Bromine contains 35 protons, 36 electrons, and 45 neutrons. The mass number of Bromine is 80. The ion charge of bromine is +7. "Br" is the symbol of Bromine.
Discussion about bromine:
Two chemists, Carl Jacob Löwig and Antoine Balard, independently discovered bromine in 1825 and 1826, respectively.
The chemical element bromine has the atomic number 35 and the symbol Br. It is the 3rd halogen, and at room temperature, it is a flammable red-brown liquid that easily evaporates to create a vapor of a similar color. Its characteristics fall in between those of iodine and chlorine.
Due to its high reactivity, elemental bromine does not naturally occur in its free form but rather as crystals minerals halide salts that are colorless and soluble, similar to table salt. Although the bromide ion (Br) is relatively uncommon in the Earth's mantle, its great solubility has led to its buildup in the seas.
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Gold atoms find their "birth" inside of huge _________.
Explanation:
he is very keen on taking up and is the age
A student pushes a box to the right with a force of 10 N. At the same time, another
student pushes the same box to the left with a force of 5N.
What is the net force
Answer:
5 N
Explanation:
To find the net force of 2 objects pushing against each other you subtract them and that’s how you get your answer.
The net force acting on a system is defined as the resultant of all the force acting on all the body. The value of net force will be 5N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem will be;
F₁ is the force act to the right = 10 N
F₂ is the force act to the left= 5N
F is the net force=?
According to the equilibrium concept, the net force acting on the body is equal to zero.
F = F₁ - F₂
F = 10-5
F = 5N
Hence the value of net force will be 5N.
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07. 1
Explain why the light refracts as it passes from air into glass. GCSE PHYSICS HIGHER
Answer:
Light is faster in air than in glass so the speed of light decreases when it passes through glass.
WORTH 15 POINTS WILL GIVE BRAINLIEST
What is the mechanical advantage of a handle on a water well that requires 5 newtons of force to lift a 40-Newton bucket of water?
200
8
0.125
12.5%
Option B. The mechanical advantage of a handle on a water well that requires 5 newtons of force to lift a 40-Newton bucket of water is 8.
Mechanical advantage is a measure of the force amplification completed by means of the usage of a device, mechanical tool or gadget device. The device trades off input forces towards motion to gain a preferred amplification in the output pressure.
The version for this is the regulation of the lever. The mechanical advantage is the degree how which tons of force is increased with the aid of using a device or gadget. it is equal to the pressure exerted with the aid of the tool or system divided via the carried-out effort.
calculation:-
Mechanical advantage = load/effort
= 40/5
= 8
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Describe in brief the importance of measurement in our daily life?
Measurement tools make our lives safer and better? And they increase the quality and quantity of life. Arguably, the ability to measure calculating
physical properties accurately have tremendous survival value that gives humans adaptive, evolutionary advantages sharpened through many years of natural selection.
the pulley is a uniform disk with a mass of 0.75 kg and a radius of 6.5
on between the 5.8 kg mass and the horizontal surface is 0.25, and the
The system is released from rest. Use work-energy principles to deter
2.8 kg mass and (b) the pulley after the 5.8 kg mass has moved 2.2 m
Answer:
please find the answer in the attached images , in 2 parts, btw thanks for so many points. i hope my answers are correct.
Describe or identify some uses of an electromagnet.
Answer:
Electromagnets are widely used as components of other electrical devices, such as motors, generators, electromechanical solenoids, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment.Explanation:
If a person meets an accident, which of the following factors will have more effect on his Kinetic energy and hence on the fatality of the accident?
A.velocity of the vehicle
B.Mass of the vehicle
Answer:
b
Explanation:
A go-cart and rider have a mass of 100 kg. If the cart accelerates at 5 m/s2 during a 25 m sprint, how much work did the cart do
Answer:20watts
Explanation:
Answer:
The solution is given below
Explanation:
The computation is shown below;
We know that
Work done = Fs cosθ
But before that we need to determine the force i.e.
