why are metals good conducts of heat??????
Materials that are good conductors of thermal energy are called thermal conductors. Metals are especially good thermal conductors because they have freely moving electrons that can transfer thermal energy quickly and easily
Answer:
Explanation:
Materials that are good conductors of thermal energy are called thermal conductors. Metals are especially good thermal conductors because they have freely moving electrons that can transfer thermal energy quickly and easily.1
. What is the molarity of 5.30 moles of NaCl dissolved in 0.400 L of solution?
Answer:
13.25 M
Explanation:
Molarity is moles over liters so simply plug your values in as such:
5.30 mol ÷ 0.400 L = 13.25 M
what is 1 mol / 66.04g
Answer:
15.142338 mol/kg
Explanation:
(1 mole) / (66.04 grams)
What is the theoretical oxygen demand in liters of air for a 50 mg / L acetone solution, CH3COCH3, to decompose completely?
Answer:
18.368 Liters
Explanation:
Given that balanced Acetone oxidation,
= C3H6O + 4O2 = 3CO2 + 3H2O
lets assume volume of acetone = 1 liter
mass of acetone = 50 mg
number of moles present = (5*10^-3)g / ( 58.08 ) = 0.0000861 mol
Given that : I mol of ( acetone ) = 4 mol of oxygen
∴0.0000861 mol of acetone = 0.0003444 mol of oxygen
also note that the ratio of air to oxygen is
0.21 mol of oxygen = 1 mol of air
∴ 0.0003444 mol of oxygen = 0.00164 mol of air (0.0003444 / 0.21 )
note : 1 mol at STP = 22.4 L (at STP = Temperature = O°C
Finally the theoretically oxygen demand in liters of air for a 50 mg/L of acetone to decompose
Given that Acetone decompose/degrade completely between 500°C - 600°
we will take 500° for the sake of this calculation
The oxygen demand in liters will be
= 22.4 * 0.00164 * 500 = 18.368 Liters
The theoretical oxygen demand in liters of air for a 50 mg / L acetone solution, to decompose completely is 18.368 Liters.
How we calculate moles?Moles of any substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
CH₃COCH₃ + 4O₂ → 3CO₂ + 3H₂O
Given mass of acetone = 50mg = 0.05g
Moles of acetone = 0.05g / 58.08g/mol = 0.0000861 mole
From the stoichiometry of the reaction, it is clear that:
1 mole of CH₃COCH₃ = 4 moles of O₂
0.0000861 mole of CH₃COCH₃ = 4×0.0000861=0.0003444 moles of O₂
We know that ratio of air is:
0.21 mole of oxygen present = in 1 mole of air
0.0003444 mole of oxygen present = in 0.0003444/0.21=0.00164 mole of air
At STP 1 mole of gas is present in 22.4 Liter.
Degradation of acetone takes place in 500°C - 600°C.
Theoretical oxygen demand = 22.4×0.00164×500 = 18.368 Liters
Hence, theoretical oxygen demand is 18.368 Liters.
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https://brainly.com/question/13251445
CH3OH=CO+H2 Balance the equations and tell the atoms. Giving brainliest
Answer:
CII + 4 e- → C-II (reduction)
4 H0 - 4 e- → 4 HI (oxidation)
Explanation:
Answer:
The correct answer should be:
[blank] CO + [2] H2 => [blank] CH3OH
or
CO + [2] H2 => CH3OH
Which time shows the lowest composition of all green house gases?
Answer:
1750
Explanation:
Greenhouse gases are those gases that are believed to contribute to the rise in the temperature of the earth by trapping infrared rays close to the surface of the earth.
Prominent among the greenhouse gases are; N2O, methane and CO2.
From the chart, we can see that the lowest sum of concentration of greenhouse gases measured in ppm was obtained in 1750. Thus this period shows the lowest composition of greenhouse gases.
SOMEONE HELP PLEASE !!
Which is not an electrolyte
1. Ionic salt
2. Acid
3. Base
4. Water
PLEASE HELP ME
salt is not because it gets u dehydrated
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Answer:
I think Sr I think so maybe
how many formula units are present in 0.354 moles of copper (III) chloride, CuCl2
Answer:
47.596008
Explanation:
Wat two common uses for Zinc???
