What is the final velocity of a 1400 kg drag racer that’s engine applies 910000 N of Force for 120m

Answers

Answer 1

Answer:

468,000,000 m/s

Explanation:

According to newtons first law of motion;

Force = mass * acceleration

F = ma

where a = v-u/t

v is the final velocity

u is the initial velocity

t is the time taken

F = m(v-u/t)

Ft = m(v-u)

Given parameters;

F = 910,000N

t = 120m = 120 *60 = 7200secs

m = 1400kg

u = 0m/s

Required parameter

Final velocity v

Substituting the given parameters into the formula to get v;

Ft = m(v-u)

910,000 * 72000 = 1400(v-0)

910,000 * 72000  = 1400v

v = (910,000 * 72000)/1400

v = 910,000 * 720/14

v = 910,000 * 60

v = 468,000,000 m/s

Hence the final velocity of the drag racer is 468,000,000 m/s


Related Questions

A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total area A of the panels is 10m2.
1) The intensity of the sun's radiation incident upon the earth is about I = 1.4kW/m2. Suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. What is the total solar power P absorbed by the panels?
2) What is the total force F on the panels exerted by radiation pressure from the sunlight?

Answers

Answer:

0.00004666N

Explanation:

We know that

intensity (I) = P/ A

Where

P= power

A= Area

So lets say that the power absorbed

Will be = Intensity x Area

Which Is = 1.4 x 10^3 x(10)

So

14000 Watt = 14 kWatt

However we know that radiation pressure is equal to

time-averaged intensity all over the speed of light in free space

So

P = (1.4 x 1000)/c

But

F= P x A

So

((1.4 x 1000)/(3 x1 0^8)) x 10

Which is

=0.000046666N

Explanation:

Water forming a droplet is an example of:________.

Answers

Answer:

A perfect example of Surface tension

Explanation:

what is surface tension?

simply put, surface tension is the ability of water to act or behave as if it were or were covered by an elastic skin.

other notable examples of surface tension are

Examples of surface tension of water

1. Ants walking on water

2.Razor blades floating on water  

3. Capillary action (water rising or falling in a narrow capillary tube)

Should you need further clarification do not hesitate to let me know

A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:

Answers

Complete Question

A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:

a) frequency

b) the maximum acceleration

c) the maximum velocity

Answer:

a

[tex]f =  2  \ Hz[/tex]

b

[tex]a_{max} =  3.2 \ m/s^2[/tex]

c

[tex]v_{max} =  0.25 \  m/s[/tex]

Explanation:

From the question we are told that

   The period is  [tex]T  =  0.5 \ sec[/tex]

    The  amplitude is  [tex]A =  2 \ cm  =  0.02 \ m[/tex]

    The  vibration of the scale is  [tex]Acos(wt +  \phi )[/tex]

Generally the frequency is mathematically represented as

   [tex]f =  \frac{1}{T}[/tex]

=>   [tex]f =  \frac{1}{0.5}[/tex]

=>    [tex]f =  2  \ Hz[/tex]

The  maximum acceleration is mathematically represented as

    [tex]a_{max} =  A *(2 \pi f)^2[/tex]

=>    [tex]0.02 *  (2 * 3.142  *  2)^2[/tex]

=>  [tex]a_{max} =  3.2 \ m/s^2[/tex]

The  maximum velocity is mathematically represented as  

     [tex]v_{max} =  A *  (2 \pi f)[/tex]

=>    [tex]v_{max} =  0.02 *  (2 * 3.142 *  2)[/tex]

=>    [tex]v_{max} =  0.25 \  m/s[/tex]

The inhabitants of a small island begin exporting beautiful clothmade from a rare plant that grows only on their island. Seeing howpopular the small quantity that they export has been, they steadilyraise their prices. A clothing maker from New York, thinking thathe can save money by "cutting out the middleman," decides to travelto the small island and buy the cloth himself. Ignorant of thelocal custom of offering strangers outrageous prices and thennegotiating down, the clothing maker accepts (much to everyone'ssurprise) the initial price of 400 tepizes/m^2. The price of thiscloth in New York is 120 dollars/yard^2.If the clothing maker bought 500m^2 of this fabric, how muchmoney did he lose? Use = 0.625Express your answer in dollars tothree significant figures.

