What is Hydroelectric energy used for? Use in your own words.

Answers

Answer 1
Hydroelectric energy, also called hydroelectric power or hydroelectricity, is a form of energy that harnesses the power of water in motion—such as water flowing over a waterfall—to generate electricity. People have used this force for millennia. Over two thousand years ago, people in Greece used flowing water to turn the wheel of their mill to ground wheat into flour.

Related Questions

An ideal gas expands quasi-statically and isothermally from a state with pressurepand volumeVto a state with volume 4V. How much heat is added to the expanding gas?

Answers

Answer:

Q = PV(In 4)

Explanation:

We are told that the volume expands from V to a state with volume 4V.

Thus, initial volume is V and Final volume is 4V.

We want to find How much heat is added to the expanding gas.

For an isothermal process, the work done is calculated from;

W = nRT(In(V_f/V_i))

Where;

V_f is final volume

V_i is initial volume

Thus;

W = nRT(In(4V/V))

W = nRT(In 4)

Now, from ideal gas equation, we know that;

PV = nRT

Thus;

W = PV(In 4)

Now from first law of thermodynamics, we know that internal energy is zero and thus; Q = W

Where Q is quantity of heat

Thus;

Q = PV(In 4)

Which computational model can be applied to the total internal energy of a system with two point masses?

{Energy Flows Quick Check}

Answers

Answer:

D

Explanation:

Took the test :)

A 4.5 kg puffer fish expands to 40% of its mass by taking in water. When the puffer fish is threatened, it releases the water toward the threat to move quickly forward. What is the ratio of the speed of the puffer fish forward to the speed of the expelled water backwards?

Answers

Answer:

2:5

Explanation:

We have the initial mass of the fish = 4.5kg

The mass of water intake = 40%of 4.5kg

= 0.40x4.5kg

= 1.8kg

The formula for conserving momentum

M1V1 = M2V2

M1 = mass of the puffer fish = 4.5kg

M2 = mass of the applied water = 1.8kg

V1 = velocity of the puffer fish

V2 = velocity of water

We are then to find v1/v2

V1/V2 = M2/M1

V1/V2 = 1.8/4.5

= 1/2.5

This is also 2/5

Therefore we have the ratio to be 2:5

Jared walks 120 m east, 150 m south, and then 40 m west. Find the total
distance traveled by Jared

Answers

Answer:

310 m

Explanation:

120+150+40=310

On a double-well roller coaster, the person starts from a height of 10.5 meters, the height of the middle bump of the well is 6.7 meters. How much kinetic energy does this person have at the middle of the middle bump from the bottom if the mass of the person is 79 kg? (g=9.8 m/s2) Round to two decimal places.

Answers

Answer:

"2941.96 J" is the appropriate answer.

Explanation:

The given values are:

Mass,

m = 79 kg

Height,

h = 10.5 m

Now,

The total energy at the given height will be,

Potential energy = mgh

On substituting the values, we get

                                = [tex]79\times 9.8\times 10.5[/tex]

                                [tex]=8129.1 \ J[/tex]

So,

⇒ At height 6.7 m, total energy =  At height 10.5 m, total energy

On substituting the values, we get

⇒ [tex]Potential \ energy+Kinetic \ energy=8129.1[/tex]      

⇒       [tex]79\times 9.8\times 6.7+Kinetic \ energy=8129.1[/tex]

⇒                [tex]5187.14+Kinetic \ energy=8129.1[/tex]

⇒                                   [tex]K.E=8129.1-5187.14[/tex]

⇒                                   [tex]K.E=2941.96 \ J[/tex]

A solid spherical ball and a hollow spherical ball made out of the same material are released from rest at the top of a ramp. They roll down the ramp without slipping to the bottom. On what quantities does the speed of each ball at the bottom of the ramp depend?A. Radius of the ball.B. Distribution of mass within the ball.C. Mass of the ball.D. Height of the ramp.

