What is the most descriptive name for the illustration below?

A. quadrilateral
B. polygon
C. rhombus
D. trapezoid

The graph of y=|x| is a v-shaped graph that starts at the origin and continues infinitely in both the positive and negative x-directions. The graph of y=|x|+2 is the same v-shaped graph, but it has been shifted up two units so that it no longer intersects the x-axis. Finally, the graph of y=|x|-1 is a v-shaped graph that has been shifted down one unit so that it intersects the x-axis at (1,0) and (-1,0). All three graphs are symmetric with respect to the y-axis.

The gross premium for the endowment insurance is 73.

To calculate the gross premium for the endowment insurance, we can use the equivalence principle, which states that the present value of the premiums must equal the present value of the benefits.

We can break down the problem into two parts: the present value of the death benefit and the present value of the endowment benefit.

First, let's calculate the present value of the death benefit. The death benefit is payable at the moment of death, and the probability of dying at age x is given by qx, where qx is the probability of surviving to age x.

Since deaths are uniformly distributed between integral ages, we can assume that deaths occur at the midpoint of the age interval. Therefore, the probability of dying at age x can be approximated by

.

Let's denote the present value of the death benefit as DB. Using the equivalence principle, we can write:

DB = A*(1+0.35) - E0 - C1 - 0.05A(1+0.05)

- 0.05A(1+0.05)

- ... - 0.05A(1+0.05)

where A is the annual premium, E0 is the expense paid at the beginning of the first year, and C1 is the commission and tax paid at the beginning of the first year.

The factor (1+0.35) accounts for the commission and tax on the first year premium.

Using the formula for the present value of a perpetuity, we can simplify the above equation to:

DB =

= 116.22

where q65/2 is the probability of dying at age 65. We can obtain q65/2 from the Illustrative Life Table, which gives

q65/2 = 0.112488.

Therefore, the gross premium for the endowment insurance is 73.

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The answer of the given question based on the experimental probability is the next pizza sold at Downtown Pizza will have pepperoni is 2/3 or approximately 0.67.

Experimental probability is  ratio of number of times  event occurs to the total number of trials or observations conducted in  experiment or real-life situation. It is based on actual observations or data and is also known as empirical probability.

Experimental probability is used when it is not possible or feasible to determine the theoretical probability of an event, or when the theoretical probability does not match the actual outcomes observed in a given situation. In such cases, experimental probability provides an estimate of the likelihood of an event occurring based on real-life data.

The experimental probability that the next pizza sold will have pepperoni is the ratio of the number of pepperoni pizzas sold to the total number of pizzas sold in the recent past.

According to the problem, 4 of the last 6 pizzas sold had pepperoni. So, the experimental probability of the next pizza sold having pepperoni is:

experimental probability = number of pepperoni pizzas sold / total number of pizzas sold

experimental probability = 4 / 6

experimental probability = 2 / 3

Therefore, the experimental probability that the next pizza sold at Downtown Pizza will have pepperoni is 2/3 or approximately 0.67.

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The cost for wall-to-wall carpeting is equal to $ 318.

In this problem we need to compute the cost for wall-to-wall carpeting, that is, the cost of covering the floor of the entire room. This can be done by using the following formula:

C = (1 / 9) · c · w · l

Where:

If we know that c = 13.25, w = 12 and l = 18, then the cost of the wall-to-wall carpeting is:

C = (1 / 9) · 13.12 · 12 · 18

C = 318

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Answer:

To determine the scale factor used, we need to find the ratio of corresponding side lengths in both triangles.

Let's compare the length of the first side in both triangles:

x/3.8 = 2/4.8

Cross-multiplying, we get:

4.8x = 7.6

Dividing both sides by 4.8, we get:

x = 1.58

Now, let's compare the length of the second side in both triangles:

2.4/4.2 = 0.57

Finally, let's compare the length of the third side in both triangles:

2.1/4.8 = 0.44

Since the scale factor is the same for all corresponding side lengths, we can take the average of the ratios:

(scale factor) = (1.58/3.8 + 0.57 + 0.44)/3

(scale factor) = 1.01

Therefore, the scale factor used is approximately 1.

Answer: Well that wouldn't work quite as well.

Step-by-step explanation:

Answer:

8a^2 + 6ats - 2t^2s^2

Step-by-step explanation:

(4a-ts)(2a+2ts)

4a(2a+2ts) -ts(2a+2ts)

8a^2 + 8ats - 2ts - 2t^2s^2

= 8a^2 + 6ats - 2t^2s^2

The images best represents the result is image W.

We have, the image is rotated about the x-axis.

Now, rotating around x axis can give the other half of the image.

Also, rotating about x axis gives the mirror image of the figure.

So, the rotation leads to a circle.

and, In three dimensional we can say that Sphere.

Thus, the required image is W.

