Answer:
2.343 g of HEPES sodium salt is needed.
Explanation:
So, from the question above we have the following parameters which is going to help in solving this particular question.
The number of moles = 90mM, the pH = 7.50, FW for the HEPES sodium salt = 260.31, and the volume of HEPES sodium salt required = 100mL.
Therefore, the amount of HEPES sodium salt required to make the buffer = 260.31 × 9 × 0.001 = 2.343 grams of HEPES sodium salt is needed in 10mL.
. Predict the possible products for the following reaction and include
molecular, complete ionic, and net ionic equations.
NA2SO4 (aq) +γ (BrO3)2 (aq) --->
Answer:
Introduction
As a diligent student of chemistry, you will likely encounter tons of reactions that occur in aqueous solution (perhaps you are already drowning in them!). When ions are involved in a reaction, the equation for the reaction can be written with various levels of detail. Depending on which part of the reaction you are interested in, you might write a molecular, complete ionic, or net ionic equation.
Definitions of molecular, complete ionic, and net ionic equations
A molecular equation is sometimes simply called a balanced equation. In a molecular equation, any ionic compounds or acids are represented as neutral compounds using their chemical formulas. The state of each substance is indicated in parentheses after the formula. [Huh?]
Let's consider the reaction that occurs between \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text. When aqueous solutions of \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text are mixed, solid \text{AgCl}AgClstart text, A, g, C, l, end text and aqueous \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript are formed. Using this information, we can write a balanced molecular equation for the reaction:
\text{AgNO}_3(aq) + \text{NaCl}(aq) \rightarrow \text{AgCl}(s) + \text{NaNO}_3(aq)AgNO
3
(aq)+NaCl(aq)→AgCl(s)+NaNO
3
(aq)start text, A, g, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis, plus, start text, N, a, C, l, end text, left parenthesis, a, q, right parenthesis, right arrow, start text, A, g, C, l, end text, left parenthesis, s, right parenthesis, plus, start text, N, a, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis
[What kind of reaction is this?]
If we could zoom in on the contents of the reaction beaker, though, we wouldn't find actual molecules of \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, or \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript. Since \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, and \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript are soluble ionic compounds, they dissociate into their constituent ions in water. For example, \text{NaCl}NaClstart text, N, a, C, l, end text dissociates into one ion of \text{Na}^+Na
+
start text, N, a, end text, start superscript, plus, end superscript for every ion of \text{Cl}^-Cl
−
start text, C, l, end text, start superscript, minus, end superscript; these ions are stabilized by ion-dipole interactions with the surrounding water molecules. [I don't get it!]
Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.
Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.
Sodium chloride dissociates into sodium and chloride ions in water, and these ions become solvated by the highly polar water molecules. Image credit: "Salts: Figure 1" by OpenStax Anatomy and Physiology, CC-BY-NC-SA 4.0.
From the molecular formula, we can rewrite the soluble ionic compounds as dissociated ions to get the complete ionic equation:
\text{Ag}^+(aq) + \blueD{{\text{NO}_3}^-(aq)} + \maroonD{\text{Na}^+(aq)} + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \maroonD{\text{Na}^+(aq)} + \blueD{{\text{NO}_3}^- (aq)}Ag
+
(aq)+NO
3
−
(aq)+Na
+
(aq)+Cl
−
(aq)→AgCl(s)+Na
+
(aq)+NO
3
−
−
(aq)
+
Na
+
(aq)
+Cl
−
(aq)→AgCl(s)+
Na
+
(aq)
+
NO
3
−
(aq)
a. Use the balanced equation C3H8 + 5O2 -> 3CO2 + 4H2O to answer the following questions
i. How many moles of CO2 are produced from 5 moles 02? (1 point)
ii. How many grams of CO2 are produced from 5 moles O2? (2 points)
iii how many grams of CO2 are produced from 128.00g O2? (2 points)
Answer:
i. 3 moles.
ii. 132.03 grams.
iii. 105.6 grams.
Explanation:
Hello!