Answers

Answer:

D. Height of the ramp.

Explanation:

The solid spherical ball is expected to have more mass than that of the hollow spherical ball. And the speed of both balls would be influenced by the gravitational force as they roll down the ramp. Thus, the masses would move at different speed.

At the bottom of the ramp, the speed of the balls can be varied by varying the height of the ramp. So that the speed of both balls depend on the height of the ramp. As the height of the ramp increases, consequently, the speed of the balls increases. And if the height of the ramp decreases, the speed of the balls decreases consequently.

A rock is thrown straight upward with a speed 6.000 m/s. If this rock takes 1.540 s to fall to the ground, from what height h was it released?

Answers

Answer:

3.8961038961038

Explanation:

6000/1540=3.8961038961038

X= v/t

A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency of 2 Hz, what is the speed of the wave that travels through the string to the other end? The speed of the wave is __ m/s.

Answers

Answer:

1m/s

Explanation:

Speed of a wave is expressed as;

Speed = frequency × wavelength

Given

Frequency = 2Hz

Wavelength = 0.5m

Required

Speed of the wave

Substitute

Speed = 2×0.5m

Speed = 1.0m/s

Hence the speed is 1.0m/s



5.List the four goals of Psychology. Give your own example for each one using a behavior

Answers

Answer:

describe, explain, predict, and change/control behavior.

Explanation:

describe: What are they doing? -Pavlov noticed that dogs were salivating when they would see his lab assistant before food was presented to them. This observation acted as a description of what was happening to them.

explain: Why are they doing that?- Pavlov started to look into why they were doing it. There was a stimulus, the assistant giving them food in the past to where they started to salivate at the sight of the lab assistant

predict: What would happen if I responded in this way?- Pavlov predicted that he could get the same reaction if he used a bell as a stimulus. Using this he was able to condition dogs to salivate at the ring of the bell.

change/control: What can I do to get them to stop doing that? Because of this discovery we can use conditioning today. For example, in the classroom teachers can use conditioning with their students to make it easier, parents to teach their children right from wrong and to have good behavior. (you do this bad thing you get time out, do a good thing and I will praise you, etc) It can be used when training employees and many other places.

Find the net work done by friction on the body of a snake slithering in a complete circle of 3.93 m radius. The coefficient of friction between the ground and the snake is 0.25, and the snake's weight is 54.0 N.

Answers

Answer:

The net work done by friction on the body of the snake is 333.35J

Explanation:

Work done is given by

W = F × s

Where W is the Work done

F is the force

and s is the distance covered

Since we are to determine the work done by friction, then we will determine the frictional force. The frictional force is given by

f = μN = μw

Where μ is the coefficient of friction

N is the normal reaction

and w is the weight

But, F = f

∴ W = μws

From the question

μ = 0.25

w = 54.0 N

Now, we will determine s

From the question,

We are to determine the work done by friction on the body of a snake slithering in a complete circle of 3.93 m radius.

The distance s here is given by the circumference of the circle. Circumference of a circle is given by 2πr

∴ s = 2πr

s = 2 × π × 3.93

s = 7.86π m

Hence,

W = 0.25 × 54.0 × 7.86π

W = 333.35 J

Hence, the net work done by friction on the body of the snake is 333.35J.

The net work done by friction on the body of the snake is :

-333.35J

Friction

Formulas:

Work done (W) = F × s

F = force

s = distance covered

f = μN = μw

μ = coefficient of friction

N = normal reaction

w = weight

Solution:

F = f

Weight is :

W = μws

μ = 0.25

w = 54.0 N

Distance covered:

s = 2πr

s = 2 × π × 3.93

s = 7.86π m

Therefore,

W = 0.25 × 54.0 × 7.86π

W = 333.35 J

The net work done by friction on the body of the snake is 333.35J.

