Answer:
1.73 M
Explanation:
Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.
7.47/4.31 ≈ 1.73 M
how to get a girl
need to get a girl
Answer:
pretty easy
Explanation:
step 1: Approach her
step 2: Ask her for something (make it look like you're lost even when you aren't)
step 3: engage in a conversation with her
step 4: you talk for hours and she give you her number
step 5: you wake up from your dream
step 6: wait you woke up
step 7: go back to dreaming again.
Answer: Girls are tough. Girls are....attitude, we all know its true.
Explanation
Best thing to start is shush when shes talking.
Calculate the specific heat capacity for bone based on the above data. Show your work.
Answer:
What above data?
Explanation:
There is no data to be seen here.
Using your freshly made 5M stock aqueous solution of NaCl and your 10% aqueous stock of SDS, you find a prepackaged bottle of 1M Tris-Hcl (aqueous solution) along with a 95% solution of liquid NP-40 in a bottle. Using these stock reagents calculate the amount needed for the following final concentrations for each reagent as well as the final volume of water needed to obtain:
Total Final volume of 500 mL
Final Concentrations:
150 mM NaCl
50 mM Tris-HCl
1% NP-40 .
1% SDS
Answer:
1. Volume of stock required = 15 mL
Volume of water required = 485 mL
2. Volume of stock required = 5 mL
Volume of water required = 495 mL
3. Volume of stock required = 5.30 mL
Volume of water required = 494.70 mL
4. Volume of stock required = 50 mL
Volume of water required = 450 mL
Explanation:
Using the dilution formula C₁V₁ = C₂V₂
Where C₁ = initial concentration; C₂ = final concentration; V₁ = initial volume; V₂ = final volume
1. C₁ = 5 M NaCl, C₂ = 150 mM NaCl = 0.15 M NaCl
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 0.15 × 500/ 5 = 15 mL
Volume of stock required = 15 mL
Volume of water required = 500 mL - 15 mL
Volume of water required = 485 mL
2. C₁ = 1 M Tris-HCl, C₂ = 50 mM Tris-HCl = 0.05 M Tris-HCl
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 0.05 × 500/ 5 = 5 mL
Volume of stock required = 5 mL
Volume of water required = 500 mL - 5 mL
Volume of water required = 495 mL
3. C₁ = 95% NP-40, C₂ = 1% NP-40
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 1 × 500/ 95 = 5.30 mL
Volume of stock required = 5.30 mL
Volume of water required = 500 mL - 5.30 mL
Volume of water required = 494.70 mL
4. C₁ = 1% SDS, C₂ = 10% SDS
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 1 × 500/ 10 = 50 mL
Volume of stock required = 50 mL
Volume of water required = 500 mL - 50 mL
Volume of water required = 450 mL
What was the independent variable in Mendel's pea plant experiment?
A.The temperature
B.Cross-pollination
C.Type of plant
D.Characteristic of the offspring
When NH3(g) reacts with O2(g) to form N2O(g) and H2O(l) , 342 kJ of energy are evolved for each mole of NH3(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term (including the units) in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.
Answer:
2 NH₃(g) + 2 O₂(g) ⇒ N₂O(g) + 3 H₂O(l) ΔH° = -684 kJ
Explanation:
Let's consider the unbalanced equation that occurs when NH₃(g) reacts with O₂(g) to form N₂O(g) and H₂O(l).
NH₃(g) + O₂(g) ⇒ N₂O(g) + H₂O(l)
We will begin balancing N atoms by multiplying NH₃(g) by 2.
2 NH₃(g) + O₂(g) ⇒ N₂O(g) + H₂O(l)
Then, we will balance H atoms by multiplying H₂O(l) by 3.
2 NH₃(g) + O₂(g) ⇒ N₂O(g) + 3 H₂O(l)
Finally, we will get the balanced equation by multiplying O₂(g) by 2.
2 NH₃(g) + 2 O₂(g) ⇒ N₂O(g) + 3 H₂O(l)
Since 342 kJ of energy are evolved for each mole of NH₃(g), and there are 2 moles of NH₃(g) in the balanced equation, the heat evolved will be2 × 342 kJ = 684 kJ. By convention, when heat is evolved, it takes a negative sign. The balanced thermochemical equation is:
2 NH₃(g) + 2 O₂(g) ⇒ N₂O(g) + 3 H₂O(l) ΔH° = -684 kJ
What is the mass of 4.76 moles of Na3Po4?
