What is the nature of the roots of the quadratic equation 4x²8x 9 0?

Answers

Answer 1

The nature of the roots of the quadratic equation 4[tex]x^{2}[/tex] - 8x + 9 =0 are imaginary.

given equation:

4[tex]x^{2}[/tex] - 8x + 9 =0

now we need to find the nature of the quadratic equation

nature of roots :

Case I: [tex]b^{2}[/tex] – 4ac > 0

When a, b, and c are real numbers, a ≠ 0 and the discriminant is positive, then the roots α and β of the quadratic equation ax2 +bx+ c = 0 are real and unequal.

Case II: [tex]b^{2}[/tex]– 4ac = 0

When a, b, and c are real numbers, a ≠ 0 and the discriminant is zero, then the roots α and β of the quadratic equation ax2+ bx + c = 0 are real and equal.

Case III: [tex]b^{2}[/tex]– 4ac < 0

When a, b, and c are real numbers, a ≠ 0 and the discriminant is negative, then the roots α and β of the quadratic equation ax2 + bx + c = 0 are unequal and not real. In this case, we say that the roots are imaginary.

Case IV: [tex]b^{2}[/tex] – 4ac > 0 and perfect square

When a, b, and c are real numbers, a ≠ 0 and the discriminant is positive and perfect square, then the roots α and β of the quadratic equation ax2 + bx + c = 0 are real, rational and unequal.

for the above given equation:

a = 4

b = -8

c = 9

=[tex]b^{2}[/tex] - 4ac

= [tex](-8)^{2}[/tex] - 4(4)(9)

= (56) -144

= -88< 0

the roots are imaginary

The nature of the roots of the quadratic equation 4[tex]x^{2}[/tex] - 8x + 9 =0 are imaginary

To learn more about quadratic equation:

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Answers

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Answers

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Answers

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