We know that
Force (F) = mass (m) × Acceleration (a)
= 100 × 5
= 500 N
Now, work done by the go-cart is
Work done (W) = Fs cosθ
= 500 × 25 × cos(0°)
= 500 × 25 × 1
= 12,500 J
help.....please science
Answer:
please mark me brainliest
Explanation:
ohm
The SI-derived unit of electric resistance is the ohm, which is defined as a volt per ampere.
Answer:
I cant see that
Which of the following is an example of an omnivore?
A
an herb like basil, which gets energy from the sun
B
a dog, which eats meat and vegetables
с
a dinosaur that only eats marsh grasses
D
a buzzard that only eats roadkill
Answer:
B a dog omnivor is like us we are hunter gatherers, plants and meat
Answer:
B
Explanation:
omnivores eat both crops and meat .The dog exhibited this trait.
An object on the moon feels lighter than the same object on earth. which statement explains this phenomenon?
A. The moon has less mass than earth.
B. The object has a greater gravitational attraction to the moon.
C. The object has less mass on the moon then on earth.
D. The moon is in orbit around earth.
Answer:
B
Explanation:
cause
Answer: A
Explanation:
The moon has less mass than Earth.
Just took the test.
A proton is 0.9 meters away from a 1.4 C charge. What is the magnitude of the electric force between the proton and the charge
Answer:
F = 2.49 x 10⁻⁹ N
Explanation:
The electrostatic force between two charged bodies is given by Colomb's Law:
[tex]F = \frac{kq_1q_2}{r^2}\\[/tex]
where,
F = Electrostatic Force = ?
k = colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = charge on proton = 1.6 x 10⁻¹⁹ C
q₂ = second charge = 1.4 C
r = distace between charges = 0.9 m
Therefore,
[tex]F = \frac{(9\ x\ 10^9\ N.m^2/C^2)(1.6\ x\ 10^{-19}\ C)(1.4\ C)}{(0.9\ m)^2}[/tex]
F = 2.49 x 10⁻⁹ N
31.5N
I have confirmed it is the right answer.
The angle of incidence of another red ray is 65º. The refractive index of the glass of block
ABCD for red light is 1.62.
(i) Calculate the angle of refraction in the glass for this ray.
Answer:
34º
Explanation:
The computation of the angle of refraction in the glass for this ray is shown below:
Given that
the angle of incidence of another red ray is 65º
And, n_1 = 1
n_2 = 1.62
According to shell law
n_1 sin [tex]\theta[/tex]_1 = n_2 sin [tex]\theta[/tex]_r
sin [tex]\theta[/tex]_r = 1 sin 65÷ 1.62
= 0.559
[tex]\theta[/tex]_r = sin^-1 (0.559)
= 34º
Dr. Kirwan is preparing a slide show that he will present to the executive board at tonight's committee meeting. He places a 3.50-cm slide behind a lens of 20.0 cm focal length in the slide projector. A) How far from the lens should the slide be placed in order to shine on a screen 6.00 m away? B) How wide must the screen be to accommodate the projected image?
