What is the name of the compound Cd(MnO4)2?
A
cadmium manganate
B.
cadmium manganite
C.
cadmium permanganate
O
D.
admium permanganite

Answers

Answer 1
C ) cadmium permanganate

Related Questions

Which is a reason to use rate laws?
A. to investigate how the pressure of liquids affects reaction rates
B. to find the new rate when the concentration of reactants changes
C. to calculate the molecular weight of compounds in a reaction
D. to find the number of moles of solute that are dissolved in 1 L of solution

Answers

Answer:

B

Explanation:

to find the new rate when the concentration of reactants changes

Which of the following is a metal?


a.
silicon, Si, Z = 14

b.
phosphorus, P, Z = 15

c.
thallium, Tl, Z = 81

d.
arsenic, Z = 33

e.
nitrogen, N, Z = 7

Answers

Answer:

A.................. I think the answer

Why are diamonds unevenly distributed on Earth?

Soil forms only in places where rock particles are deposited.
Soil forms only in places where larger rocks are broken into smaller rocks.
Soil forms only within the Earth under heavy pressure.
Soil forms in the air and is then deposited mainly in places that get a lot of rain.

Answers

Answer:

Why aren't diamonds found evenly distributed on Earth? Diamonds are only formed under specific conditions that involve geological processes, such as volcanic activities and plate movements. Since these conditions and processes only take place in certain areas, you can only find diamonds in these special places.

Explanation:

Which of the following is NOT a benefit of strength training? WILL GIVE BRAINLIEST! :)

A. Better control of muscle

B. More efficient movement

C. Decreased force variance

D. Increased flexibility

Answers

I think it's D

Explanation:

if you think abt it strength training means weights and stuff so I dont think it increases flexibility. it's that or letter C

Which ecosystem is the least stable?
A. A rain forest
B. A cornfield
C. A savanna
D. A coral reef

Answers

C. Savanna is the correct answer

18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work

Answers

Answer:

[tex]\boxed {\boxed {\sf 976.5 \ Joules}}[/tex]

Explanation:

We are asked to find the heat energy. Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

[tex]q=mc\Delta T[/tex]

Where m is the mass, c is the specific heat, and ΔT is the change in temperature.

We know this is a 35.0 gram piece of wire, the temperature changes from 21 °C to 52°C and the specific heat is 0.900 J/ g °C.

Therefore,

m= 35.0 gc= 0.900 J/g °CΔT= 52 °C - 21°C= 31°C

Substitute these values into the formula.

[tex]q= (35.0 \ g)(0.900 \ J/g \ \textdegree C)(31 \textdegree C)[/tex]

Multiply the first two values. The grams will cancel each other out.

[tex]q=31.5 \ J/ \textdegree C (31 \textdegree C)[/tex]

Multiply again. This time, the degrees Celsius cancel each other out, so the final units are Joules.

[tex]q=976.5 \ J[/tex]

976.5 Joules of energy were required to heat the piece of metal.

How many grams are present in 3.4
moles of CH2COOH?
Show all work

Answers

Answer:

m = 200.6 gr

Explanation:

CH2COOH : n = 3.4 mol

Mr = 12 + 2 + 12 + 2×16 + 1 = 59

n= m / Mr => m = n× Mr => m = 3.4×59 => m = 200.6 gr


1 Write the chemical symbols for following elements: Nitrogen-
Phosphorus- bromine- Zinc-Potassium-Magnesium.

Answers

Answer:

I think

Explanation:

N for nitrogen

P for phosphorus

Br for bromine

K for potassium

Mg for magnesium

Last time I'm asking this, answer, this time, 50 points.
Think about a single cell and its parts; for example, think about a cell inside the human body. Now, select an everyday object that could be used as a model for a cell and its parts. In words and/or pictures, describe your model and how it is like the cell.

Answers

Explanation:

Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?

what is the electrolysis of water

Answers

the process of using electricity to decompose water into oxygen and hydrogen gas.

solution with low concentration of hydrogen ions have a __________ ph .

Answers

Answer:

6.37

Explanation:

Answer:

high ph

Explanation:

if you have high conc of H+ ph is low therefore acidic but if vice versa basic

high ph

the desity of gold is 19.3 g/cm3. what is the volume of a 13 g gold nugget .

Answers

Answer:

0.67 cm³

Explanation:

We can solve this problem by using the definition of density:

Density = Mass / Volume

We can rearrange the equation and isolate volume:

Volume = Mass / Density

As we are given both the mass and the density, we can now calculate the volume:

Volume = 13 g ÷ 19.3 g/cm³Volume = 0.67 cm³

PLEASE HURRY IM TIMED I WILL GIVE BRAINYEST
What is another name for the sunlit zone of the ocean?

