Answer:
The minimum mass of ethylene glycol = 6.641 Kg
Explanation:
[tex]\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f[/tex]
Where T_f = freezing point of pure solvent water, 0°C
T_f'= Freezing point of solvent after mixture
K_f = Freezing point depression constant = 1.86 °C/m
Moecular weight of ethylene glycol = 60 g/mol
Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g
molality of ethylene glycol
[tex]m = \frac{weight}{mol.wt} \times\frac{1000}{V}[/tex]
Substitute the values to calculate m
[tex]m = \frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
by formula
[tex]0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
calculating we get w = 6641.93 g
Therefore, The minimum mass of ethylene glycol = 6.641 Kg
Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.
Explanation:
[tex] = 2.5\% \times 2000 \\ = \frac{2.5}{100} \times 2000 \\ = 50 \: g[/tex]
A mixture of 0.224 g of H2, 1.06 g of N2, and 0.834 g of Ar is stored in a closed container at STP. Find the volume (in L) of the container, assuming that the gases exhibit ideal behavior.
Answer: The volume of given container is 3.83 L.
Explanation:
Given: Mass of [tex]H_{2}[/tex] = 0.224 g
Mass of [tex]N_{2}[/tex] = 1.06 g
Mass of Ar = 0.834 g
Since, moles is the mass of a substance divided by its molar mass. Therefore, moles of given substances present in the mixture are as follows.
Moles of [tex]H_{2}[/tex] are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.224 g}{2 g/mol}\\= 0.112 mol[/tex]
Moles of [tex]N_{2}[/tex] are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.06 g}{28 g/mol}\\= 0.038 mol[/tex]
Moles of Ar are:
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.834 g}{40 g/mol}\\= 0.021 mol[/tex]
Total moles = (0.112 + 0.038 + 0.021) mol = 0.171 mol
Now, using ideal gas equation the volume is calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]V = \frac{nRT}{P}\\= \frac{0.171 mol \times 0.0821 L atm/mol K \times 273 K}{1 atm}\\= 3.83 L[/tex]
Thus, we can conclude that the volume of given container is 3.83 L.
Acids and bases are chemical molecules with very different characteristics.
a. True
b. Fasle
Answer:
TRUE ,hope it helped you
Explanation:
Brainiest and 10 points
Which has a HIGHER frequency?
A. Orange light
B. Blue light
Answer:
A. Orange light
Explanation:
According to the band spectrum of white light ( ROYGBIV )
Answer:
I think it blue light is higher
A heavy brick weighs more than a fluffy cushion, but the cushion takes up more space. Which object has more matter?
Answer:
The brick has more matter because it has more mass.
Explanation:
About how long did it take for this population to reach the carrying capacity of this habitat
Answer:100
Explanation:
why did researchers at the university of Antwerp study high speed videos of the black woodpecker
here's your answer..
Find the concentration of Pb2 (aq) in ppm by mass of a 1.13 L sample of contaminated water that was assayed by adding NaI(s) and obtaining 55.1x10-3 g of PbI2(s) precipitate. Assume that Pb2 (aq) is completely precipitated as PbI2(s). The molar mass of PbI2(s) is 461.01 g/mol. Assume that the density of the solution is 1.00 kg/L. Give the answer with 3 or more significant figures.
Answer:
22.1 ppm
Explanation:
The equation of the reaction is;
Pb2+ (aq) + 2NaI(s) ------>PbI2(s) + 2 Na^2+
Mass of precipitate = 55.1x10-3 g
Number of moles of precipitate = 55.1x10-3 g/461.01 g/mol = 1.2 * 10^-4 moles
1 mole of Pb2+ yields 1 mole of PbI2
Hence 1.2 * 10^-4 moles of Pb2+ also yields 1.2 * 10^-4 moles of PbI2.
Hence mass of Pb2+ present = 1.2 * 10^-4 moles * 207 g/mol = 0.025 g or 25 mg
Mass of solution = Density of solution * volume of solution
Mass of solution = 1.00 kg/L * 1.13 L
Mass of solution = 1.13 Kg
Concentration in mg/Kg(ppm) = mass of solute/mass of solution
= 25 mg/1.13 kg
= 22.1 ppm
When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light,motion,or electricity. This is called
Answer: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.
Explanation:
The chemical energy present in fuels actually releases when these fuels are burned or by combustion.
Hence when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.
For example, gasoline present in vehicles burns and undergoes chemical change which is then converted into thermal energy. This thermal energy then converts into mechanical energy due to which car moves.
Thus, we can conclude that when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.
Write a balanced chemical equation for the reaction. Na2CO3Na2CO3 and AgNO3AgNO3 Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].
Explanation:
The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.
[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]
Here, number of atoms present on reactant side are as follows.
Na = 2[tex]CO_{3}[/tex] = 1Ag = 1[tex]NO_{3}[/tex] = 1Number of atoms present on product side are as follows.
Na = 1[tex]CO_{3}[/tex] = 1Ag = 2[tex]NO_{3}[/tex] = 1To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.
Hence, the equation can be rewritten as follows.
[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]
Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.
Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].
Answer:
2
Explanation:
The pressure of a gas is 1.0 atm, the volume is 3.0 L, and the temperature is 200 K. A chemist changes one factor while keeping another constant so that the new pressure is 2.0 atm. Which of the following could be the new conditions?