Learn more about "Friction":

https://brainly.com/question/13357196?referrer=searchResults

At high noon, the sun is almost directly above (about 2.0 degrees from the vertical) and a tall redwood tree casts a shadow that is 10m long. How tall is the redwood tree?

Answers

290m

The light always travels in a straight line.

At high noon, the ray from the sun is 2° from the vertical axis.

tan θ = (Opposite side)/(Adjacent side)

On applying above trigonometric formula, we get,

tan 2 = 10/h

0.035 = 10/h

∴ h = 10/0.035 = 290 m

How far out from the sun is the rock line?

Answers

Answer:

5 million miles

Explanation:

A barge is 10 m wide and 60 m long and has vertical sides. The bottom of the boat is 1.2 m below the water surface. What is the weight of the barge and its cargo, if it is floating in fresh water of density 1000 kg/m^3?

a. 6.8 MN
b. 3.5 MN
c. 6.4 MN
d. 9.5 MN
e. 7.1 MN

Answers

Answer:

e. 7.1 MN  approx.

Explanation:

Step one:

given data

density of water= 1000kg/m^3

the dimension of the barge

width= 10m

length= 60m

depth of the boat in the water= 1.2m

Hence the volume occupied by the boat is

volume=10*60*1.2

volume= 720m^2

Step two:

Required is the weight of the barge

we can first find the mass using the relation

density = mass/volume

mass= density*volume

mass= 1000*720

mass= 720000kg

Step three:

Weight =mg

g=9.81m/s^2

W=720000*9.81

W=7063200N

divided by 10^6

W=7.06MN

W=7.1MN approx.

A 3520 kg truck moving north makes an INELASTIC collision with an 1480 kg car moving 13.0 m/s east. After colliding, they have a velocity of 9.80 m/s at 66.9 degrees. What was the initial velocity of the truck? (m/s)

Answers

Answer:

v = 12.8 m/s

Explanation:

Assuming no external forces acting during the collision, total momentum must be conserved.Since momentum is a vector, their components must be conserved too.Choosing a pair of axes coincident with the N-S and W-E directions, naming x to the W-E axis and y to the N-S one, we can write the following algebraic equations:      

       [tex]p_{ox} = p_{fx} (1)[/tex]

       [tex]p_{oy} = p_{fy} (2)[/tex]

Since we know all the information needed to solve (1), assuming a completely inelastic collision, we can focus in (2), writing both sides of the equation as follows:

       [tex]p_{oy} = m_{t} * v_{ot} = 3520 kg* v_{ot} (3)[/tex]

       [tex]p_{fy} = m_{f} * v_{fy} = 5000 kg* 9.8 m/s * sin 66.9 = 45080 kg*m/s (4)[/tex]

Since (4) and  (3) are equal each other, we can solve for vot, as follows:

       [tex]v_{ot} =\frac{45080kg*m/s}{3520kg} = 12.8 m/s (5)[/tex]

Need help ASAP..please help

Answers

Answer:

option 3

Explanation:

can i get brainliest

A falling stone takes delta t = 0.32s to travel past a window 2.2m Tall. From what height above the top of the window did the stone fall?

Answers

Answer:

The height above the top of the window is 1.44 m

Explanation:

Given;

time of motion, t = 0.32 s

height traveled at the given time, h = 2.2m

determine the initial velocity of the stone;

h = ut + ¹/₂gt²

2.2 = u(0.32) + ¹/₂ x 9.8 x 0.32²

2.2 = 0.32u + 0.502

0.32u = 2.2 - 0.502

0.32u = 1.698

u = 1.698 / 0.32

u = 5.31 m/s

This initial velocity on top of the window becomes the final velocity from the height above the window.

v² = u² + 2gh

where;

u is the initial velocity of the stone from the height above the window;

5.31² = 0 + (2 x 9.8)h

19.6h = 28.196

h = 28.196/19.6

h = 1.44 m

Therefore, the height above the top of the window is 1.44 m

A repeated back and forth or up and down motion is called a

Answers

Answer:

A vibration is a repeated back-and-forth or up-and-down motion.