Answers

Answer:

Lost Money = $ 53200

Explanation:

First, we calculate the selling price of the cloth:

Selling Price = (Area of Bought Fabric)(Unit Price in America)

Selling Price = (500 m²)($ 120/yard²)(1 yard/0.9144 m)²

Selling Price = $ 71759.4

Now, we calculate the amount that the cloth maker paid (cost) for buying the fabric from America:

Cost = (Area of Fabric Bought)(Unit Selling Price)

Cost = (500 m²)(400 tepizes/ m²)($ 0.625/1 tepize)

Cost = $ 125000

Hence, the money lost is given as:

Lost Money = Cost - Selling Price

Lost Money = $ 125000 - $ 71759.4

Lost Money = $ 53240

Rounding off to 3 significant figures, we get:

Lost Money = $ 53200

A particle is moving along the x-axis. Its position as a function of time is given as x=bt-ct^2a) What must be the units of the constants b and c, if x is in meters and t in seconds?b) At time zero, the particle is at the origin. At what later time t does it pass the origin again?c) Derive an expression for the x-component of velocity.d) At what time t is the particle momentarily at rest?e) Derive an expression for the x-component of the particles acceleration, ax

Answers

Answer:

We are given x= bt +ct²

So

A. bxt= m

Because m/s*s= m

So b= m/s and c= m/s²

B.

x= bt-ct²

So at x=0 t=0

x=0 t= 2

We have

bt = ct² so t = b/c at x= 0

So b-2ct= 0

B. To find velocity we use

dx / dt = b - 2 Ct

C. At rest wen V= 0

We have t= b/2c

D. To find acceleration we use

dv / dt = - 2C

When We are given x= bt +ct²

Then A. bx.t = mJust Because of the  m/s*s= mSo that,  b= m/s and c= m/s²Now B. x= bt-ct²the So at x=0 t=0After that x=0 t= 2Now We have bt = ct² so t = b/c at x= 0After that So b-2ct= 0Then B. To find velocity we use that isThen dx / dt = b - 2 CtThen C. At rest wen V= 0We have t= b/2cNow D. To find acceleration we useNow the answer is dv / dt = - 2C

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A toy car that is 0.12 m long is used to model the actions of an actual car that
is 6 m long. Which ratio shows the relationship between the sizes of the
model and the actual car?
A: 5:1
B: 1:50
C: 50:1
D: 1:5

Answers

Answer:

it is B 1:50

Explanation:

just did it on apex

The pilot of a helicopter drops a lead brick from a height of 500 m. (assume no air resistance and g~10 m/s2) roles Evalu How long does it take to reach the ground?

Answers

Answer:

The  value  is  [tex]t = 10 \  s[/tex]

Explanation:

From the question we are told that

  The  height is  [tex]h = 500 \ m[/tex]

  The acceleration is  [tex]g =  10 \  m/s[/tex]

 

Generally from the second equation of motion we have that

    [tex]h  =  ut  +  \frac{1}{2} a t^2[/tex]

Here  the initial velocity u =  0  m/s  given that the stone started from rest

       So

            [tex]500 =  0 (t) +0.5 *  (10) t^2[/tex]

=>         [tex]t = 10 \  s[/tex]

The moon is half dark, half lit on two days each month . What causes this?

Answers

Answer:

This is caused by the rotation and position of the Earth with respect to the sun.

Explanation:

The constant change of the Moon's surface relative to Earth is called "The moon phases".

These modifications in our satellite are due to the change of position of the satellite with respect to the Earth and the Sun.

During the lunar phases of the third quarter and the first quarter, the moon lights up just a half, being that both only light half, the first quarter lights the right side of the moon, and the last quarter lights the left side.

A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.(a) Is the projectile a freely falling body? (b) What is its acceleration in the vertical direction? (c) What is its acceleration in the horizontal direction?

Answers

Answer:

Explanation:

When a projectile is launched at some angle to the horizontal with some speed vi , and air resistance is negligible , it is definitely a freely falling body .

It is so because it is free to accelerate towards the earth with acceleration of g . Air has no resistance , hence no force is acting on it except the gravitational force . Hence it is a freely falling body .

b )

The acceleration in the vertical direction is due to force exerted by the earth that is gravitational force on it  . Hence its  acceleration is equal to g in vertically downward direction .

c )

It has zero acceleration in horizontal direction . It is so because no force is acting on it in horizontal direction . So no acceleration will be present in horizontal direction . It will move in horizontal direction with constant speed of vi cos θ where θ is the angle vi make with the horizontal .

