Answer:
5,120
Step-by-step explanation:
an = 5.(-2)^(n-1)
a11 = 5.(-2)^(11-1)
= 5.(-2)^10
= 5.(1,024)
= 5,120
The average marks for 25 students in a mathematics was was 48.
what was the total marks scored by the students?
Answer:
total of the data points = 1200
Step-by-step explanation:
The 'average' of a data set is the total of the data points divided by the number of data points.
Here:
total of the data points
---------------------------------- = 48
25
Multiplying both sides of this equation by 25 yields:
total of the data points = 1200
What is the range of the given function?
Answer:
-2
Step-by-step explanation:
range is y values
Answer:
-2
Step-by-step explanation:
That's the minimum range, which is basically the lowest point on the y-axis that the line touches
1. tu no eres linda eres.
2. tu no eres buena tu eres.
3. tu no te metas en la cama tú te.
Study the adjoining figure and then explain why x = y
Answer:
Step-by-step explanation:
y is the remote exterior angle. The remote exterior angle has the strange property that it is equal to the two remote interior angle. The two remote interior angles are the two, neither of which is the supplement of the exterior angle
So y = x/2 + x/2 which are marked as being opposite equal angles.
1/2 x + 1/2 x = x
y by substitution is = x /2 + x/2
y = x
Bro i dont know what the x is tbh
Find the value of x.
A.6 B.5 C. 50/3 D.7
The value of x is 7.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
The two triangles PQR and P'Q'R' are similar triangles
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
Firstly let us find the P'Q' by using pythagoras theorem
R'Q'²=PR'²+P'Q'²
12²=10²+P'Q'²
144-100=P'Q'²
44=P'Q'²
P'Q'=6.6
The value of PR is x
The value of x is 7. as R it is a midpoint of P'Q'R'
Hence the value of x is 7
To learn more on Triangles click:
https://brainly.com/question/2773823
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A Driver’s Ed program is curious if the time of year has an impact on number of car accidents in the U.S. They assumethat weather may have a significant impact on the ability of drivers to control their vehicles. They take a randomsample of 150 car accidents and record the season each occurred in. They found that 27 occurred in the Spring, 39 inthe Summer, 31 in the Fall, and 53 in the Winter.
Required:
Can it be concluded at the 0.05 level of significance that caraccidents are not equally distributed throughout the year?
Answer:
p-value = 0.0145
Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )
we reject null hypothesis.
Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year
Step-by-step explanation:
Given the data in the question;
Hypothesis;
Null hypothesis : H₀ : Car accidents are equally distributed throughout the year
Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year
significance level ∝ = 0.05
x ;
Spring = 27
Summer = 39
Fall = 31
Winter = 53
Test Statistics;
Chi Square = ∑[ (O – E)²/E ]
O E (O – E)²/E
Spring 27 37.4 2.94
Summer 39 37.4 0.06
Fall 31 37.4 1.1267
Winter 53 37.4 6.4067
Total 150 150 10.5334
so; z = ∑[ (O – E)²/E ] = 10.5334
{from table}
p-value = 0.0145
Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )
we reject null hypothesis.
Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year
In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:
There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.
Given the data in the question;
[tex]Null \ hypothesis: H_0[/tex][tex]Alternative \ hypothesis : H_a[/tex] [tex]Significance\ level = 0.05[/tex]Now the values given in the statement can be exemplified below as:
[tex]Spring = 27[/tex][tex]Summer = 39[/tex][tex]Fall = 31[/tex][tex]Winter = 53[/tex]In this way, we can assemble a table of values with the statistical data previously informed and using the formula given below:
[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]
[tex]Z = 10.5334[/tex]
So:
[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]
Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.
See more about probability at brainly.com/question/795909
what is the system of equations shown in the graph?
Answer:
bugo.ka pag answer bobo ka bah ha wag kanang umasa dito piste ka
3/7-2/14+1/21
What is the answer to this
Answer:
1/3
Step-by-step explanation:
Hope this is useful even though there isn't any working
Consider randomly selecting a single individual and having that person test drive different vehicles. Define events , , and by Suppose that , , , , , and . What is the probability that the individual likes both vehicle
Answer:
[tex]P(A_1\ n\ A_2) = 0.40[/tex]
Step-by-step explanation:
Let:
[tex]A_1 \to[/tex] An Individual likes vehicle 1
[tex]A_2 \to[/tex] An Individual like vehicle 2
[tex]P(A_1) = 0.55[/tex]
[tex]P(A_2) = 0.65[/tex]
[tex]P (A_1\ u\ A_2 ) = 0.80[/tex]
Required
[tex]P(A_1\ n\ A_2)[/tex] --- probability that both vehicles are liked by the individual.
