What is .63 as a fraction

The range of the function is {-34, -2, -20}

The function is given as:

f(x) = -2x^2 - 2

The domain is {-4, 0, 3}

Substitute the domain values in the function.

f(-4) = -2(-4)^2 - 2 = -34

f(0) = -2(0)^2 - 2 = -2

f(3) = -2(3)^2 - 2 = -20

This means that the range of the function is {-34, -2, -20}

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The amplitude is 2.5

Equation:

the equation to find the amplitude is (max-min) / 2.

using this equation, it would be (4 - (-1)) / 2

5 / 2 = 2.5

The system of equations that have a solution of (-2,-2,-2) is (b) x + 2y = -6, y + 2z = -6 and x - y - z = 2

The attached figure represents the proper format of the equations.

The solution is given as:

(x,y,z) = (-2,-2,-2)

To determine the system of equation, we simply substitute the values of x, y and z in the equations in the options.

So, we have:

Option 1:

x + y = 0

y - z = -2

x + y - z = -4

Evaluate

x + y = 0

-2 - 2 = 0 --- False

This means that this system of equations do not have a solution of (-2,-2,-2)

Option 2:

x + 2y = -6

y + 2z = -6

x - y - z = 2

Evaluate

x + 2y = -6

-2 + 2 * -2 = -6 --- True

y + 2z = -6

-2 + 2 * -2 = -6 ---- True

x - y - z = -2

-2 + 2 + 2 = 2

This means that this system of equations have a solution of (-2,-2,-2)

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Answer: 3ln4 + 3lna

Step-by-step explanation:

[tex]\ln (4a)^{3}\\=3 \ln 4a\\=3(\ln 4+\ln a)\\=\boxed{3\ln 4+3\ln a}[/tex]

Answer:

C and second one is A

Answer:

[tex]\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}[/tex]

Step by step explanation:

[tex]\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\[/tex]

[tex]\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}[/tex]

[tex]\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}[/tex]

Answer:

6 + 2 + 3 + 4 = 15

so 15 blocks

a block is about 0.05 miles

so 15 blocks in miles is 0.75 miles

By looking at the given graph, we can see that:

First, we want to find the value f(4). To get that, we need to look at the graph and see the y-value of the function f(x) when x = -4.

By looking at the graph, we can see that f(4) = -10.

Now we know that g(x) = 2, and we want to find the value of x.

Then we need to see the x-value such that g(x) = 2, by looking at the graph of g(x), we can see that it is equal to 2 in the vertex, which is at x = 0.

Then g(x) = 2 when x = 0.

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The function that has the same domain as y= 2√x is (a) y = √2x

The function is given as:

y= 2√x

The above function is a square root function.

All square root functions have the same domain when they are not translated.

This means that

y = √2x has the same domain as y= 2√x  because it is not translated

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All solutions to the equation 3 cos (5t) + 3 = 2 in the interval from 0 to π will be 0.3821, 0.2462, and 0.8745. Then the correct option is A.

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The equation is given below.

3 cos (5t) + 3 = 2

By simplifying the equation, then we have

3 cos 5t = -1

   cos 5t = -1/3

Then the value of t will be

5t = 1.91063, 1.12096, 4.3725

 t = 0.3821, 0.2462, 0.8745

Then the correct option is A.

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The volume of the rectangular prism will be 16.2 cubic ft.

Suppose that the right rectangular prism in consideration be having its dimensions as 'a' units, 'b' units, and 'c' units,

then its volume is given as:

V =  a x b x c unit^3

The dimensions of the given rectangular prism;

Length = 2.7ft

Width = 3 ft

Height = 2 ft

The volume of the rectangular prism

V =  a x b x c unit^3

V = 2.7 x 3 x 2

V = 16.2 cubic ft

Hence, the volume of the rectangular prism will be 16.2 cubic ft.

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Answer:

b = 17.318    height = 23.318 ft

Step-by-step explanation:

This IS very similar to the other one, Emily..... Have you tried to solve it the same way?

b =   152 tan 6.5  = 17.318 ft      (using a calculator)

    add the height of the victim's head (6 ft)

17.318 + 6 = 23.318 ft

Based on the calculations, the surface area (SA) of a cylinder is equal to: B.  2,813.44 in.²

Mathematically, the surface area (SA) of a cylinder can be calculated by using this formula:

SA = 2πrh + 2πr²

Where:

The dimensions of this new cylinder would be equal to:

Radius = 8 × 2 = 16 in.