Answer:
A) d_o = 20.7 cm
B) h_i = 1.014 m
Explanation:
A) To solve this, we will use the lens equation formula;
1/f = 1/d_o + 1/d_i
Where;
f is focal Length = 20 cm = 0.2
d_o is object distance
d_i is image distance = 6m
1/0.2 = 1/d_o + 1/6
1/d_o = 1/0.2 - 1/6
1/d_o = 4.8333
d_o = 1/4.8333
d_o = 0.207 m
d_o = 20.7 cm
B) to solve this, we will use the magnification equation;
M = h_i/h_o = d_i/d_o
Where;
h_o = 3.5 cm = 0.035 m
d_i = 6 m
d_o = 20.7 cm = 0.207 m
Thus;
h_i = (6/0.207) × 0.035
h_i = 1.014 m
A cannon and a supply of cannonballs are in a sealed system railroad car. The car has a length of 20 meters, and a mass of 2000kg. The cannon fires to the right, the car recoils to the left. Fired cannonballs remain in the car after hitting the wall and land on the floor at the end of the car. The cannonballs have a mass of 15 kg each, and there are ten of them. (neglect mass of cannon) How far will the car move after all ten have been fired
Answer:
The distance the car moves after all ten cannonballs have been fired is 1.5 meters
Explanation:
The parameters given in the question are;
The length of the car = 20 meters
The mass of the of the cannon ball, m₁ = 2,000 kg
The direction the cannon fires = The right
The direction the car recoils = The left
The mass of each cannonball, m₂ = 15 kg
The number of cannonballs = 10
Let v₁ represent the speed of the car and let v₂ represent the speed of the cannonball, where momentum is conserved, we have;
m₁·v₁ = m₂·v₂
2000 × v₁ = 15 × v₂
400·v₁ = 3·v₂
Therefore, when the cannon ball travels 400 meters, the railroad car travels 3 meters
Similarly, when the cannon ball travels 400/20 = 20 meters, the distance the railroad car travels, d = 3/20 meters
We not that the railroad car and the car are brought to a stop each time the cannonball hits the watt
Therefore, the total distance moved by the car after all ten have been fired, [tex]d_{total}[/tex], is given as follows;
[tex]d_{total}[/tex] = d × The number of balls fired
∴ [tex]d_{total}[/tex] = 3/20 meters per ball × 10 balls = 3/2 meters = 1.5 meters
The total distance moved by the car, [tex]d_{total}[/tex] = How far the car moves after all ten have been fired = 1.5 meters.
A car has wheels of radius of 0.380 m and they rotate once every 0.100 s. What is the linear velocity of the wheels? (Units = m/s)
Answer:
v = 23.87 m/s
Explanation:
Given that,
The radius of wheels, r = 0.380 m
The wheels rotate once every 0.1 s
We need to find the linear velocity of the wheels. The linear velocity of a wheel is given by :
[tex]v=\dfrac{2\pi r}{t}\\\\=\dfrac{2\pi \times 0.38}{0.1}\\\\=23.87\ m/s[/tex]
So, the required linear velocity of the wheel is equal to 23.87 m/s.
Choose the correct statement below that accurately describes the shear and normal stresses in a beam. A. Shear stresses are maximum at the neutral axis and normal stresses are maximum furthest from the neutral axis. B. Normal stresses are maximum at the neutral axis and shear stresses are maximum furthest from the neutral axis. C. Shear stresses and normal stresses are maximum at the neutral axis. D. Shear stresses and normal stresses are maximum furthest from the neutral axis.
Answer:
A. Shear stresses are maximum at the neutral axis and normal stresses are maximum furthest from the neutral axis.
Explanation:
Normal stress :
Normal stress is defined as the stress or the restoring force that occurs on the plane when an external axial load is applied on it. For a beam the normal stress is maximum at the point furthest from the neutral axis and is zero at the neutral axis of the beam.
Shear stress :
Shear stress is a stress which occurs when the force acts on the surface of the member in a parallel direction. It changes the shape of the member. For a beam, the shear stress is maximum at the neutral axis.
U will be marked as brainlest if you solve this ex
Answer:
.
Explanation:
name them all
then multiply
after it simplify
If one light bulb breaks in a series circuit containing three bulbs will it remain lit?
In a series circuit, every device must function for the circuit to be complete. One bulb burning out in a series circuit breaks the circuit. In parallel circuits, each light has its own circuit, so all but one light could be burned out, and the last one will still function
Which of the following describes a transfer of energy through work?
A student carries a heavy backpack one km
O A laboratory burner is used to heat 250 ml of water to boiling,
O A woman pushes a luggage cart in an airport over a distance of 100 m
O A man pushes on a large piece of furniture for 15 min, but it does not move.
A lens with f=15.0 cm is held 29.0 cm from an object. Where does the image form
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
v is image distance
Magnification,
So, the magnification of the lens is 3.
Answer:
31.1
Explanation:
Trust brother
A truck gradually starts off from rest with a uniform
acceleration of 2 m/s2
. It reaches a velocity of 16 m/s. Using the
equation
[tex] {v}^{2}={u }^{2}+2as[/tex]
,calculate the distance it travels while it is
accelerating
Write your views on pyramid.