Explanation:

Waves carry energy through empty space or through a medium without transporting matter.

A typical sheet of printer paper is 8.5 inches wide and 11 inches long.
a.) Calculate the length of one sheet in cm
b.) Calculate the width of one sheet in cm?

Answers

Answer:

Explanation:

Given the length and width in inches

Length = 8.5in

Width = 11in

b) Convert to centimeters

1in = 2.54cm

8.5in = x

Cross multiply

x = 8.5 × 2.54

x = 21.59cm

Hence the width in cm is 21.59cm

a) 11in = y

1in = 2.54cm

Cross multiply

x = 11 × 2.54

x = 27.94cm

Hence the length in cm is 27.94cm

A lightweight vertical spring of force constant k has its lower end mounted on a table. You compress the spring by a distance d, place a block of mass m on top of the compressed spring, and then release the block. The spring launches the block upward, and the block rises to a maximum height some distance above the now-relaxed spring. Find the speed of the block just as it loses contact with the spring.

Answers

Answer:

[tex]v=d\sqrt{\frac{k}{m}} [/tex]

Explanation:

In order to solve this problem, we can do an analysis of the energies involved in the system. Basically the addition of the initial potential energy of the spring and the kinetic energy of the mass should be the same as the addition of the final potential energy of the spring and the kinetic energy of the block. So we get the following equation:

[tex]U_{0}+K_{0}=U_{f}+K_{f}[/tex]

In this case, since the block is moving from rest, the initial kinetic energy is zero. When the block loses contact with the spring, the final potential energy of the spring will be zero, so the equation simplifies to:

[tex]U_{0}=K_{f}[/tex]

The initial potential energy of the spring is given by the equation:

[tex]U_{0}=\frac{1}{2}kd^{2}[/tex]

the Kinetic energy of the block is then given by the equation:

[tex]K_{f}=\frac{1}{2}mv_{f}^{2} [/tex]

so we can now set them both equal to each other, so we get:

[tex]=\frac{1}{2}kd^{2}=\frac{1}{2}mv_{f}^{2}[/tex]

This new equation can be simplified if we multiplied both sides of the equation by a 2, so we get:

[tex]kd^{2}=mv_{f}^{2}[/tex]

so now we can solve this for the final velocity, so we get:

[tex]v=d\sqrt{\frac{k}{m}} [/tex]

Astronauts on the first trip to Mars take along a pendulum that has a period on earth of 1.26 s. The period on the other planet turns out to be 3.82 s. What is the free-fall acceleration on that other planet?

Answers

Answer:

1.066 m/s^2

Explanation:

On the earth and on Mars respectively, the time periods of the pendulums are expressed as:

Tearth = 2pi * sqrt(L/gearth)

Tmars = 2pi * sqrt(L/gMars)

Divide the two equations above:

Tearth/Tmars = sqrt(gMars/gearth)

gMars = gearth(Tearth/Tmars)^2 = (9.80m/s^2)(1.26s/3.82s)^2 = 1.066 m/s^2




You are standing on a circular track that is 332 m long. You begin jogging at the start line and keep jogging until you complete a full lap and stop at the same point you

started at.

ard

• What is your final displacement?

Answers

Answer:

Zero.

Explanation:

By definition, the displacement is the difference between the final position and the initial position, so independent from the distance traveled (in this case a full lap), since the initial and final position are the same, the net displacement is just Zero.

A diffraction pattern is created on a screen when blue light is passed through a single slit. Does the central bright maximum in this pattern become wider or narrower, when the blue light is replaced by red light?

Answers

Answer:

becomes wider

Explanation:

From;   asin θ= m λ

It was said in the question that in this particular instance  blue light is replaced by red light. The wavelength of blue light is less than that of red light, it then follows that the central bright maximum in this pattern widens when red light is used.

