What does k equal?
As in y=kx
Pls help

Answer: x intercept is 2/5, and y intercept is -2

Step-by-step explanation:

Bascially when your solving for x intercept, substitute 0 for y, then for this equation u get 0=5x-2, which is equal to 5x=2, so the x intercept is 2/5. You do the same thing for y intercept, so substitute 0 for x this time, then you'd get y=-2.

Answer:

so i did the math and i got c

Step-by-step explanation:

√-100

= √100 * √-1 (√mn = √m * √n)

= 10i. (i² = -1, i = √-1)

Answer:

The answer is 0.02469090

Step-by-step explanation:

1.234545÷50=0.02469090

Hope this helps you.

Answer:

in triangle

sin45=p/h

1/√2=8/h

h=8√2

Answer: 310.3° or 5.41 radians.

Step-by-step explanation:

The area of a circle of radius R is calculated as:

A = pi*R^2

Now, if we have a sector of an angle θ degrees, the area of that sector is:

A = (θ/360°)*pi*R^2

In this case, we know that:

R = 15yd

And the area of the sector is 609 yd^2

Then we can replace these two values in the equation to get:

609yd^2  =(θ/360°)*3.14*(15yd)^2

(609yd^2)*360°/(3.14*(15yd)^2) = θ = 310.3°

And we want the angle also in radians.

We know that:

3.14 rad = 180°

(3.14 rad/180°) = 1

Then:

310.3° = 310.3°*(3.14 rad/180°) = (310.3°/180°)*3.14 rad = 5.41 radians.

The measure of the central angle in degrees and radians are 310.32° and 5.42 rad respectively

where

r = radius

∅ = central angles

Therefore,

609 = ∅ / 360 × 3.14 × 15²

609 = 706.5∅ / 360

219240 = 706.5∅

∅ = 219240 / 706.5

∅ = 310.318471338

∅ = 310.32°

1° = 0.0174533 rad

310.32° = ?

Angle in radian = 310.32° × 0.0174533  = 5.41610573 ≈ 5.42 rad  

learn more on circles here; https://brainly.com/question/19340105?referrer=searchResults

Answer:

x = 133.33°

Step-by-step explanation:

The Law of Cosines

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

[tex]c^2=a^2+b^2-2ab\cos x[/tex]

Since we know the values of all three side lengths, we solve the equation for x:

[tex]\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}[/tex]

For the triangle in the figure: a=4.1, b=8.5, c=11.7, x=angle C. Applying the formula:

[tex]\displaystyle \cos x=\frac{4.1^2+8.5^2-11.7^2}{2*4.1*8.5}[/tex]

[tex]\displaystyle \cos x=\frac{-47.83}{69.7}[/tex]

[tex]\displaystyle \cos x=-0.6862[/tex]

[tex]x = \arccos (-0.6862)[/tex]

x = 133.33°

Answer:

due

Step-by-step explanation:

Answer:

12× = 2, 2, 3, x

18 = 2, 3, 3

GCF = 6

6( 2x + 3)

Step-by-step explanation:

Answer:

b = 3

Step-by-step explanation:

Answer:

Since f(n + 1) = f(n) - 3, we can also say that f(n - 1) = f(n) + 3.

By which we can say f(n - 3) = f(n) + 9

Since f(4) is 22, then f(1) must be 22 + 9, or 31.

Answer: 3/100

Step-by-step explanation:

Answer:

3/100

Step-by-step explanation:

Answer:

13,64% decrease.

Explanation:

[tex]420/3079*100=13,64[/tex]

Answer:

○ [tex]\displaystyle Perpendicular[/tex]

Step-by-step explanation:

Convert each equation to Slope-Intercept Form:

[tex]\displaystyle 3y - 6x - 7 = 0 → 3y - 6x = 7 → 3y = 6x + 7 → y = 2x + 2\frac{1}{3} \\ \\ 2y + x = 3 → 2y = -x + 3 → y = -\frac{1}{2}x + 1\frac{1}{2}[/tex]

Take a look at [tex]\displaystyle 2[/tex] and [tex]\displaystyle -\frac{1}{2}.[/tex] Their rate of changes [slopes] have a '2' in common, they are not similar. This tells you that these linear equations are not parallel, but perpendicular, because perpendicular equations have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES].

