Using the statistical definition of entropy, what is the entropy of a system where W = 4?

A. 1.87 × 10–23 joules/kelvin

B. 1.56 × 10–23 joules/kelvin

C. 1.91 × 10–23 joules/kelvin

D. 2.07 × 10–23 joules/kelvin

Answer:

1-state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."

2-give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the learning context. But in more complex labs, the background may require more paragraphs.

Explanation:

Answer:2.47

Explanation:

So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!

Answer:

11 because the number of protons is the atomic humber

Explanation:

Answer:

d

Explanation:

The watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.

The given problem is based on the concept and fundamentals of watershed boundary. The watershed boundary is defined as the topmost elevations surrounding the lake or river segment, such that the drop of water falling outside the boundary will drain to another watershed.

Thus, we can conclude that the watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.

Learn more about the watershed boundary here:

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Answer:

The mass of the truck is 11,000 Kg.

Explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

It's given a truck travels at a constant acceleration of [tex]a=3.6~m/s^2[/tex] when a net force of F=39,600 N is applied.

To find the mass of the truck, solve the equation for m:

[tex]\displaystyle m=\frac{F}{a}[/tex]

[tex]\displaystyle m=\frac{39,600}{3.6}[/tex]

Operating:

m = 11,000 Kg

The mass of the truck is 11,000 Kg.

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

[tex]P=60+100\\P=160 [W][/tex]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

[tex]P=V*I[/tex]

where:

P = power [W]

V = voltage [V]

I = current [amp]

[tex]I = P/V\\I=160/240\\I=0.67 [amp][/tex]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

[tex]V=I*R[/tex]

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

[tex]P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R[/tex]

[tex]60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm][/tex]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

[tex]R = 133.66 + 225\\R = 358.67 [ohms][/tex]

Answer:

true

Explanation:

Answer:

false

Explanation:

Answer:

heat

Explanation:

Answer:

A. element

Explanation:

A molecule is formed when two or more atoms join together chemically. If atoms combine that are of two or more different elements, we call that a compound. All compounds are molecules, but not all molecules are compounds.

Answer: No, constant speed does not mean constant velocity.

A classic often used example would be to consider a car driving in circles. If the speedometer reads say 20 mph the entire time, then the speed of the car is held constant (ie the same). But the velocity is changing because velocity measures direction along with speed. The car is changing direction as it moves in a circle.

Answer:

Cell wall and chloroplasts (only for leaves)

Explanation:

All plant cells have cell walls to give the cell a fixed shape but animal cells do not have cell walls. Some cells like leaf cells have chloroplasts to make their own food for the plant while animal cells do not have chloroplasts.

Answer:

Freudian

Explanation:

Answer:

Freudian

Explanation:

Answer:

The inner planets are much smaller than the outer planets and because of this have relatively low gravity and were not able to attract large amounts of gas to their atmospheres.

Answer:

Part A:

The other two ways we can rewrite F = m·a are;

1) F = dp/dt

2) F = m × d(v)/dt

Part B:

The mass of the wheelbarrow is 60 kg

Explanation:

Part A:

The other two ways of rewriting the equation are;

1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and

2) From the above equation, where, m is constant, we have;

F = d(m·v)/dt  = m × d(v)/dt

∴ F = m × d(v)/dt

Part B:

The force with which we push the wheelbarrow = 240 N

The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²

From F = m × a

Where;

m = The mass of the wheelbarrow

m = F/a = 240 N/(4 m/s²) = 60 kg

The mass of the wheelbarrow = m = 60 kg.

Answer:

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015×10−34 when expressed in the unit J⋅s, which is equal to kg⋅m2⋅s−1, where the metre and the second are defined in terms of c and ΔνCs.

Answer:

The kilogram (abbreviation, kg) is the standard international (SI)system of units.it was originally defined as the mass of 1 litre(10-3 cubic meter) of pure water.At the earth's surface ,a mass of 1 kg weight approximately 2.20 pounds (IB)

Explanation:

the force of attraction exerted by the earth on a body of certain mass. It's SI unit is Newton(N).

Answer:

42.69J

Explanation:

The question is not complete, here the complete one

A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy

and it velocity vx= -3.4m/s

Step one:

given

mass m= 2.3kg

spring constant k= 120 N/m

x= 0.7m

vx=-3.4m/s

Step two:

The expression for the total energy is

[tex]Energy= 1/2mv^2 + 1/2Kx^2[/tex]

substituting we have

[tex]Energy= 1/2*2.3*3.4^2+1/2*120*0.7^2[/tex]

[tex]Energy= 13.29+29.4\\\\Energy=42.69J[/tex]

Answer:

1. What similarities do you notice

Within a group(column)?