A twilight zone

B abyssal zone

C photic zone

D benthic zone

Answers

Answer:

The answer is the C. Photic zone.

Explanation:

I wish you good luck! :>

Answer: C photic zone

Explanation:

Try moving an electron from the metal to the non metal.What happens?

Answers

Answer:

Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.

Explanation:

In alpha decay, the parent nucleus loses an alpha particle, which is two protons and two neutrons.

a. True
b. False

Answers

Answer:

True

Explanation:

In an alpha decay, the isotope of an element releases two protons and two neutrons. An alpha particle or helium has two protons and two neutrons and hence, in an alpha decay an alpha particle is released.

Hence, the given statement is true

I will mark brainliest
What kind of weather forms with an occluded front?

Answers

Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.

Explanation:

Occluded fronts usually form when the area is of low atmospheric pressure.

According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s - Al2S3

Answers

Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles[/tex]

The balanced chemical equation is:

[tex]2Al+3S\rightarrow Al_2S_3[/tex]  

According to stoichiometry :

3 moles of [tex]S[/tex] require = 2 moles of [tex]Al[/tex]

Thus 3.125 moles of [tex]S[/tex] will require=[tex]\frac{2}{3}\times 3.125=2.08moles[/tex]  of [tex]Al[/tex]  

Mass of [tex]Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g[/tex]

Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

What is the frequency of a light source that has a wavelength of 430 NM? What is the energy of this wave?​

Answers

Answer:

Explanation:

[tex]c = f \lambda[/tex]

where c = speed of light (3x10^8m/s)

f = frequency

[tex]\lambda[/tex] = wavelength.

We can solve that the frequency is (3x10^8)/(420 x 10^-9) = 7.14x10^14 Hz

Also, E  = hf where h = 6.62x10^-34.

So the energy is (6.62x10^-34) x  (7.14x10^14) = 4.73x10^-19 J.

Hope this helps and tell me if I made any mistakes.

When i make an account for different college can I use the same email username for each one or do I have make a different username email

Answers

Answer:

No you have to use a new email unless you delete the other accaount

Explanation:

hope that helps

In the laboratory, a general chemistry student measured the pH of a 0.341 M aqueous solution of benzoic acid, C6H5COOH to be 2.351. Use the information she obtained to determine the Ka for this acid.

Answers

Answer:  [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]

Explanation:

[tex]C_6H_5COOH\rightarrow H^+C_6H_5COO^-[/tex]

 cM                    0             0

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]          

So dissociation constant will be:

[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Give c= 0.341 M and = 2.351

[tex]K_a=?[/tex]

[tex]pH=-log[H^+][/tex]

[tex][H^+]=10^{-2.351}=0.0044[/tex]

[tex][H^]=c\alpha=0.0044[/tex]  

[tex]K_a=\frac{(0.0044)^{2}}{0.341-0.0044}[/tex]  

[tex]K_a=5.75\times 10^{-5} [/tex]

Thus [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]

Silver sulfate dissociates into silver ions and sulfate ions:
Ag2SO4(s) = 2Ag+ (aq) + SO42- (aq)
Which of the following equations is the equilibrium constant expression for
this reaction?
A. Kot
[Ag+][80.21
[Ag 2504)
O B. Ko = [Ag+ 12 [5042")
[A92504)
O C. KE =
[Ag+1?[s042-7
O D. KG
[A92504
[Ag+ ][5042-)

Answers

Answer:

A its a step by step equation the answer is A

36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide. (b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. (c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. (d) Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Answers

Answer:

a) 2Cu(s) + S(s) → Cu₂S(s)

b) 2SO₂(g) + O₂(g) → 2SO₃(g)

c) 4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

Explanation:

First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.

a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.

Reactants: solid copper (Cu(s)) and solid sulfur (S(s)). Product: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.

The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:

2Cu(s) + S(s) → Cu₂S(s)

(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.

Reactants: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). Products: sulfur trioxide gas (SO₃(s)).

The balanced equation is:

2SO₂(g) + O₂(g) → 2SO₃(g)

We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.

(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.

Reactants: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). Products: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).

The balanced chemical equation is:

4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).

The balanced chemical equation is:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).