SHOW WORK PLEASE - NO LINKS OR FILES(I will not open them)
( btw if your user is Alexgrelli do not answer , I have already reported your account )
Answer:
780 g
Explanation:
Step 1: Given data
Moles of sodium phosphate: 4.76 moles
Step 2: Calculate the mass corresponding to 4.76 moles of sodium phosphate
To convert moles to mass, we need a conversion factor. In this case, we will use the molar mass of sodium phosphate, which is 163.94 g/mol.
4.76 mol × 163.94 g/mol = 780 g
Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2
with solutions
Answer:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Explanation:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
The above equation can be balance as illustrated below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
There are 16 atoms of H on the left side and 1 atom on the right side. It can be balance by writing 16 before HF as shown below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + 16HF + CoF₂
There are 3 atoms of F on the left side and a total of 34 atoms on the right side. It can be balance by writing 32 before CoF₃ and 32 before CoF₂ as shown below:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Now, the equation is balanced.
from your findings what conclusions and recommendations can you make on the issue of human rights violations to Government and communities
Explanation:
Recommendations:
1.To make strict rules and regulations against those who violates rights
2.To mobilize police actively to stop such incidents
3.To raise public awareness to prevent human rights violation
A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the equivalence point. In a separate titration, a 10.0 mL H3PO4 solution was titrated with the same NaOH solution. This time, 34.9 mL NaOH was required to reach the equivalence point. What is the concentration of the H3PO4 solution
Answer:
0.172 M
Explanation:
The reaction for the first titration is:
HCl + NaOH → NaCl + H₂OFirst we calculate how many HCl moles reacted, using the given concentration and volume:
19.6 mL * 0.189 M = 3.704 mmol HClAs one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:
3.704 mmol / 25.0 mL = 0.148 MAs for the second titration:
H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂OWe determine how many NaOH moles reacted:
34.9 mL * 0.148 M = 5.165 mmol NaOHThen we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:
5.165 mmol NaOH * [tex]\frac{1mmolH_3PO_4}{3mmolNaOH}[/tex] = 1.722 mmol H₃PO₄Finally we determine the H₃PO₄ solution concentration:
1.722 mmol / 10.0 mL = 0.172 MA reaction occurs in which carbon combines with sulfur to form carbon
disulfide. Is this a chemical reaction or a nuclear reaction, and how do you
know?
A. This is a nuclear reaction, because mass was conserved.
B. This is a chemical reaction, because only the electrons were
rearranged.
C. This is a nuclear reaction, because there was a change in the
atoms' nuclei.
D. This is a chemical reaction, because mass was not conserved.
The reaction in which carbon combines with sulfur to form carbon
disulfide. Is
B. This is a chemical reaction, because only the electrons were rearranged.What is a chemical reaction?In a chemical reaction, bonds between molecules of the reactant are broken and new bonds between molecules of the product are established to create a new substance.
Chemical reactions occur all around us, including in our body's digestion of food and the creation of the sunlight's light. Understanding physical and chemical changes is crucial before starting any chemical reactions.
Sulfur and carbon combine to form carbon disulfide in an endothermic reaction that absorbs 92 kJ/mol of heat.
Learn more about carbon disulphide at:
https://brainly.com/question/16157463
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The reaction between dihydrogen sulfide and sulfur dioxide is outlined below. 2 H2S(g) S02(g) -Y 3 S(s) 2 H20(g) a. Identify the limiting reactant when 3.89 g of dihydrogen sulfide react with 4.11 g of sulfur dioxide. Justify your answer. d. Based on your answer from part (a), determine the maximum mass of sulfur that can be produced in this reaction. c. Ifthe actual yield of sulfur is found to be 4.89 g, find the percent yield in this reaction.
Answer:
Explanation:
2 H₂S(g) +S0₂(g) = 3 S(s) + 2H₂0(g)
2 x 34 g 64 g 3 x 32 g
68 g of H₂S reacts with 64 g of S0₂
3.89 g of H₂S reacts with 64 x 3 .89 / 68 g of S0₂
3.89 g of H₂S reacts with 3.66 g of S0₂
S0₂ given is 4.11 g , so it is in excess .
Hence H₂S is limiting reagent .
68 g of H₂S reacts with S0₂ to give 96 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
5.49 g of Sulphur is produced .
Actual yield is 4.89
percentage yield = 4.89 x 100 / 5.49
= 89 % .
Considering the reaction stoichiometry and the definition of percent yield:
a. H₂S will be the limiting reagent.
b. the maximum mass of sulfur that can be produced in the reaction is 5.49 grams.
c. the percent yield of the reaction is 89%.