The final volume is 6.0 L, while temperature is kept constant.
The final temperature is 100 K, while volume is kept constant.
The final volume is 4.0 L, while temperature is kept constant.
The final temperature is 400 K, while volume is kept constant.
Answer: The correct answer is actually: The final temperature is 400 K, while volume is kept constant.
Explanation: Got it right on test!
Construct a Lewis structure for hydrogen peroxide, H2O2, in which each atom achieves a stable noble-gas electron configuration. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.
Answer:
See explanation and image attached
Explanation:
Hydrogen peroxide is made up of two atoms of hydrogen and two atoms of oxygen as shown in the image attached.
The two oxygen atoms are joined together by a single covalent bond and each of the oxygen atoms are bonded to one hydrogen atom each.
There are two lone pairs on each of the oxygen atoms.
The Lewis(dot) structure for hydrogen peroxide is shown in the image attached to this answer.
To double-check a chemical in lab before using it, sniff near the opening of the container, true or false?
What volume of 0.686 M HCl would contain 0.037 moles of solute?
Given :
Molarity of HCl solution, M = 0.686 M.
Number of moles, n = 0.037 moles.
To Find :
The volume of solution.
Solution :
We know, molarity is given by :
[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]
Hence, this is the required solution.
Butane C4H10, is an easily liquedfied gaseous fuel. calculate the density of butane gas at 0.897 atm and 24°C. give the answer in grams per litre
Answer:
Density = 2.137 gram per liter (Approx.)
Explanation:
Given:
Gaseous fuel Butane C4H10
Pressure = 0.897 atm
Temperature = 24°C = 24 + 273 = 297 k
Find:
Density of butane gas
Computation:
We know that molar mass of butane = 58.12 g/mol
Density = [molar mass x pressure] / Rt
Density = [58.12 x 0.897] / [0.0821 x 297]
Density = [52.13] / [24.3837]
Density = 2.137 gram per liter (Approx.)
An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound.
Answer:
The molecular formula of the compound is C10H16O.
Explanation:
Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.
The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.
The formula of osmotic pressure is,
P = CRT
Now putting the values in the formula we get,
0.328 = C*0.0821*300
C = 0.013317
C = (mass/molecular mass) * (1000/volume of solution in ml)
0.013317 = (0.152/Molecular mass) * (1000/75)
Molecular mass = 152.186
C mass = 152.186 * 0.789 = 120.07 grams
C mole = 120.07/12 = 10
H mass = 152.186 * 0.1059 = 16.11 grams
H mole = 16.11/1 = 16
O mass = 152.186 - 120.07 - 16.116 = 16 grams
O mole = 16/16 = 1
Thus, the molecular formula of the compound will be,
C10H16O
Explain why the ability of PLP to catalyze an amino acid transformation is greatly reduced if the OHOH substituent of pyridoxal phosphate is replaced by OCH3OCH3.
Answer:
Following are the responses to the given question:
Explanation:
In the given question the OH could be generated as the H-bond with both the N (nitrogen), which is used to place its N as the partially positive value(+). It is used to simplifies the addition for either its AA with the imine C. In the above H-bond, the w N is not required as the possibility to use the OCH3
What
is the major engine driving the planet's constant evolution and contains a geological record of much of the Earth's history
1. Mantle
2. Crust
3. Inner Core
4. Outer Core
How are the stratosphere and the mesosphere similar
Answer:
stay safe healthy and happy...El butano, C4H10, se quema en presencia de oxígeno gas, O2, y se produce dióxido de carbono, CO2, y agua. ¿Cuántos kg de CO2 se obtendrán al quemarse 12 kg de butano?
Answer:
don't know really and don't know at alll
in any chemical reaction each type of atom is conserved
Answer:
Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction. The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.
7 grams of oxygen gas is reacted with excess C4H8. How many grams of CO2 gas at STP are produced?
If the temperature decreases, then the pressure will
Positive or negative , guys?
How many grams of O2 can be produced from 3 moles KCIO3-
Answer:
In the question the mass has two significant figures; thus the mass of O2 released would be 4.0 g (two significant figures). 122.55 g of KClO3 yields 3*32 g of O2
Explanation:
A chemist adds of a magnesium fluoride solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to significant digits.
The given question is incomplete, the complete question is:
A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to
3 significant digits.
Answer:
The correct answer is 1.35 microgram.
Explanation:
Based on the given information,
The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.
Now the moles of MgF₂ can be determined by using the formula,
Moles = Concentration × Volume
Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂
= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml
= 217 × 10⁻⁷ mmol
The molecular mass of magnesium fluoride is 62.3 gram per mole
Thus, the mass of MgF₂ is,
= 217 × 10⁻⁷ mmol × 62.3 g/mol
= 13500 × 10⁻⁷ mg
= 1.35 microgram
which functional group does the molecule below contain
Answer:
All functional groups in organic chemistry
Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.
Hope this helps Have a good day
can u pls help me i need the answer ASAP
How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?
Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.
I need help with my chemistry but you can only choose one correct answer
Answer:
Explanation:
photosynthesis
the given chemical reaction is photosynthesis.
During photosynthesis carbon dioxide absorbed by plants reacts with water in presence of sunlight to give glucose and oxygen.