Answer:
It is used to prevent rusting and corrosion on steel and iron. It is also used for batteries
Explanation:
It is used to prevent rusting and corrosion on steel and iron. It is also used for batteries
Which two radioisotopes have the same decay mode?
A)220Fr and 60C0
B)37K and 42K
C)37Ca and 53Fe
D)99Tc and 19Ne
Answer:
c
Explanation:
37Ca and 53Fe have the same decay mode.
What are the three common modes of radioactive decay?Three of the most common types of decay are alpha decay (α-decay), beta decay (β-decay), and gamma decay (γ-decay), all of which involve emitting one or more particles.
Which isotopes are most likely to decay?The most likely mode of decay for a neutron-rich nucleus is one that converts a neutron into a proton. Every neutron-rich radioactive isotope with an atomic number smaller than 83 decays by electron emission. C, 32P, and 35S, for example, are all neutron-rich nuclei that decay by the emission of an electron.
Learn more about radioisotopes here https://brainly.com/question/18640165
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2. If you have 100 graham crackers, unlimited chocolate, and only five marshmallows, how many S’mores can you make? Show calculations.
Answer:
I'm pretty sure it's only 5, because once you've used up all 5 marshmallows, you can't make any more s'mores. Unless just graham crackers and chocolate counts as a s'more...
:)
Is silicon(IV) oxide the same as silicon dioxide
Answer:
Yes, it is
Explanation:
Silicon (IV) oxide, commonly known as silica is a substance that majorly constitutes SAND. It has the chemical formula, SiO2, which contains a combination of silicon and oxygen.
The IUPAC name of SiO2 is Silicon IV oxide, which can also be referred to as Silicon dioxide because the structure the compound contains two (-di) oxygen atoms. Hence, based on the question, silicon(IV) oxide is the same as silicon dioxide.
HELP ME PLEASE WILL GIVE BRAINLY NO BAD ANSWERS
Answer:
7.17
Explanation:
convert 5.50g to moles of salicylic acid. Then use mole ratios and convert the moles of salicylic acid to moles of Asprin(mole ratio is 1:1). Then convert the moles to grams using the molar mass of asprin.
Hi can anyone help me ?
Answer:
its 4
Explanation:
Geothermal energy is produced from a combination of high pressure and the breakdown of______ underground.
Fill in the blank
How many formula units are there in 7.55 moles potassium chloride?
Answer:
mole is equal to 1 moles Potassium Chloride, or 74.5513 grams.
unknown substance's mass: 75.0g, unknown substances molar mass = 150.0 g/mol, Hfus = 5.0x10^3 J/mol, Hvap = 1.00 x 10^4 J/mol, unknown substance's specific heat (liquid) = 2.2 J/g, unknown substance's specific heat (gas) = 4.8 J/g, unknown substances's specific heat (solid) = 5.0 J/g; Calculate the amount of heat (in J) for the unkown sample as it is heated at a constant rate from 10.0c to 25.0c as it passes through each of the following regions: region uv
Answer:
kkajqjjqjqjnqnqnqjqjq
HELP!!! WILL MARK BRAINLIEST!!!
picture attached below
Answer:
0.2 cm
Explanation:
looking at the ruler, you can see that the diameter is 0.4 cm. to get the radius, just divide by two, which gets 0.2 cm as the radius
Show work on how you answer it, please.
Answer:
the frist one is balance
by the side of reactant is
C=8
O=8
H2=17×2=34
from the product side
C=8
O=8×1=8
H2=18+(8×2)=34
and they are balance
the second one is
the reactant side
Fe=4
S=4
O2=7×2=14
the product side of the chemical equation
Fe=3×2=6
S=4
O=(4×2)+(3×3)=6+9=15
it is not balance.
#THE FRIST ONE IS BALANCE.
#THE SECOND ONE IS NOT BALANCE.
Valerie creates a model using three different rocks. The rocks are classified as igneous, metamorphic, and sedimentary.
Which property does Valerie use for classification purposes?
color
formation
shape
texture
The rocks are classified as igneous, metamorphic, and sedimentary use the formation for classification purposes.
What are the 3 types of rocks existing on earth?The outermost of them, called the crust, is composed of three types of rocks: magmatic, sedimentary and metamorphic. They are defined through the origin of several minerals and can be characterized with chemical composition, texture or shape, but the most used specification is based on composition.