Challenge Problem
5.
A man is standing on the top of a hill and sees a flagpole he knows is 45 feet high. The angle of
depression to the bottom of the pole is 12 degrees, and the angle of elevation to the top of the
pole is 16 degrees. Find his distance from the pole.

Answers

Answer: his distance from the pole is 90.16 ft

Explanation:

based on the diagram of the question i will upload along this answer;

45 - d is equal to part of the pole below the horizontal line

d/x = tan(16) ; x = d/tan(16)............equ1

(45-d) / x = tan(12); x = (45-d) / tan(12)-----------equ2

∴ d/tan(16) = (45-d) / tan(12)

d.tan(12) = (45-d).tan(16)  

d.tan12 = (45×tan16) - d.tan16

0.2125d = 12.9034 - 0.2867d

0.2125d + 0.2867d = 12.9034

0.4992d = 12.9034

d = 12.9034/0.4992

d = 25.85 ft

now substitute value of d into any of our previous equation, lets take equation 1

x = 25.85 / tan(16)

x = 25.85 / 0.2867

x = 90.16 ft

Therefore his distance from the pole is 90.16 ft

A 2250 kg truck has a velocity of 25 m/s to the east. What is the momentum of the truck? p = mv

Answers

Momentum, p=mass* velocity
P=2250(25)
p=56250 kgm/s

Hope this can help.

The momentum of the truck is "56250 kgm/s".

According to the question,

Mass,

m = 2250 kg

Velocity,

v = 25 m/s

As we know,

→ [tex]p = mv[/tex]

By putting the values, we get

→    [tex]= 2250\times 25[/tex]

→    [tex]= 56250 \ kgm/s[/tex]

Thus the answer is right.

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The second law of thermodynamics leads us to conclude what?
a. the total energy of the universe is constant
b. disorder in the universe is increasing with the passage of time
c. it is theoretically impossible to convert work into heat with 100% efficiency
d. the total energy in the universe is increasing with time
e. the total energy in the universe is decreasing with time

Answers

Answer:

b. disorder in the universe is increasing with the passage of time

Explanation:

The second law of thermodynamics states that the total entropy of an isolated system  increases over time . The entropy of a system measures the randomness or disorder  in the system . So the we can state,  in terms of disorder , the second  law of thermodynamics as follows .

The disorder in the universe is increasing with the passage of time .

The second law of thermodynamics leads us to conclude that disorder in the universe is increasing with the passage of time. So, here, option b is the correct option.

Entropy is a measure of the disorder or randomness in a system. The second law of thermodynamics states that in any spontaneous process, the total entropy of an isolated system (including both the system and its surroundings) tends to increase or, at best, remain constant. This means that over time, natural processes tend to lead to an increase in the overall disorder or randomness of the system. It's important to note that while the increase in entropy is a statistical tendency on a macroscopic scale, there can still be localized decreases in entropy within a system. 

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Enter the following expression in the answer box below: 2gλ3m−−−−√, where λ is the lowercase Greek letter lambda.

Answers

Answer:

  [tex]\sqrt{\dfrac{2g\lambda^3}{m}}[/tex]

Explanation:

We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.

  [tex]\boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}[/tex]

You travel down the highway at a steady rate of 75 mph (33.53 m/s)  for a total of 25 minutes, calculate how far you traveled in meters

Answers

Answer:

50280 meters

Explanation:

33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)

2011.2 meters/m * 25 minutes = answer

Which is NOT one of the 11 organ systems of the body?
Integumentary system
Immune system
Skeletal system
Digestive system

Answers

Answer:

Immune

Explanation:

because I remember taking that test and I I specifically remember that question and that's the answer

Which of the following describes how the mechanical advantage of a simple machine affects the amount of force needed for work? A. By decreasing the distance over which the input force is applied, less force is needed to do the same amount of work. B. By increasing the distance over which the input force is applied, more force is needed to do the same amount of work. C. By decreasing the distance over which the input force is applied, more force is needed to do the same amount of work. D. By increasing the distance over which the input force is applied, less force is needed to do the same amount of work.

Answers

Answer:

The answer is a

Explanation:

If A= +4j - 2i - 3k and C= -4i -2j - 3k , which of the following numbers is closest to the magnitude of A-C ?

Answers

The magnitude of Dot product of two vectors is 3.