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a. To create a pie chart to show the total medal winnings of the Top 10 NOCs at the Beijing 2022 Winter Olympic games:

Obtain the data for the medal winnings of the Top 10 NOCs

Calculate the total medal winnings for each NOC (i.e., the sum of gold, silver, and bronze medals)

Create a pie chart in Excel or any other software by selecting the data and choosing the pie chart option

Add a title and labels to the chart to show the NOCs and their corresponding medal winnings

b. The interpretation of the pie chart produced in Question 8a) depends on the shape and distribution of the chart. Two probable justifications for the behavior of the data are:

Dominance of certain NOCs: The pie chart may show that certain NOCs have a significantly higher share of medal winnings compared to others. This may be due to the dominance of these NOCs in specific sports or events, or due to their superior training and preparation.

Balanced distribution of medals: The pie chart may show a relatively balanced distribution of medal winnings among the Top 10 NOCs. This may indicate a high level of competitiveness and equal opportunities for success among the NOCs.

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The increase in crime was caused by D. Both are the result of implementing social service programs.

Significant modifications made to a society's social and political structures can cause periods of instability and uncertainty, leading to a rise in crime rates. The daunting tasks of restructuring society that came with the abolishment of apartheid in South Africa and Germany's reunification represent examples of such changes.

When power structures, economic systems, and social norms abruptly shift, gaps in authority may arise, thereby presenting opportunities for criminal activity to escalate. Criminal elements can capitalize on these unexpected power vacuums.

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a. The basketball player is 19.50 cm tall. (Assuming you meant to write

195 cm instead of 1950 cm)

b. A new piece of chalk is about 81.00 cm long.

c. The speed limit in town is 40.0 km/hr. (Assuming you meant to write 40 km/hr instead of 400 km/hr).

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

By placing a decimal point in the appropriate location, we can make the numbers more reasonable.

a. The basketball player cannot be 1950 cm tall, as that is almost 20 meters or over 65 feet.

The average height of a basketball player in the NBA is around 6'7'' (or about 2 meters).

Therefore, we can assume that the correct height of the basketball player is 195 cm, or about 6'5''.

b. A piece of chalk that is 8100 cm long is over 80 meters long, which is clearly too long for a piece of chalk.

Therefore, we can assume that the correct length of the chalk is 81.00 cm or about 32 inches.

c. A speed limit of 400 km/hr is unreasonably high, as it is equivalent to over 248 miles per hour.

The highest speed limits in the world are typically around 80-85 mph (130-140 km/hr), so 400 km/hr is clearly incorrect.

Therefore, we can assume that the correct speed limit is 40.0 km/hr, which is a more reasonable speed limit for a town or residential area.

Hence,

a. The basketball player is 19.50 cm tall. (Assuming you meant to write

195 cm instead of 1950 cm)

b. A new piece of chalk is about 81.00 cm long.

c. The speed limit in town is 40.0 km/hr. (Assuming you meant to write 40 km/hr instead of 400 km/hr).

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The volume of the triangular base prism is  120 inches³.

The prism above is a triangular base prism. The volume of the triangular base prism can be calculated as follows:

volume of the prism = base area × height

Therefore,

base area = 1 / 2 bh

base area = 1 / 2 × 8 × 10

base area = 80 / 2

base area = 40 inches²

Therefore,

volume of the prism = 40 × 3

volume of the prism = 120 inches³

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10x² + 13x + 11 is the sum of linear equation .

What is a linear equation in mathematics?

The algebraic equation y=mx+b is known as a linear equation. All of its terms are constant, first-order linear ones. where m denotes the slope and b the y-intercept.

                             The aforementioned is occasionally referred to as a "linear equation in two variables" where y and x are variables. One or more variables may be present in a linear equation. The term "bivariate linear equation" refers to a linear equation with two variables.

two equations are  10x² + 7x + 6 and 6x + 5.

now add both equations

= (10x² + 7x + 6 )+ (6x + 5)

=  10x² + 7x + 6 + 6x + 5

= 10x² + 13x + 11

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It should be noted that to find the equation of a line, two pieces of information are necessary: the slope and coordinates of a point on the line.

Also, to acquire this, one can leverage either the point-slope form or the slope-intercept form to compose it.

If both the slope (m) and coordinates of the point  (x1, y1) on the line are known, then one can express the equation in its point-slope style as follows:

y - y1 = m(x - x1)

Or, if only the slope (m) and the y-intercept (b), which is the value of y where the line crosses the y-axis, are accessible, then the equation can be expressed via the slope-intercept form with: y = mx + b

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Answer: The 290 millimeters long is the ribbon.

Step-by-step explanation:

To convert centimeters to millimeters

1 cm =10 millimeters

therefore,

29cm= 290 millimeters

Therefore, the ribbon is 290 millimeters long.