The property does Valerie use for classification purposes is formation.
See more about rocks at brainly.com/question/19930528
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What is the range of pH values in a basic solution?
a.pH=7
b.pH is greater than 7
c.pH is between 0 and 14
d.pH is less than 7
Answer:
b. ph is greatet than 7
Explanation:
ph=7 neutral
ph=7-14 basicity as you go up increase basicity
ph=0-7 acodity as you go down increasing acidity
what are protons, what is their charge, and where they located?
Answer:
Protons are the positive parts in an atom, they are positively charged and they are located in the nucleus of an atom..
Explanation:
prolly not the best explanation but hope it helps <3
A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is the volume of the gas?
Answer:
9.91 mL
Explanation:
Using the combined gas law equation as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (torr)
P2 = final pressure (torr)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
V1 = 15.0mL
V2 = ?
P1 = 760 torr
P2 = 1252 torr
T1 = 10°C = 10 + 273 = 283K
T2 = 35°C = 35 + 273 = 308K
Using P1V1/T1 = P2V2/T2
760 × 15/283 = 1252 × V2/308
11400/283 = 1252V2/308
Cross multiply
11400 × 308 = 283 × 1252V2
3511200 = 354316V2
V2 = 3511200 ÷ 354316
V2 = 9.91 mL
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O How many moles of oxygen gas (O2) are needed to create EXACTLY 6 moles of Carbon dioxide(CO2)?.
The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?
Answer:
The pressure of the gas would be 3.06 atm
Explanation:
Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:
P1 / T1 = P2 / T2
Where P1 is the initial pressure = 3.16atm
T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K
P2 is our incognite
And T2 is = 273.15 + 22.9°C = 296.05K
Replacing:
3.16atm / 305.35K = P2 / 296.05K
3.06 atm = P2
The pressure of the gas would be 3.06 atm1pt which blood vessel carries waste-rich blood from the capillaries back to the healt?
O A. vein
OB. neuron
O C. vena cava
OD. aorta
why can lime juice remove rust stain
Answer:
El limon por su alto contenido en ácido cítrico, actúa como un excelente limpiador natural debido a su bajo pH y propiedades antibacterianas. A parte de todas estas propiedades, los limones huelen muy bien y es una rareza que pudiesen manchar o dañar algún material de la casa.
Explanation:
Answer:
It's the citric acid reacting to the iron oxide -which is basically the rust- it dissolves.
Explanation:
Determine the number of representative particles in each of the following:
(a) 0.294 mol silver
____ atoms
(b) 8.98 10-3 mol sodium chloride
____ formula units
(c) 23.3 mol carbon dioxide
____ molecules
(d) 0.310 mol nitrogen (N2)
____ molecules
Answer:
(a) 0.294 mol silver = [tex]1.770 * 10^{23}[/tex]
(b) 8.98 * 10-3 mol sodium chloride - [tex]5.407 *10^{23}[/tex]
(c) 23.3 mol carbon dioxide = [tex]1.403 * 10^{25}[/tex]
(d) 0.310 mol nitrogen (N2) = [tex]1.866 * 10^{23}[/tex]
Explanation:
In one mole there are [tex]6.022 * 10^{23}[/tex] atoms/molecules
(a) 0.294 mol silver = [tex]6.022 * 10^{23} * 0.294 = 1.770 * 10^{23}[/tex]
(b) 8.98 * 10-3 mol sodium chloride - [tex]5.407 *10^{23}[/tex]
(c) 23.3 mol carbon dioxide = [tex]23.3 * 6.022 * 10^{23} = 1.403 * 10^{25}[/tex]
(d) 0.310 mol nitrogen (N2) = [tex]0.310 * 6.022 * 10^{23} = 1.866 * 10^{23}[/tex]
PLS HELP
A 20.8 gram piece of metal at 184.9 oC is dropped into 87.7 grams of water at 19.2 oC. The water temperature rose to 54.6 oC. Calculate the specific heat of metal in J/g oC. (round to the tenths place) (DO NOT PUT UNITS IN YOUR ANSWER.)
Assume that all of the heat lost by the metal is transferred to the water and no heat is lost to the surroundings. The specific heat of water is 4.184 J / g oC.
Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1