Height = 6 × 2 = 12 in.

Substituting the given parameters into the formula, we have;

SA = (2 × 3.14 × 16 × 12) + 2 × 3.14 × 16²

SA = 1,205.76 + 1,607.68

SA = 2,813.44‬ square inches.

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Complete Question:

If the dimensions of the following cylinder are doubled, what will be the surface area of the new cylinder? Radius: 8 in and Height: 6 in.

Group of answer choices.

A. 1,406.72 in.²

B.  2,813.44 in.²

C. 1,607.68 in.²

D. 5,626.88 in.²

Answer:

c=2

Step-by-step explanation:

We can first take out the parenthesis: 27-2c-3=2c+14+c. We can combine: -2c+24=3c+14. Then, we can subtract 14 from both sides: -2c+10=3c. Then, we can add 2c on both sides: 10=5c. To find c, we can do 10/5=2.

To solve this problem, we have to consider the fact that if the probability that the cyclist may crash due to some circumstance. The probability the cyclist doesn't crash at any given day is 3/8

The probability the cyclist crash when it's wet or dry will be the

[tex]P = P_w_e_t * P_d_r_y[/tex]

The probability the cyclist crash on any given day is

[tex]P = \frac{5}{8}*\frac{1}{8} =\frac{5}{64}[/tex]

we can subtract 1 from the value above to find the probability the cyclist doesn't crash at any given day

[tex]P = 1 - \frac{5}{64} \\P=\frac{3}{8}[/tex]

The probability the cyclist doesn't crash at any given day is 3/8

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What does y equal to? I think you had a typo

Answer:

the answr is 87 jistg ebcaujse

Step-by-step explanation:

3,500 tickets were sold for $15 each and 4,600 tickets were sold for $25 each.

Let x be the number of $15 tickets and y be the number of $25 tickets.

We know that:

x + y = 7,500 (the total number of tickets sold)

15x + 25y =  153,500 (the total amount of money made from ticket sales)

We can use the first equation to express y in terms of x:

y = 7,500  - x

We can substitute this expression of y into the second equation:

15x + 25(7,500  - x) = 153,500

Solving for x:

15x + 25(7,500) - 25x =  153,500

15x + 187500 - 25x =  153,500

-10x = -34,000

x = 3400

Therefore, 3,400 tickets were sold for $15 each and  7,500 - 3,500 = 4000 tickets were sold for $25 each.

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The area of a 2D form is the amount of space within its perimeter. The lateral area of the right prism is 120 cm².

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm², m², and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

Given the perimeter of the base of the right prism is 20 cm, while the lateral height is 6 cm. Therefore, the lateral area of the right prism is,

Lateral Area of Right Prism = 6cm × 20cm = 120cm²

Hence, the lateral area of the right prism is 120 cm².

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If the original pendulum completed one swing every 1.5 seconds. How long should the new pendulum be is: C. 55.9 centimeters.

Using this formula

T=2π√I/g

Where:

T=1.5 seconds

l =length of pendulum

g= acceleration of gravity=9.8m/s²

Let plug in the formula

1.5 seconds=2π√I/9.8

l/9.8=0.05699

l=0.05699×9.8

l=0.5585

l=55.9 centimeters (Approximately)

Therefore How long should the new pendulum be is: C. 55.9 centimeters.

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Answer:

2.08

Step-by-step explanation:

[tex]sin^{-1} 4/5 = 53.13\\tan 53.13 = 1.33\\cot 53.13 = 0.75\\1.33 + 0.775 = 2.08[/tex]

Answer:

The answer is 2

Step-by-step explanation:

[tex]Cot(x)=\frac{1}{tan(x)} =\frac{Cos(x)}{Sin(x)}[/tex]

[tex]Tan(x) = \frac{Sin(x)}{Cos(x)}[/tex]

[tex]Cos(\frac{\pi }{2} -x)=sin(x)[/tex]

This means that
[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+\frac{\sin \left(\frac{4}{5}\right)}{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}[/tex]

This will be a long one to solve
-> apply cos identity to right side

[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+\frac{\sin \left(\frac{4}{5}\right)}{\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{4}{5}\right)+\sin \left(\frac{\pi }{2}\right)\sin \left(\frac{4}{5}\right)}[/tex]

-> simplify according to unit circle

[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+1[/tex]

->apply cos identity again

[tex]\frac{\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{4}{5}\right)+\sin \left(\frac{\pi }{2}\right)\sin \left(\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+1[/tex]

If you apply for unit circle numbers,

you will get 2

I do not recommend using a calculator for these questions, but instead, turn the form into [tex]sin\frac{\pi }{2}[/tex] other base unit circle locations, and most likely this is the method that your teacher counts as "right."
when using a calculator, it tends to "round" the number, which result in a inaccurate answer

The letter that will be on the side opposite D is letter B

The attached image represents the missing piece in the question

The opposite sides of a cube always have a face in between them, when represented as a net.