=> No copy Paste
=> Conspiracy theories are accepted
Answer:
pyramid is a body or structure whose outer surfaces are triangular and converge to a first step at the the top which base may be in a shape of triangle ,rectangle,square and other any shape.
Explanation:
its volume is equal to product of area of base and height of it..
the lateral surface area of a regular pyramid is equal to the sum of the areas of its lateral faces.
the total surface area of a regular pyramid is equal to the sum of the lateral surface areas of pyramid and base.
Answer:
A pyramid is a polyhedron for which the base is a polygon and all lateral faces are triangles. A pyramid is described by the shape of its base . for example , a triangular pyramid has a triangular base , square pyramid has a square base .hope it is helpful to you
A 1200 kg car accelerates from rest to 10.0 m/s in a time of 4.50 seconds. Calculate the force that the car’s tires exerted on the road.
please help me i need the answer in 10 mins
Answer:
the force that the car’s tires exerted on the road is 2,666.67 N.
Explanation:
Given;
mass of the car, m = 1,200 kg
initial velocity of the car, u = 0
final velocity of the car, v = 10.0 m/s
time of motion, t = 4.50 s
The force the car’s tires exerted on the road is calculated as follows;
[tex]F = ma= \frac{m(v-u)}{t} \\\\F = \frac{1200(10-0)}{4.5} \\\\F = 2,666.67 \ N[/tex]
Therefore, the force that the car’s tires exerted on the road is 2,666.67 N.
a uniform metre scale rests horizontally on a knife edge at the 60cm mark when a mass of 10 gram is suspended from one end . at which end this mass be suspended . what is the mass of meter scale?
Answer:
40 gram or 0.04 kilogram
Explanation:
From the diagram attached,
The mass must be suspended at end B.
Applying the principle of moment,
Sum of clockwise moment = sum of anti-clockwise moment.
From the diagram,
Taking the moment about the pivot,
X(60-50) = 0.1(100-60)
Where X = weigth of the meter rule
10X = 4
X = 4/10
X = 0.4 N
X = 0.4/10
X = 0.04 kg
X = 40 g
Hence the mass of the meter rule = 0.04 kg or 40 gram
John often sees squiggly lines when he looks at a bright sky or white paper. His doctor says that they are called eye floaters, which are small bits of protein in the fluid that fills the eyeball.
In what part of the eye are eye floaters found?
a) cornea
b) vitreous humor
c) retina
d) convex lens
Answer- It's B, i double checked it on a few websites
The vitreous humor is the eye is eye floaters.
What is vitreous humor?The vitreous body (vitreous meaning "glass-like"; from Latin vitreus 'glassy', from vitrum 'glass', and -eus) is the clear gel that fills the space between the lens and the retina of the eyeball (the vitreous chamber) in humans and other vertebrates. It is often referred to as the vitreous humor (also spelled humour, from Latin meaning liquid) or simply "the vitreous". Vitreous fluid or "liquid vitreous" is the liquid component of the vitreous gel, found after a vitreous detachment. It is not to be confused with the aqueous humor, the other fluid in the eye that is found between the cornea and lens.
StructureThe vitreous humor is a transparent, colorless, gelatinous mass that fills the space in the eye between the lens and the retina. It is surrounded by a layer of collagen called the vitreous membrane (or hyaloid membrane or vitreous cortex) separating it from the rest of the eye. It makes up four-fifths of the volume of the eyeball.The vitreous humour is fluid-like near the centre, and gel-like near the edges.
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What is the Deepest point of the ocean and where is it?
Answer:
marinas trench in Pacific Ocean
mark it as brainliestExplanation:
Located in the western Pacific Ocean, the Marina Trench
Doing science by inquiry always involves:
4) Explain which electric charges attract and which electric charges repel (push away)
Explanation:
According to the fundamental law of electrostatics, like charges which are ( only positive or only negative charges) repel while unlike charges which are ( positive and negative charges ) attract each other.
that is: ( +++++ ++++++) they repel
while ( +++++++ ———) they attract