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Answer:

Step-by-step explanation:

temperature is heated half an hour

19°c+71°c=90°c

{since its increased by 71°c}

90°c-[2°c*30]=30°c

The value of the derivative of the composite function h(x) = f[g(x)] is equal to h'(3) = 2.

In this problem we find a function in the form of a composite function of the form h(x) = f[g(x)], whose derivative is defined by the chain rule:

h'(x) = f'(g) · g'(x)

If we know that g'(3) = 2 and f'(2) = 1, then the exact value of the derivative of the composite function is:

h'(3) = 2 · 1

h'(3) = 2

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Answer:

1.  CON (convenience sampling) - This sampling technique involves selecting participants who are readily available and willing to participate. In this case, the researcher is only selecting from their 5th period class, which is not a representative sample of the entire student population.

2.  SYS (systematic sampling) - This sampling technique involves selecting every nth element from a population. In this case, the researcher is selecting every 15th student on their list of the entire school population.

3.  R (random sampling) - This sampling technique involves selecting participants at random from the population. In this case, the researcher is using a random number table to generate two-digit numbers and selecting 10 people from the population.

Hope this helps!

Answer:

1.  CON (convenience sampling) - This sampling technique involves selecting participants who are readily available and willing to participate. In this case, the researcher is only selecting from their 5th period class, which is not a representative sample of the entire student population.

2.  SYS (systematic sampling) - This sampling technique involves selecting every nth element from a population. In this case, the researcher is selecting every 15th student on their list of the entire school population.

3.  R (random sampling) - This sampling technique involves selecting participants at random from the population. In this case, the researcher is using a random number table to generate two-digit numbers and selecting 10 people from the population.

Hope this helps!

Answer:

102

Step-by-step explanation:

34 is d so 34×3=102

pls correct me if im wrong

The weighted mean of the deliveries each week can be found to be 5. 38 .

The weighted mean is a type of mean that takes into account, the weight of the various items in question.

First, find the total frequency :

= 1 + 5 + 4 + 3

= 13

The weighted mean would then be:

= ∑ ( weight of delivery x number of deliveries )

= ( 1 / 13 x 2 ) + ( 5 / 13 x 4 ) + ( 4 / 13 x 6 ) + ( 3 / 13 x 8 )

= 0. 15  + 1. 54 + 1. 84 + 1. 85

= 5. 38

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There are four possible outcomes in this game: winning $1, winning $5, winning $10, or winning $0.

The probability of winning $1is the probability of drawing one of the 11 hearts that are not the ace of hearts. There are 52 cards in the deck, so the probability of drawing any one of them is 1/52. However, there are 11 hearts that win $1, so the probability of winning $1 is:

P(W = $1 ) = 11/52

The probability of winning $5 is the probability of drawing the ace of hearts, which is 1/52.

P(W = $5) = 1/52

The probability of winning $10 is the probability of drawing the king of spades, which is also 1/52.

P(W = $10) = 1/52

The probability of winning $0 is the probability of drawing any other card, which is 39/52.

P(W = $0) = 39/52

the Correct option of  coordinates of polygon A′B′C′D′ if polygon ABCD is rotated 90° counterclockwise is A

A coordinate is a set of numbers that represents the position of a point in space. It is often used to describe the location of a point on a graph or a map

To determine the coordinates of polygon A′B′C′D′, we need to rotate each vertex of polygon ABCD 90° counterclockwise.

We can do this by using the following formulas for a 90° counterclockwise rotation of a point (x, y):

x' = -y

y' = x

Using these formulas, we can find the coordinates of each vertex of polygon A′B′C′D′ as follows:

A′(0, 0): Since (0, 0) is the origin, a 90° counterclockwise rotation will still result in (0, 0).

B′(-2, 5): To rotate the point (5, 2) 90° counterclockwise, we have x' = -y = -2 and y' = x = 5. So, B′ is (-2, 5).

C′(5, 5): To rotate the point (5, -5) 90° counterclockwise, we have x' = -y = 5 and y' = x = 5. So, C′ is (5, 5).

D′(3, 0): To rotate the point (0, -3) 90° counterclockwise, we have x' = -y = 0 and y' = x = 3. So, D′ is (3, 0).

Therefore, the coordinates of polygon A′B′C′D′ are A′(0, 0), B′(-2, 5), C′(5, 5), and D′(3, 0).

So, the answer is A) A′(0, 0), B′(−2, 5), C′(5, 5), D′(3, 0).

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Answer: ∠EFB, ∠DFE, and ∠CFB

Step-by-step explanation:

Starting Angle: ∠CFD

Since its in an X formation: ∠EFB, ∠DFE, and ∠CFB would all work.

As we have shown that both AE is congruent to CE and BE is congruent to DE.

