What are the characteristics of ionic compounds?​

Explanation:

hope the working on picture helps :)

93.5 is the percent yield for this reaction.

The theoretical yield is the maximum possible mass of a product that can be made in a chemical reaction.

Step 1: Solve for the mass of CH_2O produced.

Mass [tex]CH_2O[/tex] = 15.4 g [tex]CH_3OH[/tex] × (1 mol [tex]CH_3OH[/tex] ÷ 32.04 g [tex]CH_3OH[/tex]) × (1 mol [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_3OH[/tex]) × (30.03 g [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_2O[/tex])

Mass [tex]CH_2O[/tex]= 14.43 g

Step 2: Determine the theoretical yield.

Theoretical yield = mass [tex]CH_2O[/tex]

Theoretical yield = 14.43 g

Step 3: Solve for the percent yield.

Percent yield = (actual yield ÷ theoretical yield) × 100

Percent yield = (13.5 g ÷ 14.43 g) × 100

Percent yield = 0.9355509356 × 100 =93.5  percent

Hence, 93.5 is the percent yield for this reaction.

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Answer:

the characteristics of primary standard substances are:

1.High purity.

2.Stability (low reactivity)

3.Low hygroscopicity

4.High equivalent weight

5.Non-toxicity.

Ready and cheap availability.

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

Answer:

PubChem CID 7991

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C5H10O2 or CH3(CH2)3COOH

Synonyms Valeric acid PENTANOIC ACID n-Valeric acid 109-52-4 n-Pentanoic acid More.

A molecular formula is an expression that states the number and type of atoms present in a molecule of a substance.

Example : H2O (water) There are 2 atoms of Hydrogen and 1 atom of Oxygen in this substance

Answer:

0.348 L

Explanation:

Step 1: Given data

Step 2: Calculate the volume of the concentrated solution

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.07 M × 2.11 L / 6.49 M = 0.348 L

When NaOH is an Arrhenius base so it is dissociated in water so the given statement is false.

It is this base since it dissociates in water to provide the hydroxide (OH-) and sodium (Na+) ions.

It is the substance that is ionized at the time when it is dissolved in water to provide the hydrogen ion.

hence, the given statement is false.

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Answer:

true

Explanation:

i took the test and got it right the other guy is wrong

M = 3.0 mol/L

V = 4 L

n

M = n / V

n = MV

n = (3.0 mol/L)(4 L)

n = 12 mol

Therefore, the number of moles of NaCl present is 12 mol.

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Answer 12 mol

Explanation: [tex]C_{M} = \frac{n}{V} ==> n = C_{M} *V=4*3=12 mol[/tex]

Answer:

The correct answer is - d. hydrogen bonding.

Explanation:

Water has strong hydrogen bonds between its molecules that require a very high amount of energy in order to break. Water molecules are joined together or bound with a strong intermolecular force called hydrogen bonds.

These bonds require more kinetic energy which means more temperature or heat in order to break the bonds and turn into steam and this is the reason it has a high boiling point.

Answer:

[tex]rate = k[C] {}^{2} [D] {}^{2} \\ 7.5 \times {10}^{ - 3} = k {(0.25)}^{2} {(0.50)}^{2} \\ k = \frac{7.5 \times {10}^{ - 3} }{ {(0.25)}^{2} {(0.50)}^{2} } \\ k = 0.48 \: {mol}^{ - 3} {dm}^{9} {s}^{ - 1} [/tex]

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

Answer:

O2 is the limiting reactant.

Explanation:

Hello there!

In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:

[tex]14.3molH_2S*\frac{2molSO_2}{2molH_2S}=14.3molSO_2 \\\\17.1molO_2*\frac{2molSO_2}{3molO_2}=11.4molSO_2[/tex]

Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.

Regards!

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

[tex]W=P(V_2-V_1)[/tex]

So we plug in the given pressure and volumes to obtain:

[tex]W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L[/tex]

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

[tex]W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J[/tex]

Regards!

Answer:

Explanation:

The missing image can be seen below.

From the given information:

The elimination process follows E2 mechanism which is a 2nd order kinetics.

At E2 mechanism, the base attaches with the beta hydrogen while also removing the leaving group in the same process. In the given compound 2-chloro-2-methylpropane, chloride is the leaving group that results in the product; 2-methylprop-1-ene.