The balanced reaction is:
2 H₂S(g) + SO₂(g) → 3 S(s) + 2 H₂O(g)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
H₂S: 2 molesSO₂: 1 moleS: 3 moles H₂O: 2 molesThe molar mass of each compound is:
H₂S: 34 g/moleSO₂: 64 g/moleS: 32 g/mole H₂O: 18 g/moleSo, by reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
H₂S: 2 moles× 34 g/mole= 68 gramsSO₂: 1 moles× 64 g/mole= 64 gramsS: 3 moles× 32 g/mole= 96 grams H₂O: 2 moles× 18 g/mole= 36 gramsa. Limiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 64 grams of SO₂ reacts with 68 grams of H₂S, 4.11 grams of SO₂ react with how much mass of H₂S?
[tex]mass of H_{2} S=\frac{4.11 grams of SO_{2}x 68 grams of H_{2} S }{64 grams of SO_{2}}[/tex]
mass of H₂S= 4.37 grams
But 4.37 moles of H₂S are not available, 3.89 grams are available. Since you have less mass than you need to react with 4.11 grams of SO₂, H₂S will be the limiting reagent.
b. Maximum mass of sulfur
Using the limiting reagent, you can apply the following rule of three: if by stoichiometry 68 grams of H₂S produce 96 grams of S, 3.89 grams of H₂S will produce how much mass of S?
[tex]mass of S=\frac{96 grams of Sx 3.89 grams of H_{2} S }{68 grams of H_{2}S}[/tex]
mass of S= 5.49 grams
So, the maximum mass of sulfur that can be produced in the reaction is 5.49 grams.
c. Percent yieldThe amount of product that is obtained when all the limiting reagent reacts. This is called the theoretical yield of the reaction. That is, the theoretical yield is the maximum amount of product that can be produced in a reaction.
On the other hand, the actual yield is the amount of product actually obtained from a reaction.
The percent yield determines the efficiency of the reaction, and describes the ratio of the actual yield to the theoretical yield:
[tex]percent yield=\frac{actual yield}{theoretical yield}x100[/tex]
In this case, you know:
actual yield= 4.89 gtheoretical yield= 5.49 gSo, the percent yield can be calculated as:
[tex]percent yield=\frac{4.89 grams}{5.49 grams}x100[/tex]
Solving:
percent yield= 89%
Finally, the percent yield of the reaction is 89%.
Learn more about reaction stoichiometry:
brainly.com/question/16487206?referrer=searchResults brainly.com/question/14446695?referrer=searchResults brainly.com/question/11564309?referrer=searchResults brainly.com/question/4025026?referrer=searchResults brainly.com/question/18650135?referrer=searchResultswhat characteristics of a metallic bond explains some of the properties of metals
Answer:
See Explanation
Explanation:
Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.
The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.
Due to the nature of the bonding between metal atoms,metals are malleable and ductile.
Due to the strong electrostatic interaction between metal ions and electrons, the metallic bond is very strong and is very difficult to break thereby accounting for the greater strength of metals as the size of the metallic ion decreases.
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Answer:
412 g Cl₂
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
[Given] 3.50 × 10²⁴ molecules Cl₂
[Solve] grams Cl₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})[/tex][DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 412.072 \ g \ Cl_2[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
412.072 g Cl₂ ≈ 412 g Cl₂
What type of climate conditions are needed to form coal deposits.
Answer:
Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).
Sub-types: Cannel coal
Child material class: Lignite
Explanation:
Which of the following is the weakest of the intermolecular forces?
A.Hydrogen bonds
B. Dipole-dipole interactions
C. Dipole-hydrogen interactions
D. London dispersion force
Answer:c
Explanation:yes
Why is it important to make sure that the endpoint is noted accurately in titration?
In the oxidation of ethane: 2 C2H6 + 7 02 → 4 CO2 + 6 H2O how many
liters of O2 are required to react with 90 grams of ethane?
Answer:
10.5 L of O₂.
Explanation:
We'll begin by calculating the number of mole in 90 g of C₂H₆. This can be obtained as follow:
Molar mass of C₂H₆ = (12×2) + (6×1)
= 24 + 6
= 30 g/mol
Mass of C₂H₆ = 90 g
Mole of C₂H₆ =?
Mole = mass / molar mass
Mole of C₂H₆ = 90 / 30
Mole of C₂H₆ = 3 moles.
Finally, we shall determine the volume of O₂ required. This is illustrated:
2C₂H₆ + 7O₂ —> 4CO₂ + 6H₂O
From the balanced equation above, we can say that:
2 L of C₂H₆ required 7 L of O₂.
Therefore, 3 L of C₂H₆ will require
= (3 × 7)/ 2 = 10.5 L of O₂.
Thus, 10.5 L of O₂ is required for the reaction.