Now, let's focus on the diagonals of the parallelogram, AC and BD. We are told that they intersect at point E.

To prove that AE is congruent to CE, we can use the fact that opposite sides of a parallelogram are congruent. Since AC is a diagonal of the parallelogram, it divides it into two congruent triangles, AEC and CED. This is because AE is parallel to CD (as they are opposite sides of the parallelogram), and EC is common to both triangles.

Therefore, by the Side-Angle-Side (SAS) congruence theorem, we can conclude that triangle AEC is congruent to triangle CED. In particular, this means that AE is congruent to CE.

Similarly, to prove that BE is congruent to DE, we can use the same reasoning. Since BD is a diagonal of the parallelogram, it divides it into two congruent triangles, AEB and DEC. This is because BE is parallel to AC (as they are opposite sides of the parallelogram), and ED is common to both triangles.

Therefore, by the SAS congruence theorem, we can conclude that triangle AEB is congruent to triangle DEC. In particular, this means that BE is congruent to DE.

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An compound inequality that describes the acceptable weights for a 20 oz box is 19.25 ≤ x ≤ 20.75.

We have,

The absolute value of a number is defined as its magnitude irrespective of the sign of the number. To determine the absolute value of a real number, we consider only the number and remove the sign. It can only be a non-negative value.

We are Given that, cereal manufacturer has a tolerance of 0.75 oz for a box of cereal that is supposed to weigh 20 oz.

Let the weight of cereal box be; w

Now, the inequality is

20-0.75 ≤ x ≤ 20+0.75

Add 20 on both sides of an inequality, we get

19.25 ≤ x ≤ 20.75

Here, 19.25 ≤ x ≤ 20.75

Therefore, an absolute value inequality to find the range of acceptable weights is 19.25 ≤ x ≤ 20.75.

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The equation of the transformed logarithmic function that passes through the points (1,0) and (-3,3) is f(x) = 4.366*log10(x+4)

To find the equation of the transformed logarithmic function that passes through the points (1,0) and (-3,3), we need to determine the values of a, b, h, and k.

First, we know that the function passes through (1,0), so we can substitute x=1 and y=0 in the general equation of the transformed logarithmic function to get:

0 = a x log b(1-h) + k

Since log b(1-h) = 0 for any base b and any value of h, we can simplify the equation to:

0 = k

Therefore, k=0 and the equation becomes:

f(x) = a x log b(x-h)

Now, we have two equations with two unknowns (a and h), which we can solve by substitution or elimination. For simplicity, we can substitute b=10 (base 10 logarithm) since it is a common base and the values of a and h do not depend on the base of the logarithm. We get:

10⁶/ᵃ = 3-h

Since h is the horizontal shift of the graph, we can choose any value of h that makes the expression inside the logarithm positive. For example, we can choose h=-4, which makes x-h=-3-(-4)=1, the same as the x-coordinate of the point (1,0).

Taking the logarithm of both sides with base 10, we get:

log(4) = (6/a)*log(10)

Solving for a, we get:

a = 6/(log(4)*log(10)) ≈ 4.366

Now, we can substitute the values of a and h in the equation of the transformed logarithmic function to get:

f(x) = 4.366*log10(x+4)

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All the correct values are,

⇒ ∠ABD = 60°

⇒ ∠ADB = 90°

⇒ ∠BAD = 30°

⇒ ∠CAD = 30°

⇒ BD = 3

⇒ AD = √27

⇒ The value of area of triangle ABC is, 3√27

Given that;

In the diagram shown, ABC is equilateral. AD is an altitude.

Hence, We get;

All the angles of a equilateral triangle are,

⇒ 60°

Thus, We get;

⇒ ∠ABD = 60°

Since, AD is an altitude.

⇒ ∠ADB = 90°

And,

⇒ ∠BAD = 60 / 2 = 30°

⇒ ∠CAD = 60/2 = 30°

By Pythagoras theorem;

AB² = AD² + BD²

6² = AD² + 3²

36 = AD² + 9

AD² = 27

AD = √27

Thus, The value of area of triangle ABC is,

⇒ 1/2 × AD × BC

⇒ 1/2 × √27 × 6

⇒ 3√27

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The probability that an 18-year-old man picked at random is taller than 74 inches is approximately 0.0228 or 2.28%.

We have,

We can use the standard normal distribution to solve this problem by standardizing the height value using the formula:

z = (x - μ) / σ

where:

x = the height value (in inches)

μ = the mean height (in inches)

σ = the standard deviation (in inches)

Substituting the given values, we get:

z = (74 - 68) / 3

z = 2.0

Using a standard normal table or calculator, we can find the probability that a random standard normal variable is greater than 2.0 to be approximately 0.0228.

Therefore,

The probability that an 18-year-old man picked at random is taller than 74 inches is approximately 0.0228 or 2.28%.

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