Use the following chemical equation, how many moles of ammonia (NH 3 ) produced when 3.15 moles of nitrogen (N 2 ) reacts with hydrogen (H 2 ) ? N 2(g) + 3H 2(g) 2NH 3(g)

Answers

Answer:

[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to use the 1:2 mole ratio of nitrogen to ammonia to calculate the moles of the latter that are produced when reacting 3.15 moles of the former with hydrogen as shown below:

[tex]n_{NH_3}^{produced}=3.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]

Thus, by solving the equation we obtain:

[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]

Best regards!

What type of reaction is this? FeSO4 + Al(OH)3 → Al2(SO4)3 + Fe(OH)2

Answers

This is a double replacement reaction
Explanation:
There are two compounds on the left side that switch and make new compounds on the right side

i need help help me please

Answers

Answer:

C is the correct answer.

Explanation:

We can eliminate some answers immediately:

A is incorrect because nitrogen and hydrogen do not change their identity, they just combine into a new molecule that contains them. Notice how there are 2 nitrogen atoms and 6 hydrogen atoms on both sides of the equation.

B is incorrect because the first law of thermodynamics tells us that matter and energy will always be conserved, so the mass of the products must be equal to the mass of the reactants, not less than the mass of the reactants.

C is correct because balanced chemical equations help chemists predict how much product will form from certain amounts of reactants.

D is incorrect because this equation is showing the exact opposite. Molecular hydrogen and nitrogen can combine stoichiometrically to form ammonia.

What is the vapor pressure of an aqueous solution that has a solute mole fraction of 0.1000? The vapor pressure of water is 25.756 mmHg at 25 °C.​

Answers

Answer:

χsolvent = 1.0000 - 0.1000 = 0.9000

Use Raoult's Law:

Psolution = (χsolvent) (P°solvent)

x = (0.900) (25.756)

x = 23.18 mmHg (to four sig figs)

The vapor pressure of an aqueous solution is  x = 23.18 mmHg (to four sig figs)

χsolvent = 1.0000 - 0.1000 = 0.9000

Use Raoult's Law:

P solution = (χsolvent) (P°solvent)

x = (0.900) (25.756)

x = 23.18 mmHg (to four sig figs)

What is an aqueous solution?

An aqueous answer is one in which the solvent is liquid water. that is, solute (dissolved) ions and molecules are surrounded by water molecules and integrated into the network of bonds within the water. The dissolved species then spread in the course of the water.

A solution wherein water is the solvent is called an aqueous solution. although water is an exceptional solvent, now not the whole thing dissolves comfortably in the water.

Aqueous' in a chemical equation suggests that the cloth dispersed in water (an answer in water). As an example, when we pour sodium hydroxide answer into dilute hydrochloric acid, we get an aqueous solution of sodium chloride. The liquid is used to signify the formation of liquid materials in response.

Learn more about the aqueous solution here: https://brainly.com/question/19587902

#SPJ2

Your teacher gives you 0.09 L of a 0.850 M solution of NaCl dissolved in water. What will the new volume be if you dilute it down to 0.500 M?

Answers

Answer:

[tex]V_2=0.153L[/tex]

Explanation:

Hey there!

In this case, according to the equation for dilution process, in which the moles of the solute remain the same after the addition of additional solvent:

[tex]M_1V_1=M_2V_2[/tex]

Thus, by solving for the new volume, V2,  of the base, NaOH, we can obtain:

[tex]V_2=\frac{M_1V_1}{M_2}=\frac{0.09L*0.850M}{0.500M}\\\\V_2=0.153L[/tex]

Best regards!

What is the molarity of a 9.79 L solution that contains 0.400 mol HCI

Answers

Answer:

0.041 M

Explanation:

The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula

[tex]c = \frac{n}{v} \\ [/tex]

n is the number of moles

v is the volume in L

We have

[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]

We have the final answer as

0.041 M

Hope this helps you

How many grams of water can be heated from 15.0°C to 75°C using 12,500 Joules?

Answers

Answer:

m = 49.8 g

Explanation:

Hello there!

In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:

[tex]Q=mC\Delta T[/tex]

Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:

[tex]m=\frac{Q}{C\Delta T}\\\\m=\frac{12500J}{4.184\frac{J}{g\°C}(75\°C-15.0\°C)} \\\\m=49.8g[/tex]

Best regards!

How many moles of argon gas would be present in a 37.0 liter vessel at 45.00 °C at a pressure of 2.50 atm?

Answers

Answer:

3.54 mol

Explanation:

Step 1: Given data

Volume (V): 37.0 LTemperature (T): 45.00 °CPressure (P): 2.50 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 45.00°C + 273.15 = 318.15 K

Step 3: Calculate the number of moles (n) of argon gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol

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