From the attached image, the adjacent sides are:

A B C D

F C E

The opposite sides as represented above are;

A and C

B and D

F and E

Hence, the letter that will be on the side opposite D is letter B

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[tex]\\ \rm\Rrightarrow \sum^{60}_{n=1}3n[/tex]

It will form a arithmetic sequence as

[tex]\\ \rm\Rrightarrow 3(1)+3(2)+3(3)\dots 3(60)[/tex]

So

Summation

[tex]\\ \rm\Rrightarrow \dfrac{n}{2}(a+\ell)[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{60}{2}(3+180)[/tex]

[tex]\\ \rm\Rrightarrow 30(183)[/tex]

[tex]\\ \rm\Rrightarrow 5490[/tex]

Option D

Answer:

[tex]\mathsf {5,490}[/tex]

Step-by-step explanation:

[tex]\textsf {Given :}[/tex]

[tex]\lim_{1 \to \660} \sum3n[/tex]

[tex]\textsf {Finding the necessary :}[/tex]

[tex]\textsf {1. first term (a)}[/tex]

[tex]\implies \mathsf {a = 3(1) = 3}[/tex]

[tex]\textsf {2. final term}[/tex] [tex]\mathsf {(a_n)}[/tex]

[tex]\implies \mathsf {a_n = 3(60) = 180}[/tex]

[tex]\textsf {3. common difference (d)}[/tex]

[tex]\implies \mathsf {a_2 = 3(2) = 6}[/tex]

[tex]\implies \mathsf {d = a_2 - a_1 = 6 - 3 = 3}[/tex]

[tex]\textsf {Finding the sum of the series :}[/tex]

[tex]\implies \mathsf {S_n =\frac{n}{2}(a + a_n) }[/tex]

[tex]\implies \mathsf {S_6_0 = \frac{60}{2} (3 + 180)}[/tex]

[tex]\implies \mathsf {S_6_0 = 30 \times 183}[/tex]

[tex]\implies \mathsf {S_6_0 = 5,490}[/tex]

Answer:

B) Angle D is congruent to Angle P

Step-by-step explanation:

In order for the triangles to be congurent due to ASA, we need to know two pairs of congruent angles and one pair of congruent sides. We have one pair of sides and angles, so we only need another angle pair, therefore eliminating C and D, which are giving sides. If we chose option A we would get SAA property since it's supposed to be read clockwise. The only option left is option B.

Have a nice day!

The value of k based on the information given will be k = 2.

It should be noted that the line of f(x) passes through the point (-4, 0) and (0, 4). The line of g(x) goes through (-2, 0) and (0, 4).

The slope of x will be:

= (4 - 0)/(0 + 4)

= 4/4

= 1

By using slope point form, y = kx + 4.

Substitute x = 2.

g(-2) = -2k + 4 = 0

2k = 4

k = 4/2 = 2

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Explanation:

I'm going to relabel the figure as triangle ABC.

As the instructions mention, we'll use the law of cosines to find the missing side.

Use these facts to find side c

c^2 = a^2 + b^2 - 2*a*b*cos(C)

c^2 = 147^2 + 166^2 - 2*147*166*cos(50)

c^2 = 17794.393497

c = sqrt(17794.393497)

c = 133.395628

c = 133

Answer:

1 and 3  

Step-by-step explanation:

1 and 3 are vertical angles

Answer:

4/5

Step-by-step explanation:

First, we know that we have 5 envelopes. So the denominator of the probability is going to be x/5. We then realize that only one envelope has the car, so the probability of that is 1/5. If we subtract 1/5 from the probability of choosing an envelope (5/5), we get 5/5-1/5=4/5.

Step-by-step explanation:

I don't see question 1 and 2.

but it did be way for you : the distance from the verge of a circle to a point on the circle is always the radius.

that is the whole concept of a circle : it is the line (or curve) of all points that have the same, constant distance r from a single point.