In this case, given the balanced chemical reaction, we can proceed as follows:
i. By starting with 5 moles of oxygen, via the 5:3 mole ratio we compute the produced moles of CO2:
[tex]n_{CO_2}=5molO_2*\frac{3molCO_2}{5molO_2} =3molCO_2[/tex]
ii. Now, since we have previously computed the moles of CO2 from the same moles of oxygen, by using its molar mass (44.02 g/mol), we obtain:
[tex]m_{CO_2}=3molCO_2*\frac{44.01gCO_2}{1molCO_2} =132.03gCO_2[/tex]
iii. Now, we need to combine the previously used two proportional factors for the calculation of the mass of CO2 from 128.00 grams of oxygen (molar mass 32.00 g/mol):
[tex]m_{CO_2}=128.00gO_2*\frac{1molO_2}{32.00gCO_2}*\frac{3molCO_2}{5molO_2}*\frac{44.01gCO_2}{1molCO_2}\\\\m_{CO_2}=105.6gCO_2[/tex]
Best regards!
what is a difference between water and wind
Answer:
You could have looked it up, but here ya go...
Explanation:
Wind is a type of dry deposition method. If original soil is eroded and wind exists, soil particles move via wind (sometimes it is called dust transport) and finally are deposited at final destination regions/areas. However, water erosion occurs when rainfall or hail occurs.
Hope this Helped! :)
Crude oil has many applications once it has been distilled at a refinery. According to the diagram, what process is used to distill crude oil into its various components to use energy distribution?
A) separation by density
B) separation by boiling points
C) separation by the porosity of the components
D) separation by the organic content or each component
Answer:
B) separation by boiling points
Explanation:
According to the diagram depicted, crude oil is separated into its different units using boiling points.
The boiling points of a compound is the temperature at which it begins to boil. The process of fractional distillation is used in the oil industry to separate crude oil into its components. When the boiling point of a oil fraction is reached, it becomes vaporized and rises within the columnMost organic compounds are made of just four elements.
What are they?
Answer:
hydrogen, carbon, oxygen and nitrogen
Explanation:
Most organic compounds are made up of the four elements: hydrogen, carbon, oxygen and nitrogen.
Most organic compounds are made of just four elements are hydrogen, carbon, oxygen and nitrogen.
What do you mean by an organic compound ?The term organic compound is defined as a substance that contains covalently - bonded carbon and hydrogen and often with other elements.
Benzoic acid, aromatic compounds, benzoic aldehyde, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, VOC, benzoic acid, and diethyl malonate are some examples of organic compounds.
Carbohydrates, lipids, proteins, and nucleotides are all organic compounds that are required for human function. Because they contain both carbon and hydrogen, these compounds are classified as organic.
Thus, Most organic compounds are made of just four elements are hydrogen, carbon, oxygen and nitrogen.
To learn more about the organic compound, follow the link;
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air is trasferred from 75 L tank where the pressure is 125 psi and the temperature is 288 K to a tire with a volume. of 6.1 L and a pressure of 25 psi. what is the new temperature ?
Answer:
4.7K
Explanation:
Given parameters:
Initial volume = 75L
Initial pressure = 125psi
to atm gives 8.5atm
Initial temperature = 288K
New volume = 6.1L
New pressure = 25psi
to atm gives 1.7atm
Unknown:
New temperature = ?
Solution:
To solve this problem, we use the combined gas law which is given below:
[tex]\frac{P1 V1}{T1}[/tex] = [tex]\frac{P2 V2}{T2}[/tex]
P, V and T are pressure, volume and temperature
1 and 2 are initial and new states
[tex]\frac{8.5 x 75}{288}[/tex] = [tex]\frac{1.7 x 6.1}{T2}[/tex]
T2 = 4.7K
What is the measure of the amount of dissolved salts in ocean water?
Answer:
Salinity
HOPE THIS HELPS! :)
Explanation:
use scientific notation to solve
which of the following is a strong acid?