Given vectors are,

     [tex]A= 4j - 2i - 3k[/tex]  and [tex]C= -4i -2j - 3k[/tex]

The dot product two vectors shown below,

        [tex]A\cdot C=(-4*4)+(-2*-2)+(-3*-3)\\\\A\cdot C=-16+4+9\\\\A\cdot C=-16+13=-3[/tex]

Thus,  The magnitude of Dot product of two vectors is 3.

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what is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow

Answers

The complete question is;

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?

Answer:

2.185 × 10^(14) electrons/seconds

Explanation:

We are given current as 35 μA = 35 × 10^(-6) Amperes

The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs

Now, from conversions;

One ampere = one coulomb/second =

Then, 35 × 10^(-6) Ampere's would give;

35 × 10^(-6) Coulombs/sec

Now,

1.602 × 10^(-19) coulombs = 1 electron

Thus;

35 × 10^(-6) Coulombs/sec gives;

(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec

The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec

The flow of charge:

The question is as given below:

In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?

Given information:

Current I = 35 μA = 35 × 10⁻⁶ A

charge on electron e = 1.602 × 10⁻¹⁹C

We know that:

I = de/dt, rate of flow of charge.

1A = 1C/s

Thus,

35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s

Now, one electron has a charge of  1.602 × 10⁻¹⁹C

So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:

n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)

n = 2.185 × 10⁻¹⁴ electrons /sec

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Which is the least dense liquid?

Answers

Answer:

lamp oil.

Explanation: the ping pong ball doesnt sink through the lamp oil.

I REALLY NEED HELP What is a closed physical system A.A system where matter and energy can enter, but not leave the system B.non of the answers are true C.A system where matter and energy can leave, but not enter the system D.A system where matter and energy cannot enter or leave the system

Answers

You probably already took this but if anyone wanted to know the answer it's D. "A system where matter and energy cannot enter or leave the system".

(I also took the quiz for it and got it correct)

A closed physical system is a system where matter and energy cannot enter or leave the system. The correct option is D.

What is a physical system?

A physical system is any item or part of an object that can be analyzed using physics laws.

An atom and lake water are both examples of physical systems. Everything outside the system is referred to as the environment, and it is ignored in the analysis except for its effects on the system.

A physical system is a collection of parts or elements that, when combined, exhibit behavior that the constituents do not. Matter and energy make up physical systems.

A closed system is a natural physical system that does not allow the transfer of matter into or out of the system, though it does allow the transfer of energy in contexts such as physics, chemistry, or engineering.

Thus, the correct option is D.

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Which law of motion is this an example of?
Newton's 1st Law of Motion
Newton's 2nd Law of Motion
Newton's 3rd Law of Motion​

Answers

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation:

Answer: newtons 2nd law of motion because in order to push the object you must put force to the mass and move it causing motion

Explanation:

One multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm. How many cells does it have? If each side doubles in length how many cells will it then have? Show your work below.​

Answers

Answer:

W23e45rdfytg

Explanation:

Eawsredtrftgvbyhgtfrd54e

One multicellular organism is a cube. Each of its sides is 3 cm long. If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.

What is the matter?

Anything which has mass and occupies space is known as matter , mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

As given in the problem, one multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm.

The volume of the  multicellular organism = 3 × 3× 3

                                                                      = 27 cm³

The number of cells = 27 cm³ / 1 cm³

                                  = 27

Thus, If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.

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Can you please help me? ​

Answers

Answer:

a= 18.4m

b= 26.2m

Explanation:

Please see the attached picture for full solution.

Which of the following are properties of a conductor in electrostatic equilibrium? The force on a charge near the conductor is zero. Electric field lines just outside the conductor are perpendicular to the surface. All net charge in the conductor is on the surface. The electric field inside the conductor is zero.

Answers

Answer:

The electric field inside the conductor is zero.

Explanation:

In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.

I = 0

From the ohm's law

ΔV= IR = 0

⇒ΔV =0

Therefore, potential V is same through the conductor.

Also, E = -ΔV d = 0

Hence, The electric field inside the conductor is zero.

Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave spreads out uniformly into a hemisphere above the ground.
A) At a home 5.50km away from the antenna, what average pressure does this wave exert on a totally reflecting surface? answer in PA units
B) At a home 5.50km away from the antenna, what are the amplitudes of the electric and magnetic fields of the wave? answer in N/C, T
C) At a home 5.50km away from the antenna, what is the average density of the energy this wave carries? answer in J/m^3
D) For the energy density in part (c), what percentage is due to the electric field?
E) For the energy density in part (c), what percentage is due to the magnetic field?

Answers

Answer:

A. Using

I= P/ A

So = P/ 2π R²

So=777E3 watt/ 2*πx (²5.5E3m)

4.3*10^ -3W/m²

So pressure= 2I/c

=2* 4.3*10^ -3W/m²/ 3*10^ 8

2.7*10^-11p.a

B.

Using Emax= √2I/Eoc

So

√ 2*4.3*10^-3/8.8E-12*3*10^8

= 5.48V/m

So

Bmax= Emax/c

5.58/3E8

= 1.83*10-9T

D.average density is given by

= Eo(Emax/√2)²

= 8.85E-12(5.48/√2)²

1.3*10^10W/m²

A wire carries a steady current of 2A.the Charge that passes a cross Section in 2s is

Answers

Answer :

◈ Electric current :

Electric current is defined as the rate of charge flow. (per unit time)

I = Q/t

I denotes current

Q denotes charge

t denotes time

Given : I = 2A and t = 2s

To Find : Charge flow in wire (Q)

[tex]:\implies\sf\:I=\dfrac{Q}{t}[/tex]

[tex]:\implies\sf\:2=\dfrac{Q}{2}[/tex]

[tex]:\implies\:\boxed{\bf{\red{Q=4\:C}}}[/tex]

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current.  The charge that will be in the wire is 4 C.

What is current?

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The capital letter I is a typical sign for current. The ampere, abbreviated as A, is the standard unit.

As it is given to us that the current in the wire is 2A, while the time for which the current flows through the wire is 2 seconds.

[tex]\rm I=\dfrac Qt[/tex]

Substitute the value we will get,

[tex]\rm 2\ A = \dfrac{Q}{2\ sec}\\\\Q = 4\ C[/tex]

Thus, the charge that will be in the wire is 4 C.

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If a car is driving at 10 m/s and is driving for 2 minutes, what is the total distance it will
cover?

Answers

Distance = (speed) x (time)

Distance = (10 meter/second) x (2 minutes)

Distance = (10 meter/second) x (2 minutes) x (60 second/minute)

Distance = (10 x 2 x 60) (meter-minute-second / second-minute)

Distance = 1,200 meters

Based on these units, select any of the following expressions that could be valid expressions?v=a/tt=3√d2/vad=ata=d/t2a=√vd/t3v=at

Answers

Answer:

Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at

while the Invalid expressions are;  v = a/t and  d = at

Explanation:

Given expressions

1) v = a/t

2) t = ∛(d²/va)

3) d = at

4) a = d/t²

5) a = √(vd/t³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/s²

so

1)

v = a/t

we substitute in our units of parameters

v = m/s² / s = m/s² × 1/s = m/s³

v ≠ m/s³

therefore it is false

2)

t = ∛(d²/va)

we substitute

t = ∛(m² / m/s × m/s²)

t = ∛(m² / m²/s³)

t = ∛(s³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/s² × s

d = m/s² × s/1 =  ms/s² = m/s

d ≠ m/s (because d = m)

so expression is false

4)

a = d/t²

we substitute

a = m / s² = m/s²

correct

the expression is true

5)

a = √(vd/t³)

we substitute

a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³)  = √(m²/s⁴) = m/s²

so a = m/s²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/s² × s = m/s² ×s/1 = ms/s² = m/s

v = m/s

correct

the expression is correct

how much heat is required to convert 1 gm of ice into steam​

Answers

Answer:

Heat required in converting 1g of ice at −10∘C into steam at 100∘C is: latent heat of fusion= 80 cal/g80 cal/g. latent heat of vaporization=540 cal/g.

Choose the correct definition of angular momentum.
the product of the object’s moment of inertia and the object’s angular velocity
the product of the object’s momentum and the object’s angular velocity
the product of the object’s momentum and the object’s moment of inertia
the product of the object’s momentum and the object’s angle through space

Answers

The answer is "the product of the object's moment of inertia and the object's angular velocity.

The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem we have to find the correct definition of angular momentum,

The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle

The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.

To learn more about momentum from here, refer to the link given below ;

brainly.com/question/17662202

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