Therefore the diffraction pattern becomes wider.

If the velocity of a car changes from 0 meters per second (m/s) to 100 m/s in 10 seconds, what is the acceleration over that 10 second period?

Answers

Answer:

10m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 100m/s

Time taken  = 10s

Unknown:

Acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

  A = [tex]\frac{v - u}{t}[/tex]

v = final velocity

u = initial velocity

t = time taken

 So, insert the parameters and solve;

  A = [tex]\frac{100 - 0}{10}[/tex]   = 10m/s²

A man runs 400 meters north with a speed of 3 meters/second. How long does it take him to complete his trip? Answer in seconds. Round your answer to 3 decimal places. *

Answers

Answer:

133.333 s

Explanation:

From the question given above, the following data were obtained:

Displacement = 400 m North

Velocity (v) = 3 m/s

Time (t) =?

Thus, we can obtain the time taken for the man to complete his trip as shown below:

Velocity = Displacement /Time

3 = 400/time

Cross multiply

3 × time = 400

Divide both side by 3

Time = 400/3

Time = 133.333 s

Therefore, it will take the man 133.333 s to complete his trip.

At which stage of the scientific process should a scientific look at experimental data from other scientists to set up a new experimental study

Answers

Answer:

Hypothesis

Explanation:

At an instant when a particle of mass 80 g has a velocity of 25 m/s in the positive y direction, a 75-g particle has a velocity of 20 m/s in the positive x direction. What is the speed of the center of mass of this two-particle system at this instant?

a. 16 m/s
b. 45 m/s
c. 23 m/s
d. 20 m/s
e. 36 m/s

Answers

Answer:

16 m/s

Explanation:

Given that

y momentum = 0.080 *25 = 2

x momentum = 0.075*20 = 1.5

total momentum = √(4 + 2.25)

Total momentum = √6.25

Total momentum = 2.5

total mass = mass of x and y momentum = 0.075 + 0.080 = 0.155

speed of mass center = total momentum / total mass = 2.5/0.155 = 16.

And thus, the speed of the center of mass of this two-particle system at this instant is 16 m/s

an object of mass 4kg moving with the initial velocity of 20m/s accelerates for 10s and attaind a final velocity of 60m/s calculate the initial momentum​

Answers

Explanation:

m = 4kg

u = 20m/s

t = 10s

v = 60m/s

initial momentum = mass × initial velocity

= 4 × 20 = 80kgm/s

Which city did King David make the royal capital of the Kingdom of Israel?
Canaan
Jerusalem
Philistine
Cairo

Answers

Answer:

Jerusalem

Explanation:

because now a days jerusalem is the royal capital of the kingdom of israel so i conclude that the answer is jerusalem

24- What happens to a given mass of water as it is cooled from 4°C to zero?
(a) expands
(b) contracts
(c) vaporizes
(d) Neither expands, contracts, nor vaporizes.

Answers

Explanation:

A-It starts to expand. Hence ice and water of same weight has different volumes

Expansion happens to a given mass of water as it is cooled from 4°C to zero. Option A is correct.

What is temperature?

Temperature directs to the hotness or coldness of a body. In straightforward terms,

it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

Water loses density when it is cooled from 4°C to 0°C. It turns out that the temperature at which liquid water has the most significant density is 4 degrees Celsius.

It will increase in size when heated or cooled. Since most liquids shrink when they are chilled, it is rare for water to expand when cooled to lower temperatures.

As a mass of water is cooled from 4°C to zero, expansion occurs.

Hence, option A is correct.

To learn more about the temperature refer to the link;

https://brainly.com/question/7510619

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Suppose a cart with no fans has a starting velocity of 2 m/s. What will be the velocity of the cart when it reaches the wall?

Answers

Answer:

less than stating velocity due to friction and air resistance.

Explanation:

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