Real world scenario: cancer prevention
Answer:
for skin cancer use sunscreen but for cancer that's most common eat healthy and take vitamins as much as you can.
Explanation:
Which of the following factors would affect weather?
When warm air meets cool air, the warm air rises, cools off, and falls as rain.
Air moves as wind from an area of high pressure to an area of low pressure.
Air stays awhile over a surface area with uniform humidity and temperature.
All of the above
Answer: Hewo, there!
All of the above wold be my answer
Explanation:
Although many factors combine to influence weather, the four main ones are solar radiation, the amount of which changes with Earth's tilt, orbital distance from the sun and latitude, temperature, air pressure and the abundance of water.
Hope this helps you!!
Have a great day
which solution has a higher percent ionization of the acid , a .10 M solution of HC2H3O2 (aw) or a .010 M solution of HC2H3O2(aq)
Answer:
0.0010 M of HC2H302(aq)
Thorium-236 has a half life of 10.0 minutes. If I have 250 grams of Thorium-236, How many half lives will have taken place after 50.0 minutes?
A metal forms two oxides X and Y when contains 28.9% and 21.0% oxygen respectively.
a) calculate the ratio by mass of metal in the two oxides
b) what chemical law does it illustrate
Please help no Link please
What happens to the entropy when a solution is made?
A. The entropy increases.
B. The entropy decreases.
C. The entropy goes to zero.
D. The entropy is unaffected.
Answer:
The entropy increases
Explanation:
Just took the quiz
One way to remove the pollutant nitrogen monoxide, NO, from mobile diesel exhaust is by reacting it with ammonia, NH, as seen in the balanced reaction below. What mass, in grams, of NH, is required to remove 57.0 grams of NO from the air? 4 NH3 + 6 NO → 5 N, + 6H2O
Answer:
[tex]m_{NH_3}=21.6gNH_3[/tex]
Explanation:
Hello there!
In this case, in agreement to the given chemical reaction, it is possible for us to calculate the mass of NH3 required to remove 57.0 g NO via the stoichiometry based off the 4:6 mole ratio between them:
[tex]m_{NH_3}=57.0g NO*\frac{1molNO}{30.01gNO}*\frac{4molNH_3}{6molNO} *\frac{17.03gNH_3}{1molNH_3} \\\\m_{NH_3}=21.6gNH_3[/tex]
Best regards!
While playing hockey in gym class, Timmy is trying to send a plastic puck across the floor and into the goal. Which of the following best describes the forces acting on the plastic puck as it travels across the floor and into to the goal? A.-electromagnetic and gravity. B-.gravity and friction. C.-mechanical force and friction. D-.magnetism and friction
NO LINKS.....pls!
Answer:
The answer is gravity and friction.
Explanation:
Answer the above pic
i bet no one can solve this correctly with steps
Answer:
solution given:
log k=4-[tex] \frac{200}{t} [/tex]
so,
On comparison
∆S°/R = 4
∆ S° = 4R
mousam brother is correct
hope it helps you have a good day
For the gaseous reaction below, the Kc value is 3.67. What is the Kp value at the same temperature? CO2 + H2 = CO + H20
Answer:
3.67
Explanation:
Step 1: Write the balanced equation
CO₂(g) + H₂(g) = CO(g) + H₂O(g)
Step 2: Calculate the value of the pressure equilibrium constant (Kp)
The concentration equilibrium constant (Kc) is 3.67.
We can calculate the value of the pressure equilibrium constant using the following expression.
[tex]Kp = Kc \times (R \times T)^{\Delta n(g)}[/tex]
where,
R: ideal gas constant
T: absolute temperature
Δn(g): moles of gaseous products - moles of gaseous reactants
Δn(g) = 2 mol - 2 mol = 0
Then,
Kp = Kc × (R × T)⁰ = Kc = 3.67
If 1.00 g of KCl is completely dissolved in 24.5 g of water, what is the percent composition (by mass) of the solution that is formed?
Answer:
3.92%
Explanation:
The solution that is formed is of KCl in water. This means that the percent composition by mass is given by the formula:
Mass of KCl / Mass of Solution * 100%We now calculate the mass of solution:
Mass of Solution = Mass of KCl + Mass of Water = 1.00 g + 24.5 gMass of Solution = 25.5 gFinally we calculate the percent composition:
1.00 g / 25.5 g * 100% = 3.92%What is the correct definition of temperature
Answer:
i'm pretty sure its the last answer and if not its the 2nd one
please help i don’t know this:(
Answer:
29.5 days
Explanation:
orginally 27.3 days but 29.5 days is also correct