
The major product as shown is the image attached to this answer. The first step is the loss of the bromide ion followed by nucleophillic attack of the solvent. Loss of H^+ completes the mechanism.
A change In which properly of light will have no effect on whether or not the photoelectric effect occurs
Answer: intensity is the answer. Intensity has no affect on whether or not the photoelectric effect occurs.
Explanation:
How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?
NO3−(aq) + ClO−(aq) + H2O(l) → NO(g) + ClO2−(aq) + OH−(aq)
Explain what is meant by a river’s load, and describe how the load is carried.
Please hurry I m timed T-T
Answer:
A rivers load is gravel and sand. It is carried by being dragged, rolled, and bounced along the bed of the river.
Explanation:
Answer:
the amount of gravel and sand at a river
the load is carried by the moving water
Look at the diagram. Which shows the correct arrangement of electrons in water?
Answer:
Option 4
Explanation:
In water molecule, oxygen has -2 charge on it while the hydrogen has +1 charge and one atom of oxygen combines with two hydrogen atoms. A hydrogen need only two electrons to complete its octet (one electron is its own the second electron is shared by oxygen) and a oxygen needs 8 electrons (It has six of its own and two are shared by two hydrogen atom).
Hence, option 4 is correct
Answer:
Option 2
It's more balanced than the others
12. Which organelle is found in plant and animal cells and is involved in making cellular energy from
respiration?
Answer:
The mitochondria is the organelle found in plant and animal cells and is involved in making cellular energy from respiration.
Explanation:
Determine the equilibrium constant for the system N204 = 2NO2 at 25°C.
The concentrations are shown here: [N2O4]= 2.48x10-2M, [NO_]=1.41x10-2M.
HURRRYYY
Answer: K = 8.01 ·10^-3 M
Explanation: K = [NO2] ² / [N2O4] = (0.0141 M)² / 0.0248 M = 0.00801 M
what are the examples of Biosphere
patulong po thank you ❣️❣️
Answer:
[tex]\color{Blue}\huge\boxed{Answer} [/tex]
An example of the biosphere is where live occurs on, above and below the surface of Earth. The zone of planet earth where life naturally occurs, extending from the deep crust to the lower atmosphere. The living organisms and their environment composing the biosphere. The living organisms of the earth.
The molecular weight (MW) of CuSO4 is 250g/mol. How many grams of CuSO4 are needed to make a 10 ml solution that has a molarity of 2.0 M?
Answer:
Explanation:
(The MW of CuSO4 is 250 g/mol).
Answer:
5 grams of CuSO4
Explanation:
First you make a stoichiometric relationship between the molarity and liters. So there is 2 mols per every liter. Then you put in the moleculur weight( for every mol there is 250 g). Then you have to get rid of the liters, so you times the equation by 0.01(this was found by 10ml converted into liters). After all of that you should end up with 5 grams of CuSo4
CHEMISTRY HELP ASAP
Use this balanced equation for the two questions below:
2KClO3(s) → 2KCl(s) + 3O2(g)
9. How many moles of KClO3 are used to produce 9.9 moles of O2?
10. How many moles of O2 are produced from 11.2 moles of KClO3?
PLS SHOW WORK TOO THX
Answer:
1 mole of KClO_3 contains 3 moles of O.
10 moles of O_2 contains 20 moles of O.
You need 20/3 moles of KClO_3 to produce 10 moles of O_2
Explanation:
sana makatulong
when iron rust it reacts with nitrogen from the air
true or false
it is false it reacts with oxygen
give brainliest if right
To solve such this we must know the concept of oxidation reaction. Therefore, the given statement is incorrect. When iron rust it reacts with oxygen from the air.
What is chemical reaction?Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.
In oxidation reaction, one of the element of the given compound oxidises to its higher oxidation state. Rusting is an example of oxidation reaction. The balanced equation for the rusting reaction can be given as
4Fe + 3O[tex]_2[/tex] + 6H[tex]_2[/tex]O → 4Fe(OH)[tex]_3[/tex]
Therefore, the given statement is incorrect.
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Morgan wants to compare the weather conditions at her school each day during the week. She decides to measure and record weather data each day at noon. Which of the following measurements would be least useful to report?
humidity
elevation
wind speed
air temperature
Answer: Air Temperature
Every force has a what?
Answer:
What do you mean Every force has a what?
Answer:
The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. ... The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.
40 POINTS!!! Ice at 0.0 degrees C is combined with 50.0g of water at 75.0 degrees C. Calculate the grams of ice present initially if the entire mixture comes to a final temperature of 25.0 degrees C after the ice melts. Specific heat of water is 4.18 J/goC. SHOW WORK!
Answer:
mi = 31.28 g
Explanation:
According to the law of conservation of energy:
[tex]Heat\ Gain\ by\ Ice = Heat\ Lost\ by\ Water\\m_iL = m_wC\Delta T\\[/tex]
where,
mi = mass of ice = ?
L = Latent heat of fusion of ice = 334 J/g
mw = mass of water = 50 g
C = specific heat of water = 4.18 J/g.°C
ΔT = change in temperature of water = 75°C - 25°C = 50°C
Therefore,
[tex]m_i(334\J/g) = (50\ g)(4.18\ J/g.^oC)(50^oC)[/tex]
mi = 31.28 g
A 36.6-mol sample of Co represents how many atoms?
Answer:
2.20 x 10²⁵ atoms
Explanation:
Atoms of CO= 36.6-mol sample
From Avogadro's constant, which is
(6.022 × 10^ 23 atoms per mole)
Then
Number of atoms=[ 6.022 × 10^ 23 atoms/mole] × [36.6-mol]
= 2.20 x 10²⁵ atoms
Hence, number of atom is 2.20 x 10²⁵ atoms
Solid A at 80°C is immersed in liquid B at 60°C. Which statement correctly describes the energy changes between A and B?
Heat energy will be released by solid A which will then be absorbed by liquid B.
What is heat energy?
These little particles vibrate back and forth or run into each other constantly. All matter contains a type of energy known as heat (or thermal) energy, which is produced by the movement of particles.
Particle energy increases with temperature. It is possible for some of this energy to be transferred to cooler particles. For instance, in the gas state, when a fast-moving particle strikes a slower-moving particle, some of the energy from the collision is transferred to the slower-moving particle, increasing its speed.
A region of high energy will gradually spread throughout the material as a result of billions of moving particles colliding with one another until thermal equilibrium is established.
Therefore, heat energy will be released by solid A which will then be absorbed by liquid B.
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