This is calculated as:
[tex]P(A_1\ n\ A_2) = P(A_1) + P(A_2) - P(A_1\ u\ A_2)[/tex]
So, we have:
[tex]P(A_1\ n\ A_2) = 0.55 + 0.65 - 0.80[/tex]
[tex]P(A_1\ n\ A_2) = 0.40[/tex]
36 apples cost $6. How many apples can you buy for $1?
Answer: you can buy 6apples for$1
Step-by-step explanation: you divide 36 by 6 and get 6 so it’s 6apples.
Find the measure of theta to the nearest tenth helpppp pleaseeee
Answer:
54.3°
Step-by-step explanation:
sinθ=opposite/hypotenuse
sinθ=26/32
sinθ=0.8125
θ=54.3°
A student solves for v
Which statement explains how to correct the error that was made?
The subtraction property of equality should have been applied to move m to the other side of the equation.
O The multiplication property of equality should have been applied before the division property of equality.
The division property of equality should have been applied to move the fraction to the other side of the equation.
The square root property should have been applied to both complete sides of the equation instead of to select variables.
Answer:
D (The square root property should have been applied to both complete sides of the equation instead of to select variables)
Step-by-step explanation:
On edge 2021
PLSSSSSSS HELP ASAP !!! PLSSS
Answer:wpeleoe
Step-by-step explanation:
Suppose that $2000 is invested at a rate of 4%, compounded semiannually. Assuming that no withdrawals are made, find the total amount after 5 years. Do not round any intermediate computations, and round your answer to the nearest cent.
Answer:
Step-by-step explanation:
A = P(1+r/n)^ nt
A = 2000(1+.04/2)^(5*2)
A = [tex]2000(1.02)^{10}[/tex] = $2437.99
For each sequence, find the first 4 terms and the 10th term.
a) 12-n
B 5 - 2n
Answer:
Solution given:
a.
tn=12-n
1 st term =12-1=11
2nd term =12-2=10
3rd term=12-3=9
4th term=12-4=8
10th term=12-10=2
b.
tn=5-2n
1st term=5-2*1=3
2nd term=5-2*2=1
3rd term=5-2*3=-1
4th term=5-2*4=-3
10th term=5-2*10=-15
(a) Solution
T(n) = 12 - n
T(1) = 12 - 1 = 11
T(2) = 12 - 2 = 10
T(3) = 12 - 3 = 9
T(4) = 12 - 4 = 8
T(10) = 12 - 10 = 2
(b) Solution
T(n) = 5 - 2n
T(1) = 5 - 2 = 3
T(2) = 5 - 4 = 1
T(3) = 5 - 6 = -1
T(4) = 5 - 8 = -3
T(10) = 5 - 20 = -15
In a marketing survey, a random sample of 1020 supermarket shoppers revealed that 268 always stock up on an item when they find that item at a real bargain price.
a. Find a 95% confidence interval for p?
b. What is the margin of error based on a 95% confidence interval?
Answer:
a) 95% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.
b) Margin of error = 0.0270.
Step-by-step explanation:
a)
[tex]\hat{p}[/tex] = point estimate of p [tex]= 268/1020 =0.2627[/tex]
[tex]\hat{q}= 1 - 0.2627 = 0.7373[/tex]
[tex]SE = \sqrt{\hat{p}\hat{q}/n}\\\\=\sqrt{0.2627\times 0.7373/1020}=0.0138\\\alpha = 0.05[/tex]
From Table, critical values of [tex]Z= \pm1.96[/tex] ,
Lower limit
[tex]= \hat{p} - Z SE\\ = 0.2627 - (1.96 X 0.0138) \\ = 0.2627 - 0.0276 \\ = 0.236[/tex]
upper limit = 0.2627 + 0.0276
= 0.2903
Correct option:
95% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.
b) Margin of error =Z SE
= 1.96 X 0.0141
= 0.0270.