Within a row (period)?

2. Locate the element in Period 4, Column 1.

Predict the number of valence electrons.

Predict the Lewis Dot Structure

Answer:

A. There is hydrogen bonding between water molecules

Explanation:

Boiling point is a physical property of matter. It is typically conditioned by the intermolecular forces present between the molecules of a compound.

Answer:

A)

Explanation:

There is hydrogen bonding between water molecules

Answer:

Explanation:

Hell im good dude

Answer: The work is 1863 N*m

Explanation:

We can define work as:

W = F*d

Where F is the force that the mover needs to apply to the refrigerator, and d is the distance that the refrigerator is moved.

To move the refrigerator, the minimal force that the mover needs to do is exactly the friction force (In this case, the refrigerator will move with constant speed).

Then we will have:

F = 230 N

and the distance is 8.1 meters, then the work will be:

W = 230N*8.1 m = 1863 N*m

Answer:

low frequencies

Explanation:

The type of sonar that causes loud noises in the water is known as active sonar.

Active sonar is a system that emits sound waves into the water and listens for their reflections to detect objects and measure distances. It works by sending out a pulse of sound, which travels through the water and reflects off objects such as submarines, ships, or marine life.

The reflected sound, or echo, is then received by the sonar system's hydrophone, allowing it to analyze the data and provide information about the surrounding environment.

While active sonar is effective for detecting objects and underwater features, it can also produce loud noises that may have various effects on marine life.

The loud sound pulses can potentially disturb or harm marine animals, particularly marine mammals like whales and dolphins, which rely heavily on sound for communication and navigation. The use of active sonar has been a topic of environmental concern, and efforts are made to minimize its impact on marine ecosystems through regulations and responsible use.

Hence, The type of sonar that causes loud noises in the water is known as active sonar.

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#SPJ2

Answer:

this conponent is a bulb

and is used to measure brightness

Answer:

none

Explanation:

~both of them show to the nearest metre.

~millimeter has (mm) unit eg 0.7mm

0.76cm is the correct answer

bcoz after Mili metre there is centi metre so option c is correct

[tex]\frak{\huge{Mark \: me \: brainliest}}[/tex]

Answer:

E₀ = 5.97 10⁸ N / C

Explanation:

Coulomb's law in a material medium is written

       [tex]F = \frac{1}{4\pi \epsilon } \frac{q_{1} q_{2} }{r^{2} }[/tex]

ε is the electrical permittivity of the material

Electric field and force are related        

          F = q E

in dielectric materials such as mica there is an electric field inside the material that decreases the external field

           E = E₀ /ε

where ε is the electrical permittivity of the material; in general it is tabulated in the form

           [tex]\epsilon _{r} =\frac{\epsilon}{\epsilon_{o}}[/tex]

          [tex]\epsilon = \epsilon_{r} \ \epsilon_{o}[/tex]

we substitute

          F = q E₀ /  \epsilon_{r}  \epsilon_{o}

         [tex]E_{o} = \frac{F \ \epsilon_{r} \ \epsilon_{o} }{q}[/tex]

for the case of mica it is equal to er = 5.4 and suppose a test charge equal to the charge of the electron

we calculate

          E₀ = 2  5.4  8.85 10⁻¹² / 1.6 10⁻¹⁹

          E₀ = 59.74 10⁷

          E₀ = 5.97 10⁸ N / C

Answer:

False!!

Explanation:

Answer:

The speed with which a rock would have to be thrown to put it in 234 Ida's orbit, near its surface is approximately 12.917 m/s

Explanation:

The given parameters are;

The mass of Ida, M = 4 × 10¹⁶ kg

The radius of 234 Ida, r = 16 km = 16,000 m

The speed, v, required to put a rock in 234 Ida's orbit near its surface is given by the orbital velocity equation as follows;

[tex]v = \sqrt{{\dfrac{G \times M}{r} } }[/tex]

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Substituting the known values gives;

[tex]v = \sqrt{{\dfrac{6.67408 \times 10^{-11} \times 4 \times 10^{16}}{16,000} } } \approx 12.917[/tex]

Therefore, the speed required to put a rock in 234 Ida's orbit near its surface = v ≈ 12.917 m.