Did you catch it at all?! ;)

I am joyous to assist you at any time.

Answer:

3/4(n)+1

3/4(8)+1=

6+1=7

3/4(12)+1=

9+1=10

3/4(14)+1=

10.5+1=11.5

3/4(20)+1=

15+1=16

I hope this helps:

Answer:

x = -2

Step-by-step explanation:

[tex]3[- x + (2x + 1)] = x - 1[/tex]

[tex] = > 3[ - x + 2x + 1 ] = x - 1[/tex]

[tex] = > 3[x + 1] = x - 1[/tex]

[tex] = > 3x + 3 = x - 1[/tex]

[tex] = > 3x - x = - 1 - 3[/tex]

[tex] = > 2x = - 4[/tex]

[tex] = > x = \frac{ - 4}{2} = - 2[/tex]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[tex] - \frac{2}{5} - ( - \frac{9}{15} ) = \\ [/tex]

[tex] - \frac{2 \times 3}{5 \times 3} + \frac{9}{15} = \\ [/tex]

[tex] \frac{ - 6}{15} + \frac{9}{15} = \frac{9 - 6}{15} = \\ [/tex]

[tex] \frac{3}{15} \\ [/tex]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

Answer:

um

Step-by-step explanation:

what problem is their to figure out

Answer:

1 1/3 feet by 3 feet

Step-by-step explanation:

Answer:

1/3x + 1/2y < or equal to 12

2x + y < or equal to 12

x > or equal to 0

y > or equal to 0

1/3x + 1/2y < or equal to 4

Step-by-step explanation:

none

Answer:

A on edge :)

Step-by-step explanation:

edge2021

Answer:

Numbers 1, 3, 5, 7, and 9 and so on are uneven. These are only up to ten. Numbers 0, 2, 4, 6, 8, and 10 are even. If 0 is even just skip one number (you skip 1) and the number after (which is 2) is even and you continue so. For uneven numbers you do the same you start from 1 then skip a number (which is 2) and end up with 3 and you also co tune onward for this. I hope it helps!

Answer:

Area of the triangle covered by the cars = 910.45 square km

Step-by-step explanation:

Since, all the sides of triangle ABC are given,

And formula for the area of a triangle with all sides given is,

Area = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

Here, s = [tex]\frac{a+b+c}{2}[/tex]

And a, b, c are the measures of the sides of the triangle.

If a = 39 km, b = 87 km and c = 58 km

s = [tex]\frac{39+87+58}{2}[/tex]

s = 92

Therefore, (s - a) = 92 - 39

                            = 53

(s - b) = 92 - 87

         = 5

(s - c) = 92 - 58

         = 34

Now area of the triangle ABC = [tex]\sqrt{92(53)(5)(34)}[/tex]

                                                  = [tex]\sqrt{828920}[/tex]

                                                  = 910.45 km²

Area of the triangle covered by the cars = 910.45 square km

6 1/8

6 1/8

this is the answer

Answer:

The total area of the figure is 68.5 square centimeters.

Step-by-step explanation:

To calculate the total area, we must concieve it by the sum of areas of smaller triangles and rectangles. We present our strategy in the image attached below:

[tex]A = A_{1}+A_{2}+A_{3}+A_{4}+A_{5}[/tex] (1)

Where all areas are measured in square centimeters.

Please notice that [tex]A_{2}[/tex], [tex]A_{3}[/tex] and [tex]A_{5}[/tex] are triangles and [tex]A_{1}[/tex] and [tex]A_{4}[/tex] are rectangles.

The resulting area is calculated below:

[tex]A = (1)\cdot (2) + \frac{1}{2}\cdot (2)^{2} +\frac{1}{2}\cdot (3)\cdot (7)+(9)\cdot (5)+\frac{1}{2}\cdot (2)\cdot (9)[/tex]

[tex]A = 68.5\,cm^{2}[/tex]

The total area of the figure is 68.5 square centimeters.