The mechanism is seen in the second image,

Answer:Muscle growth or “skeletal muscle hypertrophy,” as it's called at science parties) is the result of a complex process that adds more myosin “filaments” to each muscle fiber. This makes the “engine” of the cell bigger and stronger over time. ... This process is called muscle protein synthesis, or MPS. Skeletal muscle is composed of thread-like myofibrils and sarcomeres that form a muscle fiber and are the basic units of contraction. The 650 skeletal muscles in the human body contract when they receive signals from motor neurons, which are triggered from a part of the cell called the sarcoplasmic reticulum.

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

We input the data given by the problem:

And solve for n:

Answer:

False

Explanation:

Gets used by other animals.

[tex] \huge \mathbb{ HI !!}[/tex]

Although caffeine (a stimulant found in coffee and tea) is a relatively complicated molecule, it's only eight atoms of carbon, ten of hydrogen, four of nitrogen and two of oxygen – C8H10N4O2. This kind of representation is called a molecular formula – it tells us what kind of atoms we have, and how many of each.

There are 10 hydrogen atoms in one mole of caffeine.

Caffeine belongs to the methylxanthine category of nervous system stimulants. It's just a cognitive booster that improves alertness but also attentional performance.

Caffeine's chemical formula would be C8H10N4O2, that indicates it contains eight carbon atoms, ten hydrogen atoms, four nitrogen atoms, and two oxygen atoms.

So it can be seen that , 10 hydrogen resent in caffeine molecule.

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Answer:

The hydride ion,H−is a stronger base, so it will abstract a proton from the water. As the water will give protons, so water will work as an acid and an acid-base reaction will take place. Hydride ions get protons from water and form hydrogen gas and hydroxide ions.

Sodium hydride is the chemical compound with the empirical formula NaH. This alkali metal hydride is primarily used as a strong yet combustible base in organic synthesis. NaH is a saline (salt-like) hydride, composed of Na+ and H− ions, in contrast to molecular hydrides such as borane, methane, ammonia, and water.

Answer:

[tex]Key=2.5x10^{-9}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

[tex]2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)[/tex]

By knowing that the equilibrium expression is actually:

[tex]Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}[/tex]

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

[tex]Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}[/tex]

Regards!

Answer:

132 amu

Explanation:

ammonium sulphate is [tex](NH_4)_{2} SO_4[/tex]

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

Answer:

C

Explanation:

Answer:

C.

Explanation:

Brainiest?

Answer:

Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon

Answer:

its saturated

cus its like

CnH2n+2

Explanation:

this explanation may help u to understand:)

Answer:

4

Explanation:

Explanation:

don't know .............

.....how

Answer:

Yes I would believe that this report was true, because nobody would lie on a news channel that they cured cancer and then not cure it. That would completely ruin their credibility as well as the news channels credibility. So no news channel would take the story if it was made up.

I would like to see there studies on how the medicine kills off the cancer and the side effects of the medicine on the human body. I would want to know how the medicine is made, if its FDA approved, and how the medicine will be distributed across the globe and at what prices, as well as how easily the medicine expires.

Answer:

Explanation:

I will probably believe the report but want to find out more details. First is cure for which cancer has been found. Cancer is a general name for a large family of different diseases. So it is very likely that the cure is for some specific cancers.

Secondly I want to know if the cure has any side effect. The typical treatments for cancer now are radiation and chemo therapy. Both can cause serious side effects.

Lastly the cost of cure is important. New drugs with patent protection can be very expensive which limit on how many people can afford the treatment.

Answer: The mass of [tex]CO_2[/tex] produced is 12.32 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of ethane = 4.21 g

Molar mass of ethane = 30 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol[/tex]

Given mass of oxygen gas = 31.9 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol[/tex]

The chemical equation for the combustion of ethane follows:

[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]

By stoichiometry of the reaction:

If 2 moles of ethane reacts with 7 moles of oxygen gas  

So, 0.140 moles of ethane will react with = [tex]\frac{7}{2}\times 0.140=0.49mol[/tex] of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, ethane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of ethane produces 4 moles of [tex]CO_2[/tex]

So, 0.140 moles of ethane will produce = [tex]\frac{4}{2}\times 0.140=0.28mol[/tex] of [tex]CO_2[/tex]

We know, molar mass of [tex]CO_2[/tex] = 44 g/mol

Putting values in above equation, we get:

[tex]\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g[/tex]

Hence, the mass of [tex]CO_2[/tex] produced is 12.32 g