A, HCI (hydrochloric acid)
B, HF (hydrofluoric acid)
C, NaOH (sodium hydroxide)
D, NH3 (ammonia)
Twelve grams of gas occupies 14.5 liters at a pressure of 52.0cm Hg. What is the volume when the pressure has increased to 85.0cm Hg?
Answer:
8.87 L.
Explanation:
From the question given above, the following data were obtained:
Mass (m) of gas = 12 g
Initial volume (V₁) = 14.5 L
Initial pressure (P₁) = 52 cmHg
Final pressure (P₂) = 85 cmHg
Final volume (V₂) =?
The final volume of the gas can be obtained by using the Boyle's Las equation as illustrated below:
P₁V₁ = P₂V₂
52 × 14.5 = 85 × V₂
754 = 85 × V₂
Divide both side by 85
V₂ = 754 / 85
V₂ = 8.87 L
Thus the volume of the gas will be 8.87 L
What did organizing information on the periodic table reveal?
A. Subatomic particles
B. New forms of energy
C. Molecular structures
D. Periodic patterns and trends
Answer:
The groupings of elements in the periodic table reveal various trends, present in groups such as the alkali metals and noble gases, or the lanthanides and actinides. The periodic table can be used to find information on elements or predict the properties of as-of-yet undiscovered elements.
Explanation:
Answer: D
Just took the quiz
US
What is the percent of H in
NH3?
(H = 1.008 amu, N = 14.01 amu)
[?]%
Answer:
17.6
Explanation:
Answer is explained above
1. What are the two effects of the continental plate/continental plate convergent boundary?
2. Where can you find an example of this type of divergent boundary? Which country, continent or ocean?
Answer
oh you again?
Explanation:
___________ changes affect the nuclei (nucleus) of an atom, which produces new elements. (A Nuclear (B Chemical (C Physical
Answer:
A
Explanation:
Is Gold (Au) soluble?
Answer:
yes
Explanation:
A solution was diluted 1/40, and the final concentration was 20%. What was the original concentration?
The original concentration : 800%
Further explanationGiven
Diluted 1/40
Final concentration 20%
Required
The original concentration
Solution
Dilution is the process of adding solvent to get a more dilute solution.
The moles(n) before and after dilution are the same.
Can be formulated :
n₁ = n₂
M₁.V₁ = M₂.V₂
diluted 1/40(dilution factor)⇒ V₁/V₂=1/40⇒V₂/V₁=40
M₂ = 0.2(20%)
Input the value for M₁ :
M₁=M₂ x (V₂/V₁)
M₁ = 0.2 x 40
M₂ = 8(800%)
=
What is Sr(NO3)2 + ZN ?
Answer:
strontium nitrate
Explanation:
hope this helps you....:)
What are important things we can figure out by looking at a food web?
Answer:
We can find out what animals eat..and how long a food chain could get..?
Explanation:
Measure that affects the thermal energy of matter but not it's temperature.
Answer: mass
Explanation:
Mr. Smith wanted to see if the color of light shined on a plant had an effect on the number of leaves it had. He gathered a 2
groups of the same species of plants, gave them the same amount of water, and did the test for the same amount of time.
On one group of plants he used white light. On the second group he changed the light color to red. Identify:
Independent variable:
Dependent variable:
Constants:
Control group (What would Mr. Smith use as a control group?):
Experimental group (what would Mr. Smith use as a experimental group?)
The table below shows properties of two compounds at standard pressure. Which statement classifies the two compounds? 1)Both compounds are ionic, 2)Both compounds are molecular, 3) Compound 1 is ionic, and compound 2 is molecular, 4)Compound 1 is molecular, and compound is ionic
Answer:
3) Compound 1 is ionic, and compound 2 is molecular
Explanation:
Compound-1 is an ionic compound while Compound-2 is a molecular compound. Option 3 is correct.
Ionic Compound:
They are formed when an atom donates its electron to another atom. This results in one positive and one negative ion.
Hence, it is a very strong bond. These compounds have a very high melting and boiling point. They are very good electric conductors in the aqueous solution.
For example- NaCl.