For a rock concert a rectangular field of size 100 m by 50 m was reserved for the
audience.
The concert was completely sold out and the field was full with all the fans standing.
Which one of the following is likely to be the best estimate of the total number of people
attending the concert?
2000
5000
20000
50000
100000
Answer:
5000
Step-by-step explanation:
but this depends upon how much room each person needs
I need help with #1 . Please help. I have to show all work so please explain
Answer:C=10
Step-by-step explanation:
Follow along with the picture below
The formula for this type of problem is a^2+b^2=c^2
We know that 6=a and 8=b so we fill in the formula and square them
we then add the two values we got which get us to 100=c^2
we want to get rid of that square with we square root bothe sides and get c and the square root of 100 is 10.
So C=10
A (non-zero) number multiplied by zero equals zero, whereas a non-zero number divided by zero is undefined.
a. True
b. False
What is the volume, in cubic centimeters, of a rectangular prism with a height of 17 centimeters, a width of 17 centimeters, and a length of 11 centimeters?
Answer:
3179cm^3
Step-by-step explanation:
[tex]volum = height × width × length \\ = 17cm \times 17cm \times 11cm \\ = {3179cm}^{3} [/tex]
Find the volume V and surface area S of a
rectangular box with length 2 meters, width 6 meters,
and height 9 meters.
Answer:
Surface area add together all 6 sides = 24+36+108=168m^2
Volume L x W x D = 2 x 6 x 9 = 108 m ^3
Step-by-step explanation:
2 x 6 = 12
12 x 2 = 24 base and top
2 x 9 = 18
2 x 18 = 36 identical pair sides
6 x 9 = 54
2 x 54 = 108 identical pair sides
Surface area add together all 6 sides = 24+36+108=168m^2
Volume L x W x D = 2 x 6 x 9 = 108 m ^3
No links please :) Love you guys stay safe 3
Answer:
C
Step-by-step explanation:
I've completed the test before. :)
help me please thanks
Answer:
option 3
Step-by-step explanation:
ORIGINAL REFLECTED
A = ( 2, 0) A' = (-2, 0)
B = (5 , 0) B' = (-5, 0)
C = (5, -2) C' = (-5, -2)
D = (2, -2) D' = (-2, -2)
What is the equation, written in vertex form, of a parabola with a vertex of (–2, 6) that passes through (1, –3)?
Answer:
Step-by-step explanation:
( x - 1 )2 + ( y + 3 )2 = 90
PLEASE HELPPPPPPPP MEEE PLEASE!
Answer:
Root Multiplicity
-4 2
-1 2
2 1
5 3
---------------------------
y = a(x + 4)²(x + 1)²(x - 2)(x - 5)³
find "a" using point (0, 20000)
20000 = a(0 + 4)²(0 + 1)² (0 - 2)(0 - 5)³
20000 = a(16)(1)(-2)(-125)
20000 = a (4000)
a = 20000/4000
a = 5
y = 5(x + 4)²(x + 1)²(x - 2)(x - 5)³
Two numbers are 10 units away in different directions from their midpoint, m, on a number line. The product of the numbers is –99.
Which equation can be used to find m, the midpoint of the two numbers?
(m – 5)(m + 5) = 99
(m – 10)(m + 10) = 99
m2 – 25 = –99
m2 – 100 = –99
Answer:
[tex]m {}^{2} - 100 = - 99[/tex]
Step-by-step explanation:
Set up the binomial.
[tex](m - 10)[/tex]
[tex](m + 10)[/tex]
Multiply the binomial.
[tex](m - 10)(m + 10) = - 99[/tex]
Apply difference of squares rule
[tex](p + q)(p - q) = p {}^{2} - q {}^{2} [/tex]
[tex]m {}^{2} - 100 = - 99[/tex]
Answer: m^2-100=-99
Step-by-step explanation:
Set up the binomial.
(m-10)
(m+10)
Multiply the binomial.
(m-10)(m+10)=-99
Apply difference of squares rule
(p+q)(p-q) = p2-q2
Answer: m^2-100=-99
the angle in a semi circle is?
help please. I cant figure it out and it’s hard.
Answer:
The student is comparing the different heart rates due to the temperature. The independent variable is the Temperature and the dependent variable is the beats of the heart from the larva.
Find the radius of the circle,
Answer:
the correct answer is option D. 7