Molecular compounds:
They are compounds that are made up of discrete molecular units. For example- [tex]\bold {H_2O}[/tex]
They have very weak intermolecular bonds hence have low boiling and melting point and do not conduct electricity.
SInce Compound-1 has higher MP and BP and Compound-2 has low melting and boiling point.
Therefore, Compound-1 is an ionic compound while Compound-2 is a molecular compound.
To know more about Ionic Compound:
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How many moles are in 1.23 x 1024 molecules of oxygen gas.
Answer:
2.04moles
Explanation:
Given parameters:
Number of molecules = 1.23 x 10²⁴molecules
Unknown:
Number of moles of oxygen gas = ?
Solution:
To solve this problem;
6.02 x 10²³ molecules makes up 1 mole of any substance
1.23 x 10²⁴molecules will make up [tex]\frac{1.23 x 10^{24} }{6.02 x 10^{23} }[/tex] = 2.04moles
6.02 x 10²³ molecules makes up 1 mole of any substance
1.23 x 10²⁴molecules will make up = 2.04moles
(9) How many moles of oleum in 1780. g of oleum? - Write an equation to summarize the process.
Answer:
1. 10moles
2. Find the summarized equation below
Explanation:
Mole = mass ÷ molar mass
Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)
= 2 + 64 + 112
= 178g/mol
According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:
Mole = 1780/178
Mole = 10moles
2. The summarized equation of the contact process is:
1) S + O2 → SO2
2) 2SO2 + O2 → 2SO3
3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7
4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)
As a heavy metal ball rolls down a hill, it goes faster and faster. Which statement is true?
The ball's potential energy is transferring into kinetic energy
Brainly if correct? Thanks!
Answer:
A
Explanation:
The balls potential energy is changing to kinetic energy
All moving objects have kinetic energy. True False
Answer:
true
.......................
Answer: You're Welcome!
Oh, It's False - Kinetic energy depends upon the speed of the object; potential energy depends upon the position of the object.
Electromagnetic waves travel because of ____
because they need a medium to travel they can travel everywhere if they got the medium
Propane is what type of matter?
Element
Compound
Homogeneous mixture
Heterogeneous mixture
How do the percent compositions for C3H6 and C4H7 compare?
A. They are the same
B. C4H8 has a higher percentage of carbon than C3H6.
C. C4H8 has a higher percentage of hydrogen than C3H6.
D. none of the above
A. They are the same
Further explanationGiven
C3H6 and C4H8
Required
The percent compositions
Solution
C₃H₆(MW = 42 g/mol)%C = 3.12/42 x 100% = 85.71%
%H = 6.1/42 x 1005 = 14.29%
C₄H₈(MW=56 g/mol)
%C = 4.12/56 x 100% = 85.71%
%H = 8.1/56 x 100%=14.29%
So they are the same, because mol ratio of C and H in both compounds is the same, 1: 2
A chemist adds 600.0mL of a 0.444/gL calcium sulfate CaSO4 solution to a flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.
Answer:
0.266 grams of calcium sulfate
Explanation:
We can calculate the mass of calcium sulfate added using the given volume and concentration of the solution:
First we convert 600.0 mL to L ⇒ 600.0 mL equals 0.6000 L (600 ÷ 1000).
0.444 g/L * 0.6000 L = 0.266 g
Thus the answer is 0.266 grams of calcium sulfate.
How many grams of water are produced when 37.7 g of hydrogen peroxide (H2O2) decomposes into oxygen gas and water?
Answer:
Mass of water produced = 19.8 g
Explanation:
Given data:
Mass of hydrogen peroxide = 37.7 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂O₂ → 2H₂O + O₂
Number of moles of H₂O₂:
Number of moles = mass/molar mass
Number of moles = 37.7 g/ 34 g/mol
Number of moles = 1.1 mol
Now we will compare the moles of H₂O₂ and H₂O from balance chemical equation in order to determine the moles of water formed.
H₂O₂ ; H₂O
2 : 2
1.1 : 1.1
Mass of water formed:
Mass = number of moles × molar mass
Mass = 1.1 mol × 18 g/mol
Mass = 19.8 g